The empirical formula indicates the relative proportions of the elem.pdf
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The empirical formula indicates the relative proportions of elements in a molecule, not the actual number of atoms. The empirical formula for the molecule described is A1Br3, indicating it contains aluminum, bromine, and the subscripts show their relative amounts in the molecule. The empirical formula provides the simplest whole number ratio of the elements in a compound.
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The empirical formula indicates the relative proportions of the elem.pdf
Samantha Corporation Total Manufacturing OH 490,000 Fixed part of
manufacturing OH 190,000 Variable part of Manufacturing OH 300,000 Total
units produced 100,000 Variable Manufacturing OH /Unit 3 Selling
& Admin OH 520,000 Variable Selling & Admin @$4 /unit 400,000 Fixed
Selling & Admin 120,000 Break even analysis Details Product 1 Product 2
Material cost per unit 6 8 Direct Labor per unit
4 6 Variable Manufacturing OH per unit 3
3 Variable Selling & Admin OH per unit 4 4
Total Variable cost per unit 17 21 Selling Price/unit
24 32 Contribution margin /unit 7
11 Sales volume 60,000 40,000 Sales volume ratio 60%
40% Weighted contribution per unit =7*0.60+11*0.40 Weighted contribution per unit
= 8.60 Total Fixed cost Fixed part of manufacturing OH 190,000
Fixed Selling & Admin 120,000 Total Fixed cost 310,000 Weighted
contribution per unit 8.60 Break Even Units 36,047 Break Even units
Product 1 21,628 (at 60% ratio) Break Even units Product 2 14,419 (at 40%
ratio)
Solution
Samantha Corporation Total Manufacturing OH 490,000 Fixed part of
manufacturing OH 190,000 Variable part of Manufacturing OH 300,000 Total
units produced 100,000 Variable Manufacturing OH /Unit 3 Selling
& Admin OH 520,000 Variable Selling & Admin @$4 /unit 400,000 Fixed
Selling & Admin 120,000 Break even analysis Details Product 1 Product 2
Material cost per unit 6 8 Direct Labor per unit
4 6 Variable Manufacturing OH per unit 3
3 Variable Selling & Admin OH per unit 4 4
Total Variable cost per unit 17 21 Selling Price/unit
24 32 Contribution margin /unit 7
11 Sales volume 60,000 40,000 Sales volume ratio 60%
40% Weighted contribution per unit =7*0.60+11*0.40 Weighted contribution per unit
= 8.60 Total Fixed cost Fixed part of manufacturing OH 190,000
Fixed Selling & Admin 120,000 Total Fixed cost 310,000 Weighted
contribution per unit 8.60 Break Even Units 36,047 Break Even units
Product 1 21,628 (at 60% ratio) Break Even units Product 2 14,419 (at 40%
ratio).
There are two ways to solve this problem. I will .pdf
The ‘nuclei effect’ Cesium formate brine has a natural high density. The weight
comes from cesium ions rather than added particles, such as barite. In traditional OBMs, the
weighting agent is stopped at the well bore wall and forms a ?lter cake. With cesium formate the
problem of ?lter cakes are eliminated, however one needs to correct for the drilling ?uid that
?ltrates into the near formation. “The traditional logging tool algorithm is only good for elements
with atomic numbers less than roughly 24, which means that the element has one neutron for
every proton. Cesium, with an atomic number of 55, has considerably more neutrons than
protons in its nucleus. Therefore when measuring electron density, which is then used to
calculate bulk density, the algorithm should show an under-estimation of density due to this large
‘nuclei effect,’” explains Pedersen. “The only problem was that bulk density was over-
estimated,” he continues. So what was the explanation? “When going through the data I noticed
an intriguing correlation between the gamma logs and the photoelectric factor. To cut a long
story short, higher-numbered atomic elements, such as cesium, produce a dramatically higher
photoelectric effect. This increases the absorption of gamma rays in the formation so that the
electron density appears higher than it is and physical density is therefore over estimated. This
far outweighs the ‘nuclei effect’ previously mentioned,” says Pedersen. A simple solution Now
StatoilHydro understood why the logging results were wrong when interpreted using
methodology based on drilling ?uids with lower atomic numbers, the challenge was to ?nd a way
of interpreting the numbers accurately. The simplicity of the solution was stunning. After close
examination of the calibration data, a linear relationship was found between the photoelectric
factor (Pef) and the over-estimation of density. Consequently, by consistently adjusting bulk
density by the measured Pef, porosity was correctly calculated. “The beauty of this correction is
that it relies only on the Pef measurements, which are logged simultaneously with bulk density,
and can therefore apply to any cesium formate concentration,” says Pedersen. The perfect model
The logged photoelectric factor isn’t only useful for correcting the density curve and estimating
saturation of the invading ?ltrate, but is also ideal for de?ning permeable sands. Combining the
photoelectric factor and its high vertical resolution with resistivity measurements from both the
drill pass and ream pass produces a very reliable and accurate net reservoir de?nition.
Furthermore, by applying a conductive drilling ?uid based on cesium formate brine in all
production wells high-quality resistivity image logs can be run. These logs provide important
information on structural dip, depositional environment, sedimentary features, facies and
geological correlations, all used by geomodelers to produce better reservoir models. “The results
match cor.
If an oxide has the formula MO, then since O is normally found in th.pdf
I2 + 6H2O ---> 2HIO3 +10H+ +10e- HNO3 + 1H+ +1e- --->NO2 + H2O In order to balance
electrons, we have to multiply the reductionhalf-reaction by 10. This gives us: I2 +6H2O
+10HNO3 +10H++ 10e- ----> 2HIO3 + 10H+10NO2 +10H2O + 10e- We can cancel things that
are on the left and right side, likewater and protons. This gives us: I2 +10HNO3 ---->
2HIO3+10NO2 +4H2O Hope this helps, Steve
Solution
I2 + 6H2O ---> 2HIO3 +10H+ +10e- HNO3 + 1H+ +1e- --->NO2 + H2O In order to balance
electrons, we have to multiply the reductionhalf-reaction by 10. This gives us: I2 +6H2O
+10HNO3 +10H++ 10e- ----> 2HIO3 + 10H+10NO2 +10H2O + 10e- We can cancel things that
are on the left and right side, likewater and protons. This gives us: I2 +10HNO3 ---->
2HIO3+10NO2 +4H2O Hope this helps, Steve.
This is a titration of a weak base w a strong ac.pdf
This equation makes it able for you to plug-and-play the numbers.
Let\'s classify the variables first.
n is the number of people
p is the profit acquired
If you plug in p=0 (the situation when the profit is 0), you get
0 = 10(120-n)-50n
Now all you have to do is solve for n.
Solution
This equation makes it able for you to plug-and-play the numbers.
Let\'s classify the variables first.
n is the number of people
p is the profit acquired
If you plug in p=0 (the situation when the profit is 0), you get
0 = 10(120-n)-50n
Now all you have to do is solve for n..
1. True2. I am having trouble understanding the phrasing. A precip.pdf
1. The answer is: B. Macrophage processes foreign antigen for presentation to T helper cells
which activate B cells to produce antibodies.
3. The answer is: MHC class II markers
MHC class II markers are needed for T helper cell binding to other immune cells.
Solution
1. The answer is: B. Macrophage processes foreign antigen for presentation to T helper cells
which activate B cells to produce antibodies.
3. The answer is: MHC class II markers
MHC class II markers are needed for T helper cell binding to other immune cells..
1) The main thrust behind the Brexit vote was the fear that UK based.pdf
1) Measurement of time depends on the reaction time of the human measuring the time /
operating the stop clock. There will always be error in measuiring the time whereas measuring
the distance is limited by the least count of the measuring device. Hence distance / displacement
measurement yeilds better results compared to experiment invlving measurement of time.
2) Frictional force generated by Air also called drag force which is proportional to the speed and
opposes the motion of the projectile introduces error in the experiment.
Solution
1) Measurement of time depends on the reaction time of the human measuring the time /
operating the stop clock. There will always be error in measuiring the time whereas measuring
the distance is limited by the least count of the measuring device. Hence distance / displacement
measurement yeilds better results compared to experiment invlving measurement of time.
2) Frictional force generated by Air also called drag force which is proportional to the speed and
opposes the motion of the projectile introduces error in the experiment..
#include algorithm #include vector #include iostream usi.pdf
#include
#include
#include
using namespace std;
template //For Template
void bogosort(std::vector& array) //For bogosort
{
while (! is_sorted(array))
{
std::random_shuffle(array.begin(), array.end());
}
}
template
bool is_sorted(const std::vector& array) //Conforming for display
{
for (typename std::vector::size_type i = 1; i < array.size(); ++i)
{
if (array[i] < array[i-1])
{
return false;
}
}
return true;
}
std::vector a (10); //Creates a vector of size 10
int arr[10];
template
void accept(std::vector& array) //Accepts data to a vector
{
int c;
for(c = 0; c < 10; c++)
cin>>arr[c];
a.assign (arr,arr+10); //Assign array data to the vector
}
template
void display(std::vector& array) //Display the vector contents
{
for (std::vector::iterator it = array.begin(); it != array.end(); ++it)
std::cout << \' \' << *it;
}
template
void selection(std::vector& arr) //Selection soring operation
{
int mini, loc, temp, x, y;
mini = arr[0];
for(x = 0; x <= arr.size()-1; x++)
{
mini = arr[x]; //x position value of array is considered as minimum value
loc = x; //Stores the location of the minimum value
for(y = x + 1; y <= arr.size()-1; y++)
{
if(arr[y] < mini) //Checks the already minimum value with the array contents
{
mini = arr[y]; //Stores the new minimum value
loc = y; //Stores the location of the minimum value
}
}
if(loc != x) //If it is not the same location
{
temp = arr[x];
arr[x] = arr[loc];
arr[loc] = temp;
}
}
}
template
void bubble(std::vector &ar) //Bubble sort operation
{
bool swapp = true;
while(swapp)
{
swapp = false;
for (int i = 0; i < ar.size()-1; i++)
{
if (ar[i]>ar[i+1] )
{
ar[i] += ar[i+1];
ar[i+1] = ar[i] - ar[i+1];
ar[i] -=ar[i+1];
swapp = true;
}
}
}
}
int main()
{
char ch;
do
{
cout<<\"\ MENU\";
cout<<\"\ a Fill the array with user input\";
cout<<\"\ b Display the array\";
cout<<\"\ c Suffel the array element randomly\";
cout<<\"\ d Sort the array using bubble sort\";
cout<<\"\ e Sort the array using Selection Sort\";
cout<<\"\ f Exit Program\";
cout<<\"\ Enter your choice: \";
cin>>ch;
switch(ch)
{
case \'a\':
case \'A\':
accept(a);
cout<<\"\ Accept data operation completed \ \";
break;
case \'b\':
case \'B\':
display(a);
cout<<\"\ Display data operation completed \ \";
break;
case \'c\':
case \'C\':
bogosort(a);
bool b = is_sorted(a);
if(b == true)
display(a);
cout<<\"\ Bugg Sorting operation completed \ \";
break;
case \'d\':
case \'D\':
bubble(a);
display(a);
cout<<\"\ Bubble Sort operation completed \ \";
break;
case \'e\':
case \'E\':
selection(a);
display(a);
cout<<\"\ Selection Sort operation completed \ \";
break;
case \'f\':
case \'F\':
exit(0);
default:
cout<<\"\ Wrong Choice\";
}
}while(1); //Loop will continue infinitely till F or f is pressed
}
Output
MENU
a Fill the array with user input
b Display the array
c Suffel the array element randomly
d Sort the array using bubble sort
e Sort the array using Selection Sort
f Exit Program
Enter your choice: a
10
5
4
78
9
65
3
1
45
66
Accept data operation completed
MENU
a Fill th..
