[程式設計]判斷閏年
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A program is presented to determine if a given year is a leap year or not. The program takes a year as input, calls the leap_year function passing the year, and the function returns 1 if it's a leap year or 0 if it's not. The function checks if the year is divisible by 4, then if it's also divisible by 100 it's not a leap year, unless it's also divisible by 400, in which case it is a leap year.
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![[程式設計]判斷閏年<br />#include<stdio.h><br />int leap_year(int y);<br />void main(void){<br /> int year;<br /> scanf(quot;
%dquot;
, &year);<br /> if (leap_year(year))<br /> printf(quot;
%d is leap year.quot;
, year);<br /> else<br /> printf(quot;
%d is not leap year.quot;
, year);<br /> <br />}<br />int leap_year(int y){<br /> int r=0;<br /> if (y%4==0){<br /> r=1;<br /> if (y%100==0)<br /> r=0;<br /> if (y%400==0)<br /> r=1;<br /> };<br /> return r;<br />}<br />](https://image.slidesharecdn.com/random-100505230238-phpapp01/85/-1-320.jpg)
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