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Section 2.2 
Graphing Linear Equations 
 Solutions of Equations in Two Variables 
 Graphing from a Table of Points 
 Graphing from the Intercepts 
 Horizontal & Vertical Lines 
 Linear Models
Solutions to Equations 
 A solution to an equation in two variables is any 
ordered pair of numbers (a,b) that makes a true 
statement when substituted into the equation. 
 Example: (2,7) is a solution to y = 3x + 1 
because 7 = 3(2) + 1 
 You can find solutions by choosing a value for one 
variable, then solving the equation for the other variable 
 Example: For y = 3x + 1 Let x = 9 
then y = 3(9) + 1 = 28 
and this solution is shown by (9,28)
Class Exercise – Finding Solutions 
5 
1 
y   x  
3 
 a.) What is the solution 
when x = 6 ? 
 b.) What is the solution 
when y = 5 ? 
    
   
3 
6 5 
1 
3 
2 5 
 
y 
y 
y 
1 
   
3 
  
  
x 
x 
x 
 
0 
1 
3 
0 
5 
5 5 
5
Why graph equations? 
 Consider the equation with two variables, 
y  2x 3 
 What will the solutions for this equation look like? 
 Ordered pairs: (x-value, y-value) (0,-3) for example 
 How many solutions are there? 
 Infinitely many
Definitions 
• The graph of an equation 
is the set of all points (x, y) on the rectangular 
coordinate system whose coordinates satisfy the 
equation. It is the visual solution set for the equation. 
• A linear equation in two variables 
is an equation that can be put into the form Ax+By=C 
(A and B can’t both be zero). 
The graph of a linear equation is always a line.
Rough Graphing 
 Plan to use about 
1/6 of a sheet 
of paper 
 Neatly draw the 
x-axis and y-axis 
 Label every 5 units 
15 
10 
5 
-15 -10 -5 0 5 10 15 
-5 
-10 
-15
Class Exercise – Graphing an Equation 
5 
1 
y   x  
3 
You already found two points: (6,3) and (0,5) 
 Find another point when x = -3 
 Use these 3 points to rough graph the equation
Graphing using 
The Intercept Method (“Cover-up Method”) 
1 
y   x  
 The y-intercept of a line is the point (0, b), where 
the line intersects the y-axis. 
 To find b, substitute 0 for x in the equation of the line and 
solve for y. 
 The x-intercept of a line is the point (a, 0), where 
the line intersects the x-axis. 
 To find a, substitute 0 for y in the equation of the line and 
solve for x. 
 Another Example: 7x – 14y = 35 
5 
3
In-Class Exercises: 
 Make a table of 3 points and use it to graph 
5 
2 
1 
y   x  
2 
 Graph using intercepts: 
4x 3y 12
How would you graph the following 
equations? 
y  3 
x  2
Horizontal & Vertical Lines 
 Is y = 3 a Linear Equation? 
 0x + y = 3 Yes! 
 Is x = 2 a Linear Equation? 
 x + 0y = 2 Yes! 
Graph: x = -5 y=-4 y = 0
Horizontal and Vertical Lines 
If a is any real number: 
The graph of x = a is a vertical line with x-intercept (a, 0) 
If a is 0, ( x = 0 ) the line is the y-axis. 
If b is any real number: 
The graph of y = b is a horizontal line with y-intercept (0, b) 
If b is 0, ( y = 0 ) the line is the x-axis.
Linear Models 
 We can use linear equations to mathematically model some real-life 
situations. This way we can use observations about what happened in the 
past to predict what might take place in the future.
Exercise 
56. TELEPHONE COSTS 
In a community, the monthly 
cost of local telephone service 
is $5 per month, plus 25¢ per call. 
a.Write a linear equation that gives the cost c for 
a. person making n calls. 
b. Then graph the equation. (need 2 points) 
c. Use the graph to estimate the cost of service in 
a month when 20 calls were made. 
c = 5 + .25n 
(0,?) -> (0,5) 
(10,?) -> (10,7.5)
What Next? 
 Present Section 2.3 
Rate of Change & Slope of a Line 
 Accessing these Powerpoint Slides from the Internet: 
http://faculty.rcc.edu/vandewater/Section02_2.ppt 
Click on Open

