N=N0e^-kt =Half-life = ( time x log 2 ) log [.pdf
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N=N0e^-kt =>Half-life = ( time x log 2 ) / log [ beginning amount / ending amount ] =>4*log2/log(100/70.8) =>2.77/0.34 =>8.14 days Solution N=N0e^-kt =>Half-life = ( time x log 2 ) / log [ beginning amount / ending amount ] =>4*log2/log(100/70.8) =>2.77/0.34 =>8.14 days.
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![N=N0e^-kt =>Half-life = ( time x log 2 ) / log [ beginning amount / ending amount
] =>4*log2/log(100/70.8) =>2.77/0.34 =>8.14 days
Solution
N=N0e^-kt =>Half-life = ( time x log 2 ) / log [ beginning amount / ending amount
] =>4*log2/log(100/70.8) =>2.77/0.34 =>8.14 days](https://image.slidesharecdn.com/nn0e-kthalf-lifetimexlog2log-230412110851-cd9ee9a9/85/N-N0e-kt-Half-life-time-x-log-2-log-pdf-1-320.jpg)
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1)Journal entries
T- Accounts
Common Stock
Common Stock dividends distributable
Paid in capital in excess of par - common stock
Retained earnings
Cash dividends 235,776 $483,144
Stockholders equity
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Total Stockholder\'s equity
$4,185,504DateDescriptionDebitCreditFeb1Dividends$192,000To Dividends payable(
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Solution
1)Journal entries
T- Accounts
Common Stock
Common Stock dividends distributable
Paid in capital in excess of par - common stock
Retained earnings
Cash dividends 235,776 $483,144
Stockholders equity
Common stock (145920 shares @11) $1,605,120
Paid in capital in excess of par- common stock 246,060
Total paid in capital $1,851,180
Add: Retained earnings 483,144
Total Stockholder\'s equity
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64,000@3)$192,000March 1Dividends payable$192,000To Cash$192,000April 1No
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earnings$371,000Retained earnings$250,880To Stock dividends$250,880Retained
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b. Pandemic H1N1 influenza strain infect: Pandemic contaminate bottom or lower respiratory
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(ii) Further, the financial accounting makes calculation of ratios easier, which can lead to a
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the case may be.
Two disadvantages thereagainst are :
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decision to be taken correctly.
(ii) In major cases of decision making, budgets are also required to be analysed. This information
is not provided for by financial accounting, but by management accounting..
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Paid in capital in excess of par - common stock
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Solution
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(ii) Further, the financial accounting makes calculation of ratios easier, which can lead to a
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the case may be.
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their joint probability is the product of the probability of the events
Solution
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the human virus was infecting pigs; it led to the emergence of the H1N1 swine strain, which later
became the swine flu.
Then the avian strain H1N1 infected humans again; this time the virus met the strain H2N2, and
then the strain H3N2 originated.
Around 1979, the avian H1N1 strain infected pigs and gave rise to Euroasiatic swine flu and
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Solution
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1918. Around 1918, the ancestral virus, of avian origin, crossed the species boundaries and
infected humans as human H1N1 in North America. The same phenomenon took place, where
the human virus was infecting pigs; it led to the emergence of the H1N1 swine strain, which later
became the swine flu.
Then the avian strain H1N1 infected humans again; this time the virus met the strain H2N2, and
then the strain H3N2 originated.
Around 1979, the avian H1N1 strain infected pigs and gave rise to Euroasiatic swine flu and
H1N1 Euroasiatic swine virus.
The 2009 outbreak is a triple reassortment process in a pig host of North American H1N1 swine
virus, the human H3N2 virus and avian H1N1 virus which generated the swine H1N2 strain.
Finally, the last step was in 2009, when the virus H1N2 co-infected a human host at the same
time as the Euroasiatic H1N1 swine strain. This led to the emergence of a new human H1N1
strain, which caused the 2009 pandemic.
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The Program to find out the middle of a given linked listclass Lin.pdf
The Program to find out the middle of a given linked list
class LinkedList
{
Node head;
class Node
{
int data;
Node next;
Node(int d)
{
data = d;
next = null;
}
}
void printMiddle()
{
Node slow_ptr = head;
Node fast_ptr = head;
if (head != null)
{
while (fast_ptr != null && fast_ptr.next != null)
{
fast_ptr = fast_ptr.next.next;
slow_ptr = slow_ptr.next;
}
System.out.println(\"The middle element is [\" +
slow_ptr.data + \"] \ \");
}
}
public void push(int new_data)
{
Node new_node = new Node(new_data);
new_node.next = head;
head = new_node;
}
public void printList()
{
Node tnode = head;
while (tnode != null)
{
System.out.print(tnode.data+\"->\");
tnode = tnode.next;
}
System.out.println(\"NULL\");
}
public static void main(String [] args)
{
LinkedList llist = new LinkedList();
for (int i=5; i>0; --i)
{
llist.push(i);
llist.printList();
llist.printMiddle();
}
}
}
Solution
The Program to find out the middle of a given linked list
class LinkedList
{
Node head;
class Node
{
int data;
Node next;
Node(int d)
{
data = d;
next = null;
}
}
void printMiddle()
{
Node slow_ptr = head;
Node fast_ptr = head;
if (head != null)
{
while (fast_ptr != null && fast_ptr.next != null)
{
fast_ptr = fast_ptr.next.next;
slow_ptr = slow_ptr.next;
}
System.out.println(\"The middle element is [\" +
slow_ptr.data + \"] \ \");
}
}
public void push(int new_data)
{
Node new_node = new Node(new_data);
new_node.next = head;
head = new_node;
}
public void printList()
{
Node tnode = head;
while (tnode != null)
{
System.out.print(tnode.data+\"->\");
tnode = tnode.next;
}
System.out.println(\"NULL\");
}
public static void main(String [] args)
{
LinkedList llist = new LinkedList();
for (int i=5; i>0; --i)
{
llist.push(i);
llist.printList();
llist.printMiddle();
}
}
}.
