Mitochondria and chloroplasts have small genomes becauseQuestion .pdf
•
0 likes•2 views
Mitochondria and chloroplasts have small genomes because: Question 8 options: their bacterial ancestors did over time, much of their DNA has migrated to the host cell nucleus they lack most coding DNA the genes the need to function are shorter than eukaryotic genes their bacterial ancestors did over time, much of their DNA has migrated to the host cell nucleus they lack most coding DNA the genes the need to function are shorter than eukaryotic genes Solution Answer : The correct answer is A (their bacterial ancestors). Both mitochondria and chloroplasts are closely realed to prokaryotes and also lacks introns, which are the non coding sequences..
Report
Share
Report
Share
Download to read offline
Recommended
Please help with this JAVA Assignment and show output if you can ple.pdf
Please help with this JAVA Assignment and show output if you can please
Complete required scripts based on eclipse and troubleshoot the scripts until the tasks are done.
1. Implement linear-sort, merge-sort and quick-sort (write the code for them).
Solution
Linear or Insertion Sort
import java.util.*;
import java.lang.*;
import java.io.*;
import java.util.Scanner;
class LinearSort
{
public static void sort( int values[] )
{
int N = values.length;
int i, j, temp;
for (i = 1; i< N; i++)
{
j = i;
temp = values[i];
while (j > 0 && temp < values[j-1])
{
values[j] = values[j-1];
j = j-1;
}
values[j] = temp;
}
}
public static void main(String[] args)
{
Scanner scan = new Scanner( System.in );
int n, i;
System.out.println(\"Enter number of elements\");
n = scan.nextInt();
int values[] = new int[n];
System.out.println(\"\ Enter elements\");
for (i = 0; i < n; i++)
values[i] = scan.nextInt();
sort(values);
System.out.println(\"\ Sorted Elements\");
for (i = 0; i < n; i++)
System.out.print(values[i]+\" \");
System.out.println();
}
}
Output:
Enter number of elements
6
Enter elements
34 56 12 8 9 23
Sorted Elements
8 9 12 23 34 56
Merge Sort
import java.util.Scanner;
public class Mergesort
{
public static void mergesort(int[] a, int low, int high)
{
int N = high - low;
if (N <= 1)
return;
int mid = low + N/2;
mergesort(a, low, mid);
mergesort(a, mid, high);
int[] temp = new int[N];
int i = low, j = mid;
for (int k = 0; k < N; k++)
{
if (i == mid)
temp[k] = a[j++];
else if (j == high)
temp[k] = a[i++];
else if (a[j] pivot)
j--;
if (i <= j)
{
temp = values[i];
values[i] = values[j];
values[j] = temp;
i++;
j--;
}
}
if (low < j)
quickquicksort(values, low, j);
if (i < high)
quickquicksort(values, i, high);
}
public static void main(String[] args)
{
Scanner scan = new Scanner( System.in );
int n, i;
System.out.println(\"Enter number of elements\");
n = scan.nextInt();
int values[] = new int[ n ];
System.out.println(\"\ Enter elements\");
for (i = 0; i < n; i++)
values[i] = scan.nextInt();
quicksort(values);
System.out.println(\"\ qSorted Elements \");
for (i = 0; i < n; i++)
System.out.print(values[i]+\" \");
System.out.println();
}
}
Output:
Enter number of elements
8
Enter elements
89 23 90 56 13 71 46 13
Sorted Elements
13 13 23 46 56 71 89 90.
ooo T-Mobile LTE 820 PM courses.apexlearning.com Question 34 of 42 M.pdf
ooo T-Mobile LTE 8:20 PM courses.apexlearning.com Question 34 of 42 Multiple Choice:
Please select the best answer and click submit.\" Which of the following is an example of a
discrete variable? O A The height of a teenager O B. The speed of a police car O C. The weight
of water in a bucket O D. The number of apples in a bag
Solution
D) the number of apples in a bag
this is example for discrete variable.
ood evening people. Ive been working on this code that sends a bur.pdf
ood evening people. I\'ve been working on this code that sends a burst on the client side as well
as the private fifo name over a struct, to a server which will process several clients and the burst
time that will be sent back to the client through the private fifo.
The issue is that once I enter the burst on the client side, it won\'t send the proper burst to the
server, which in turn it will read the private fifo name but not the burst, since there is no burst
(and the server has a set burst entered by the user), the actual burst will become a giantnumber.
