Place your solid components in water (this will b.pdf
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Place your solid components in water (this will be step one). The result will be that A will remain as a solid and will sink to the bottom of the solution. Pour off the water that remains containing B and C. Heat the water to evaporate it, and you will be left with a mixture of B and C in solid form. Next, place this resulting solid mixture in ethanol. Again, C will sink to the bottom, and B will remain in the liquid. Pour off the liquid, obtaining the pure solid C. Heat the ethanol containing only B, and when the liquid has evaporated you will be left with B. as a flow chart, this will be ABC - Add to water BC in water A remains solid Evaporate water, add BC to ethanol B in ethanol C remains solid Evaporate ethanol and obtain B Hope this helps! Solution Place your solid components in water (this will be step one). The result will be that A will remain as a solid and will sink to the bottom of the solution. Pour off the water that remains containing B and C. Heat the water to evaporate it, and you will be left with a mixture of B and C in solid form. Next, place this resulting solid mixture in ethanol. Again, C will sink to the bottom, and B will remain in the liquid. Pour off the liquid, obtaining the pure solid C. Heat the ethanol containing only B, and when the liquid has evaporated you will be left with B. as a flow chart, this will be ABC - Add to water BC in water A remains solid Evaporate water, add BC to ethanol B in ethanol C remains solid Evaporate ethanol and obtain B Hope this helps!.
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a) False - correlation says nothing about particular values. b) F.pdf
a) False - correlation says nothing about particular values.
b) False - follows from above.
c) and d) True because positive correlation
e) False
Solution
a) False - correlation says nothing about particular values.
b) False - follows from above.
c) and d) True because positive correlation
e) False.
In an octahedral field f orbitals are split into three parts. 1. Sin.pdf
In an octahedral field f orbitals are split into three parts. 1. Singly degenerate lowest energy
state 2. Triply degenerate 3. Highest energy triply degenerate
Solution
In an octahedral field f orbitals are split into three parts. 1. Singly degenerate lowest energy
state 2. Triply degenerate 3. Highest energy triply degenerate.
SO4I- is the reaction intermediate in the mechani.pdf
SO4I- is the reaction intermediate in the mechanism1 as it is generated inthe first
step and being consumed in the second step. I2 is the reaction intermediate in the mechanism2
by the same reason.
Solution
SO4I- is the reaction intermediate in the mechanism1 as it is generated inthe first
step and being consumed in the second step. I2 is the reaction intermediate in the mechanism2
by the same reason..
no there is no such relation ... .pdf
This very short document does not provide any information to summarize in 3 sentences or less. It contains only the phrase "no there is no such relation ..." repeated twice without any other context.
zinc sulfide == solid (insoluble) cobalt(II) ca.pdf
zinc sulfide ==> solid (insoluble) cobalt(II) carbonate ==> solid (insoluble) lead
nitrate ======. aq (soluble) Please refer the solubility chart. most of the carbonate and sulphide
salt are insoluble whereas nitrate salt are soluble)
Solution
zinc sulfide ==> solid (insoluble) cobalt(II) carbonate ==> solid (insoluble) lead
nitrate ======. aq (soluble) Please refer the solubility chart. most of the carbonate and sulphide
salt are insoluble whereas nitrate salt are soluble).
where is the table .pdf
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Its e2 reaction so replace cl by -OH- .pdf
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Cl in elemental form has oxidation 0 & in NaCl ha.pdf
Cl in elemental form has oxidation 0 & in NaCl has -1 => Reduced Br goes from -1
to elemental (0) => Oxidized (C)
Solution
Cl in elemental form has oxidation 0 & in NaCl has -1 => Reduced Br goes from -1
to elemental (0) => Oxidized (C).
Recommended
a) False - correlation says nothing about particular values. b) F.pdf
a) False - correlation says nothing about particular values.
b) False - follows from above.
c) and d) True because positive correlation
e) False
Solution
a) False - correlation says nothing about particular values.
b) False - follows from above.
c) and d) True because positive correlation
e) False.
In an octahedral field f orbitals are split into three parts. 1. Sin.pdf
In an octahedral field f orbitals are split into three parts. 1. Singly degenerate lowest energy
state 2. Triply degenerate 3. Highest energy triply degenerate
Solution
In an octahedral field f orbitals are split into three parts. 1. Singly degenerate lowest energy
state 2. Triply degenerate 3. Highest energy triply degenerate.
SO4I- is the reaction intermediate in the mechani.pdf
SO4I- is the reaction intermediate in the mechanism1 as it is generated inthe first
step and being consumed in the second step. I2 is the reaction intermediate in the mechanism2
by the same reason.
Solution
SO4I- is the reaction intermediate in the mechanism1 as it is generated inthe first
step and being consumed in the second step. I2 is the reaction intermediate in the mechanism2
by the same reason..
no there is no such relation ... .pdf
This very short document does not provide any information to summarize in 3 sentences or less. It contains only the phrase "no there is no such relation ..." repeated twice without any other context.
zinc sulfide == solid (insoluble) cobalt(II) ca.pdf
zinc sulfide ==> solid (insoluble) cobalt(II) carbonate ==> solid (insoluble) lead
nitrate ======. aq (soluble) Please refer the solubility chart. most of the carbonate and sulphide
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Solution
zinc sulfide ==> solid (insoluble) cobalt(II) carbonate ==> solid (insoluble) lead
nitrate ======. aq (soluble) Please refer the solubility chart. most of the carbonate and sulphide
salt are insoluble whereas nitrate salt are soluble).
where is the table .pdf
The document asks "where is the table?" and provides a simple one word response of "Solution" without any further context or details to answer the question about the table's location.