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Question 1:
Answer: b. The returned value, return address, parameters, and local variables
Question 2:
Answer: Pointers have to point to a certain type
Question 3:
Answer: True
Question 4:
Answer: True
Solution
Question 1:
Answer: b. The returned value, return address, parameters, and local variables
Question 2:
Answer: Pointers have to point to a certain type
Question 3:
Answer: True
Question 4:
Answer: True.
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Plasma membrane of human is made of phospholipids; these are fluids so fluidity is reflected to
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High viscosity causes to low fluidity.
Cholesterol plays an important role for the binding of phospholipids in the membrane.
Cholesterol has hydrocarbon ring. They interact with the hydrophilic head of phospholipids
through their polar hydroxyl groups. This binding helps to decrease mobility of membrane to
outside; make more rigid. When the temperature downs from 37 0C (200C) the cholesterol plays
such important role because it prevents the closeness of lipid hydrocarbon chains by binding with
them. When the temperature rises (400C) cholesterol holds some methylene group of fatty acid
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Solution
Plasma membrane of human is made of phospholipids; these are fluids so fluidity is reflected to
the viscosity of the membrane. The fluidity is reciprocal to viscosity of the lipids of membrane.
High viscosity causes to low fluidity.
Cholesterol plays an important role for the binding of phospholipids in the membrane.
Cholesterol has hydrocarbon ring. They interact with the hydrophilic head of phospholipids
through their polar hydroxyl groups. This binding helps to decrease mobility of membrane to
outside; make more rigid. When the temperature downs from 37 0C (200C) the cholesterol plays
such important role because it prevents the closeness of lipid hydrocarbon chains by binding with
them. When the temperature rises (400C) cholesterol holds some methylene group of fatty acid
chains and thus increases the melting temperature..
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P( both correct) = P( first correct)P( second correct) = 1212 = .pdf
P( both correct) = P( first correct)*P( second correct) = 1/2*1/2 = 1/4
Solution
P( both correct) = P( first correct)*P( second correct) = 1/2*1/2 = 1/4.
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One of the functions of skin is to regulate the temperature. The skin under the influence of
homeostatic control regulates the body temperature. Skin coordinates with the blood vessels
present in it to regulate the temperature. When the outside environment is hot with high
temperature, the blood vessels are dilated to initiate the heat loos. Simulatneously, the sweat
glands in skin produce sweat or prespiration along with salts. The sweat with the blow of wind
from outside cools the body immediately and allow the drop of internal temperature.
When the external environment is cold with low temperatures, blood vessels constrict and pores
and sweat glands in skin are tightened initiating shivering to retain or generate heat in the body
and to resist the cold temperatures. The heat or cold temperatures are snesed by the
thermorteceptors present in the skin and that carry the sensory information to temperature
regulation center in the brain (pituitary gland). The signals received back by the receptors
integrate the message with skin and regulates the temperature.
Solution
One of the functions of skin is to regulate the temperature. The skin under the influence of
homeostatic control regulates the body temperature. Skin coordinates with the blood vessels
present in it to regulate the temperature. When the outside environment is hot with high
temperature, the blood vessels are dilated to initiate the heat loos. Simulatneously, the sweat
glands in skin produce sweat or prespiration along with salts. The sweat with the blow of wind
from outside cools the body immediately and allow the drop of internal temperature.
When the external environment is cold with low temperatures, blood vessels constrict and pores
and sweat glands in skin are tightened initiating shivering to retain or generate heat in the body
and to resist the cold temperatures. The heat or cold temperatures are snesed by the
thermorteceptors present in the skin and that carry the sensory information to temperature
regulation center in the brain (pituitary gland). The signals received back by the receptors
integrate the message with skin and regulates the temperature..
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Main class --------------------------import java.awt.FlowLayout.pdf
Main class :-
-------------------------
import java.awt.FlowLayout;
import java.awt.Graphics;
import java.awt.GridLayout;
import java.awt.Insets;
import java.awt.event.ActionEvent;
import java.awt.event.ActionListener;
import javax.swing.JButton;
import javax.swing.JFrame;
import javax.swing.JLabel;
import javax.swing.JPanel;
import javax.swing.JTextField;
public class Main {
/**
* @param args
*/
public static void main(String[] args) {
// TODO Auto-generated method stub
final InfixExperssionEvaluator ie = new InfixExperssionEvaluator();
JFrame frame = new JFrame(\"FrameDemo\");
frame.setSize(600,200);
frame.setLayout(new FlowLayout());
JPanel main = new JPanel(new GridLayout(3, 1));
JPanel panel1 = new JPanel(new GridLayout(1, 2));
panel1.setSize(500, 250);
panel1.add(new JLabel(\"Enter Infix Expression\"));
final JTextField field1 = new JTextField();
field1.setSize(150,100);
panel1.add(field1);
main.add(panel1);
JPanel panel2 = new JPanel(new GridLayout(1, 1));
panel1.setSize(300, 150);
JButton button = new JButton();
button.setSize(200, 100);
button.setText(\"Submit\");
panel2.add(button);
main.add(panel2);
JPanel panel3 = new JPanel(new GridLayout(1, 2));
panel3.add(new JLabel(\"Value : \"));
final JLabel lbl = new JLabel();
panel3.add(lbl);
main.add(panel3);
frame.getContentPane().add(main);
frame.setVisible(true);
button.addActionListener(new ActionListener() {
@Override
public void actionPerformed(ActionEvent e) {
// TODO Auto-generated method stub
if (\"Submit\".equals(e.getActionCommand())) {
String expr = field1.getText();
lbl.setText(Double.toString(ie.infixToValue(expr)));
}
}
});
button.setActionCommand(\"Submit\");
String expr = \"((2*5)+(6/2))\";
System.out.println(\"value is ::\"+ ie.infixToValue(expr));
}
}
Class for Evaluate methods :-
-----------------------------------------
import java.util.ArrayDeque;
import java.util.HashMap;
import java.util.Map;
import java.util.Stack;
import java.util.StringTokenizer;
public class InfixExperssionEvaluator {
Stack expressionStack = new Stack();
Stack valueStack = new Stack(); //to hold only non-decimal values
public static final String OPERATORS=\"+-/*()\"; //ignore the \"(\" as an operator
//Map For Operator precedence Key(+,-,*,/) , value 0/1/2/3..