I\'m attaching my code hoping than maybe another pair of eyes can see where I am getting my
mistake and help me to correct it. Thanks
client:
my input for the client:
server:
the input and outcome from the server:
at this point I canceled the program with a ctrl + C to cancel the recurring burst in reversive
count.
Again any help or suggestion is well received. Thanks
Solution
client:
#include
#include
#include
#include
#include
#include
#include
#include
typedef struct values {
char name[30];
int arrivalTime;
int burst; //used for both the initial size of the process and to send the completion time
} Process; /*Datatype of the elements in the queue*/
int main( int argc, char *argv[] ){
Process process;
int fdIN; //to write to character server
int fdOUT; //to read from character server
int clientID;
clientID = getpid();
sprintf(process.name, \"FIFO_%d\", clientID);
printf(\"\ FIFO name is %s \", process.name);
if((mkfifo(process.name, 0666)<0 && errno != EEXIST))
{
perror(\"Can\'t create private FIFO\ \");
exit(-1);
}
printf(\"\ Enter burst: \ \")
scanf(\"%d\", &process.burst);
if((fdIN=open(\"commFIFO\", O_WRONLY))<0) //writting into fifo
printf(\"cant open fifo to write\");
write(fdIN, &process, sizeof(process));
if((fdOUT=open(process.name, O_RDONLY))<0) //reading from fifo
printf(\"cant open fifo to read\");
read(fdOUT, &process, sizeof(process));
printf(\"\ arrival time: %d \ \", process.arrivalTime);
unlink (\"commFIFO\");
unlink (process.name);
close(fdIN);
close(fdOUT);
}
SERVER:
#include
#include
#include
#include
#include
#include
#include
#include
//Inbox/Outbox structure
typedef struct values {
char name[30];
int arrivalTime;
int burst; //used for both the initial size of the process and to send the completion time
} Process;
//Node definition
typedef struct node{ /*Nodes stored in the linked list*/
struct values request;
struct node *next;
} Node;
//Queue Definition
typedef struct queue{ /*A struct facilitates passing a queue as an argument*/
Node *head; /*Pointer to the first node holding the queue\'s data*/
Node *tail; /*Pointer to the last node holding the queue\'s data*/
int sz; /*Number of nodes in the queue*/
} Queue;
int size( Queue *Q ){
return Q->sz;
}
int isEmpty( Queue *Q ){
if( Q->sz == 0 ) return 1;
return 0;
}
void enqueue( Queue *Q, struct values elem ){
Node *v = (Node*)malloc(sizeof(Node));/*Allocate memory for the Node*/
if( !v ){
printf(\"ERROR: Insufficien.
Multiply. 0 072(10,000) Multiply. 317.02 middot 0.01 Write the nu.pdf
Multiply. 0 072(10,000) Multiply. 317.02 middot 0.01 Write the number in standard notation.
80.1 billion Multiply. -5.7(3.7) Multiply. -4.5(-2.3) Multiply. 678 552(-1,000) Evaluate the
expression. -(-0.6)^2 + 6|-6.6 - 2.5|
Solution
0.072 × 10,000 = 72 × 10 = 720
317.02 × 0.01 = 3.1702
Please upload rest questions in a clear image as some of them are not visible....
Meta-population theory and island biogeography theory are similar in .pdf
Meta-population theory and island biogeography theory are similar in that: larger habitat
patches and islands will generally have larger populations of a species than smaller patches and
islands sub-populations of a meta-populations are invariably initiated through immigration from
a single, large population (similar to a mainland) the local extinction rate of a population is
higher on larger islands and habitat patches immigration of new individuals of a species is
necessary to maintain populations of that species
Solution
Metapopulation and Island biogeography are similiar in that there is an immigration of new
individuals of a species so that is necessary to maintain the population of the species. This can be
defended by understanding what is metapopulation and island biogeography individually.
Metapopulation consists of a group of widely diverse population of a particular species which
interact at some level thus it can be termed as a population of populations An ideal example of
metapopulation would be on an unoccupied area there will a variety of species living together.
While as Island biogeography is a theory which studies the species composition and the species
richness on an island.Island biogeography is a study aimed at establishing and explaining the
factors that affect species diversity of a specific community.