This is a titration of a weak base w a strong ac.pdf
This is a titration of a weak base w/ a strong acid. So when you add the acid, it will
dissociate into H+ and Cl- ions completely, but some of A- will consume the H+ and it will form
HA. So this will in affect become a buffered solution. So i believe you can use henderson
hasselbach for this equation.
Solution
This is a titration of a weak base w/ a strong acid. So when you add the acid, it will
dissociate into H+ and Cl- ions completely, but some of A- will consume the H+ and it will form
HA. So this will in affect become a buffered solution. So i believe you can use henderson
hasselbach for this equation...
Recommended
The empirical formula indicates the relative proportions of the elem.pdf
Samantha Corporation Total Manufacturing OH 490,000 Fixed part of
manufacturing OH 190,000 Variable part of Manufacturing OH 300,000 Total
units produced 100,000 Variable Manufacturing OH /Unit 3 Selling
& Admin OH 520,000 Variable Selling & Admin @$4 /unit 400,000 Fixed
Selling & Admin 120,000 Break even analysis Details Product 1 Product 2
Material cost per unit 6 8 Direct Labor per unit
4 6 Variable Manufacturing OH per unit 3
3 Variable Selling & Admin OH per unit 4 4
Total Variable cost per unit 17 21 Selling Price/unit
24 32 Contribution margin /unit 7
11 Sales volume 60,000 40,000 Sales volume ratio 60%
40% Weighted contribution per unit =7*0.60+11*0.40 Weighted contribution per unit
= 8.60 Total Fixed cost Fixed part of manufacturing OH 190,000
Fixed Selling & Admin 120,000 Total Fixed cost 310,000 Weighted
contribution per unit 8.60 Break Even Units 36,047 Break Even units
Product 1 21,628 (at 60% ratio) Break Even units Product 2 14,419 (at 40%
ratio)
Solution
Samantha Corporation Total Manufacturing OH 490,000 Fixed part of
manufacturing OH 190,000 Variable part of Manufacturing OH 300,000 Total
units produced 100,000 Variable Manufacturing OH /Unit 3 Selling
& Admin OH 520,000 Variable Selling & Admin @$4 /unit 400,000 Fixed
Selling & Admin 120,000 Break even analysis Details Product 1 Product 2
Material cost per unit 6 8 Direct Labor per unit
4 6 Variable Manufacturing OH per unit 3
3 Variable Selling & Admin OH per unit 4 4
Total Variable cost per unit 17 21 Selling Price/unit
24 32 Contribution margin /unit 7
11 Sales volume 60,000 40,000 Sales volume ratio 60%
40% Weighted contribution per unit =7*0.60+11*0.40 Weighted contribution per unit
= 8.60 Total Fixed cost Fixed part of manufacturing OH 190,000
Fixed Selling & Admin 120,000 Total Fixed cost 310,000 Weighted
contribution per unit 8.60 Break Even Units 36,047 Break Even units
Product 1 21,628 (at 60% ratio) Break Even units Product 2 14,419 (at 40%
ratio).
There are two ways to solve this problem. I will .pdf
The ‘nuclei effect’ Cesium formate brine has a natural high density. The weight
comes from cesium ions rather than added particles, such as barite. In traditional OBMs, the
weighting agent is stopped at the well bore wall and forms a ?lter cake. With cesium formate the
problem of ?lter cakes are eliminated, however one needs to correct for the drilling ?uid that
?ltrates into the near formation. “The traditional logging tool algorithm is only good for elements
with atomic numbers less than roughly 24, which means that the element has one neutron for
every proton. Cesium, with an atomic number of 55, has considerably more neutrons than
protons in its nucleus. Therefore when measuring electron density, which is then used to
calculate bulk density, the algorithm should show an under-estimation of density due to this large
‘nuclei effect,’” explains Pedersen. “The only problem was that bulk density was over-
estimated,” he continues. So what was the explanation? “When going through the data I noticed
an intriguing correlation between the gamma logs and the photoelectric factor. To cut a long
story short, higher-numbered atomic elements, such as cesium, produce a dramatically higher
photoelectric effect. This increases the absorption of gamma rays in the formation so that the
electron density appears higher than it is and physical density is therefore over estimated. This
far outweighs the ‘nuclei effect’ previously mentioned,” says Pedersen. A simple solution Now
StatoilHydro understood why the logging results were wrong when interpreted using
methodology based on drilling ?uids with lower atomic numbers, the challenge was to ?nd a way
of interpreting the numbers accurately. The simplicity of the solution was stunning. After close
examination of the calibration data, a linear relationship was found between the photoelectric
factor (Pef) and the over-estimation of density. Consequently, by consistently adjusting bulk
density by the measured Pef, porosity was correctly calculated. “The beauty of this correction is
that it relies only on the Pef measurements, which are logged simultaneously with bulk density,
and can therefore apply to any cesium formate concentration,” says Pedersen. The perfect model
The logged photoelectric factor isn’t only useful for correcting the density curve and estimating
saturation of the invading ?ltrate, but is also ideal for de?ning permeable sands. Combining the
photoelectric factor and its high vertical resolution with resistivity measurements from both the
drill pass and ream pass produces a very reliable and accurate net reservoir de?nition.
Furthermore, by applying a conductive drilling ?uid based on cesium formate brine in all
production wells high-quality resistivity image logs can be run. These logs provide important
information on structural dip, depositional environment, sedimentary features, facies and
geological correlations, all used by geomodelers to produce better reservoir models. “The results
match cor.
If an oxide has the formula MO, then since O is normally found in th.pdf
I2 + 6H2O ---> 2HIO3 +10H+ +10e- HNO3 + 1H+ +1e- --->NO2 + H2O In order to balance
electrons, we have to multiply the reductionhalf-reaction by 10. This gives us: I2 +6H2O
+10HNO3 +10H++ 10e- ----> 2HIO3 + 10H+10NO2 +10H2O + 10e- We can cancel things that
are on the left and right side, likewater and protons. This gives us: I2 +10HNO3 ---->
2HIO3+10NO2 +4H2O Hope this helps, Steve
Solution
I2 + 6H2O ---> 2HIO3 +10H+ +10e- HNO3 + 1H+ +1e- --->NO2 + H2O In order to balance
electrons, we have to multiply the reductionhalf-reaction by 10. This gives us: I2 +6H2O
+10HNO3 +10H++ 10e- ----> 2HIO3 + 10H+10NO2 +10H2O + 10e- We can cancel things that
are on the left and right side, likewater and protons. This gives us: I2 +10HNO3 ---->
2HIO3+10NO2 +4H2O Hope this helps, Steve.
This is a titration of a weak base w a strong ac.pdf
This equation makes it able for you to plug-and-play the numbers.
Let\'s classify the variables first.
n is the number of people
p is the profit acquired
If you plug in p=0 (the situation when the profit is 0), you get
0 = 10(120-n)-50n
Now all you have to do is solve for n.
Solution
This equation makes it able for you to plug-and-play the numbers.
Let\'s classify the variables first.
n is the number of people
p is the profit acquired
If you plug in p=0 (the situation when the profit is 0), you get
0 = 10(120-n)-50n
Now all you have to do is solve for n..
1. True2. I am having trouble understanding the phrasing. A precip.pdf
1. The answer is: B. Macrophage processes foreign antigen for presentation to T helper cells
which activate B cells to produce antibodies.
3. The answer is: MHC class II markers
MHC class II markers are needed for T helper cell binding to other immune cells.
Solution
1. The answer is: B. Macrophage processes foreign antigen for presentation to T helper cells
which activate B cells to produce antibodies.
3. The answer is: MHC class II markers
MHC class II markers are needed for T helper cell binding to other immune cells..
1) The main thrust behind the Brexit vote was the fear that UK based.pdf
1) Measurement of time depends on the reaction time of the human measuring the time /
operating the stop clock. There will always be error in measuiring the time whereas measuring
the distance is limited by the least count of the measuring device. Hence distance / displacement
measurement yeilds better results compared to experiment invlving measurement of time.
2) Frictional force generated by Air also called drag force which is proportional to the speed and
opposes the motion of the projectile introduces error in the experiment.
Solution
1) Measurement of time depends on the reaction time of the human measuring the time /
operating the stop clock. There will always be error in measuiring the time whereas measuring
the distance is limited by the least count of the measuring device. Hence distance / displacement
measurement yeilds better results compared to experiment invlving measurement of time.
2) Frictional force generated by Air also called drag force which is proportional to the speed and
opposes the motion of the projectile introduces error in the experiment..
