1. Name ________________________________________ Date _________________________
Mrs. Labuski / Mrs. Portsmore Period ____________ Unit 10 Lesson 3 Surface Area Day 2
OC 6-6 / TB 10-7
A closed box in the shape of a rectangular prism has a length of 13 cm, a width of 5.3 cm, and a
height of 7.1 cm.
Part A: Draw a net of the box and find its surface area in square centimeters.
Answer: ____________________
2. Part B: A smaller box has dimensions that are half the measurements of the original. Find the
ratio of the surface area of the original box to the surface area of the smaller box.
Answer: ____________________
3. Name ________________________________________ Date _________________________
Mrs. Labuski / Mrs. Portsmore Period ____________ Unit 10 Lesson 3 Surface Area Day 2
OC 6-6 / TB 10-7
A closed box in the shape of a rectangular prism has a length of 13 cm, a width of 5.3 cm, and a
height of 7.1 cm.
Part A: Draw a net of the box and find its surface area in square centimeters.
Face Base Height Area
top 5.3 13 68.9 ft2
bottom 5.3 13 68.9 ft2
front 13 7.1 92.3 ft2
back 13 7.1 92.3 ft2
right 7.1 5.3 37.63 ft2
left 7.1 5.3 37.63 ft2
397.66
total
ft2
4. Answer: 397.66 ft2
Part B: A smaller box has dimensions that are half the measurements of the original. Find the
ratio of the surface area of the original box to the surface area of the smaller box.
***NOTE: when the dimensions are cut in half, then the surface area
is divided by 4
5. the surface area of the original box = 397.66 ft2
÷4
the surface area of the smaller box = 99.415 ft2
The ratio of the surface area of the original box to the surface area of the
smaller box is 397.66 to 99.415 or 4:1
Answer: 4:1
6. the surface area of the original box = 397.66 ft2
÷4
the surface area of the smaller box = 99.415 ft2
The ratio of the surface area of the original box to the surface area of the
smaller box is 397.66 to 99.415 or 4:1
Answer: 4:1