Its e2 reaction so replace cl by -OH- .pdf
This is an E2 reaction so the chlorine will be replaced by a hydroxyl group (-OH-) when reacted with a strong base. The chlorine will be eliminated and replaced by an alcohol functional group in an anti-periplanar orientation during the E2 reaction.
Cl in elemental form has oxidation 0 & in NaCl ha.pdf
Cl in elemental form has oxidation 0 & in NaCl has -1 => Reduced Br goes from -1
to elemental (0) => Oxidized (C)
Solution
Cl in elemental form has oxidation 0 & in NaCl has -1 => Reduced Br goes from -1
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fluorosilicic acid is the inorganic compound with.pdf
fluorosilicic acid is the inorganic compound with the formula H2SiF6 Moles of
acid =10^-3/144.09 =6.94*10^-6 See 1 mole of acid has 6 mole of fluoride ions in the formula
So Increase in concentration = 6*6.94*10^-6/V =4.164*10^-5/V You haven\'t given volume of
water. Put V and get concentration.
Solution
fluorosilicic acid is the inorganic compound with the formula H2SiF6 Moles of
acid =10^-3/144.09 =6.94*10^-6 See 1 mole of acid has 6 mole of fluoride ions in the formula
So Increase in concentration = 6*6.94*10^-6/V =4.164*10^-5/V You haven\'t given volume of
water. Put V and get concentration..
Li2 means two Li atom bound to each other. it is .pdf
Li2 means two Li atom bound to each other. it is neither oxidized, nor reduced.
Thus, Li\'s oxidation number is zero.
Solution
Li2 means two Li atom bound to each other. it is neither oxidized, nor reduced.
Thus, Li\'s oxidation number is zero..
Yes some of the jobs are in decliened state due to online marketing .pdf
Yes some of the jobs are in decliened state due to online marketing and internet facilities.Some
of these are:
1. Bank Workers
We’re doing more and more banking online these days, and even though some Australian banks
are advertising that you can find “real people” in their branches to assist you, the customer
service element of banking is sharply in decline.
Services that have been traditionally performed by tellers are now done electronically. Automatic
teller machines are being used more frequently and tellers are only needed for complex
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learn about a particular banking product that their company offers. They also generally need to
be good with people and customer service.
2. Filing and Registry Workers
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It’s becoming less and less important for most businesses to employ someone just to file
documents as technology has increased; most workers are able to perform this function
themselves. Keeping copies of important documents in hard copy is still a necessary occurrence
in many cases, but more often than not, having digital copies of documents is more time and
space efficient. Filing workers need to have great organisation skills and be good with systems
and dealing with different types of people and management levels.
3. Manufacturers
In Australia, we are seeing more and more manufacturing moving overseas. It’s well understood
that Australia is a high wage country, and has been since the 1820s. After Federation, high wages
were cemented in place by reformers and trade unions; Australian governments were among the
first to grant age pensions and other welfare benefits as well.
The downside is that Australian manufacturing has become uncompetitive against nations whose
manufacturers “carried lighter burdens”. Chesty Bonds, King Gee and Hard Yakka have joined
“a conga line of Aussie brands exiting the country” leaving many individuals jobless.
4. Data Entry/Keyboard Operators
Over the last two decades, the amount of data generated has grown, but these days there is less
need for a person to translate, transfer or manipulate this data, as a lot of this is now done
automatically. Another reason for the drop in employment is the fact that where companies still
use data entry operators, they may outsource this function to overseas where wages are lower.
For those people who are thinking about a job in this field, or for those who are currently
employed in this line of work, contemplate expanding your skill-set to encompass other valuable
office skills.
5. Postal Worker / Mail Sorter
The number of people who are employed in positions where they sort and distribute mail has
sharply declined.
When acid is addedMolecular NaCHO2(aq) + H+(aq) = HCHO2(aq) + N.pdf
When acid is added:
Molecular: NaCHO2(aq) + H+(aq) => HCHO2(aq) + Na+(aq)
Ionic: CHO2-(aq) + H+(aq) => HCHO2(aq)
When base is added:
Molecular: HCHO2(aq) + NaOH(aq) => NaCHO2(aq) + H2O(l)
Ionic: HCHO2(aq) + OH-(aq) => CHO2-(aq) + H2O(l)
Solution
When acid is added:
Molecular: NaCHO2(aq) + H+(aq) => HCHO2(aq) + Na+(aq)
Ionic: CHO2-(aq) + H+(aq) => HCHO2(aq)
When base is added:
Molecular: HCHO2(aq) + NaOH(aq) => NaCHO2(aq) + H2O(l)
Ionic: HCHO2(aq) + OH-(aq) => CHO2-(aq) + H2O(l).
We can not simply come to the conclusion that original asteroid had .pdf
We can not simply come to the conclusion that original asteroid had a similar comosition of
metals and
carbon.
There may be a possibility of nuclear radiactivity from which initial compostion is redistributed
into metals and carbon type
The unstable elements in the asteroids have been acquired the stable configuration and then
redistributed as two separate belts.
Solution
We can not simply come to the conclusion that original asteroid had a similar comosition of
metals and
carbon.
