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Elev: Sima Marcel Cls a XI-a B
Enuntul problemei ,[object Object],[object Object],[object Object]
Pentru linia i pentru  i<n se obtine astfel: ,[object Object],[object Object],[object Object]
T: 2 3 3 5 5 6 6 4 4 1 5 6 1 4 12 9 9 9 8 7 C: 6 6 6 + + + + + + 5 = = = = = = 11 11 12 < < < < 3 3 6 1 4 > 4 3 3 3 4 4 4 + + + + + 1 = = = = = 5 5 8 6 6 6 9 > 5 5 3 4 8 8 9 9 2 2 + = 3 5 5 5 7 12 8 9 9 9 7
2 3 3 5 5 6 6 4 4 1 T: 5 6 1 4 C: 12 9 9 6 6 6 + + + + 5 = = = = 11 11 12 < 3 3 6 1 4 > 4 8 + = = < 4 4 4 + 1 5 5 8 12 + + + + + + 5 = = = = = = 17 3 3 9 12 15 15 12 5 9 8 14 14 13 13 > > 2 2 15 14 17 16 16 > 12 9 8 15 14 17
Algoritmul  ,[object Object],[object Object]
[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],T:
Implementarea programului: ,[object Object],[object Object],[object Object]
Programul ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]

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Triunghi

  • 1. Elev: Sima Marcel Cls a XI-a B
  • 2.
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  • 4. T: 2 3 3 5 5 6 6 4 4 1 5 6 1 4 12 9 9 9 8 7 C: 6 6 6 + + + + + + 5 = = = = = = 11 11 12 < < < < 3 3 6 1 4 > 4 3 3 3 4 4 4 + + + + + 1 = = = = = 5 5 8 6 6 6 9 > 5 5 3 4 8 8 9 9 2 2 + = 3 5 5 5 7 12 8 9 9 9 7
  • 5. 2 3 3 5 5 6 6 4 4 1 T: 5 6 1 4 C: 12 9 9 6 6 6 + + + + 5 = = = = 11 11 12 < 3 3 6 1 4 > 4 8 + = = < 4 4 4 + 1 5 5 8 12 + + + + + + 5 = = = = = = 17 3 3 9 12 15 15 12 5 9 8 14 14 13 13 > > 2 2 15 14 17 16 16 > 12 9 8 15 14 17
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