Map operator_levels = new HashMap();
public InfixExperssionEvaluator(){
operator_levels.put(\")\", 0);
operator_levels.put(\"*\", 1);
operator_levels.put(\"/\", 1);
operator_levels.put(\"+\", 2);
operator_levels.put(\"-\", 2);
operator_levels.put(\"(\", 3);
}
double infixToValue(String inputExpression) {
String eachNumber=\"\"; //to hold multiple digit values. lame idea, i know, but can\'t
think of anything else at 2 AM
int totalCharInInput = inputExpression.length();
inputExpression.replaceAll(\"\\\\s+\",\"\");
//Devide String to Tokens
StringTokenizer tokens = new StringTokenizer(inputExpression, \"{}()*/+-\", true);
//Loop through each Token
while(tokens.hasMoreTokens()){
String eachChar = tokens.nextToken();
if (isValidOperator(eachCh.
It is a test for iron(III) ion present in the solution , so it is a .pdf
It is a test for iron(III) ion present in the solution , so it is a chemical change
The chemical reaction involved in it is
Fe 3+ + SCN- -------> [Fe(NCS)(H2O)5]2+.
blood red
Solution
It is a test for iron(III) ion present in the solution , so it is a chemical change
The chemical reaction involved in it is
Fe 3+ + SCN- -------> [Fe(NCS)(H2O)5]2+.
blood red.
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I think that y=21SolutionI think that y=21.pdf
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Connects cerebral cortex to other brain regions - Projection track
Connects different parts of the same hemisphere - Association track
Conscious planning, control of voluntary movement- Frontal lobe
Control center for homeostasis and circadian rhythm- Hypothalamus
Deep gray matter involved in arousal and memory- Basal forebrain nuclei
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Somatosensory cortex, integration of sensory information - Parietal lobe
Specialized for visual processing - Occipital lobe
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Solution
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Connects cerebral cortex to other brain regions - Projection track
Connects different parts of the same hemisphere - Association track
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Control center for homeostasis and circadian rhythm- Hypothalamus
Deep gray matter involved in arousal and memory- Basal forebrain nuclei
Process sensory information and relay it to cerebral cortex - Thalamus
Secretes melatonin to coordinate circadian functions - Epithalamus
Senses of smell and hearing - Temporal lobe
Somatosensory cortex, integration of sensory information - Parietal lobe
Specialized for visual processing - Occipital lobe
Unconscious control of repetitive movements- basal ganglia
Visceral senses, taste, integration of sensory information - Insula.
Comments added... method to check divisble by particular number..pdf
Comments added...
// method to check divisble by particular number....
public boolean isDivisibleBy(Node firstNode, int divisor){
// current node and previous node declaring for iterating purpose
Node curr = firstNode;
Node prev = null;
// boolean value holds divisble or not
boolean isDivible = true;
while(curr != null) // iterating until list ends reach
{
if(curr.data % divisor != 0){ // if not divisble then exit and change flag to false
isDivible = false;
break;
}
// iterate to next node
prev = curr;
curr = curr.next;
}
// return result
return isDivible;
}
Solution
Comments added...
// method to check divisble by particular number....
public boolean isDivisibleBy(Node firstNode, int divisor){
// current node and previous node declaring for iterating purpose
Node curr = firstNode;
Node prev = null;
// boolean value holds divisble or not
boolean isDivible = true;
while(curr != null) // iterating until list ends reach
{
if(curr.data % divisor != 0){ // if not divisble then exit and change flag to false
isDivible = false;
break;
}
// iterate to next node
prev = curr;
curr = curr.next;
}
// return result
return isDivible;
}.
c) Li is oxidized F is reduced as li goes to +1 oxidation state an.pdf
c) Li is oxidized F is reduced
as li goes to +1 oxidation state and f is in -1 state
Solution
c) Li is oxidized F is reduced
as li goes to +1 oxidation state and f is in -1 state.
Balance sheet of Doctors PartnershipNotesPartners capital con.pdf
Balance sheet of Doctor\'s Partnership
Notes:
Partners capital contribution is computed as follows:Current assetsAmountCash
(A)$37,737.00Supplies (B)$2,513.00Accounts receivable (C
)$35,661.00$4,227.00$31,434.00Total Current assets D= A+B+C$71,684.00Fixed assets (E
)Land (F)$17,589.00Buildings (G)$75,344.00Equipment (H)$47,114.00Total Fixed Assets I
=F+G+H$140,047.00Total Assets J =D+ I$211,731.00Liabilities and Owner\'s EquityCurrent
LiabilitiesMortagage loan (K)$20,134.00Partners equity:Terry (L)$55,070.00Nick
(M)$72,799.00Frank (N)$63,728.00Total Partner\'s equity O=L+M+N$191,597.00Total
Liabilities and Owner\'s Equity P=K+O$211,731.00
Solution
Balance sheet of Doctor\'s Partnership
Notes:
Partners capital contribution is computed as follows:Current assetsAmountCash
(A)$37,737.00Supplies (B)$2,513.00Accounts receivable (C
)$35,661.00$4,227.00$31,434.00Total Current assets D= A+B+C$71,684.00Fixed assets (E
)Land (F)$17,589.00Buildings (G)$75,344.00Equipment (H)$47,114.00Total Fixed Assets I
=F+G+H$140,047.00Total Assets J =D+ I$211,731.00Liabilities and Owner\'s EquityCurrent
LiabilitiesMortagage loan (K)$20,134.00Partners equity:Terry (L)$55,070.00Nick
(M)$72,799.00Frank (N)$63,728.00Total Partner\'s equity O=L+M+N$191,597.00Total
Liabilities and Owner\'s Equity P=K+O$211,731.00.
As per the above scenario, please find the short report below.The .pdf
As per the above scenario, please find the short report below.
The art of sending the message that is hidden in the grapical images is mainly called as
\"STEGANOGRAPHY\".
It is mainly followed , to protect the message from the unknown source. were other they cannot
see the message that is hidded. Only the reciever and sender alone the way to encrypt or decrypt
the hidden message from the images that are sent.