There may be a possibility of nuclear radiactivity from which initial compostion is redistributed
into metals and carbon type
The unstable elements in the asteroids have been acquired the stable configuration and then
redistributed as two separate belts..
The term meiosis was originally introduced by J. B. Farmer and J.E.S.pdf
The term meiosis was originally introduced by J. B. Farmer and J.E.S Moore in the year 1905. It
was discovered by Oscar Hertwig in 1876. Meiosis is a type of cell division wherein which the
chromosome number of a diploid cell is halved, creating haploid cells. It takes place in
reproductive cells of all organisms. It is responsible for the formation of gametes which are
essentially haploid in nature.
In meiosis after the occurrence of DNA replication there is the formation of four daughter cells
by two rounds of cell divisions. There are two stages in meiosis stage I and stage II. The different
phases of meiosis are called as Prophase, Metaphase, Anaphase and Telophase.
Solution
The term meiosis was originally introduced by J. B. Farmer and J.E.S Moore in the year 1905. It
was discovered by Oscar Hertwig in 1876. Meiosis is a type of cell division wherein which the
chromosome number of a diploid cell is halved, creating haploid cells. It takes place in
reproductive cells of all organisms. It is responsible for the formation of gametes which are
essentially haploid in nature.
In meiosis after the occurrence of DNA replication there is the formation of four daughter cells
by two rounds of cell divisions. There are two stages in meiosis stage I and stage II. The different
phases of meiosis are called as Prophase, Metaphase, Anaphase and Telophase..
Typical resting potential of neuron is -70 mV.Correct answer is op.pdf
Typical resting potential of neuron is -70 mV.
Correct answer is option A.
It is negative due to uneven distribution of ions and also due to the presence of nucleic acids.
Solution
Typical resting potential of neuron is -70 mV.
Correct answer is option A.
It is negative due to uneven distribution of ions and also due to the presence of nucleic acids..
The value of a IEEE-754 number is computed assign 2exponent m.pdf
The value of a IEEE-754 number is computed as:
sign * 2exponent * mantissa
The sign is stored in bit 32. The exponent can be computed from bits 24-31 by subtracting 127.
The mantissa (also known as significand or fraction) is stored in bits 1-23. An invisible leading
bit (i.e. it is not actually stored) with value 1.0 is placed in front, then bit 23 has a value of 1/2,
bit 22 has value 1/4 etc. As a result, the mantissa has a value between 1.0 and 2. If the exponent
reaches -127 (binary 00000000), the leading 1 is no longer used to enable gradual underflow.
Binary equivalents of:
14.0 is 01000001011000000000000000000000
32.0 is 01000010000000000000000000000000
-3.0 is 11000000010000000000000000000000
128.0 is 01000011000000000000000000000000
-6.0 is 11000000110000000000000000000000
-15.0 is 11000001011100000000000000000000
Solution
The value of a IEEE-754 number is computed as:
sign * 2exponent * mantissa
The sign is stored in bit 32. The exponent can be computed from bits 24-31 by subtracting 127.
The mantissa (also known as significand or fraction) is stored in bits 1-23. An invisible leading
bit (i.e. it is not actually stored) with value 1.0 is placed in front, then bit 23 has a value of 1/2,
bit 22 has value 1/4 etc. As a result, the mantissa has a value between 1.0 and 2. If the exponent
reaches -127 (binary 00000000), the leading 1 is no longer used to enable gradual underflow.
Binary equivalents of:
14.0 is 01000001011000000000000000000000
32.0 is 01000010000000000000000000000000
-3.0 is 11000000010000000000000000000000
128.0 is 01000011000000000000000000000000
-6.0 is 11000000110000000000000000000000
-15.0 is 11000001011100000000000000000000.
The Lewis acid (electron pair acceptor) is Zn(OH)2The Lewis base (.pdf
The Lewis acid (electron pair acceptor) is Zn(OH)2
The Lewis base (electron pair donor) is OH
Solution
The Lewis acid (electron pair acceptor) is Zn(OH)2
The Lewis base (electron pair donor) is OH.
The answer is E. are referred to as task functionsSolutionThe .pdf
The answer is E. are referred to as task functions
Solution
The answer is E. are referred to as task functions.
For the first one it will be zero because only H-.pdf
For the first one it will be zero because only H- H interaction on axial position For
second there should be interaction energy between isopropyl and methyl should be specified
otherwise theproblem can not be done
Solution
For the first one it will be zero because only H- H interaction on axial position For
second there should be interaction energy between isopropyl and methyl should be specified
otherwise theproblem can not be done.
first is more basic.. as negative charge in 2nd a.pdf
first is more basic.. as negative charge in 2nd and 3rd is reduced by resonance in
benzene ring
Solution
first is more basic.. as negative charge in 2nd and 3rd is reduced by resonance in
benzene ring.
Please rate with 5 stars ) Abs = log10(IoI) Transmittance = I.pdf
Please rate with 5 stars :)
Abs = log10(Io/I)
Transmittance = I/Io
Io incident light intensity
I exiting light intensity
Hence, Absorbance = log10(1.00/0.753)
Cheers!
Solution
Please rate with 5 stars :)
Abs = log10(Io/I)
Transmittance = I/Io
Io incident light intensity
I exiting light intensity
Hence, Absorbance = log10(1.00/0.753)
Cheers!.
Option d) all of the above is correct. This is because these structu.pdf
Option d) all of the above is correct. This is because these structures are anatomically disimilar
but superficially similar.
Solution
Option d) all of the above is correct. This is because these structures are anatomically disimilar
but superficially similar..