#include algorithm #include vector #include iostream usi.pdf
#include
#include
#include
using namespace std;
template //For Template
void bogosort(std::vector& array) //For bogosort
{
while (! is_sorted(array))
{
std::random_shuffle(array.begin(), array.end());
}
}
template
bool is_sorted(const std::vector& array) //Conforming for display
{
for (typename std::vector::size_type i = 1; i < array.size(); ++i)
{
if (array[i] < array[i-1])
{
return false;
}
}
return true;
}
std::vector a (10); //Creates a vector of size 10
int arr[10];
template
void accept(std::vector& array) //Accepts data to a vector
{
int c;
for(c = 0; c < 10; c++)
cin>>arr[c];
a.assign (arr,arr+10); //Assign array data to the vector
}
template
void display(std::vector& array) //Display the vector contents
{
for (std::vector::iterator it = array.begin(); it != array.end(); ++it)
std::cout << \' \' << *it;
}
template
void selection(std::vector& arr) //Selection soring operation
{
int mini, loc, temp, x, y;
mini = arr[0];
for(x = 0; x <= arr.size()-1; x++)
{
mini = arr[x]; //x position value of array is considered as minimum value
loc = x; //Stores the location of the minimum value
for(y = x + 1; y <= arr.size()-1; y++)
{
if(arr[y] < mini) //Checks the already minimum value with the array contents
{
mini = arr[y]; //Stores the new minimum value
loc = y; //Stores the location of the minimum value
}
}
if(loc != x) //If it is not the same location
{
temp = arr[x];
arr[x] = arr[loc];
arr[loc] = temp;
}
}
}
template
void bubble(std::vector &ar) //Bubble sort operation
{
bool swapp = true;
while(swapp)
{
swapp = false;
for (int i = 0; i < ar.size()-1; i++)
{
if (ar[i]>ar[i+1] )
{
ar[i] += ar[i+1];
ar[i+1] = ar[i] - ar[i+1];
ar[i] -=ar[i+1];
swapp = true;
}
}
}
}
int main()
{
char ch;
do
{
cout<<\"\ MENU\";
cout<<\"\ a Fill the array with user input\";
cout<<\"\ b Display the array\";
cout<<\"\ c Suffel the array element randomly\";
cout<<\"\ d Sort the array using bubble sort\";
cout<<\"\ e Sort the array using Selection Sort\";
cout<<\"\ f Exit Program\";
cout<<\"\ Enter your choice: \";
cin>>ch;
switch(ch)
{
case \'a\':
case \'A\':
accept(a);
cout<<\"\ Accept data operation completed \ \";
break;
case \'b\':
case \'B\':
display(a);
cout<<\"\ Display data operation completed \ \";
break;
case \'c\':
case \'C\':
bogosort(a);
bool b = is_sorted(a);
if(b == true)
display(a);
cout<<\"\ Bugg Sorting operation completed \ \";
break;
case \'d\':
case \'D\':
bubble(a);
display(a);
cout<<\"\ Bubble Sort operation completed \ \";
break;
case \'e\':
case \'E\':
selection(a);
display(a);
cout<<\"\ Selection Sort operation completed \ \";
break;
case \'f\':
case \'F\':
exit(0);
default:
cout<<\"\ Wrong Choice\";
}
}while(1); //Loop will continue infinitely till F or f is pressed
}
Output
MENU
a Fill the array with user input
b Display the array
c Suffel the array element randomly
d Sort the array using bubble sort
e Sort the array using Selection Sort
f Exit Program
Enter your choice: a
10
5
4
78
9
65
3
1
45
66
Accept data operation completed
MENU
a Fill th..
This is a titration of a weak base w a strong ac.pdf
This is a titration of a weak base w/ a strong acid. So when you add the acid, it will
dissociate into H+ and Cl- ions completely, but some of A- will consume the H+ and it will form
HA. So this will in affect become a buffered solution. So i believe you can use henderson
hasselbach for this equation.
Solution
This is a titration of a weak base w/ a strong acid. So when you add the acid, it will
dissociate into H+ and Cl- ions completely, but some of A- will consume the H+ and it will form
HA. So this will in affect become a buffered solution. So i believe you can use henderson
hasselbach for this equation...
There are two ways to solve this problem. I will .pdf
There are two ways to solve this problem. I will show both ways. First, you can
find the pOH. The formula for pOH is: pOH = -log([OH-]). You take the negative log of the
concentration of OH-. pOH = -log(0.15M) = 0.824 Now, pH + pOH = 14. So, you can subtract
both sides by pOH to get pH. 14 - pOH = 14 - 0.824 = 13.176 = pH The second way to solve
this problem is to find the concentration of H+ ions. We know that [H+] x [OH-] = 1 x 10^-14.
So, you can solve for [H+] [H+] = (1 x 10^-14)/(0.15) = 6.67 x 10 ^ -14 Now, you can take -
log([H+]) to get pH. pH = -log(6.67x10^-14) = 13.176. Notice you get the same answer. Also,
notice when you take -log([OH-]) you get pOH. When you take -log([H+]) you get pH. Hope this
helps and please rate. :)
Solution
There are two ways to solve this problem. I will show both ways. First, you can
find the pOH. The formula for pOH is: pOH = -log([OH-]). You take the negative log of the
concentration of OH-. pOH = -log(0.15M) = 0.824 Now, pH + pOH = 14. So, you can subtract
both sides by pOH to get pH. 14 - pOH = 14 - 0.824 = 13.176 = pH The second way to solve
this problem is to find the concentration of H+ ions. We know that [H+] x [OH-] = 1 x 10^-14.
So, you can solve for [H+] [H+] = (1 x 10^-14)/(0.15) = 6.67 x 10 ^ -14 Now, you can take -
log([H+]) to get pH. pH = -log(6.67x10^-14) = 13.176. Notice you get the same answer. Also,
notice when you take -log([OH-]) you get pOH. When you take -log([H+]) you get pH. Hope this
helps and please rate. :)..
1) The main thrust behind the Brexit vote was the fear that UK based.pdf
1) Measurement of time depends on the reaction time of the human measuring the time /
operating the stop clock. There will always be error in measuiring the time whereas measuring
the distance is limited by the least count of the measuring device. Hence distance / displacement
measurement yeilds better results compared to experiment invlving measurement of time.
2) Frictional force generated by Air also called drag force which is proportional to the speed and
opposes the motion of the projectile introduces error in the experiment.
Solution
1) Measurement of time depends on the reaction time of the human measuring the time /
operating the stop clock. There will always be error in measuiring the time whereas measuring
the distance is limited by the least count of the measuring device. Hence distance / displacement
measurement yeilds better results compared to experiment invlving measurement of time.
2) Frictional force generated by Air also called drag force which is proportional to the speed and
opposes the motion of the projectile introduces error in the experiment..
The empirical formula indicates the relative proportions of the elem.pdf
Samantha Corporation Total Manufacturing OH 490,000 Fixed part of
manufacturing OH 190,000 Variable part of Manufacturing OH 300,000 Total
units produced 100,000 Variable Manufacturing OH /Unit 3 Selling
& Admin OH 520,000 Variable Selling & Admin @$4 /unit 400,000 Fixed
Selling & Admin 120,000 Break even analysis Details Product 1 Product 2
Material cost per unit 6 8 Direct Labor per unit
4 6 Variable Manufacturing OH per unit 3
3 Variable Selling & Admin OH per unit 4 4
Total Variable cost per unit 17 21 Selling Price/unit
24 32 Contribution margin /unit 7
11 Sales volume 60,000 40,000 Sales volume ratio 60%
40% Weighted contribution per unit =7*0.60+11*0.40 Weighted contribution per unit
= 8.60 Total Fixed cost Fixed part of manufacturing OH 190,000
Fixed Selling & Admin 120,000 Total Fixed cost 310,000 Weighted
contribution per unit 8.60 Break Even Units 36,047 Break Even units
Product 1 21,628 (at 60% ratio) Break Even units Product 2 14,419 (at 40%
ratio)
Solution
Samantha Corporation Total Manufacturing OH 490,000 Fixed part of
manufacturing OH 190,000 Variable part of Manufacturing OH 300,000 Total
units produced 100,000 Variable Manufacturing OH /Unit 3 Selling
& Admin OH 520,000 Variable Selling & Admin @$4 /unit 400,000 Fixed
Selling & Admin 120,000 Break even analysis Details Product 1 Product 2
Material cost per unit 6 8 Direct Labor per unit
4 6 Variable Manufacturing OH per unit 3
3 Variable Selling & Admin OH per unit 4 4
Total Variable cost per unit 17 21 Selling Price/unit
24 32 Contribution margin /unit 7
11 Sales volume 60,000 40,000 Sales volume ratio 60%
40% Weighted contribution per unit =7*0.60+11*0.40 Weighted contribution per unit
= 8.60 Total Fixed cost Fixed part of manufacturing OH 190,000
Fixed Selling & Admin 120,000 Total Fixed cost 310,000 Weighted
contribution per unit 8.60 Break Even Units 36,047 Break Even units
Product 1 21,628 (at 60% ratio) Break Even units Product 2 14,419 (at 40%
ratio).
If an oxide has the formula MO, then since O is normally found in th.pdf
I2 + 6H2O ---> 2HIO3 +10H+ +10e- HNO3 + 1H+ +1e- --->NO2 + H2O In order to balance
electrons, we have to multiply the reductionhalf-reaction by 10. This gives us: I2 +6H2O
+10HNO3 +10H++ 10e- ----> 2HIO3 + 10H+10NO2 +10H2O + 10e- We can cancel things that
are on the left and right side, likewater and protons. This gives us: I2 +10HNO3 ---->
2HIO3+10NO2 +4H2O Hope this helps, Steve
Solution
I2 + 6H2O ---> 2HIO3 +10H+ +10e- HNO3 + 1H+ +1e- --->NO2 + H2O In order to balance
electrons, we have to multiply the reductionhalf-reaction by 10. This gives us: I2 +6H2O
+10HNO3 +10H++ 10e- ----> 2HIO3 + 10H+10NO2 +10H2O + 10e- We can cancel things that
are on the left and right side, likewater and protons. This gives us: I2 +10HNO3 ---->
2HIO3+10NO2 +4H2O Hope this helps, Steve.
