The current I(t) flowing in a certain electrical circuit at time t is given by I(t) = E/R (l - e-Rt/L) where E, R, and L are positive numbers. Determine the limiting value of I(t) as R rightarrow 0+. Solution applying l hospital differentiating by r E (-t/L e^(-Rt/L)) / 1 now R=0 E(-t/L).