The document discusses creating an organizational hierarchy from an employee database table. It includes the following key steps: 1. Creating two alias tables - a fact table and dimension table - from the employee data. 2. Dragging the alias tables into the BMMLayer and applying an aggregation on the salary column from the fact table. 3. Generating two queries - one to create a manager-employee hierarchy table and another PL/SQL block to populate it by traversing the employee table relationships. 4. Running the queries to build the hierarchy table in the database. Upon reopening the RPD file, the new hierarchy table can be seen.

1. For sample testIhave takenHR schemaandtable is employee.
Accordingto data,I have createdtwo aliastablesforemployee. One isfactand otherone is dimension.
Drag and drop createdaliastablesintoBMMLayer and applythe aggregationon salarycolumnfrom
fact table

2. Clickon parentcolumn(Browser) andselectparentof employee

3. Clickon parentchildsettings andclickon

4. You will gettwoqueries
CREATE TABLE Manager_Emp_hir ( MEMBER_KEY NUMBER(10,0), ANCESTOR_KEYNUMBER(10,0),
DISTANCENUMBER(10,0), IS_LEAF NUMBER(10,0) )

5. declare
v_max_depthinteger;
v_stmt varchar2(32000);
i integer;
begin
selectmax(level) intov_max_depth
from EMPLOYEES
connectby priorEMPLOYEE_ID=MANAGER_ID
start withMANAGER_ID isnull;
v_stmt := 'insertintoHR.Manager_Emp_hir(MEMBER_KEY, ANCESTOR_KEY,DISTANCE,IS_LEAF)'||
chr(10)
|| 'selectEMPLOYEE_ID as member_key,null,null,0fromEMPLOYEES where MANAGER_IDisnull'||
chr(10)
|| 'unionall'|| chr(10)
|| 'select'|| chr(10)
|| ' member_key,'||chr(10)
|| ' replace(replace(ancestor_key,''p'',''|''),'''', '''') as ancestor_key,'||chr(10)
|| ' case whendepthisnull then0' ||chr(10)
|| ' else max(depth) over(partitionbymember_key) - depth+1' || chr(10)
|| ' endas distance,'||chr(10)
|| ' is_leaf'||chr(10)
|| 'from' || chr(10)
|| '(' || chr(10)
|| ' select'||chr(10)
|| ' member_key,'||chr(10)
|| ' depth,'||chr(10)

6. || ' case'|| chr(10)
|| ' whendepthisnull then'''' ||member_key'||chr(10)
|| ' wheninstr(hier_path,''|'',1, depth+ 1) = 0 thennull'|| chr(10)
|| ' else substr(hier_path,instr(hier_path,''|'',1, depth) + 1, instr(hier_path,''|'',1, depth+ 1) -
instr(hier_path,''|'', 1, depth) - 1)' || chr(10)
|| ' endancestor_key,'||chr(10)
|| ' is_leaf'||chr(10)
|| ' from' ||chr(10)
|| ' (' ||chr(10)
|| ' selectEMPLOYEE_ID as member_key,MANAGER_IDasancestor_key,
sys_connect_by_path(replace(replace(EMPLOYEE_ID,'''',''''), ''|'', ''p''), ''|'') as hier_path,'||chr(10)
|| ' case whenEMPLOYEE_ID in(selectMANAGER_IDfromEMPLOYEES ) then0 else 1 endas
IS_LEAF' || chr(10)
|| ' from EMPLOYEES ' || chr(10)
|| ' connectby priorEMPLOYEE_ID = MANAGER_ID ' || chr(10)
|| ' start withMANAGER_ID isnull'|| chr(10)
|| ' ),'|| chr(10)
|| ' (' ||chr(10)
|| ' selectnull asdepthfromdual'|| chr(10);
for i in1..v_max_depth - 1 loop
v_stmt := v_stmt || ' unionall select'|| i || ' from dual'|| chr(10);
endloop;
v_stmt := v_stmt || ' )' || chr(10)
|| ')' || chr(10)
|| 'where ancestor_keyisnotnull'||chr(10);
execute immediatev_stmt;
end;

7. /
Run these twoqueriesintodatabase.

8. Close rpdand reopenyouwill see the hierarchytableinrpdanddatabase….