Java Programpublic class Fraction { instance variablesin.pdf
Java Program
public class Fraction {
//instance variables
int num;
int den;
//default construtcor
Fraction()
{
num=0;
den=1;
}
//parametrized constructor
Fraction(int n,int d)
{
num=n;
den=d;
}
//print fraction object
public void print()
{
System.out.println(num+\"/\"+den);
}
//return double value of fraction
public void printAsDouble()
{
try
{
double div=(double)num/(double)den;
System.out.println(div);
}
catch(ArithmeticException e)
{
System.out.println(\"infinity\");
}
catch(Exception e)
{
System.out.println(e);
}
}
//add two fractions
public Fraction add(Fraction param)
{
int tnum=(this.num *param.den)+(this.den*param.num);
int tden=this.den*param.den;
this.num=tnum;
this.den=tden;
return this;
}
//multiply two fractions
public Fraction multiply(Fraction param)
{
int tnum=(this.num *param.num);
int tden=this.den*param.den;
this.num=tnum;
this.den=tden;
return this;
}
}
public static void main(String[] args)
{
Scanner stdIn = new Scanner(System.in);
Fraction c, d, x; // Fraction objects
System.out.println(\"Enter numerator; then denominator.\");
c = new Fraction(stdIn.nextInt(), stdIn.nextInt());
c.print();
System.out.println(\"Enter numerator; then denominator.\");
d = new Fraction(stdIn.nextInt(), stdIn.nextInt());
d.print();
x = new Fraction(); // create a fraction for number 0
System.out.println(\"Sum:\");
x.add(c).add(d);
x.print();
x.printAsDouble();
x = new Fraction(1, 1); // create a fraction for number 1
System.out.println(\"Product:\");
x.multiply(c).multiply(d);
x.print();
x.printAsDouble();
System.out.println(\"Enter numerator; then denominator.\");
x = new Fraction(stdIn.nextInt(), stdIn.nextInt());
x.printAsDouble();
} //end main Modify the code so that it can handle negative numerators and negative
denominators, and provide a helping method that performs fraction reduction. Sample session
using negative numbers and reduction Enter numerator, then denominator. -5 -8 5/8 Enter
numerator, then denominator. 4 -10 2/5 Sum: 9/40 0.225 Product: 0.25 Enter numerator, then
denominator. 0 -0 indeterminate
Solution
//Fraction.java
import java.util.Scanner;
public class Fraction {
//instance variables
int num;
int den;
//default construtcor
Fraction()
{
num=0;
den=1;
}
// greatest common divisor to reduce fraction
int gcd(int n1, int n2)
{
if (n2 != 0)
return gcd(n2, n1 % n2);
else
return n1;
}
//parametrized constructor
Fraction(int n,int d)
{
num=n;
den=d;
if(d == 0)
{
System.out.println(\"indeterminate\");
System.exit(1);
}
int hcf = gcd(num,den);
num = num/hcf;
den = den/hcf;
}
//print fraction object
public void print()
{
if( (num < 0 && den > 0))
System.out.println(num+\"/\"+den);
else if((num > 0 && den < 0))
System.out.println(\"-\" + num+\"/\"+ (-1*den));
else if(num < 0 && den < 0)
System.out.println( (-1*num)+\"/\"+ (-1*den));
else
System.out.println(num+\"/\"+den);
}
//return double value of fraction
public void printAsDouble()
{
try
{
double div=(double)num/(double)den;
System.out.println(div);
}
catch(ArithmeticException e.
Kim’s revenue one week ago were $251 less than three times Janes rev.pdf
Kim’s revenue one week ago were $251 less than three times Janes revenue. Collectively they
sold $1123. Determine how much each person sold last week.
Solution
Let janes revene=x
kanes revenue=y
y-3x=251--------(!)
x+y=1123---------(2)
solving(1) and (2) we get
subtract (2) from (1)
x+y-y+3x=1123-251
4x=872
x=872/4
x =218
substitute this in (2) to get y
y=1123-218
y =905
janes revenue=$218
Kim’s =$905.
I am having a hard time with this problem, can you help me #5. .pdf
I am having a hard time with this problem, can you help me ???
