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CONSEQUENCES OF MULTIPLYING A BALANCED EQUATION

                       BY A CONSTANT

                                    IN


   CHEMICAL EQUILIBRIUM
                                  FOR

                CAPE UNIT 1 STUDENTS

        (All content here applies to both Kc and Kp;
             temperature being held constant.)
             Compiled By Denison At Global In Cunupia. 739-2656.
YOU WILL LEARN

       To find K when a balanced
equation is multiplied by any constant.




          Compiled By Denison At Global In Cunupia. 739-2656.
FACT

   “When a balanced equation is
    multiplied by a factor, n, the
equilibrium constant is raised to that
      factor, i.e. it becomes Kn”



          Compiled By Denison At Global In Cunupia. 739-2656.
EXAMPLE
The value of the equilibrium constant for:

                          N2 + 3H2 ⇌ 2NH3

is K.




                 Compiled By Denison At Global In Cunupia. 739-2656.
EXAMPLE
The value of the equilibrium constant for:

                          N2 + 3H2 ⇌ 2NH3

is K.

What is the value of the equilibrium constant for:

                     1/2N2 + 3/2H2 ⇌ NH3 ?

A. √K       B. K/2              C. 2K                   D.K2

                 Compiled By Denison At Global In Cunupia. 739-2656.
SOLUTION
For the reaction N2 + 3H2 ⇌ 2NH3

Kc = K =      [NH3]2                       * The superscript 1 is
            [N2]1 [H2]3                      included for clarity only.




                Compiled By Denison At Global In Cunupia. 739-2656.
SOLUTION
For the reaction N2 + 3H2 ⇌ 2NH3

Kc = K =      [NH3]2                       * The superscript 1 is
            [N2]1 [H2]3                      included for clarity only.

And for the reaction 1/2N2 + 3/2H2 ⇌ NH3

K’c =         [NH3]1
            [N2]1/2 [H2]3/2



                Compiled By Denison At Global In Cunupia. 739-2656.
SOLUTION
For the reaction N2 + 3H2 ⇌ 2NH3

Kc = K =          [NH3]2                       * The superscript 1 is
                [N2]1 [H2]3                      included for clarity only.

And for the reaction 1/2N2 + 3/2H2 ⇌ NH3

K’c =             [NH3]1
                [N2]1/2 [H2]3/2

           and you can see that: K’c2 = Kc = K, so K’c = √K.

                    Compiled By Denison At Global In Cunupia. 739-2656.
EXTENDING THE CONCEPT
If the coefficients of the chemical equation are:

1. Doubled, the value of K is squared.




                 Compiled By Denison At Global In Cunupia. 739-2656.
EXTENDING THE CONCEPT
If the coefficients of the chemical equation are:

1. Doubled, the value of K is squared.
2. Halved, the value of K is replaced by its square root.




                 Compiled By Denison At Global In Cunupia. 739-2656.
EXTENDING THE CONCEPT
If the coefficients of the chemical equation are:

1. Doubled, the value of K is squared.
2. Halved, the value of K is replaced by its square root.
3. Multiplied by n, the value of K is raised to the nth power.




                 Compiled By Denison At Global In Cunupia. 739-2656.
END
                 Found this helpful?

     If so, follow me on facebook for more:


http://www.facebook.com/CAPEChemistryLessons




          Compiled By Denison At Global In Cunupia. 739-2656.

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Cape unit 1 chemistry equilibrium constant based on stoichiometry

  • 1. CONSEQUENCES OF MULTIPLYING A BALANCED EQUATION BY A CONSTANT IN CHEMICAL EQUILIBRIUM FOR CAPE UNIT 1 STUDENTS (All content here applies to both Kc and Kp; temperature being held constant.) Compiled By Denison At Global In Cunupia. 739-2656.
  • 2. YOU WILL LEARN To find K when a balanced equation is multiplied by any constant. Compiled By Denison At Global In Cunupia. 739-2656.
  • 3. FACT “When a balanced equation is multiplied by a factor, n, the equilibrium constant is raised to that factor, i.e. it becomes Kn” Compiled By Denison At Global In Cunupia. 739-2656.
  • 4. EXAMPLE The value of the equilibrium constant for: N2 + 3H2 ⇌ 2NH3 is K. Compiled By Denison At Global In Cunupia. 739-2656.
  • 5. EXAMPLE The value of the equilibrium constant for: N2 + 3H2 ⇌ 2NH3 is K. What is the value of the equilibrium constant for: 1/2N2 + 3/2H2 ⇌ NH3 ? A. √K B. K/2 C. 2K D.K2 Compiled By Denison At Global In Cunupia. 739-2656.
  • 6. SOLUTION For the reaction N2 + 3H2 ⇌ 2NH3 Kc = K = [NH3]2 * The superscript 1 is [N2]1 [H2]3 included for clarity only. Compiled By Denison At Global In Cunupia. 739-2656.
  • 7. SOLUTION For the reaction N2 + 3H2 ⇌ 2NH3 Kc = K = [NH3]2 * The superscript 1 is [N2]1 [H2]3 included for clarity only. And for the reaction 1/2N2 + 3/2H2 ⇌ NH3 K’c = [NH3]1 [N2]1/2 [H2]3/2 Compiled By Denison At Global In Cunupia. 739-2656.
  • 8. SOLUTION For the reaction N2 + 3H2 ⇌ 2NH3 Kc = K = [NH3]2 * The superscript 1 is [N2]1 [H2]3 included for clarity only. And for the reaction 1/2N2 + 3/2H2 ⇌ NH3 K’c = [NH3]1 [N2]1/2 [H2]3/2 and you can see that: K’c2 = Kc = K, so K’c = √K. Compiled By Denison At Global In Cunupia. 739-2656.
  • 9. EXTENDING THE CONCEPT If the coefficients of the chemical equation are: 1. Doubled, the value of K is squared. Compiled By Denison At Global In Cunupia. 739-2656.
  • 10. EXTENDING THE CONCEPT If the coefficients of the chemical equation are: 1. Doubled, the value of K is squared. 2. Halved, the value of K is replaced by its square root. Compiled By Denison At Global In Cunupia. 739-2656.
  • 11. EXTENDING THE CONCEPT If the coefficients of the chemical equation are: 1. Doubled, the value of K is squared. 2. Halved, the value of K is replaced by its square root. 3. Multiplied by n, the value of K is raised to the nth power. Compiled By Denison At Global In Cunupia. 739-2656.
  • 12. END Found this helpful? If so, follow me on facebook for more: http://www.facebook.com/CAPEChemistryLessons Compiled By Denison At Global In Cunupia. 739-2656.