NÚMEROS ENTEROS-REPASO Y REFUERZO 
1 Resuelve operando paso a paso. 
a) 6 –15 +13 –21 –9 = 
b) 7 +12 –19 –6 +11 –9 = 
c) (–5) –(+13) +(–16) –(–8) +(+7) = 
d) (+14) +(–21) –(–18) –(+27) –(–11) = 
e) (6 –9 +7 –11) –(8 –10 +13 –16) = 
f) 4 · 8 –5 · 3 +6 · 4 –7 · 6 –3 · 6 = 
g) 6 · (–4) –2 · (–8) +5 · 3 –9· (–2) = 
2 Resuelve operando paso a paso 
a) 3 · (2 –7) –5 · (3 –6) +2 · (8 –15) +4 · (11 –9) = 
b) (4 –6) · (8 –3) –(5 –9) · (1 –7) +18 = 
c) 3 · (5 –9 +2) –8 · (3 –6 –2) +4 · (5 –12) = 
d) 20 –2 · [10 –3 · (6 –9)] = 
e) 18 +3· (8 –12) –4 · [5 –3 · (6 +3 –5 · 2)] = 
f) 21 –8 · (10 –4) +(8 –11) · [5 +(3 –6) · (8 –2)] = 
g) 6 · [5 –2 · (8 –13)] –5 · [9 –3 · (6 –10)] = 
h) (2 –5) · [4 –3 · (4 –9)] –(2 –7) · [15 –2 · (9 –4)] =

Números enteros

  • 1.
    NÚMEROS ENTEROS-REPASO YREFUERZO 1 Resuelve operando paso a paso. a) 6 –15 +13 –21 –9 = b) 7 +12 –19 –6 +11 –9 = c) (–5) –(+13) +(–16) –(–8) +(+7) = d) (+14) +(–21) –(–18) –(+27) –(–11) = e) (6 –9 +7 –11) –(8 –10 +13 –16) = f) 4 · 8 –5 · 3 +6 · 4 –7 · 6 –3 · 6 = g) 6 · (–4) –2 · (–8) +5 · 3 –9· (–2) = 2 Resuelve operando paso a paso a) 3 · (2 –7) –5 · (3 –6) +2 · (8 –15) +4 · (11 –9) = b) (4 –6) · (8 –3) –(5 –9) · (1 –7) +18 = c) 3 · (5 –9 +2) –8 · (3 –6 –2) +4 · (5 –12) = d) 20 –2 · [10 –3 · (6 –9)] = e) 18 +3· (8 –12) –4 · [5 –3 · (6 +3 –5 · 2)] = f) 21 –8 · (10 –4) +(8 –11) · [5 +(3 –6) · (8 –2)] = g) 6 · [5 –2 · (8 –13)] –5 · [9 –3 · (6 –10)] = h) (2 –5) · [4 –3 · (4 –9)] –(2 –7) · [15 –2 · (9 –4)] =