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Lecture 07 graphing linear equations

  • 1. Section 2.2 Graphing Linear Equations  Solutions of Equations in Two Variables  Graphing from a Table of Points  Graphing from the Intercepts  Horizontal & Vertical Lines  Linear Models
  • 2. Solutions to Equations  A solution to an equation in two variables is any ordered pair of numbers (a,b) that makes a true statement when substituted into the equation.  Example: (2,7) is a solution to y = 3x + 1 because 7 = 3(2) + 1  You can find solutions by choosing a value for one variable, then solving the equation for the other variable  Example: For y = 3x + 1 Let x = 9 then y = 3(9) + 1 = 28 and this solution is shown by (9,28)
  • 3. Class Exercise – Finding Solutions 5 1 y   x  3  a.) What is the solution when x = 6 ?  b.) What is the solution when y = 5 ?        3 6 5 1 3 2 5  y y y 1    3     x x x  0 1 3 0 5 5 5 5
  • 4. Why graph equations?  Consider the equation with two variables, y  2x 3  What will the solutions for this equation look like?  Ordered pairs: (x-value, y-value) (0,-3) for example  How many solutions are there?  Infinitely many
  • 5. Definitions • The graph of an equation is the set of all points (x, y) on the rectangular coordinate system whose coordinates satisfy the equation. It is the visual solution set for the equation. • A linear equation in two variables is an equation that can be put into the form Ax+By=C (A and B can’t both be zero). The graph of a linear equation is always a line.
  • 6. Rough Graphing  Plan to use about 1/6 of a sheet of paper  Neatly draw the x-axis and y-axis  Label every 5 units 15 10 5 -15 -10 -5 0 5 10 15 -5 -10 -15
  • 7. Class Exercise – Graphing an Equation 5 1 y   x  3 You already found two points: (6,3) and (0,5)  Find another point when x = -3  Use these 3 points to rough graph the equation
  • 8. Graphing using The Intercept Method (“Cover-up Method”) 1 y   x   The y-intercept of a line is the point (0, b), where the line intersects the y-axis.  To find b, substitute 0 for x in the equation of the line and solve for y.  The x-intercept of a line is the point (a, 0), where the line intersects the x-axis.  To find a, substitute 0 for y in the equation of the line and solve for x.  Another Example: 7x – 14y = 35 5 3
  • 9. In-Class Exercises:  Make a table of 3 points and use it to graph 5 2 1 y   x  2  Graph using intercepts: 4x 3y 12
  • 10. How would you graph the following equations? y  3 x  2
  • 11. Horizontal & Vertical Lines  Is y = 3 a Linear Equation?  0x + y = 3 Yes!  Is x = 2 a Linear Equation?  x + 0y = 2 Yes! Graph: x = -5 y=-4 y = 0
  • 12. Horizontal and Vertical Lines If a is any real number: The graph of x = a is a vertical line with x-intercept (a, 0) If a is 0, ( x = 0 ) the line is the y-axis. If b is any real number: The graph of y = b is a horizontal line with y-intercept (0, b) If b is 0, ( y = 0 ) the line is the x-axis.
  • 13. Linear Models  We can use linear equations to mathematically model some real-life situations. This way we can use observations about what happened in the past to predict what might take place in the future.
  • 14. Exercise 56. TELEPHONE COSTS In a community, the monthly cost of local telephone service is $5 per month, plus 25¢ per call. a.Write a linear equation that gives the cost c for a. person making n calls. b. Then graph the equation. (need 2 points) c. Use the graph to estimate the cost of service in a month when 20 calls were made. c = 5 + .25n (0,?) -> (0,5) (10,?) -> (10,7.5)
  • 15. What Next?  Present Section 2.3 Rate of Change & Slope of a Line  Accessing these Powerpoint Slides from the Internet: http://faculty.rcc.edu/vandewater/Section02_2.ppt Click on Open