1. True2. I am having trouble understanding the phrasing. A precip.pdf
1. The answer is: B. Macrophage processes foreign antigen for presentation to T helper cells
which activate B cells to produce antibodies.
3. The answer is: MHC class II markers
MHC class II markers are needed for T helper cell binding to other immune cells.
Solution
1. The answer is: B. Macrophage processes foreign antigen for presentation to T helper cells
which activate B cells to produce antibodies.
3. The answer is: MHC class II markers
MHC class II markers are needed for T helper cell binding to other immune cells..
#include algorithm #include vector #include iostream usi.pdf
#include
#include
#include
using namespace std;
template //For Template
void bogosort(std::vector& array) //For bogosort
{
while (! is_sorted(array))
{
std::random_shuffle(array.begin(), array.end());
}
}
template
bool is_sorted(const std::vector& array) //Conforming for display
{
for (typename std::vector::size_type i = 1; i < array.size(); ++i)
{
if (array[i] < array[i-1])
{
return false;
}
}
return true;
}
std::vector a (10); //Creates a vector of size 10
int arr[10];
template
void accept(std::vector& array) //Accepts data to a vector
{
int c;
for(c = 0; c < 10; c++)
cin>>arr[c];
a.assign (arr,arr+10); //Assign array data to the vector
}
template
void display(std::vector& array) //Display the vector contents
{
for (std::vector::iterator it = array.begin(); it != array.end(); ++it)
std::cout << \' \' << *it;
}
template
void selection(std::vector& arr) //Selection soring operation
{
int mini, loc, temp, x, y;
mini = arr[0];
for(x = 0; x <= arr.size()-1; x++)
{
mini = arr[x]; //x position value of array is considered as minimum value
loc = x; //Stores the location of the minimum value
for(y = x + 1; y <= arr.size()-1; y++)
{
if(arr[y] < mini) //Checks the already minimum value with the array contents
{
mini = arr[y]; //Stores the new minimum value
loc = y; //Stores the location of the minimum value
}
}
if(loc != x) //If it is not the same location
{
temp = arr[x];
arr[x] = arr[loc];
arr[loc] = temp;
}
}
}
template
void bubble(std::vector &ar) //Bubble sort operation
{
bool swapp = true;
while(swapp)
{
swapp = false;
for (int i = 0; i < ar.size()-1; i++)
{
if (ar[i]>ar[i+1] )
{
ar[i] += ar[i+1];
ar[i+1] = ar[i] - ar[i+1];
ar[i] -=ar[i+1];
swapp = true;
}
}
}
}
int main()
{
char ch;
do
{
cout<<\"\ MENU\";
cout<<\"\ a Fill the array with user input\";
cout<<\"\ b Display the array\";
cout<<\"\ c Suffel the array element randomly\";
cout<<\"\ d Sort the array using bubble sort\";
cout<<\"\ e Sort the array using Selection Sort\";
cout<<\"\ f Exit Program\";
cout<<\"\ Enter your choice: \";
cin>>ch;
switch(ch)
{
case \'a\':
case \'A\':
accept(a);
cout<<\"\ Accept data operation completed \ \";
break;
case \'b\':
case \'B\':
display(a);
cout<<\"\ Display data operation completed \ \";
break;
case \'c\':
case \'C\':
bogosort(a);
bool b = is_sorted(a);
if(b == true)
display(a);
cout<<\"\ Bugg Sorting operation completed \ \";
break;
case \'d\':
case \'D\':
bubble(a);
display(a);
cout<<\"\ Bubble Sort operation completed \ \";
break;
case \'e\':
case \'E\':
selection(a);
display(a);
cout<<\"\ Selection Sort operation completed \ \";
break;
case \'f\':
case \'F\':
exit(0);
default:
cout<<\"\ Wrong Choice\";
}
}while(1); //Loop will continue infinitely till F or f is pressed
}
Output
MENU
a Fill the array with user input
b Display the array
c Suffel the array element randomly
d Sort the array using bubble sort
e Sort the array using Selection Sort
f Exit Program
Enter your choice: a
10
5
4
78
9
65
3
1
45
66
Accept data operation completed
MENU
a Fill th.
#include algorithm #include vector #include iostream usi.pdf
#include
#include
#include
using namespace std;
template //For Template
void bogosort(std::vector& array) //For bogosort
{
while (! is_sorted(array))
{
std::random_shuffle(array.begin(), array.end());
}
}
template
bool is_sorted(const std::vector& array) //Conforming for display
{
for (typename std::vector::size_type i = 1; i < array.size(); ++i)
{
if (array[i] < array[i-1])
{
return false;
}
}
return true;
}
std::vector a (10); //Creates a vector of size 10
int arr[10];
template
void accept(std::vector& array) //Accepts data to a vector
{
int c;
for(c = 0; c < 10; c++)
cin>>arr[c];
a.assign (arr,arr+10); //Assign array data to the vector
}
template
void display(std::vector& array) //Display the vector contents
{
for (std::vector::iterator it = array.begin(); it != array.end(); ++it)
std::cout << \' \' << *it;
}
template
void selection(std::vector& arr) //Selection soring operation
{
int mini, loc, temp, x, y;
mini = arr[0];
for(x = 0; x <= arr.size()-1; x++)
{
mini = arr[x]; //x position value of array is considered as minimum value
loc = x; //Stores the location of the minimum value
for(y = x + 1; y <= arr.size()-1; y++)
{
if(arr[y] < mini) //Checks the already minimum value with the array contents
{
mini = arr[y]; //Stores the new minimum value
loc = y; //Stores the location of the minimum value
}
}
if(loc != x) //If it is not the same location
{
temp = arr[x];
arr[x] = arr[loc];
arr[loc] = temp;
}
}
}
template
void bubble(std::vector &ar) //Bubble sort operation
{
bool swapp = true;
while(swapp)
{
swapp = false;
for (int i = 0; i < ar.size()-1; i++)
{
if (ar[i]>ar[i+1] )
{
ar[i] += ar[i+1];
ar[i+1] = ar[i] - ar[i+1];
ar[i] -=ar[i+1];
swapp = true;
}
}
}
}
int main()
{
char ch;
do
{
cout<<\"\ MENU\";
cout<<\"\ a Fill the array with user input\";
cout<<\"\ b Display the array\";
cout<<\"\ c Suffel the array element randomly\";
cout<<\"\ d Sort the array using bubble sort\";
cout<<\"\ e Sort the array using Selection Sort\";
cout<<\"\ f Exit Program\";
cout<<\"\ Enter your choice: \";
cin>>ch;
switch(ch)
{
case \'a\':
case \'A\':
accept(a);
cout<<\"\ Accept data operation completed \ \";
break;
case \'b\':
case \'B\':
display(a);
cout<<\"\ Display data operation completed \ \";
break;
case \'c\':
case \'C\':
bogosort(a);
bool b = is_sorted(a);
if(b == true)
display(a);
cout<<\"\ Bugg Sorting operation completed \ \";
break;
case \'d\':
case \'D\':
bubble(a);
display(a);
cout<<\"\ Bubble Sort operation completed \ \";
break;
case \'e\':
case \'E\':
selection(a);
display(a);
cout<<\"\ Selection Sort operation completed \ \";
break;
case \'f\':
case \'F\':
exit(0);
default:
cout<<\"\ Wrong Choice\";
}
}while(1); //Loop will continue infinitely till F or f is pressed
}
Output
MENU
a Fill the array with user input
b Display the array
c Suffel the array element randomly
d Sort the array using bubble sort
e Sort the array using Selection Sort
f Exit Program
Enter your choice: a
10
5
4
78
9
65
3
1
45
66
Accept data operation completed
MENU
a Fill th.
#include algorithm #include vector #include iostream usi.pdf
#include
#include
#include
using namespace std;
template //For Template
void bogosort(std::vector& array) //For bogosort
{
while (! is_sorted(array))
{
std::random_shuffle(array.begin(), array.end());
}
}
template
bool is_sorted(const std::vector& array) //Conforming for display
{
for (typename std::vector::size_type i = 1; i < array.size(); ++i)
{
if (array[i] < array[i-1])
{
return false;
}
}
return true;
}
std::vector a (10); //Creates a vector of size 10
int arr[10];
template
void accept(std::vector& array) //Accepts data to a vector
{
int c;
for(c = 0; c < 10; c++)
cin>>arr[c];
a.assign (arr,arr+10); //Assign array data to the vector
}
template
void display(std::vector& array) //Display the vector contents
{
for (std::vector::iterator it = array.begin(); it != array.end(); ++it)
std::cout << \' \' << *it;
}
template
void selection(std::vector& arr) //Selection soring operation
{
int mini, loc, temp, x, y;
mini = arr[0];
for(x = 0; x <= arr.size()-1; x++)
{
mini = arr[x]; //x position value of array is considered as minimum value
loc = x; //Stores the location of the minimum value
for(y = x + 1; y <= arr.size()-1; y++)
{
if(arr[y] < mini) //Checks the already minimum value with the array contents
{
mini = arr[y]; //Stores the new minimum value
loc = y; //Stores the location of the minimum value
}
}
if(loc != x) //If it is not the same location
{
temp = arr[x];
arr[x] = arr[loc];
arr[loc] = temp;
}
}
}
template
void bubble(std::vector &ar) //Bubble sort operation
{
bool swapp = true;
while(swapp)
{
swapp = false;
for (int i = 0; i < ar.size()-1; i++)
{
if (ar[i]>ar[i+1] )
{
ar[i] += ar[i+1];
ar[i+1] = ar[i] - ar[i+1];
ar[i] -=ar[i+1];
swapp = true;
}
}
}
}
int main()
{
char ch;
do
{
cout<<\"\ MENU\";
cout<<\"\ a Fill the array with user input\";
cout<<\"\ b Display the array\";
cout<<\"\ c Suffel the array element randomly\";
cout<<\"\ d Sort the array using bubble sort\";
cout<<\"\ e Sort the array using Selection Sort\";
cout<<\"\ f Exit Program\";
cout<<\"\ Enter your choice: \";
cin>>ch;
switch(ch)
{
case \'a\':
case \'A\':
accept(a);
cout<<\"\ Accept data operation completed \ \";
break;
case \'b\':
case \'B\':
display(a);
cout<<\"\ Display data operation completed \ \";
break;
case \'c\':
case \'C\':
bogosort(a);
bool b = is_sorted(a);
if(b == true)
display(a);
cout<<\"\ Bugg Sorting operation completed \ \";
break;
case \'d\':
case \'D\':
bubble(a);
display(a);
cout<<\"\ Bubble Sort operation completed \ \";
break;
case \'e\':
case \'E\':
selection(a);
display(a);
cout<<\"\ Selection Sort operation completed \ \";
break;
case \'f\':
case \'F\':
exit(0);
default:
cout<<\"\ Wrong Choice\";
}
}while(1); //Loop will continue infinitely till F or f is pressed
}
Output
MENU
a Fill the array with user input
b Display the array
c Suffel the array element randomly
d Sort the array using bubble sort
e Sort the array using Selection Sort
f Exit Program
Enter your choice: a
10
5
4
78
9
65
3
1
45
66
Accept data operation completed
MENU
a Fill th.
