Mrs. Meeks
hypotenuse
leg

leg
a² + b² = c²
x
6 in

8 in
x
6 in

8 in

a² + b² = c²
6² + 8² = c²
x
6 in

8 in

a² + b² = c²
6² + 8² = c²
36 + 64 = c²
x
6 in

8 in

a² + b² = c²
6² + 8² = c²
36 + 64 = c²
100 = c²
x
6 in

8 in

a² + b² = c²
6² + 8² = c²
36 + 64 = c²
√100 = √c²
x
6 in

a² + b² = c²
6² + 8² = c²
36 + 64 = c²
√100 = √c²
10 = c

8 in

The hypotenuse is 10 in.
a

5 in

4 in

a² + b² = c²
a² + 4² = 5²
5 in
a

4 in

a² + b² = c²
a² + 4² = 5²
a² + 16 = 25
5 in
a

4 in

a² + b² = c²
6² + 8² = c²
a² + 16 = 25
-16 -16
a² = 9
5 in
a

4 in

a² + b² = c²
6² + 8² = c²
a² + 16 = 25
-16 -16
√a² = √9
5 in
a

4 in

The missing leg is 3in.

a² + b² = c²
6² + 8² = c²
a² + 16 = 25
-16 -16
√a² = √9
a=3
Now we will watch this video
demonstrating the Pythagorean Spiral
project. You will have 3 days to complete
the project. Make sure you read the
directions and rubric carefully!

Click image to go to video

The pythagorean theorem podcast

  • 1.
  • 2.
  • 3.
    a² + b²= c² x 6 in 8 in
  • 4.
    x 6 in 8 in a²+ b² = c² 6² + 8² = c²
  • 5.
    x 6 in 8 in a²+ b² = c² 6² + 8² = c² 36 + 64 = c²
  • 6.
    x 6 in 8 in a²+ b² = c² 6² + 8² = c² 36 + 64 = c² 100 = c²
  • 7.
    x 6 in 8 in a²+ b² = c² 6² + 8² = c² 36 + 64 = c² √100 = √c²
  • 8.
    x 6 in a² +b² = c² 6² + 8² = c² 36 + 64 = c² √100 = √c² 10 = c 8 in The hypotenuse is 10 in.
  • 9.
    a 5 in 4 in a²+ b² = c² a² + 4² = 5²
  • 10.
    5 in a 4 in a²+ b² = c² a² + 4² = 5² a² + 16 = 25
  • 11.
    5 in a 4 in a²+ b² = c² 6² + 8² = c² a² + 16 = 25 -16 -16 a² = 9
  • 12.
    5 in a 4 in a²+ b² = c² 6² + 8² = c² a² + 16 = 25 -16 -16 √a² = √9
  • 13.
    5 in a 4 in Themissing leg is 3in. a² + b² = c² 6² + 8² = c² a² + 16 = 25 -16 -16 √a² = √9 a=3
  • 14.
    Now we willwatch this video demonstrating the Pythagorean Spiral project. You will have 3 days to complete the project. Make sure you read the directions and rubric carefully! Click image to go to video