1) To make the message hidden in the image, first choose the message. There are so many
softwares that are available, were the images if that are stored in the local drive, they can
choosen.
2) Then type the information that you like to transfer , in terms of message. It may ask you for
the password. Then you can create the password and enter it. Its mainly for the purporse of
security.
3) After that if you , click hide message button in the available software, the message will be
hidden. It will take few minutes to create the image with message. ONce it is created we will not
able to crop the image of resize the image.
Once the encryption is done, sender will send the message to intended reciepent.
After recieving the message, the reciever need to decrypt the message.
Following steps need to be followed to see the hidden messages.
1) Select the image needed for the decryption.
2) Enter the password that was sent by the sender, once the password is entered the password
check will be done and reveal your message option need to be clicked.
3) Atlast the hidden message will be shown. It can be stored in the local drive and used.
Solution
As per the above scenario, please find the short report below.
The art of sending the message that is hidden in the grapical images is mainly called as
\"STEGANOGRAPHY\".
It is mainly followed , to protect the message from the unknown source. were other they cannot
see the message that is hidded. Only the reciever and sender alone the way to encrypt or decrypt
the hidden message from the images that are sent.
1) To make the message hidden in the image, first choose the message. There are so many
softwares that are available, were the images if that are stored in the local drive, they can
choosen.
2) Then type the information that you like to transfer , in terms of message. It may ask you for
the password. Then you can create the password and enter it. Its mainly for the purporse of
security.
3) After that if you , click hide message button in the available software, the message will be
hidden. It will take few minutes to create the image with message. ONce it is created we will not
able to crop the image of resize the image.
Once the encryption is done, sender will send the message to intended reciepent.
After recieving the message, the reciever need to decrypt the message.
Following steps need to be followed to see the hidden messages.
1) Select the image needed for the decryption.
2) Enter the password that was sent by the sender, once the password is entered the password
check will be done and reveal you.
Answer B.nitrile hydrolysis reactionNitrilase which catalyzes the.pdf
Answer: B.nitrile hydrolysis reaction
Nitrilase which catalyzes the hydrolytic cleavage of the C-N triple bond in nitrile to form acid
and ammonium.
Solution
Answer: B.nitrile hydrolysis reaction
Nitrilase which catalyzes the hydrolytic cleavage of the C-N triple bond in nitrile to form acid
and ammonium..
AnswerQuestion no 37 and 38 are not clear. 37) what molecules abs.pdf
Answer:
Question no 37 and 38 are not clear. 37) what molecules absorbed? 38) which enter the
bloodstream or lymphatic system?
39) Large intestine is also called as colon and it is last part of gastrointestinal tract (of the
digestive system of vertebrates) where the final stages of digestion occur. The major function of
the large intestine is to absorb water from the remaining indigestible food matter and remaining
waste material is stored as feces before elimination from the body.
40) Rectum is a component of the lower gastrointestinal tract. It is a straight portion which is
continuation of the sigmoid colon, and connects to the anus. The function of rectum is the
temporary storage of feces. When the rectum becomes full, the increase in intrarectal pressure
forces the walls of the anal canal apart, allowing the fecal matter to enter the canal. The rectum
shortens as material is forced into the anal canal.
41) Orifice is the external opening of the rectum, controls the expulsion of feces. Its function is
to push the feces out of the anal canal by the help of internal and external anal sphincters (two
muscular rings which control defeaecation).
42) Pancreas is an endocrine gland and a digestive organ as well, which secrete:
Solution
Answer:
Question no 37 and 38 are not clear. 37) what molecules absorbed? 38) which enter the
bloodstream or lymphatic system?
39) Large intestine is also called as colon and it is last part of gastrointestinal tract (of the
digestive system of vertebrates) where the final stages of digestion occur. The major function of
the large intestine is to absorb water from the remaining indigestible food matter and remaining
waste material is stored as feces before elimination from the body.
40) Rectum is a component of the lower gastrointestinal tract. It is a straight portion which is
continuation of the sigmoid colon, and connects to the anus. The function of rectum is the
temporary storage of feces. When the rectum becomes full, the increase in intrarectal pressure
forces the walls of the anal canal apart, allowing the fecal matter to enter the canal. The rectum
shortens as material is forced into the anal canal.
41) Orifice is the external opening of the rectum, controls the expulsion of feces. Its function is
to push the feces out of the anal canal by the help of internal and external anal sphincters (two
muscular rings which control defeaecation).
42) Pancreas is an endocrine gland and a digestive organ as well, which secrete:.
Allopatric speciation occurs due to change of environment, like jump.pdf
Allopatric speciation occurs due to change of environment, like jumping of gorilla louse to
hominins and adapted to develop into hominin pubic louse.
A sympatric speciation occurs in the same environment often due to polyploidy.ie., the fusion of
2 different species to form a new species. Louse speciation is not a sympatric speciation.
Solution
Allopatric speciation occurs due to change of environment, like jumping of gorilla louse to
hominins and adapted to develop into hominin pubic louse.
A sympatric speciation occurs in the same environment often due to polyploidy.ie., the fusion of
2 different species to form a new species. Louse speciation is not a sympatric speciation..
Walmart Business+ and Spark Good for Nonprofits.pdf
"Learn about all the ways Walmart supports nonprofit organizations.
You will hear from Liz Willett, the Head of Nonprofits, and hear about what Walmart is doing to help nonprofits, including Walmart Business and Spark Good. Walmart Business+ is a new offer for nonprofits that offers discounts and also streamlines nonprofits order and expense tracking, saving time and money.
The webinar may also give some examples on how nonprofits can best leverage Walmart Business+.
The event will cover the following::
Walmart Business + (https://business.walmart.com/plus) is a new shopping experience for nonprofits, schools, and local business customers that connects an exclusive online shopping experience to stores. Benefits include free delivery and shipping, a 'Spend Analytics” feature, special discounts, deals and tax-exempt shopping.
Special TechSoup offer for a free 180 days membership, and up to $150 in discounts on eligible orders.