#include algorithm #include vector #include iostream usi.pdf
#include
#include
#include
using namespace std;
template //For Template
void bogosort(std::vector& array) //For bogosort
{
while (! is_sorted(array))
{
std::random_shuffle(array.begin(), array.end());
}
}
template
bool is_sorted(const std::vector& array) //Conforming for display
{
for (typename std::vector::size_type i = 1; i < array.size(); ++i)
{
if (array[i] < array[i-1])
{
return false;
}
}
return true;
}
std::vector a (10); //Creates a vector of size 10
int arr[10];
template
void accept(std::vector& array) //Accepts data to a vector
{
int c;
for(c = 0; c < 10; c++)
cin>>arr[c];
a.assign (arr,arr+10); //Assign array data to the vector
}
template
void display(std::vector& array) //Display the vector contents
{
for (std::vector::iterator it = array.begin(); it != array.end(); ++it)
std::cout << \' \' << *it;
}
template
void selection(std::vector& arr) //Selection soring operation
{
int mini, loc, temp, x, y;
mini = arr[0];
for(x = 0; x <= arr.size()-1; x++)
{
mini = arr[x]; //x position value of array is considered as minimum value
loc = x; //Stores the location of the minimum value
for(y = x + 1; y <= arr.size()-1; y++)
{
if(arr[y] < mini) //Checks the already minimum value with the array contents
{
mini = arr[y]; //Stores the new minimum value
loc = y; //Stores the location of the minimum value
}
}
if(loc != x) //If it is not the same location
{
temp = arr[x];
arr[x] = arr[loc];
arr[loc] = temp;
}
}
}
template
void bubble(std::vector &ar) //Bubble sort operation
{
bool swapp = true;
while(swapp)
{
swapp = false;
for (int i = 0; i < ar.size()-1; i++)
{
if (ar[i]>ar[i+1] )
{
ar[i] += ar[i+1];
ar[i+1] = ar[i] - ar[i+1];
ar[i] -=ar[i+1];
swapp = true;
}
}
}
}
int main()
{
char ch;
do
{
cout<<\"\ MENU\";
cout<<\"\ a Fill the array with user input\";
cout<<\"\ b Display the array\";
cout<<\"\ c Suffel the array element randomly\";
cout<<\"\ d Sort the array using bubble sort\";
cout<<\"\ e Sort the array using Selection Sort\";
cout<<\"\ f Exit Program\";
cout<<\"\ Enter your choice: \";
cin>>ch;
switch(ch)
{
case \'a\':
case \'A\':
accept(a);
cout<<\"\ Accept data operation completed \ \";
break;
case \'b\':
case \'B\':
display(a);
cout<<\"\ Display data operation completed \ \";
break;
case \'c\':
case \'C\':
bogosort(a);
bool b = is_sorted(a);
if(b == true)
display(a);
cout<<\"\ Bugg Sorting operation completed \ \";
break;
case \'d\':
case \'D\':
bubble(a);
display(a);
cout<<\"\ Bubble Sort operation completed \ \";
break;
case \'e\':
case \'E\':
selection(a);
display(a);
cout<<\"\ Selection Sort operation completed \ \";
break;
case \'f\':
case \'F\':
exit(0);
default:
cout<<\"\ Wrong Choice\";
}
}while(1); //Loop will continue infinitely till F or f is pressed
}
Output
MENU
a Fill the array with user input
b Display the array
c Suffel the array element randomly
d Sort the array using bubble sort
e Sort the array using Selection Sort
f Exit Program
Enter your choice: a
10
5
4
78
9
65
3
1
45
66
Accept data operation completed
MENU
a Fill th.
#include algorithm #include vector #include iostream usi.pdf
#include
#include
#include
using namespace std;
template //For Template
void bogosort(std::vector& array) //For bogosort
{
while (! is_sorted(array))
{
std::random_shuffle(array.begin(), array.end());
}
}
template
bool is_sorted(const std::vector& array) //Conforming for display
{
for (typename std::vector::size_type i = 1; i < array.size(); ++i)
{
if (array[i] < array[i-1])
{
return false;
}
}
return true;
}
std::vector a (10); //Creates a vector of size 10
int arr[10];
template
void accept(std::vector& array) //Accepts data to a vector
{
int c;
for(c = 0; c < 10; c++)
cin>>arr[c];
a.assign (arr,arr+10); //Assign array data to the vector
}
template
void display(std::vector& array) //Display the vector contents
{
for (std::vector::iterator it = array.begin(); it != array.end(); ++it)
std::cout << \' \' << *it;
}
template
void selection(std::vector& arr) //Selection soring operation
{
int mini, loc, temp, x, y;
mini = arr[0];
for(x = 0; x <= arr.size()-1; x++)
{
mini = arr[x]; //x position value of array is considered as minimum value
loc = x; //Stores the location of the minimum value
for(y = x + 1; y <= arr.size()-1; y++)
{
if(arr[y] < mini) //Checks the already minimum value with the array contents
{
mini = arr[y]; //Stores the new minimum value
loc = y; //Stores the location of the minimum value
}
}
if(loc != x) //If it is not the same location
{
temp = arr[x];
arr[x] = arr[loc];
arr[loc] = temp;
}
}
}
template
void bubble(std::vector &ar) //Bubble sort operation
{
bool swapp = true;
while(swapp)
{
swapp = false;
for (int i = 0; i < ar.size()-1; i++)
{
if (ar[i]>ar[i+1] )
{
ar[i] += ar[i+1];
ar[i+1] = ar[i] - ar[i+1];
ar[i] -=ar[i+1];
swapp = true;
}
}
}
}
int main()
{
char ch;
do
{
cout<<\"\ MENU\";
cout<<\"\ a Fill the array with user input\";
cout<<\"\ b Display the array\";
cout<<\"\ c Suffel the array element randomly\";
cout<<\"\ d Sort the array using bubble sort\";
cout<<\"\ e Sort the array using Selection Sort\";
cout<<\"\ f Exit Program\";
cout<<\"\ Enter your choice: \";
cin>>ch;
switch(ch)
{
case \'a\':
case \'A\':
accept(a);
cout<<\"\ Accept data operation completed \ \";
break;
case \'b\':
case \'B\':
display(a);
cout<<\"\ Display data operation completed \ \";
break;
case \'c\':
case \'C\':
bogosort(a);
bool b = is_sorted(a);
if(b == true)
display(a);
cout<<\"\ Bugg Sorting operation completed \ \";
break;
case \'d\':
case \'D\':
bubble(a);
display(a);
cout<<\"\ Bubble Sort operation completed \ \";
break;
case \'e\':
case \'E\':
selection(a);
display(a);
cout<<\"\ Selection Sort operation completed \ \";
break;
case \'f\':
case \'F\':
exit(0);
default:
cout<<\"\ Wrong Choice\";
}
}while(1); //Loop will continue infinitely till F or f is pressed
}
Output
MENU
a Fill the array with user input
b Display the array
c Suffel the array element randomly
d Sort the array using bubble sort
e Sort the array using Selection Sort
f Exit Program
Enter your choice: a
10
5
4
78
9
65
3
1
45
66
Accept data operation completed
MENU
a Fill th.
Chapter wise All Notes of First year Basic Civil Engineering.pptx
Chapter wise All Notes of First year Basic Civil Engineering
Syllabus
Chapter-1
Introduction to objective, scope and outcome the subject
Chapter 2
Introduction: Scope and Specialization of Civil Engineering, Role of civil Engineer in Society, Impact of infrastructural development on economy of country.
Chapter 3
Surveying: Object Principles & Types of Surveying; Site Plans, Plans & Maps; Scales & Unit of different Measurements.
Linear Measurements: Instruments used. Linear Measurement by Tape, Ranging out Survey Lines and overcoming Obstructions; Measurements on sloping ground; Tape corrections, conventional symbols. Angular Measurements: Instruments used; Introduction to Compass Surveying, Bearings and Longitude & Latitude of a Line, Introduction to total station.
Levelling: Instrument used Object of levelling, Methods of levelling in brief, and Contour maps.
Chapter 4
Buildings: Selection of site for Buildings, Layout of Building Plan, Types of buildings, Plinth area, carpet area, floor space index, Introduction to building byelaws, concept of sun light & ventilation. Components of Buildings & their functions, Basic concept of R.C.C., Introduction to types of foundation
Chapter 5
Transportation: Introduction to Transportation Engineering; Traffic and Road Safety: Types and Characteristics of Various Modes of Transportation; Various Road Traffic Signs, Causes of Accidents and Road Safety Measures.
Chapter 6
Environmental Engineering: Environmental Pollution, Environmental Acts and Regulations, Functional Concepts of Ecology, Basics of Species, Biodiversity, Ecosystem, Hydrological Cycle; Chemical Cycles: Carbon, Nitrogen & Phosphorus; Energy Flow in Ecosystems.