Net profit after taxes=Operating income(1-tax rate)which is equal .pdf
Net profit after taxes=Operating income(1-tax rate)
which is equal to
=$2,900,000(1-0.37)=$1,827,000
Invested capital after tax=$20,000,000*0.07)=$1,400,000
Hence EVA=Net profit after taxes-Invested capital after tax
$1,827,000-$1,400,000
=$427000.
Solution
Net profit after taxes=Operating income(1-tax rate)
which is equal to
=$2,900,000(1-0.37)=$1,827,000
Invested capital after tax=$20,000,000*0.07)=$1,400,000
Hence EVA=Net profit after taxes-Invested capital after tax
$1,827,000-$1,400,000
=$427000..
Mg2+(aq) + Ca(OH)2(s) --- Mg(OH)2(s) + Ca2+(aq)the calcium and ma.pdf
Mg2+(aq) + Ca(OH)2(s) ---> Mg(OH)2(s) + Ca2+(aq)
the calcium and magnesium ions are in aqeous phase, rest are solid
Solution
Mg2+(aq) + Ca(OH)2(s) ---> Mg(OH)2(s) + Ca2+(aq)
the calcium and magnesium ions are in aqeous phase, rest are solid.
Benzoin is an organic compound consisting of an e.pdf
Benzoin, an organic compound with phenyl groups and hydroxyl and ketone functional groups, is readily oxidized by nitric acid to benzil, a diketone. The nitric acid is reduced to nitrous acid, which decomposes into oxides of nitrogen and water. Overall, the reaction converts two molecules of benzoin into two molecules of benzil, along with nitric oxide, nitrogen dioxide, and water.
import java.util.ArrayList; 2 import java.util.List; 3 impor.pdf
import java.util.ArrayList;
2
import java.util.List;
3
import java.util.regex.Matcher;
4
import java.util.regex.Pattern;
5
6
public category GenericTreeNode<T> kids = new ArrayList<GenericTreeNode<T>>();
14
}
15
16
public GenericTreeNode(T data)
20
21
public List<GenericTreeNode<T>> getChildren() come this.children;
23
}
24
25
public int getNumberOfChildren() come back getChildren().size();
27
}
28
29
public mathematician hasChildren() come back (getNumberOfChildren() > 0);
31
}
32
33
public void setChildren(List<GenericTreeNode<T>> children) kids;
35
}
36
37
public void addChild(GenericTreeNode<T> child)
40
41
public void addChildAt(int index, GenericTreeNode<T> child) throws
IndexOutOfBoundsException
44
45
public void removeChildren()
48
49
public void removeChildAt(int index) throws IndexOutOfBoundsException
52
53
public GenericTreeNode<T> getChildAt(int index) throws IndexOutOfBoundsException come
youngsters.get(index);
55
}
56
57
public T getData() come back this.data;
59
}
60
61
public void setData(T data) knowledge;
63
}
64
65
public String toString() come back getData().toString();
67
}
68
69
public mathematician equals(GenericTreeNode<T> node) come
node.getData().equals(getData());
71
}
72
73
public int hashCode() come getData().hashCode();
75
}
76
77
public String toStringVerbose()
Solution
import java.util.ArrayList;
2
import java.util.List;
3
import java.util.regex.Matcher;
4
import java.util.regex.Pattern;
5
6
public category GenericTreeNode<T> kids = new ArrayList<GenericTreeNode<T>>();
14
}
15
16
public GenericTreeNode(T data)
20
21
public List<GenericTreeNode<T>> getChildren() come this.children;
23
}
24
25
public int getNumberOfChildren() come back getChildren().size();
27
}
28
29
public mathematician hasChildren() come back (getNumberOfChildren() > 0);
31
}
32
33
public void setChildren(List<GenericTreeNode<T>> children) kids;
35
}
36
37
public void addChild(GenericTreeNode<T> child)
40
41
public void addChildAt(int index, GenericTreeNode<T> child) throws
IndexOutOfBoundsException
44
45
public void removeChildren()
48
49
public void removeChildAt(int index) throws IndexOutOfBoundsException
52
53
public GenericTreeNode<T> getChildAt(int index) throws IndexOutOfBoundsException come
youngsters.get(index);
55
}
56
57
public T getData() come back this.data;
59
}
60
61
public void setData(T data) knowledge;
63
}
64
65
public String toString() come back getData().toString();
67
}
68
69
public mathematician equals(GenericTreeNode<T> node) come
node.getData().equals(getData());
71
}
72
73
public int hashCode() come getData().hashCode();
75
}
76
77
public String toStringVerbose().
I will prefer GIT as a version control. Advantage of using GIT .pdf
I will prefer GIT as a version control.
Advantage of using GIT :
-->Git is distributed version control system. Git was initially designed and developed by Linus
Torvalds for linux kernel development in 2005.
-->Git is free software distributed under the terms of the GNU General Public License version 2.
-->In Git, every user has a complete copy of the repository locally. So making access to file
history is fast and user can access the full codebase even though disconnected from the network.
-->Every user is having full backup of the repository always.In SVN only centralized repository
has the complete history.
-->In Git except push and pull, all other operations are local. E.g. perform a diff, view file
history, commit changes, merge branches, switch branches.
-->Git’s repository and working directory sizes are extremely small when compared to SVN.
-->One place where Git is slower is in the initial clone operation. Here, Git is downloading the
entire history rather than only the latest version.