Spark Good (walmart.com/sparkgood) is a charitable platform that enables nonprofits to receive donations directly from customers and associates.
Answers about how you can do more with Walmart!"
Gender and Mental Health - Counselling and Family Therapy Applications and In...
A proprietary approach developed by bringing together the best of learning theories from Psychology, design principles from the world of visualization, and pedagogical methods from over a decade of training experience, that enables you to: Learn better, faster!
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The phylogenetic origin of the flu virus that caused the 2009 pandem.pdf
The phylogenetic origin of the flu virus that caused the 2009 pandemics can be traced before
1918. Around 1918, the ancestral virus, of avian origin, crossed the species boundaries and
infected humans as human H1N1 in North America. The same phenomenon took place, where
the human virus was infecting pigs; it led to the emergence of the H1N1 swine strain, which later
became the swine flu.
Then the avian strain H1N1 infected humans again; this time the virus met the strain H2N2, and
then the strain H3N2 originated.
Around 1979, the avian H1N1 strain infected pigs and gave rise to Euroasiatic swine flu and
H1N1 Euroasiatic swine virus.
The 2009 outbreak is a triple reassortment process in a pig host of North American H1N1 swine
virus, the human H3N2 virus and avian H1N1 virus which generated the swine H1N2 strain.
Finally, the last step was in 2009, when the virus H1N2 co-infected a human host at the same
time as the Euroasiatic H1N1 swine strain. This led to the emergence of a new human H1N1
strain, which caused the 2009 pandemic.
In 2009, the World Health Organization raised the worldwide pandemic alert level to Phase 6 for
swine flu, which is the highest alert level. This alert level means that the swine flu had spread
worldwide and there were cases of people with the virus in most countries.
Swine flu spread very rapidly worldwide due to its high human-to-human transmission rate and
due to the frequency of air travel.
This difference in the rate of spread is mainly due to the increased volume and speed of global
transportation and to a minimal extent the increased virulance of the pathogen.
Solution
The phylogenetic origin of the flu virus that caused the 2009 pandemics can be traced before
1918. Around 1918, the ancestral virus, of avian origin, crossed the species boundaries and
infected humans as human H1N1 in North America. The same phenomenon took place, where
the human virus was infecting pigs; it led to the emergence of the H1N1 swine strain, which later
became the swine flu.
Then the avian strain H1N1 infected humans again; this time the virus met the strain H2N2, and
then the strain H3N2 originated.
Around 1979, the avian H1N1 strain infected pigs and gave rise to Euroasiatic swine flu and
H1N1 Euroasiatic swine virus.
The 2009 outbreak is a triple reassortment process in a pig host of North American H1N1 swine
virus, the human H3N2 virus and avian H1N1 virus which generated the swine H1N2 strain.
Finally, the last step was in 2009, when the virus H1N2 co-infected a human host at the same
time as the Euroasiatic H1N1 swine strain. This led to the emergence of a new human H1N1
strain, which caused the 2009 pandemic.
In 2009, the World Health Organization raised the worldwide pandemic alert level to Phase 6 for
swine flu, which is the highest alert level. This alert level means that the swine flu had spread
worldwide and there were cases of people with the virus in most countries.
Swine flu spread very rapidly worldwide due to its hig.
The Program to find out the middle of a given linked listclass Lin.pdf
The Program to find out the middle of a given linked list
class LinkedList
{
Node head;
class Node
{
int data;
Node next;
Node(int d)
{
data = d;
next = null;
}
}
void printMiddle()
{
Node slow_ptr = head;
Node fast_ptr = head;
if (head != null)
{
while (fast_ptr != null && fast_ptr.next != null)
{
fast_ptr = fast_ptr.next.next;
slow_ptr = slow_ptr.next;
}
System.out.println(\"The middle element is [\" +
slow_ptr.data + \"] \ \");
}
}
public void push(int new_data)
{
Node new_node = new Node(new_data);
new_node.next = head;
head = new_node;
}
public void printList()
{
Node tnode = head;
while (tnode != null)
{
System.out.print(tnode.data+\"->\");
tnode = tnode.next;
}
System.out.println(\"NULL\");
}
public static void main(String [] args)
{
LinkedList llist = new LinkedList();
for (int i=5; i>0; --i)
{
llist.push(i);
llist.printList();
llist.printMiddle();
}
}
}
Solution
The Program to find out the middle of a given linked list
class LinkedList
{
Node head;
class Node
{
int data;
Node next;
Node(int d)
{
data = d;
next = null;
}
}
void printMiddle()
{
Node slow_ptr = head;
Node fast_ptr = head;
if (head != null)
{
while (fast_ptr != null && fast_ptr.next != null)
{
fast_ptr = fast_ptr.next.next;
slow_ptr = slow_ptr.next;
}
System.out.println(\"The middle element is [\" +
slow_ptr.data + \"] \ \");
}
}
public void push(int new_data)
{
Node new_node = new Node(new_data);
new_node.next = head;
head = new_node;
}
public void printList()
{
Node tnode = head;
while (tnode != null)
{
System.out.print(tnode.data+\"->\");
tnode = tnode.next;
}
System.out.println(\"NULL\");
}
public static void main(String [] args)
{
LinkedList llist = new LinkedList();
for (int i=5; i>0; --i)
{
llist.push(i);
llist.printList();
llist.printMiddle();
}
}
}.
Question 1Answer b. The returned value, return address, paramete.pdf
Question 1:
Answer: b. The returned value, return address, parameters, and local variables
Question 2:
Answer: Pointers have to point to a certain type
Question 3:
Answer: True
Question 4:
Answer: True
Solution
Question 1:
Answer: b. The returned value, return address, parameters, and local variables
Question 2:
Answer: Pointers have to point to a certain type
Question 3:
Answer: True
Question 4:
Answer: True.
Plasma membrane of human is made of phospholipids; these are fluids .pdf
Plasma membrane of human is made of phospholipids; these are fluids so fluidity is reflected to
the viscosity of the membrane. The fluidity is reciprocal to viscosity of the lipids of membrane.
High viscosity causes to low fluidity.
Cholesterol plays an important role for the binding of phospholipids in the membrane.