Water Pollution: Water Quality standards, Introduction to Treatment & Disposal of Waste Water. Reuse and Saving of Water, Rain Water Harvesting. Solid Waste Management: Classification of Solid Waste, Collection, Transportation and Disposal of Solid. Recycling of Solid Waste: Energy Recovery, Sanitary Landfill, On-Site Sanitation. Air & Noise Pollution: Primary and Secondary air pollutants, Harmful effects of Air Pollution, Control of Air Pollution. . Noise Pollution Harmful Effects of noise pollution, control of noise pollution, Global warming & Climate Change, Ozone depletion, Greenhouse effect
Text Books:
1. Palancharmy, Basic Civil Engineering, McGraw Hill publishers.
2. Satheesh Gopi, Basic Civil Engineering, Pearson Publishers.
3. Ketki Rangwala Dalal, Essentials of Civil Engineering, Charotar Publishing House.
4. BCP, Surveying volume 1
Wound healing PPT
This document provides an overview of wound healing, its functions, stages, mechanisms, factors affecting it, and complications.
A wound is a break in the integrity of the skin or tissues, which may be associated with disruption of the structure and function.
Healing is the body’s response to injury in an attempt to restore normal structure and functions.
Healing can occur in two ways: Regeneration and Repair
There are 4 phases of wound healing: hemostasis, inflammation, proliferation, and remodeling. This document also describes the mechanism of wound healing. Factors that affect healing include infection, uncontrolled diabetes, poor nutrition, age, anemia, the presence of foreign bodies, etc.
Complications of wound healing like infection, hyperpigmentation of scar, contractures, and keloid formation.
RHEOLOGY Physical pharmaceutics-II notes for B.pharm 4th sem students
Physical pharmaceutics notes for B.pharm students
Pengantar Penggunaan Flutter - Dart programming language1.pptx
Pengantar Penggunaan Flutter - Dart programming language1.pptx
ISO/IEC 27001, ISO/IEC 42001, and GDPR: Best Practices for Implementation and...
Denis is a dynamic and results-driven Chief Information Officer (CIO) with a distinguished career spanning information systems analysis and technical project management. With a proven track record of spearheading the design and delivery of cutting-edge Information Management solutions, he has consistently elevated business operations, streamlined reporting functions, and maximized process efficiency.
Certified as an ISO/IEC 27001: Information Security Management Systems (ISMS) Lead Implementer, Data Protection Officer, and Cyber Risks Analyst, Denis brings a heightened focus on data security, privacy, and cyber resilience to every endeavor.
His expertise extends across a diverse spectrum of reporting, database, and web development applications, underpinned by an exceptional grasp of data storage and virtualization technologies. His proficiency in application testing, database administration, and data cleansing ensures seamless execution of complex projects.
What sets Denis apart is his comprehensive understanding of Business and Systems Analysis technologies, honed through involvement in all phases of the Software Development Lifecycle (SDLC). From meticulous requirements gathering to precise analysis, innovative design, rigorous development, thorough testing, and successful implementation, he has consistently delivered exceptional results.
Throughout his career, he has taken on multifaceted roles, from leading technical project management teams to owning solutions that drive operational excellence. His conscientious and proactive approach is unwavering, whether he is working independently or collaboratively within a team. His ability to connect with colleagues on a personal level underscores his commitment to fostering a harmonious and productive workplace environment.
Date: May 29, 2024
Tags: Information Security, ISO/IEC 27001, ISO/IEC 42001, Artificial Intelligence, GDPR
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Training: ISO/IEC 27001 Information Security Management System - EN | PECB
ISO/IEC 42001 Artificial Intelligence Management System - EN | PECB
General Data Protection Regulation (GDPR) - Training Courses - EN | PECB
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Article: https://pecb.com/article
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Pollock and Snow "DEIA in the Scholarly Landscape, Session One: Setting Expec...
Pollock and Snow "DEIA in the Scholarly Landscape, Session One: Setting Expec...National Information Standards Organization (NISO)
This presentation was provided by Steph Pollock of The American Psychological Association’s Journals Program, and Damita Snow, of The American Society of Civil Engineers (ASCE), for the initial session of NISO's 2024 Training Series "DEIA in the Scholarly Landscape." Session One: 'Setting Expectations: a DEIA Primer,' was held June 6, 2024.How to Manage Your Lost Opportunities in Odoo 17 CRM
Odoo 17 CRM allows us to track why we lose sales opportunities with "Lost Reasons." This helps analyze our sales process and identify areas for improvement. Here's how to configure lost reasons in Odoo 17 CRM
What is Digital Literacy? A guest blog from Andy McLaughlin, University of Ab...
What is Digital Literacy? A guest blog from Andy McLaughlin, University of Aberdeen
Walmart Business+ and Spark Good for Nonprofits.pdf
"Learn about all the ways Walmart supports nonprofit organizations.
You will hear from Liz Willett, the Head of Nonprofits, and hear about what Walmart is doing to help nonprofits, including Walmart Business and Spark Good. Walmart Business+ is a new offer for nonprofits that offers discounts and also streamlines nonprofits order and expense tracking, saving time and money.
The webinar may also give some examples on how nonprofits can best leverage Walmart Business+.
The event will cover the following::
Walmart Business + (https://business.walmart.com/plus) is a new shopping experience for nonprofits, schools, and local business customers that connects an exclusive online shopping experience to stores. Benefits include free delivery and shipping, a 'Spend Analytics” feature, special discounts, deals and tax-exempt shopping.
Special TechSoup offer for a free 180 days membership, and up to $150 in discounts on eligible orders.
Spark Good (walmart.com/sparkgood) is a charitable platform that enables nonprofits to receive donations directly from customers and associates.
Answers about how you can do more with Walmart!"
BÀI TẬP DẠY THÊM TIẾNG ANH LỚP 7 CẢ NĂM FRIENDS PLUS SÁCH CHÂN TRỜI SÁNG TẠO ...
BÀI TẬP DẠY THÊM TIẾNG ANH LỚP 7 CẢ NĂM FRIENDS PLUS SÁCH CHÂN TRỜI SÁNG TẠO ...Nguyen Thanh Tu Collection
https://app.box.com/s/qhtvq32h4ybf9t49ku85x0n3xl4jhr15More Related Content
More from ssuseraef9da
There are two ways to solve this problem. I will .pdf
There are two ways to solve this problem. I will show both ways. First, you can
find the pOH. The formula for pOH is: pOH = -log([OH-]). You take the negative log of the
concentration of OH-. pOH = -log(0.15M) = 0.824 Now, pH + pOH = 14. So, you can subtract
both sides by pOH to get pH. 14 - pOH = 14 - 0.824 = 13.176 = pH The second way to solve
this problem is to find the concentration of H+ ions. We know that [H+] x [OH-] = 1 x 10^-14.
So, you can solve for [H+] [H+] = (1 x 10^-14)/(0.15) = 6.67 x 10 ^ -14 Now, you can take -
log([H+]) to get pH. pH = -log(6.67x10^-14) = 13.176. Notice you get the same answer. Also,
notice when you take -log([OH-]) you get pOH. When you take -log([H+]) you get pH. Hope this
helps and please rate. :)
Solution
There are two ways to solve this problem. I will show both ways. First, you can
find the pOH. The formula for pOH is: pOH = -log([OH-]). You take the negative log of the
concentration of OH-. pOH = -log(0.15M) = 0.824 Now, pH + pOH = 14. So, you can subtract
both sides by pOH to get pH. 14 - pOH = 14 - 0.824 = 13.176 = pH The second way to solve
this problem is to find the concentration of H+ ions. We know that [H+] x [OH-] = 1 x 10^-14.
So, you can solve for [H+] [H+] = (1 x 10^-14)/(0.15) = 6.67 x 10 ^ -14 Now, you can take -
log([H+]) to get pH. pH = -log(6.67x10^-14) = 13.176. Notice you get the same answer. Also,
notice when you take -log([OH-]) you get pOH. When you take -log([H+]) you get pH. Hope this
helps and please rate. :)..
1) The main thrust behind the Brexit vote was the fear that UK based.pdf
1) Measurement of time depends on the reaction time of the human measuring the time /
operating the stop clock. There will always be error in measuiring the time whereas measuring
the distance is limited by the least count of the measuring device. Hence distance / displacement
measurement yeilds better results compared to experiment invlving measurement of time.
2) Frictional force generated by Air also called drag force which is proportional to the speed and
opposes the motion of the projectile introduces error in the experiment.
Solution
1) Measurement of time depends on the reaction time of the human measuring the time /
operating the stop clock. There will always be error in measuiring the time whereas measuring
the distance is limited by the least count of the measuring device. Hence distance / displacement
measurement yeilds better results compared to experiment invlving measurement of time.
2) Frictional force generated by Air also called drag force which is proportional to the speed and
opposes the motion of the projectile introduces error in the experiment..
The empirical formula indicates the relative proportions of the elem.pdf
Samantha Corporation Total Manufacturing OH 490,000 Fixed part of
manufacturing OH 190,000 Variable part of Manufacturing OH 300,000 Total
units produced 100,000 Variable Manufacturing OH /Unit 3 Selling
& Admin OH 520,000 Variable Selling & Admin @$4 /unit 400,000 Fixed
Selling & Admin 120,000 Break even analysis Details Product 1 Product 2
Material cost per unit 6 8 Direct Labor per unit
4 6 Variable Manufacturing OH per unit 3
3 Variable Selling & Admin OH per unit 4 4
Total Variable cost per unit 17 21 Selling Price/unit
24 32 Contribution margin /unit 7
11 Sales volume 60,000 40,000 Sales volume ratio 60%
40% Weighted contribution per unit =7*0.60+11*0.40 Weighted contribution per unit
= 8.60 Total Fixed cost Fixed part of manufacturing OH 190,000
Fixed Selling & Admin 120,000 Total Fixed cost 310,000 Weighted
contribution per unit 8.60 Break Even Units 36,047 Break Even units
Product 1 21,628 (at 60% ratio) Break Even units Product 2 14,419 (at 40%
ratio)
Solution
Samantha Corporation Total Manufacturing OH 490,000 Fixed part of
manufacturing OH 190,000 Variable part of Manufacturing OH 300,000 Total
units produced 100,000 Variable Manufacturing OH /Unit 3 Selling
& Admin OH 520,000 Variable Selling & Admin @$4 /unit 400,000 Fixed
Selling & Admin 120,000 Break even analysis Details Product 1 Product 2
Material cost per unit 6 8 Direct Labor per unit
4 6 Variable Manufacturing OH per unit 3
3 Variable Selling & Admin OH per unit 4 4
Total Variable cost per unit 17 21 Selling Price/unit
24 32 Contribution margin /unit 7
11 Sales volume 60,000 40,000 Sales volume ratio 60%
40% Weighted contribution per unit =7*0.60+11*0.40 Weighted contribution per unit
= 8.60 Total Fixed cost Fixed part of manufacturing OH 190,000
Fixed Selling & Admin 120,000 Total Fixed cost 310,000 Weighted
contribution per unit 8.60 Break Even Units 36,047 Break Even units
Product 1 21,628 (at 60% ratio) Break Even units Product 2 14,419 (at 40%
ratio).