#5. fill in the copy contructor so that it sets its data to a copy of the data of the Coin that is passed
in. Be sure that it creates a DEEP COPY. ( assuming that the Country class has a copy
constructor that creates one).
public class Coin {
//data
protected Country country;
protected String coinName;
protected int value;
// constructor
// default constructor
public Coin()
{
this.country=new Country(\"US\");
this.coinName=\"Quater\";
this.value=25;
}
//parametirezed constructor
public Coin(Country where,String theName,int theValue)
{
this.country=where;
this.coinName=theName;
this.value=theValue;
}
//copy constructor
public Coin(Coin another)
{
}
//methods
//getValue()-returns its value
public int getValue()
{
return value;
}
//toString-returns its String representation
public String tostring()
{
return coinName+\"with value\"+value;
}
}
Solution
// Copy constructor modified
public Coin(Coin another)
{
this.country=new Country(another.country); // call to the copy Constructor of Country class
this.coinName=another.coinName; // assigns instance member coinName of another object to
coinName of //current object
this.value=another.value; // assigns instance member value of another object to value of current
object
}.
Recommended
Please help with this JAVA Assignment and show output if you can ple.pdf
Please help with this JAVA Assignment and show output if you can please
Complete required scripts based on eclipse and troubleshoot the scripts until the tasks are done.
1. Implement linear-sort, merge-sort and quick-sort (write the code for them).
Solution
Linear or Insertion Sort
import java.util.*;
import java.lang.*;
import java.io.*;
import java.util.Scanner;
class LinearSort
{
public static void sort( int values[] )
{
int N = values.length;
int i, j, temp;
for (i = 1; i< N; i++)
{
j = i;
temp = values[i];
while (j > 0 && temp < values[j-1])
{
values[j] = values[j-1];
j = j-1;
}
values[j] = temp;
}
}
public static void main(String[] args)
{
Scanner scan = new Scanner( System.in );
int n, i;
System.out.println(\"Enter number of elements\");
n = scan.nextInt();
int values[] = new int[n];
System.out.println(\"\ Enter elements\");
for (i = 0; i < n; i++)
values[i] = scan.nextInt();
sort(values);
System.out.println(\"\ Sorted Elements\");
for (i = 0; i < n; i++)
System.out.print(values[i]+\" \");
System.out.println();
}
}
Output:
Enter number of elements
6
Enter elements
34 56 12 8 9 23
Sorted Elements
8 9 12 23 34 56
Merge Sort
import java.util.Scanner;
public class Mergesort
{
public static void mergesort(int[] a, int low, int high)
{
int N = high - low;
if (N <= 1)
return;
int mid = low + N/2;
mergesort(a, low, mid);
mergesort(a, mid, high);
int[] temp = new int[N];
int i = low, j = mid;
for (int k = 0; k < N; k++)
{
if (i == mid)
temp[k] = a[j++];
else if (j == high)
temp[k] = a[i++];
else if (a[j] pivot)
j--;
if (i <= j)
{
temp = values[i];
values[i] = values[j];
values[j] = temp;
i++;
j--;
}
}
if (low < j)
quickquicksort(values, low, j);
if (i < high)
quickquicksort(values, i, high);
}
public static void main(String[] args)
{
Scanner scan = new Scanner( System.in );
int n, i;
System.out.println(\"Enter number of elements\");
n = scan.nextInt();
int values[] = new int[ n ];
System.out.println(\"\ Enter elements\");
for (i = 0; i < n; i++)
values[i] = scan.nextInt();
quicksort(values);
System.out.println(\"\ qSorted Elements \");
for (i = 0; i < n; i++)
System.out.print(values[i]+\" \");
System.out.println();
}
}
Output:
Enter number of elements
8
Enter elements
89 23 90 56 13 71 46 13
Sorted Elements
13 13 23 46 56 71 89 90.
ooo T-Mobile LTE 820 PM courses.apexlearning.com Question 34 of 42 M.pdf
ooo T-Mobile LTE 8:20 PM courses.apexlearning.com Question 34 of 42 Multiple Choice:
Please select the best answer and click submit.\" Which of the following is an example of a
discrete variable? O A The height of a teenager O B. The speed of a police car O C. The weight
of water in a bucket O D. The number of apples in a bag
Solution
D) the number of apples in a bag
this is example for discrete variable.
ood evening people. Ive been working on this code that sends a bur.pdf
ood evening people. I\'ve been working on this code that sends a burst on the client side as well
as the private fifo name over a struct, to a server which will process several clients and the burst
time that will be sent back to the client through the private fifo.
The issue is that once I enter the burst on the client side, it won\'t send the proper burst to the
server, which in turn it will read the private fifo name but not the burst, since there is no burst
(and the server has a set burst entered by the user), the actual burst will become a giantnumber.