Cholesterol has hydrocarbon ring. They interact with the hydrophilic head of phospholipids
through their polar hydroxyl groups. This binding helps to decrease mobility of membrane to
outside; make more rigid. When the temperature downs from 37 0C (200C) the cholesterol plays
such important role because it prevents the closeness of lipid hydrocarbon chains by binding with
them. When the temperature rises (400C) cholesterol holds some methylene group of fatty acid
chains and thus increases the melting temperature.
Solution
Plasma membrane of human is made of phospholipids; these are fluids so fluidity is reflected to
the viscosity of the membrane. The fluidity is reciprocal to viscosity of the lipids of membrane.
High viscosity causes to low fluidity.
Cholesterol plays an important role for the binding of phospholipids in the membrane.
Cholesterol has hydrocarbon ring. They interact with the hydrophilic head of phospholipids
through their polar hydroxyl groups. This binding helps to decrease mobility of membrane to
outside; make more rigid. When the temperature downs from 37 0C (200C) the cholesterol plays
such important role because it prevents the closeness of lipid hydrocarbon chains by binding with
them. When the temperature rises (400C) cholesterol holds some methylene group of fatty acid
chains and thus increases the melting temperature..
Please post the exact proplem in comments.SolutionPlease post .pdf
This document does not provide enough information to summarize. It only states to post the exact problem in comments but does not provide any other context or details about an issue being discussed.
P( both correct) = P( first correct)P( second correct) = 1212 = .pdf
P( both correct) = P( first correct)*P( second correct) = 1/2*1/2 = 1/4
Solution
P( both correct) = P( first correct)*P( second correct) = 1/2*1/2 = 1/4.
One of the functions of skin is to regulate the temperature. The ski.pdf
One of the functions of skin is to regulate the temperature. The skin under the influence of
homeostatic control regulates the body temperature. Skin coordinates with the blood vessels
present in it to regulate the temperature. When the outside environment is hot with high
temperature, the blood vessels are dilated to initiate the heat loos. Simulatneously, the sweat
glands in skin produce sweat or prespiration along with salts. The sweat with the blow of wind
from outside cools the body immediately and allow the drop of internal temperature.
When the external environment is cold with low temperatures, blood vessels constrict and pores
and sweat glands in skin are tightened initiating shivering to retain or generate heat in the body
and to resist the cold temperatures. The heat or cold temperatures are snesed by the
thermorteceptors present in the skin and that carry the sensory information to temperature
regulation center in the brain (pituitary gland). The signals received back by the receptors
integrate the message with skin and regulates the temperature.
Solution
One of the functions of skin is to regulate the temperature. The skin under the influence of
homeostatic control regulates the body temperature. Skin coordinates with the blood vessels
present in it to regulate the temperature. When the outside environment is hot with high
temperature, the blood vessels are dilated to initiate the heat loos. Simulatneously, the sweat
glands in skin produce sweat or prespiration along with salts. The sweat with the blow of wind
from outside cools the body immediately and allow the drop of internal temperature.
When the external environment is cold with low temperatures, blood vessels constrict and pores
and sweat glands in skin are tightened initiating shivering to retain or generate heat in the body
and to resist the cold temperatures. The heat or cold temperatures are snesed by the
thermorteceptors present in the skin and that carry the sensory information to temperature
regulation center in the brain (pituitary gland). The signals received back by the receptors
integrate the message with skin and regulates the temperature..
None of the options.SolutionNone of the options..pdf
This 1 sentence document does not provide any options to choose from. It simply states "None of the options" and provides no other context or information.
Main class --------------------------import java.awt.FlowLayout.pdf
Main class :-
-------------------------
import java.awt.FlowLayout;
import java.awt.Graphics;
import java.awt.GridLayout;
import java.awt.Insets;
import java.awt.event.ActionEvent;
import java.awt.event.ActionListener;
import javax.swing.JButton;
import javax.swing.JFrame;
import javax.swing.JLabel;
import javax.swing.JPanel;
import javax.swing.JTextField;
public class Main {
/**
* @param args
*/
public static void main(String[] args) {
// TODO Auto-generated method stub
final InfixExperssionEvaluator ie = new InfixExperssionEvaluator();
JFrame frame = new JFrame(\"FrameDemo\");
frame.setSize(600,200);
frame.setLayout(new FlowLayout());
JPanel main = new JPanel(new GridLayout(3, 1));
JPanel panel1 = new JPanel(new GridLayout(1, 2));
panel1.setSize(500, 250);
panel1.add(new JLabel(\"Enter Infix Expression\"));
final JTextField field1 = new JTextField();
field1.setSize(150,100);
panel1.add(field1);
main.add(panel1);
JPanel panel2 = new JPanel(new GridLayout(1, 1));
panel1.setSize(300, 150);
JButton button = new JButton();
button.setSize(200, 100);
button.setText(\"Submit\");
panel2.add(button);
main.add(panel2);
JPanel panel3 = new JPanel(new GridLayout(1, 2));
panel3.add(new JLabel(\"Value : \"));
final JLabel lbl = new JLabel();
panel3.add(lbl);
main.add(panel3);
frame.getContentPane().add(main);
frame.setVisible(true);
button.addActionListener(new ActionListener() {
@Override
public void actionPerformed(ActionEvent e) {
// TODO Auto-generated method stub
if (\"Submit\".equals(e.getActionCommand())) {
String expr = field1.getText();
lbl.setText(Double.toString(ie.infixToValue(expr)));
}
}
});
button.setActionCommand(\"Submit\");
String expr = \"((2*5)+(6/2))\";
System.out.println(\"value is ::\"+ ie.infixToValue(expr));
}
}
Class for Evaluate methods :-
-----------------------------------------
import java.util.ArrayDeque;
import java.util.HashMap;
import java.util.Map;
import java.util.Stack;
import java.util.StringTokenizer;
public class InfixExperssionEvaluator {
Stack expressionStack = new Stack();
Stack valueStack = new Stack(); //to hold only non-decimal values
public static final String OPERATORS=\"+-/*()\"; //ignore the \"(\" as an operator
//Map For Operator precedence Key(+,-,*,/) , value 0/1/2/3..