If an oxide has the formula MO, then since O is normally found in th.pdf
I2 + 6H2O ---> 2HIO3 +10H+ +10e- HNO3 + 1H+ +1e- --->NO2 + H2O In order to balance
electrons, we have to multiply the reductionhalf-reaction by 10. This gives us: I2 +6H2O
+10HNO3 +10H++ 10e- ----> 2HIO3 + 10H+10NO2 +10H2O + 10e- We can cancel things that
are on the left and right side, likewater and protons. This gives us: I2 +10HNO3 ---->
2HIO3+10NO2 +4H2O Hope this helps, Steve
Solution
I2 + 6H2O ---> 2HIO3 +10H+ +10e- HNO3 + 1H+ +1e- --->NO2 + H2O In order to balance
electrons, we have to multiply the reductionhalf-reaction by 10. This gives us: I2 +6H2O
+10HNO3 +10H++ 10e- ----> 2HIO3 + 10H+10NO2 +10H2O + 10e- We can cancel things that
are on the left and right side, likewater and protons. This gives us: I2 +10HNO3 ---->
2HIO3+10NO2 +4H2O Hope this helps, Steve.
1. True2. I am having trouble understanding the phrasing. A precip.pdf
1. The answer is: B. Macrophage processes foreign antigen for presentation to T helper cells
which activate B cells to produce antibodies.
3. The answer is: MHC class II markers
MHC class II markers are needed for T helper cell binding to other immune cells.
Solution
1. The answer is: B. Macrophage processes foreign antigen for presentation to T helper cells
which activate B cells to produce antibodies.
3. The answer is: MHC class II markers
MHC class II markers are needed for T helper cell binding to other immune cells..
#include algorithm #include vector #include iostream usi.pdf
#include
#include
#include
using namespace std;
template //For Template
void bogosort(std::vector& array) //For bogosort
{
while (! is_sorted(array))
{
std::random_shuffle(array.begin(), array.end());
}
}
template
bool is_sorted(const std::vector& array) //Conforming for display
{
for (typename std::vector::size_type i = 1; i < array.size(); ++i)
{
if (array[i] < array[i-1])
{
return false;
}
}
return true;
}
std::vector a (10); //Creates a vector of size 10
int arr[10];
template
void accept(std::vector& array) //Accepts data to a vector
{
int c;
for(c = 0; c < 10; c++)
cin>>arr[c];
a.assign (arr,arr+10); //Assign array data to the vector
}
template
void display(std::vector& array) //Display the vector contents
{
for (std::vector::iterator it = array.begin(); it != array.end(); ++it)
std::cout << \' \' << *it;
}
template
void selection(std::vector& arr) //Selection soring operation
{
int mini, loc, temp, x, y;
mini = arr[0];
for(x = 0; x <= arr.size()-1; x++)
{
mini = arr[x]; //x position value of array is considered as minimum value
loc = x; //Stores the location of the minimum value
for(y = x + 1; y <= arr.size()-1; y++)
{
if(arr[y] < mini) //Checks the already minimum value with the array contents
{
mini = arr[y]; //Stores the new minimum value
loc = y; //Stores the location of the minimum value
}
}
if(loc != x) //If it is not the same location
{
temp = arr[x];
arr[x] = arr[loc];
arr[loc] = temp;
}
}
}
template
void bubble(std::vector &ar) //Bubble sort operation
{
bool swapp = true;
while(swapp)
{
swapp = false;
for (int i = 0; i < ar.size()-1; i++)
{
if (ar[i]>ar[i+1] )
{
ar[i] += ar[i+1];
ar[i+1] = ar[i] - ar[i+1];
ar[i] -=ar[i+1];
swapp = true;
}
}
}
}
int main()
{
char ch;
do
{
cout<<\"\ MENU\";
cout<<\"\ a Fill the array with user input\";
cout<<\"\ b Display the array\";
cout<<\"\ c Suffel the array element randomly\";
cout<<\"\ d Sort the array using bubble sort\";
cout<<\"\ e Sort the array using Selection Sort\";
cout<<\"\ f Exit Program\";
cout<<\"\ Enter your choice: \";
cin>>ch;
switch(ch)
{
case \'a\':
case \'A\':
accept(a);
cout<<\"\ Accept data operation completed \ \";
break;
case \'b\':
case \'B\':
display(a);
cout<<\"\ Display data operation completed \ \";
break;
case \'c\':
case \'C\':
bogosort(a);
bool b = is_sorted(a);
if(b == true)
display(a);
cout<<\"\ Bugg Sorting operation completed \ \";
break;
case \'d\':
case \'D\':
bubble(a);
display(a);
cout<<\"\ Bubble Sort operation completed \ \";
break;
case \'e\':
case \'E\':
selection(a);
display(a);
cout<<\"\ Selection Sort operation completed \ \";
break;
case \'f\':
case \'F\':
exit(0);
default:
cout<<\"\ Wrong Choice\";
}
}while(1); //Loop will continue infinitely till F or f is pressed
}
Output
MENU
a Fill the array with user input
b Display the array
c Suffel the array element randomly
d Sort the array using bubble sort
e Sort the array using Selection Sort
f Exit Program
Enter your choice: a
10
5
4
78
9
65
3
1
45
66
Accept data operation completed
MENU
a Fill th.
#include algorithm #include vector #include iostream usi.pdf
#include
#include
#include
using namespace std;
template //For Template
void bogosort(std::vector& array) //For bogosort
{
while (! is_sorted(array))
{
std::random_shuffle(array.begin(), array.end());
}
}
template
bool is_sorted(const std::vector& array) //Conforming for display
{
for (typename std::vector::size_type i = 1; i < array.size(); ++i)
{
if (array[i] < array[i-1])
{
return false;
}
}
return true;
}
std::vector a (10); //Creates a vector of size 10
int arr[10];
template
void accept(std::vector& array) //Accepts data to a vector
{
int c;
for(c = 0; c < 10; c++)
cin>>arr[c];
a.assign (arr,arr+10); //Assign array data to the vector
}
template
void display(std::vector& array) //Display the vector contents
{
for (std::vector::iterator it = array.begin(); it != array.end(); ++it)
std::cout << \' \' << *it;
}
template
void selection(std::vector& arr) //Selection soring operation
{
int mini, loc, temp, x, y;
mini = arr[0];
for(x = 0; x <= arr.size()-1; x++)
{
mini = arr[x]; //x position value of array is considered as minimum value
loc = x; //Stores the location of the minimum value
for(y = x + 1; y <= arr.size()-1; y++)
{
if(arr[y] < mini) //Checks the already minimum value with the array contents
{
mini = arr[y]; //Stores the new minimum value
loc = y; //Stores the location of the minimum value
}
}
if(loc != x) //If it is not the same location
{
temp = arr[x];
arr[x] = arr[loc];
arr[loc] = temp;
}
}
}
template
void bubble(std::vector &ar) //Bubble sort operation
{
bool swapp = true;
while(swapp)
{
swapp = false;
for (int i = 0; i < ar.size()-1; i++)
{
if (ar[i]>ar[i+1] )
{
ar[i] += ar[i+1];
ar[i+1] = ar[i] - ar[i+1];
ar[i] -=ar[i+1];
swapp = true;
}
}
}
}
int main()
{
char ch;
do
{
cout<<\"\ MENU\";
cout<<\"\ a Fill the array with user input\";
cout<<\"\ b Display the array\";
cout<<\"\ c Suffel the array element randomly\";
cout<<\"\ d Sort the array using bubble sort\";
cout<<\"\ e Sort the array using Selection Sort\";
cout<<\"\ f Exit Program\";
cout<<\"\ Enter your choice: \";
cin>>ch;
switch(ch)
{
case \'a\':
case \'A\':
accept(a);
cout<<\"\ Accept data operation completed \ \";
break;
case \'b\':
case \'B\':
display(a);
cout<<\"\ Display data operation completed \ \";
break;
case \'c\':
case \'C\':
bogosort(a);
bool b = is_sorted(a);
if(b == true)
display(a);
cout<<\"\ Bugg Sorting operation completed \ \";
break;
case \'d\':
case \'D\':
bubble(a);
display(a);
cout<<\"\ Bubble Sort operation completed \ \";
break;
case \'e\':
case \'E\':
selection(a);
display(a);
cout<<\"\ Selection Sort operation completed \ \";
break;
case \'f\':
case \'F\':
exit(0);
default:
cout<<\"\ Wrong Choice\";
}
}while(1); //Loop will continue infinitely till F or f is pressed
}
Output
MENU
a Fill the array with user input
b Display the array
c Suffel the array element randomly
d Sort the array using bubble sort
e Sort the array using Selection Sort
f Exit Program
Enter your choice: a
10
5
4
78
9
65
3
1
45
66
Accept data operation completed
MENU
a Fill th.