-->Unlike the other systems, Git has something called the \"staging area\" or \"index\". This is
an intermediate area where commits can be formatted and reviewed before completing the
commit.
One thing that sets Git apart from other tools is that it\'s possible to quickly stage some of
your files and commit them without committing all of the other modified files in your working
directory or having to list them on the command line during the commit.
Disadvantages of using GIT :
1. High learning curve and complex to understand.
2. Because Git does not support checking out sub-trees.
Solution
I will prefer GIT as a version control.
Advantage of using GIT :
-->Git is distributed version control system. Git was initially designed and developed by Linus
Torvalds for linux kernel development in 2005.
-->Git is free software distributed under the terms of the GNU General Public License version 2.
-->In Git, every user has a complete copy of the repository locally. So making access to file
history is fast and user can access the full codebase even though disconnected from the network.
-->Every user is having full backup of the repository always.In SVN only centralized repository
has the complete history.
-->In Git except push and pull, all other operations are local. E.g. perform a diff, view file
history, commit changes, merge branches, switch branches.
-->Git’s repository and working directory sizes are extremely small when compared to SVN.
-->One place where Git is slower is in the initial clone operation. Here, Git is downloading the
entire history rather than only the latest version.
-->Unlike the other systems, Git has something called the \"staging area\" or \"index\". This is
an intermediate area where commits can be formatted and reviewed before completing the
commit.
One thing that sets Git apart from other tools is that it\'s possible to quickly stage some of
your files and commit them without committing all of the other modified files in your workin.
I dont know what ... means so ill assume its =, if its th.pdf
I don\'t know what ... means so i\'ll assume it\'s <=, if it\'s > then use the formula P(X>a) = 1-
P(X<=a)
The CDF of an exponential distribution of parameter L is F(x) = 1-e^(-Lx) for x>=0 and 0
otherwise
The mean of an exponential distribution is 1/L
1
Solution
I don\'t know what ... means so i\'ll assume it\'s <=, if it\'s > then use the formula P(X>a) = 1-
P(X<=a)
The CDF of an exponential distribution of parameter L is F(x) = 1-e^(-Lx) for x>=0 and 0
otherwise
The mean of an exponential distribution is 1/L
1.
Main Java[All of the Base Concepts}.docx
This is part 1 of my Java Learning Journey. This Contains Custom methods, classes, constructors, packages, multithreading , try- catch block, finally block and more.
The simplified electron and muon model, Oscillating Spacetime: The Foundation...
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fluorosilicic acid is the inorganic compound with.pdf
fluorosilicic acid is the inorganic compound with the formula H2SiF6 Moles of
acid =10^-3/144.09 =6.94*10^-6 See 1 mole of acid has 6 mole of fluoride ions in the formula
So Increase in concentration = 6*6.94*10^-6/V =4.164*10^-5/V You haven\'t given volume of
water. Put V and get concentration.
Solution
fluorosilicic acid is the inorganic compound with the formula H2SiF6 Moles of
acid =10^-3/144.09 =6.94*10^-6 See 1 mole of acid has 6 mole of fluoride ions in the formula
So Increase in concentration = 6*6.94*10^-6/V =4.164*10^-5/V You haven\'t given volume of
water. Put V and get concentration..
Li2 means two Li atom bound to each other. it is .pdf
Li2 means two Li atom bound to each other. it is neither oxidized, nor reduced.
Thus, Li\'s oxidation number is zero.
Solution
Li2 means two Li atom bound to each other. it is neither oxidized, nor reduced.
Thus, Li\'s oxidation number is zero..
Yes some of the jobs are in decliened state due to online marketing .pdf
Yes some of the jobs are in decliened state due to online marketing and internet facilities.Some
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1. Bank Workers
We’re doing more and more banking online these days, and even though some Australian banks
are advertising that you can find “real people” in their branches to assist you, the customer
service element of banking is sharply in decline.
Services that have been traditionally performed by tellers are now done electronically. Automatic
teller machines are being used more frequently and tellers are only needed for complex
transactions. A bank teller needs to have very good attention to detail and they often have to
learn about a particular banking product that their company offers. They also generally need to
be good with people and customer service.
2. Filing and Registry Workers
We’re not using paper files as much anymore; with some school leavers not having that many
opportunities to even use a pen these days. Environmental factors also come into play, with lots
of businesses choosing to limit the amount of paper files that they keep or print.
It’s becoming less and less important for most businesses to employ someone just to file
documents as technology has increased; most workers are able to perform this function
themselves. Keeping copies of important documents in hard copy is still a necessary occurrence
in many cases, but more often than not, having digital copies of documents is more time and
space efficient. Filing workers need to have great organisation skills and be good with systems
and dealing with different types of people and management levels.
3. Manufacturers
In Australia, we are seeing more and more manufacturing moving overseas. It’s well understood
that Australia is a high wage country, and has been since the 1820s. After Federation, high wages
were cemented in place by reformers and trade unions; Australian governments were among the
first to grant age pensions and other welfare benefits as well.
The downside is that Australian manufacturing has become uncompetitive against nations whose
manufacturers “carried lighter burdens”. Chesty Bonds, King Gee and Hard Yakka have joined
“a conga line of Aussie brands exiting the country” leaving many individuals jobless.
4. Data Entry/Keyboard Operators
Over the last two decades, the amount of data generated has grown, but these days there is less
need for a person to translate, transfer or manipulate this data, as a lot of this is now done
automatically. Another reason for the drop in employment is the fact that where companies still
use data entry operators, they may outsource this function to overseas where wages are lower.
