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Х                   1-Х

   А                       С            В

 1-Х = Х
                      1
  Х    1
                           Х1= -1 -√5
                                 2
   2
  Х +Х–1=0

       2
                           Х2 =   -1 +√5
D = b – 4 ас = 1 + 4 = 5                 ≈ 0,6
                                    2
Фидий




φ ≈ 0.6
Х                 1-Х

А                   С                   В
             1
1-Х     Х                           2
 Х
    =
        1                  1- φ = φ
            1- φ    φ
            φ      = 1
 Х=φ
                                2
                         1= φ + φ
3       4
φ   2
      φ         3
    φ       φ       2
      φ             φ

            1

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Золотое сечение

  • 1. Х 1-Х А С В 1-Х = Х 1 Х 1 Х1= -1 -√5 2 2 Х +Х–1=0 2 Х2 = -1 +√5 D = b – 4 ас = 1 + 4 = 5 ≈ 0,6 2
  • 3. Х 1-Х А С В 1 1-Х Х 2 Х = 1 1- φ = φ 1- φ φ φ = 1 Х=φ 2 1= φ + φ
  • 4. 3 4 φ 2 φ 3 φ φ 2 φ φ 1