#include algorithm #include vector #include iostream usi.pdf
#include
#include
#include
using namespace std;
template //For Template
void bogosort(std::vector& array) //For bogosort
{
while (! is_sorted(array))
{
std::random_shuffle(array.begin(), array.end());
}
}
template
bool is_sorted(const std::vector& array) //Conforming for display
{
for (typename std::vector::size_type i = 1; i < array.size(); ++i)
{
if (array[i] < array[i-1])
{
return false;
}
}
return true;
}
std::vector a (10); //Creates a vector of size 10
int arr[10];
template
void accept(std::vector& array) //Accepts data to a vector
{
int c;
for(c = 0; c < 10; c++)
cin>>arr[c];
a.assign (arr,arr+10); //Assign array data to the vector
}
template
void display(std::vector& array) //Display the vector contents
{
for (std::vector::iterator it = array.begin(); it != array.end(); ++it)
std::cout << \' \' << *it;
}
template
void selection(std::vector& arr) //Selection soring operation
{
int mini, loc, temp, x, y;
mini = arr[0];
for(x = 0; x <= arr.size()-1; x++)
{
mini = arr[x]; //x position value of array is considered as minimum value
loc = x; //Stores the location of the minimum value
for(y = x + 1; y <= arr.size()-1; y++)
{
if(arr[y] < mini) //Checks the already minimum value with the array contents
{
mini = arr[y]; //Stores the new minimum value
loc = y; //Stores the location of the minimum value
}
}
if(loc != x) //If it is not the same location
{
temp = arr[x];
arr[x] = arr[loc];
arr[loc] = temp;
}
}
}
template
void bubble(std::vector &ar) //Bubble sort operation
{
bool swapp = true;
while(swapp)
{
swapp = false;
for (int i = 0; i < ar.size()-1; i++)
{
if (ar[i]>ar[i+1] )
{
ar[i] += ar[i+1];
ar[i+1] = ar[i] - ar[i+1];
ar[i] -=ar[i+1];
swapp = true;
}
}
}
}
int main()
{
char ch;
do
{
cout<<\"\ MENU\";
cout<<\"\ a Fill the array with user input\";
cout<<\"\ b Display the array\";
cout<<\"\ c Suffel the array element randomly\";
cout<<\"\ d Sort the array using bubble sort\";
cout<<\"\ e Sort the array using Selection Sort\";
cout<<\"\ f Exit Program\";
cout<<\"\ Enter your choice: \";
cin>>ch;
switch(ch)
{
case \'a\':
case \'A\':
accept(a);
cout<<\"\ Accept data operation completed \ \";
break;
case \'b\':
case \'B\':
display(a);
cout<<\"\ Display data operation completed \ \";
break;
case \'c\':
case \'C\':
bogosort(a);
bool b = is_sorted(a);
if(b == true)
display(a);
cout<<\"\ Bugg Sorting operation completed \ \";
break;
case \'d\':
case \'D\':
bubble(a);
display(a);
cout<<\"\ Bubble Sort operation completed \ \";
break;
case \'e\':
case \'E\':
selection(a);
display(a);
cout<<\"\ Selection Sort operation completed \ \";
break;
case \'f\':
case \'F\':
exit(0);
default:
cout<<\"\ Wrong Choice\";
}
}while(1); //Loop will continue infinitely till F or f is pressed
}
Output
MENU
a Fill the array with user input
b Display the array
c Suffel the array element randomly
d Sort the array using bubble sort
e Sort the array using Selection Sort
f Exit Program
Enter your choice: a
10
5
4
78
9
65
3
1
45
66
Accept data operation completed
MENU
a Fill th.
#include algorithm #include vector #include iostream usi.pdf
#include
#include
#include
using namespace std;
template //For Template
void bogosort(std::vector& array) //For bogosort
{
while (! is_sorted(array))
{
std::random_shuffle(array.begin(), array.end());
}
}
template
bool is_sorted(const std::vector& array) //Conforming for display
{
for (typename std::vector::size_type i = 1; i < array.size(); ++i)
{
if (array[i] < array[i-1])
{
return false;
}
}
return true;
}
std::vector a (10); //Creates a vector of size 10
int arr[10];
template
void accept(std::vector& array) //Accepts data to a vector
{
int c;
for(c = 0; c < 10; c++)
cin>>arr[c];
a.assign (arr,arr+10); //Assign array data to the vector
}
template
void display(std::vector& array) //Display the vector contents
{
for (std::vector::iterator it = array.begin(); it != array.end(); ++it)
std::cout << \' \' << *it;
}
template
void selection(std::vector& arr) //Selection soring operation
{
int mini, loc, temp, x, y;
mini = arr[0];
for(x = 0; x <= arr.size()-1; x++)
{
mini = arr[x]; //x position value of array is considered as minimum value
loc = x; //Stores the location of the minimum value
for(y = x + 1; y <= arr.size()-1; y++)
{
if(arr[y] < mini) //Checks the already minimum value with the array contents
{
mini = arr[y]; //Stores the new minimum value
loc = y; //Stores the location of the minimum value
}
}
if(loc != x) //If it is not the same location
{
temp = arr[x];
arr[x] = arr[loc];
arr[loc] = temp;
}
}
}
template
void bubble(std::vector &ar) //Bubble sort operation
{
bool swapp = true;
while(swapp)
{
swapp = false;
for (int i = 0; i < ar.size()-1; i++)
{
if (ar[i]>ar[i+1] )
{
ar[i] += ar[i+1];
ar[i+1] = ar[i] - ar[i+1];
ar[i] -=ar[i+1];
swapp = true;
}
}
}
}
int main()
{
char ch;
do
{
cout<<\"\ MENU\";
cout<<\"\ a Fill the array with user input\";
cout<<\"\ b Display the array\";
cout<<\"\ c Suffel the array element randomly\";
cout<<\"\ d Sort the array using bubble sort\";
cout<<\"\ e Sort the array using Selection Sort\";
cout<<\"\ f Exit Program\";
cout<<\"\ Enter your choice: \";
cin>>ch;
switch(ch)
{
case \'a\':
case \'A\':
accept(a);
cout<<\"\ Accept data operation completed \ \";
break;
case \'b\':
case \'B\':
display(a);
cout<<\"\ Display data operation completed \ \";
break;
case \'c\':
case \'C\':
bogosort(a);
bool b = is_sorted(a);
if(b == true)
display(a);
cout<<\"\ Bugg Sorting operation completed \ \";
break;
case \'d\':
case \'D\':
bubble(a);
display(a);
cout<<\"\ Bubble Sort operation completed \ \";
break;
case \'e\':
case \'E\':
selection(a);
display(a);
cout<<\"\ Selection Sort operation completed \ \";
break;
case \'f\':
case \'F\':
exit(0);
default:
cout<<\"\ Wrong Choice\";
}
}while(1); //Loop will continue infinitely till F or f is pressed
}
Output
MENU
a Fill the array with user input
b Display the array
c Suffel the array element randomly
d Sort the array using bubble sort
e Sort the array using Selection Sort
f Exit Program
Enter your choice: a
10
5
4
78
9
65
3
1
45
66
Accept data operation completed
MENU
a Fill th.
#include algorithm #include vector #include iostream usi.pdf
#include
#include
#include
using namespace std;
template //For Template
void bogosort(std::vector& array) //For bogosort
{
while (! is_sorted(array))
{
std::random_shuffle(array.begin(), array.end());
}
}
template
bool is_sorted(const std::vector& array) //Conforming for display
{
for (typename std::vector::size_type i = 1; i < array.size(); ++i)
{
if (array[i] < array[i-1])
{
return false;
}
}
return true;
}
std::vector a (10); //Creates a vector of size 10
int arr[10];
template
void accept(std::vector& array) //Accepts data to a vector
{
int c;
for(c = 0; c < 10; c++)
cin>>arr[c];
a.assign (arr,arr+10); //Assign array data to the vector
}
template
void display(std::vector& array) //Display the vector contents
{
for (std::vector::iterator it = array.begin(); it != array.end(); ++it)
std::cout << \' \' << *it;
}
template
void selection(std::vector& arr) //Selection soring operation
{
int mini, loc, temp, x, y;
mini = arr[0];
for(x = 0; x <= arr.size()-1; x++)
{
mini = arr[x]; //x position value of array is considered as minimum value
loc = x; //Stores the location of the minimum value
for(y = x + 1; y <= arr.size()-1; y++)
{
if(arr[y] < mini) //Checks the already minimum value with the array contents
{
mini = arr[y]; //Stores the new minimum value
loc = y; //Stores the location of the minimum value
}
}
if(loc != x) //If it is not the same location
{
temp = arr[x];
arr[x] = arr[loc];
arr[loc] = temp;
}
}
}
template
void bubble(std::vector &ar) //Bubble sort operation
{
bool swapp = true;
while(swapp)
{
swapp = false;
for (int i = 0; i < ar.size()-1; i++)
{
if (ar[i]>ar[i+1] )
{
ar[i] += ar[i+1];
ar[i+1] = ar[i] - ar[i+1];
ar[i] -=ar[i+1];
swapp = true;
}
}
}
}
int main()
{
char ch;
do
{
cout<<\"\ MENU\";
cout<<\"\ a Fill the array with user input\";
cout<<\"\ b Display the array\";
cout<<\"\ c Suffel the array element randomly\";
cout<<\"\ d Sort the array using bubble sort\";
cout<<\"\ e Sort the array using Selection Sort\";
cout<<\"\ f Exit Program\";
cout<<\"\ Enter your choice: \";
cin>>ch;
switch(ch)
{
case \'a\':
case \'A\':
accept(a);
cout<<\"\ Accept data operation completed \ \";
break;
case \'b\':
case \'B\':
display(a);
cout<<\"\ Display data operation completed \ \";
break;
case \'c\':
case \'C\':
bogosort(a);
bool b = is_sorted(a);
if(b == true)
display(a);
cout<<\"\ Bugg Sorting operation completed \ \";
break;
case \'d\':
case \'D\':
bubble(a);
display(a);
cout<<\"\ Bubble Sort operation completed \ \";
break;
case \'e\':
case \'E\':
selection(a);
display(a);
cout<<\"\ Selection Sort operation completed \ \";
break;
case \'f\':
case \'F\':
exit(0);
default:
cout<<\"\ Wrong Choice\";
}
}while(1); //Loop will continue infinitely till F or f is pressed
}
Output
MENU
a Fill the array with user input
b Display the array
c Suffel the array element randomly
d Sort the array using bubble sort
e Sort the array using Selection Sort
f Exit Program
Enter your choice: a
10
5
4
78
9
65
3
1
45
66
Accept data operation completed
MENU
a Fill th.
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Chapter 2
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