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Seven times the first (smaller) of two consecutive odd integers is equal to five times the second
(larger) integer. Find each integers.
Solution
we have, let the integers be (2n+1) and ( 2n+3) now, 7(2n+1) = 5 ( 2n+3) 4n = 8 n
= 2 the numbers are : 2n + 1= 5 2n+3 = 7

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Seven times the first (smaller) of two consecutive odd integers is e.pdf

  • 1. Seven times the first (smaller) of two consecutive odd integers is equal to five times the second (larger) integer. Find each integers. Solution we have, let the integers be (2n+1) and ( 2n+3) now, 7(2n+1) = 5 ( 2n+3) 4n = 8 n = 2 the numbers are : 2n + 1= 5 2n+3 = 7