For those people who are thinking about a job in this field, or for those who are currently
employed in this line of work, contemplate expanding your skill-set to encompass other valuable
office skills.
5. Postal Worker / Mail Sorter
The number of people who are employed in positions where they sort and distribute mail has
sharply declined.
When acid is addedMolecular NaCHO2(aq) + H+(aq) = HCHO2(aq) + N.pdf
When acid is added:
Molecular: NaCHO2(aq) + H+(aq) => HCHO2(aq) + Na+(aq)
Ionic: CHO2-(aq) + H+(aq) => HCHO2(aq)
When base is added:
Molecular: HCHO2(aq) + NaOH(aq) => NaCHO2(aq) + H2O(l)
Ionic: HCHO2(aq) + OH-(aq) => CHO2-(aq) + H2O(l)
Solution
When acid is added:
Molecular: NaCHO2(aq) + H+(aq) => HCHO2(aq) + Na+(aq)
Ionic: CHO2-(aq) + H+(aq) => HCHO2(aq)
When base is added:
Molecular: HCHO2(aq) + NaOH(aq) => NaCHO2(aq) + H2O(l)
Ionic: HCHO2(aq) + OH-(aq) => CHO2-(aq) + H2O(l).
We can not simply come to the conclusion that original asteroid had .pdf
We can not simply come to the conclusion that original asteroid had a similar comosition of
metals and
carbon.
There may be a possibility of nuclear radiactivity from which initial compostion is redistributed
into metals and carbon type
The unstable elements in the asteroids have been acquired the stable configuration and then
redistributed as two separate belts.
Solution
We can not simply come to the conclusion that original asteroid had a similar comosition of
metals and
carbon.
There may be a possibility of nuclear radiactivity from which initial compostion is redistributed
into metals and carbon type
The unstable elements in the asteroids have been acquired the stable configuration and then
redistributed as two separate belts..
The term meiosis was originally introduced by J. B. Farmer and J.E.S.pdf
The term meiosis was originally introduced by J. B. Farmer and J.E.S Moore in the year 1905. It
was discovered by Oscar Hertwig in 1876. Meiosis is a type of cell division wherein which the
chromosome number of a diploid cell is halved, creating haploid cells. It takes place in
reproductive cells of all organisms. It is responsible for the formation of gametes which are
essentially haploid in nature.
In meiosis after the occurrence of DNA replication there is the formation of four daughter cells
by two rounds of cell divisions. There are two stages in meiosis stage I and stage II. The different
phases of meiosis are called as Prophase, Metaphase, Anaphase and Telophase.
Solution
The term meiosis was originally introduced by J. B. Farmer and J.E.S Moore in the year 1905. It
was discovered by Oscar Hertwig in 1876. Meiosis is a type of cell division wherein which the
chromosome number of a diploid cell is halved, creating haploid cells. It takes place in
reproductive cells of all organisms. It is responsible for the formation of gametes which are
essentially haploid in nature.
In meiosis after the occurrence of DNA replication there is the formation of four daughter cells
by two rounds of cell divisions. There are two stages in meiosis stage I and stage II. The different
phases of meiosis are called as Prophase, Metaphase, Anaphase and Telophase..
Typical resting potential of neuron is -70 mV.Correct answer is op.pdf
Typical resting potential of neuron is -70 mV.
Correct answer is option A.
It is negative due to uneven distribution of ions and also due to the presence of nucleic acids.
Solution
Typical resting potential of neuron is -70 mV.
Correct answer is option A.
It is negative due to uneven distribution of ions and also due to the presence of nucleic acids..
The value of a IEEE-754 number is computed assign 2exponent m.pdf
The value of a IEEE-754 number is computed as:
sign * 2exponent * mantissa
The sign is stored in bit 32. The exponent can be computed from bits 24-31 by subtracting 127.
The mantissa (also known as significand or fraction) is stored in bits 1-23. An invisible leading
bit (i.e. it is not actually stored) with value 1.0 is placed in front, then bit 23 has a value of 1/2,
bit 22 has value 1/4 etc. As a result, the mantissa has a value between 1.0 and 2. If the exponent
reaches -127 (binary 00000000), the leading 1 is no longer used to enable gradual underflow.
Binary equivalents of:
14.0 is 01000001011000000000000000000000
32.0 is 01000010000000000000000000000000
-3.0 is 11000000010000000000000000000000
128.0 is 01000011000000000000000000000000
-6.0 is 11000000110000000000000000000000
-15.0 is 11000001011100000000000000000000
Solution
The value of a IEEE-754 number is computed as:
sign * 2exponent * mantissa
The sign is stored in bit 32. The exponent can be computed from bits 24-31 by subtracting 127.
The mantissa (also known as significand or fraction) is stored in bits 1-23. An invisible leading
bit (i.e. it is not actually stored) with value 1.0 is placed in front, then bit 23 has a value of 1/2,
bit 22 has value 1/4 etc. As a result, the mantissa has a value between 1.0 and 2. If the exponent
reaches -127 (binary 00000000), the leading 1 is no longer used to enable gradual underflow.
Binary equivalents of:
14.0 is 01000001011000000000000000000000
32.0 is 01000010000000000000000000000000
-3.0 is 11000000010000000000000000000000
128.0 is 01000011000000000000000000000000
-6.0 is 11000000110000000000000000000000
-15.0 is 11000001011100000000000000000000.