Map operator_levels = new HashMap();
public InfixExperssionEvaluator(){
operator_levels.put(\")\", 0);
operator_levels.put(\"*\", 1);
operator_levels.put(\"/\", 1);
operator_levels.put(\"+\", 2);
operator_levels.put(\"-\", 2);
operator_levels.put(\"(\", 3);
}
double infixToValue(String inputExpression) {
String eachNumber=\"\"; //to hold multiple digit values. lame idea, i know, but can\'t
think of anything else at 2 AM
int totalCharInInput = inputExpression.length();
inputExpression.replaceAll(\"\\\\s+\",\"\");
//Devide String to Tokens
StringTokenizer tokens = new StringTokenizer(inputExpression, \"{}()*/+-\", true);
//Loop through each Token
while(tokens.hasMoreTokens()){
String eachChar = tokens.nextToken();
if (isValidOperator(eachCh.
It is a test for iron(III) ion present in the solution , so it is a .pdf
It is a test for iron(III) ion present in the solution , so it is a chemical change
The chemical reaction involved in it is
Fe 3+ + SCN- -------> [Fe(NCS)(H2O)5]2+.
blood red
Solution
It is a test for iron(III) ion present in the solution , so it is a chemical change
The chemical reaction involved in it is
Fe 3+ + SCN- -------> [Fe(NCS)(H2O)5]2+.
blood red.
C. 12Solution C. 12.pdf
This document appears to contain only technical codes or shorthand without context. It provides the letters "C.", the number "12%", and the word "Solution" but no other details. Therefore, a meaningful summary cannot be generated from the limited information given.
I think that y=21SolutionI think that y=21.pdf
This very short document states that the author thinks the value of y equals 21, but provides no working or explanation for how this solution was reached. The document simply repeats the statement that y=21 without showing any steps taken to arrive at this conclusion.
Connects corresponding regions of left and right cerebral hemisphere.pdf
Connects corresponding regions of left and right cerebral hemispheres - Corpus callosum
Connects cerebral cortex to other brain regions - Projection track
Connects different parts of the same hemisphere - Association track
Conscious planning, control of voluntary movement- Frontal lobe
Control center for homeostasis and circadian rhythm- Hypothalamus
Deep gray matter involved in arousal and memory- Basal forebrain nuclei
Process sensory information and relay it to cerebral cortex - Thalamus
Secretes melatonin to coordinate circadian functions - Epithalamus
Senses of smell and hearing - Temporal lobe
Somatosensory cortex, integration of sensory information - Parietal lobe
Specialized for visual processing - Occipital lobe
Unconscious control of repetitive movements- basal ganglia
Visceral senses, taste, integration of sensory information - Insula
Solution
Connects corresponding regions of left and right cerebral hemispheres - Corpus callosum
Connects cerebral cortex to other brain regions - Projection track
Connects different parts of the same hemisphere - Association track
Conscious planning, control of voluntary movement- Frontal lobe
Control center for homeostasis and circadian rhythm- Hypothalamus
Deep gray matter involved in arousal and memory- Basal forebrain nuclei
Process sensory information and relay it to cerebral cortex - Thalamus
Secretes melatonin to coordinate circadian functions - Epithalamus
Senses of smell and hearing - Temporal lobe
Somatosensory cortex, integration of sensory information - Parietal lobe
Specialized for visual processing - Occipital lobe
Unconscious control of repetitive movements- basal ganglia
Visceral senses, taste, integration of sensory information - Insula.
Comments added... method to check divisble by particular number..pdf
Comments added...
// method to check divisble by particular number....
public boolean isDivisibleBy(Node firstNode, int divisor){
// current node and previous node declaring for iterating purpose
Node curr = firstNode;
Node prev = null;
// boolean value holds divisble or not
boolean isDivible = true;
while(curr != null) // iterating until list ends reach
{
if(curr.data % divisor != 0){ // if not divisble then exit and change flag to false
isDivible = false;
break;
}
// iterate to next node
prev = curr;
curr = curr.next;
}
// return result
return isDivible;
}
Solution
Comments added...
// method to check divisble by particular number....
public boolean isDivisibleBy(Node firstNode, int divisor){
// current node and previous node declaring for iterating purpose
Node curr = firstNode;
Node prev = null;
// boolean value holds divisble or not
boolean isDivible = true;
while(curr != null) // iterating until list ends reach
{
if(curr.data % divisor != 0){ // if not divisble then exit and change flag to false
isDivible = false;
break;
}
// iterate to next node
prev = curr;
curr = curr.next;
}
// return result
return isDivible;
}.
c) Li is oxidized F is reduced as li goes to +1 oxidation state an.pdf
c) Li is oxidized F is reduced
as li goes to +1 oxidation state and f is in -1 state
Solution
c) Li is oxidized F is reduced
as li goes to +1 oxidation state and f is in -1 state.
Balance sheet of Doctors PartnershipNotesPartners capital con.pdf
Balance sheet of Doctor\'s Partnership
Notes:
Partners capital contribution is computed as follows:Current assetsAmountCash
(A)$37,737.00Supplies (B)$2,513.00Accounts receivable (C
)$35,661.00$4,227.00$31,434.00Total Current assets D= A+B+C$71,684.00Fixed assets (E
)Land (F)$17,589.00Buildings (G)$75,344.00Equipment (H)$47,114.00Total Fixed Assets I
=F+G+H$140,047.00Total Assets J =D+ I$211,731.00Liabilities and Owner\'s EquityCurrent
LiabilitiesMortagage loan (K)$20,134.00Partners equity:Terry (L)$55,070.00Nick
(M)$72,799.00Frank (N)$63,728.00Total Partner\'s equity O=L+M+N$191,597.00Total
Liabilities and Owner\'s Equity P=K+O$211,731.00
Solution
Balance sheet of Doctor\'s Partnership
Notes:
Partners capital contribution is computed as follows:Current assetsAmountCash
(A)$37,737.00Supplies (B)$2,513.00Accounts receivable (C
)$35,661.00$4,227.00$31,434.00Total Current assets D= A+B+C$71,684.00Fixed assets (E
)Land (F)$17,589.00Buildings (G)$75,344.00Equipment (H)$47,114.00Total Fixed Assets I
=F+G+H$140,047.00Total Assets J =D+ I$211,731.00Liabilities and Owner\'s EquityCurrent
LiabilitiesMortagage loan (K)$20,134.00Partners equity:Terry (L)$55,070.00Nick
(M)$72,799.00Frank (N)$63,728.00Total Partner\'s equity O=L+M+N$191,597.00Total
Liabilities and Owner\'s Equity P=K+O$211,731.00.
