Algebra 5 Point 6
- 3. How would we graph |x| = 2? The equation |x| = 2 can be written as the disjunction: x = 2 or x = -2
- 4. Solve: |x – 1| = 3 Rewrite as x – 1 = 3 x – 1 = -3
- 6. Solve: -2|3y + 5| + 4 = 2 -2C3y+S)+4=2 -2f3ist5)+4-=2 -69-10+4=2 ??? ??? 9--43 -as-10+4=-2 -6cg-6=-z