The Lewis acid (electron pair acceptor) is Zn(OH)2The Lewis base (.pdf
The Lewis acid (electron pair acceptor) is Zn(OH)2
The Lewis base (electron pair donor) is OH
Solution
The Lewis acid (electron pair acceptor) is Zn(OH)2
The Lewis base (electron pair donor) is OH.
The answer is E. are referred to as task functionsSolutionThe .pdf
The answer is E. are referred to as task functions
Solution
The answer is E. are referred to as task functions.
For the first one it will be zero because only H-.pdf
For the first one it will be zero because only H- H interaction on axial position For
second there should be interaction energy between isopropyl and methyl should be specified
otherwise theproblem can not be done
Solution
For the first one it will be zero because only H- H interaction on axial position For
second there should be interaction energy between isopropyl and methyl should be specified
otherwise theproblem can not be done.
first is more basic.. as negative charge in 2nd a.pdf
first is more basic.. as negative charge in 2nd and 3rd is reduced by resonance in
benzene ring
Solution
first is more basic.. as negative charge in 2nd and 3rd is reduced by resonance in
benzene ring.
Please rate with 5 stars ) Abs = log10(IoI) Transmittance = I.pdf
Please rate with 5 stars :)
Abs = log10(Io/I)
Transmittance = I/Io
Io incident light intensity
I exiting light intensity
Hence, Absorbance = log10(1.00/0.753)
Cheers!
Solution
Please rate with 5 stars :)
Abs = log10(Io/I)
Transmittance = I/Io
Io incident light intensity
I exiting light intensity
Hence, Absorbance = log10(1.00/0.753)
Cheers!.
Option d) all of the above is correct. This is because these structu.pdf
Option d) all of the above is correct. This is because these structures are anatomically disimilar
but superficially similar.
Solution
Option d) all of the above is correct. This is because these structures are anatomically disimilar
but superficially similar..
Net profit after taxes=Operating income(1-tax rate)which is equal .pdf
Net profit after taxes=Operating income(1-tax rate)
which is equal to
=$2,900,000(1-0.37)=$1,827,000
Invested capital after tax=$20,000,000*0.07)=$1,400,000
Hence EVA=Net profit after taxes-Invested capital after tax
$1,827,000-$1,400,000
=$427000.
Solution
Net profit after taxes=Operating income(1-tax rate)
which is equal to
=$2,900,000(1-0.37)=$1,827,000
Invested capital after tax=$20,000,000*0.07)=$1,400,000
Hence EVA=Net profit after taxes-Invested capital after tax
$1,827,000-$1,400,000
=$427000..
Mg2+(aq) + Ca(OH)2(s) --- Mg(OH)2(s) + Ca2+(aq)the calcium and ma.pdf
Mg2+(aq) + Ca(OH)2(s) ---> Mg(OH)2(s) + Ca2+(aq)
the calcium and magnesium ions are in aqeous phase, rest are solid
Solution
Mg2+(aq) + Ca(OH)2(s) ---> Mg(OH)2(s) + Ca2+(aq)
the calcium and magnesium ions are in aqeous phase, rest are solid.
Benzoin is an organic compound consisting of an e.pdf
Benzoin, an organic compound with phenyl groups and hydroxyl and ketone functional groups, is readily oxidized by nitric acid to benzil, a diketone. The nitric acid is reduced to nitrous acid, which decomposes into oxides of nitrogen and water. Overall, the reaction converts two molecules of benzoin into two molecules of benzil, along with nitric oxide, nitrogen dioxide, and water.
import java.util.ArrayList; 2 import java.util.List; 3 impor.pdf
import java.util.ArrayList;
2
import java.util.List;
3
import java.util.regex.Matcher;
4
import java.util.regex.Pattern;
5
6
public category GenericTreeNode<T> kids = new ArrayList<GenericTreeNode<T>>();
14
}
15
16
public GenericTreeNode(T data)
20
21
public List<GenericTreeNode<T>> getChildren() come this.children;
23
}
24
25
public int getNumberOfChildren() come back getChildren().size();
27
}
28
29
public mathematician hasChildren() come back (getNumberOfChildren() > 0);
31
}
32
33
public void setChildren(List<GenericTreeNode<T>> children) kids;
35
}
36
37
public void addChild(GenericTreeNode<T> child)
40
41
public void addChildAt(int index, GenericTreeNode<T> child) throws
IndexOutOfBoundsException
44
45
public void removeChildren()
48
49
public void removeChildAt(int index) throws IndexOutOfBoundsException
52
53
public GenericTreeNode<T> getChildAt(int index) throws IndexOutOfBoundsException come
youngsters.get(index);
55
}
56
57
public T getData() come back this.data;
59
}
60
61
public void setData(T data) knowledge;
63
}
64
65
public String toString() come back getData().toString();
67
}
68
69
public mathematician equals(GenericTreeNode<T> node) come
node.getData().equals(getData());
71
}
72
73
public int hashCode() come getData().hashCode();
75
}
76
77
public String toStringVerbose()
Solution
import java.util.ArrayList;
2
import java.util.List;
3
import java.util.regex.Matcher;
4
import java.util.regex.Pattern;
5
6
public category GenericTreeNode<T> kids = new ArrayList<GenericTreeNode<T>>();
14
}
15
16
public GenericTreeNode(T data)
20
21
public List<GenericTreeNode<T>> getChildren() come this.children;
23
}
24
25
public int getNumberOfChildren() come back getChildren().size();
27
}
28
29
public mathematician hasChildren() come back (getNumberOfChildren() > 0);
31
}
32
33
public void setChildren(List<GenericTreeNode<T>> children) kids;
35
}
36
37
public void addChild(GenericTreeNode<T> child)
40
41
public void addChildAt(int index, GenericTreeNode<T> child) throws
IndexOutOfBoundsException
44
45
public void removeChildren()
48
49
public void removeChildAt(int index) throws IndexOutOfBoundsException
52
53
public GenericTreeNode<T> getChildAt(int index) throws IndexOutOfBoundsException come
youngsters.get(index);
55
}
56
57
public T getData() come back this.data;
59
}
60
61
public void setData(T data) knowledge;
63
}
64
65
public String toString() come back getData().toString();
67
}
68
69
public mathematician equals(GenericTreeNode<T> node) come
node.getData().equals(getData());
71
}
72
73
public int hashCode() come getData().hashCode();
75
}
76
77
public String toStringVerbose().