As per the above scenario, please find the short report below.The .pdf
As per the above scenario, please find the short report below.
The art of sending the message that is hidden in the grapical images is mainly called as
\"STEGANOGRAPHY\".
It is mainly followed , to protect the message from the unknown source. were other they cannot
see the message that is hidded. Only the reciever and sender alone the way to encrypt or decrypt
the hidden message from the images that are sent.
1) To make the message hidden in the image, first choose the message. There are so many
softwares that are available, were the images if that are stored in the local drive, they can
choosen.
2) Then type the information that you like to transfer , in terms of message. It may ask you for
the password. Then you can create the password and enter it. Its mainly for the purporse of
security.
3) After that if you , click hide message button in the available software, the message will be
hidden. It will take few minutes to create the image with message. ONce it is created we will not
able to crop the image of resize the image.
Once the encryption is done, sender will send the message to intended reciepent.
After recieving the message, the reciever need to decrypt the message.
Following steps need to be followed to see the hidden messages.
1) Select the image needed for the decryption.
2) Enter the password that was sent by the sender, once the password is entered the password
check will be done and reveal your message option need to be clicked.
3) Atlast the hidden message will be shown. It can be stored in the local drive and used.
Solution
As per the above scenario, please find the short report below.
The art of sending the message that is hidden in the grapical images is mainly called as
\"STEGANOGRAPHY\".
It is mainly followed , to protect the message from the unknown source. were other they cannot
see the message that is hidded. Only the reciever and sender alone the way to encrypt or decrypt
the hidden message from the images that are sent.
1) To make the message hidden in the image, first choose the message. There are so many
softwares that are available, were the images if that are stored in the local drive, they can
choosen.
2) Then type the information that you like to transfer , in terms of message. It may ask you for
the password. Then you can create the password and enter it. Its mainly for the purporse of
security.
3) After that if you , click hide message button in the available software, the message will be
hidden. It will take few minutes to create the image with message. ONce it is created we will not
able to crop the image of resize the image.
Once the encryption is done, sender will send the message to intended reciepent.
After recieving the message, the reciever need to decrypt the message.
Following steps need to be followed to see the hidden messages.
1) Select the image needed for the decryption.
2) Enter the password that was sent by the sender, once the password is entered the password
check will be done and reveal you.
Answer B.nitrile hydrolysis reactionNitrilase which catalyzes the.pdf
Answer: B.nitrile hydrolysis reaction
Nitrilase which catalyzes the hydrolytic cleavage of the C-N triple bond in nitrile to form acid
and ammonium.
Solution
Answer: B.nitrile hydrolysis reaction
Nitrilase which catalyzes the hydrolytic cleavage of the C-N triple bond in nitrile to form acid
and ammonium..
AnswerQuestion no 37 and 38 are not clear. 37) what molecules abs.pdf
Answer:
Question no 37 and 38 are not clear. 37) what molecules absorbed? 38) which enter the
bloodstream or lymphatic system?
39) Large intestine is also called as colon and it is last part of gastrointestinal tract (of the
digestive system of vertebrates) where the final stages of digestion occur. The major function of
the large intestine is to absorb water from the remaining indigestible food matter and remaining
waste material is stored as feces before elimination from the body.
40) Rectum is a component of the lower gastrointestinal tract. It is a straight portion which is
continuation of the sigmoid colon, and connects to the anus. The function of rectum is the
temporary storage of feces. When the rectum becomes full, the increase in intrarectal pressure
forces the walls of the anal canal apart, allowing the fecal matter to enter the canal. The rectum
shortens as material is forced into the anal canal.
41) Orifice is the external opening of the rectum, controls the expulsion of feces. Its function is
to push the feces out of the anal canal by the help of internal and external anal sphincters (two
muscular rings which control defeaecation).
42) Pancreas is an endocrine gland and a digestive organ as well, which secrete:
Solution
Answer:
Question no 37 and 38 are not clear. 37) what molecules absorbed? 38) which enter the
bloodstream or lymphatic system?
39) Large intestine is also called as colon and it is last part of gastrointestinal tract (of the
digestive system of vertebrates) where the final stages of digestion occur. The major function of
the large intestine is to absorb water from the remaining indigestible food matter and remaining
waste material is stored as feces before elimination from the body.
40) Rectum is a component of the lower gastrointestinal tract. It is a straight portion which is
continuation of the sigmoid colon, and connects to the anus. The function of rectum is the
temporary storage of feces. When the rectum becomes full, the increase in intrarectal pressure
forces the walls of the anal canal apart, allowing the fecal matter to enter the canal. The rectum
shortens as material is forced into the anal canal.
41) Orifice is the external opening of the rectum, controls the expulsion of feces. Its function is
to push the feces out of the anal canal by the help of internal and external anal sphincters (two
muscular rings which control defeaecation).
42) Pancreas is an endocrine gland and a digestive organ as well, which secrete:.
Allopatric speciation occurs due to change of environment, like jump.pdf
Allopatric speciation occurs due to change of environment, like jumping of gorilla louse to
hominins and adapted to develop into hominin pubic louse.
A sympatric speciation occurs in the same environment often due to polyploidy.ie., the fusion of
2 different species to form a new species. Louse speciation is not a sympatric speciation.
Solution
Allopatric speciation occurs due to change of environment, like jumping of gorilla louse to
hominins and adapted to develop into hominin pubic louse.
A sympatric speciation occurs in the same environment often due to polyploidy.ie., the fusion of
2 different species to form a new species. Louse speciation is not a sympatric speciation..
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