I will prefer GIT as a version control. Advantage of using GIT .pdf
I will prefer GIT as a version control.
Advantage of using GIT :
-->Git is distributed version control system. Git was initially designed and developed by Linus
Torvalds for linux kernel development in 2005.
-->Git is free software distributed under the terms of the GNU General Public License version 2.
-->In Git, every user has a complete copy of the repository locally. So making access to file
history is fast and user can access the full codebase even though disconnected from the network.
-->Every user is having full backup of the repository always.In SVN only centralized repository
has the complete history.
-->In Git except push and pull, all other operations are local. E.g. perform a diff, view file
history, commit changes, merge branches, switch branches.
-->Git’s repository and working directory sizes are extremely small when compared to SVN.
-->One place where Git is slower is in the initial clone operation. Here, Git is downloading the
entire history rather than only the latest version.
-->Unlike the other systems, Git has something called the \"staging area\" or \"index\". This is
an intermediate area where commits can be formatted and reviewed before completing the
commit.
One thing that sets Git apart from other tools is that it\'s possible to quickly stage some of
your files and commit them without committing all of the other modified files in your working
directory or having to list them on the command line during the commit.
Disadvantages of using GIT :
1. High learning curve and complex to understand.
2. Because Git does not support checking out sub-trees.
Solution
I will prefer GIT as a version control.
Advantage of using GIT :
-->Git is distributed version control system. Git was initially designed and developed by Linus
Torvalds for linux kernel development in 2005.
-->Git is free software distributed under the terms of the GNU General Public License version 2.
-->In Git, every user has a complete copy of the repository locally. So making access to file
history is fast and user can access the full codebase even though disconnected from the network.
-->Every user is having full backup of the repository always.In SVN only centralized repository
has the complete history.
-->In Git except push and pull, all other operations are local. E.g. perform a diff, view file
history, commit changes, merge branches, switch branches.
-->Git’s repository and working directory sizes are extremely small when compared to SVN.
-->One place where Git is slower is in the initial clone operation. Here, Git is downloading the
entire history rather than only the latest version.
-->Unlike the other systems, Git has something called the \"staging area\" or \"index\". This is
an intermediate area where commits can be formatted and reviewed before completing the
commit.
One thing that sets Git apart from other tools is that it\'s possible to quickly stage some of
your files and commit them without committing all of the other modified files in your workin.
I dont know what ... means so ill assume its =, if its th.pdf
I don\'t know what ... means so i\'ll assume it\'s <=, if it\'s > then use the formula P(X>a) = 1-
P(X<=a)
The CDF of an exponential distribution of parameter L is F(x) = 1-e^(-Lx) for x>=0 and 0
otherwise
The mean of an exponential distribution is 1/L
1
Solution
I don\'t know what ... means so i\'ll assume it\'s <=, if it\'s > then use the formula P(X>a) = 1-
P(X<=a)
The CDF of an exponential distribution of parameter L is F(x) = 1-e^(-Lx) for x>=0 and 0
otherwise
The mean of an exponential distribution is 1/L
1.
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Place your solid components in water (this will b.pdf
- 1. Place your solid components in water (this will be step one). The result will be that A will remain as a solid and will sink to the bottom of the solution. Pour off the water that remains containing B and C. Heat the water to evaporate it, and you will be left with a mixture of B and C in solid form. Next, place this resulting solid mixture in ethanol. Again, C will sink to the bottom, and B will remain in the liquid. Pour off the liquid, obtaining the pure solid C. Heat the ethanol containing only B, and when the liquid has evaporated you will be left with B. as a flow chart, this will be ABC - Add to water BC in water A remains solid Evaporate water, add BC to ethanol B in ethanol C remains solid Evaporate ethanol and obtain B Hope this helps! Solution Place your solid components in water (this will be step one). The result will be that A will remain as a solid and will sink to the bottom of the solution. Pour off the water that remains containing B and C. Heat the water to evaporate it, and you will be left with a mixture of B and C in solid form. Next, place this resulting solid mixture in ethanol. Again, C will sink to the bottom, and B will remain in the liquid. Pour off the liquid, obtaining the pure solid C. Heat the ethanol containing only B, and when the liquid has evaporated you will be left with B. as a flow chart, this will be ABC - Add to water BC in water A remains solid Evaporate water, add BC to ethanol B in ethanol C remains solid Evaporate ethanol and obtain B Hope this helps!