I\'m attaching my code hoping than maybe another pair of eyes can see where I am getting my
mistake and help me to correct it. Thanks
client:
my input for the client:
server:
the input and outcome from the server:
at this point I canceled the program with a ctrl + C to cancel the recurring burst in reversive
count.
Again any help or suggestion is well received. Thanks
Solution
client:
#include
#include
#include
#include
#include
#include
#include
#include
typedef struct values {
char name[30];
int arrivalTime;
int burst; //used for both the initial size of the process and to send the completion time
} Process; /*Datatype of the elements in the queue*/
int main( int argc, char *argv[] ){
Process process;
int fdIN; //to write to character server
int fdOUT; //to read from character server
int clientID;
clientID = getpid();
sprintf(process.name, \"FIFO_%d\", clientID);
printf(\"\ FIFO name is %s \", process.name);
if((mkfifo(process.name, 0666)<0 && errno != EEXIST))
{
perror(\"Can\'t create private FIFO\ \");
exit(-1);
}
printf(\"\ Enter burst: \ \")
scanf(\"%d\", &process.burst);
if((fdIN=open(\"commFIFO\", O_WRONLY))<0) //writting into fifo
printf(\"cant open fifo to write\");
write(fdIN, &process, sizeof(process));
if((fdOUT=open(process.name, O_RDONLY))<0) //reading from fifo
printf(\"cant open fifo to read\");
read(fdOUT, &process, sizeof(process));
printf(\"\ arrival time: %d \ \", process.arrivalTime);
unlink (\"commFIFO\");
unlink (process.name);
close(fdIN);
close(fdOUT);
}
SERVER:
#include
#include
#include
#include
#include
#include
#include
#include
//Inbox/Outbox structure
typedef struct values {
char name[30];
int arrivalTime;
int burst; //used for both the initial size of the process and to send the completion time
} Process;
//Node definition
typedef struct node{ /*Nodes stored in the linked list*/
struct values request;
struct node *next;
} Node;
//Queue Definition
typedef struct queue{ /*A struct facilitates passing a queue as an argument*/
Node *head; /*Pointer to the first node holding the queue\'s data*/
Node *tail; /*Pointer to the last node holding the queue\'s data*/
int sz; /*Number of nodes in the queue*/
} Queue;
int size( Queue *Q ){
return Q->sz;
}
int isEmpty( Queue *Q ){
if( Q->sz == 0 ) return 1;
return 0;
}
void enqueue( Queue *Q, struct values elem ){
Node *v = (Node*)malloc(sizeof(Node));/*Allocate memory for the Node*/
if( !v ){
printf(\"ERROR: Insufficien.
Multiply. 0 072(10,000) Multiply. 317.02 middot 0.01 Write the nu.pdf
Multiply. 0 072(10,000) Multiply. 317.02 middot 0.01 Write the number in standard notation.
80.1 billion Multiply. -5.7(3.7) Multiply. -4.5(-2.3) Multiply. 678 552(-1,000) Evaluate the
expression. -(-0.6)^2 + 6|-6.6 - 2.5|
Solution
0.072 × 10,000 = 72 × 10 = 720
317.02 × 0.01 = 3.1702
Please upload rest questions in a clear image as some of them are not visible....
Meta-population theory and island biogeography theory are similar in .pdf
Meta-population theory and island biogeography theory are similar in that: larger habitat
patches and islands will generally have larger populations of a species than smaller patches and
islands sub-populations of a meta-populations are invariably initiated through immigration from
a single, large population (similar to a mainland) the local extinction rate of a population is
higher on larger islands and habitat patches immigration of new individuals of a species is
necessary to maintain populations of that species
Solution
Metapopulation and Island biogeography are similiar in that there is an immigration of new
individuals of a species so that is necessary to maintain the population of the species. This can be
defended by understanding what is metapopulation and island biogeography individually.
Metapopulation consists of a group of widely diverse population of a particular species which
interact at some level thus it can be termed as a population of populations An ideal example of
metapopulation would be on an unoccupied area there will a variety of species living together.
While as Island biogeography is a theory which studies the species composition and the species
richness on an island.Island biogeography is a study aimed at establishing and explaining the
factors that affect species diversity of a specific community.
Java Programpublic class Fraction { instance variablesin.pdf
Java Program
public class Fraction {
//instance variables
int num;
int den;
//default construtcor
Fraction()
{
num=0;
den=1;
}
//parametrized constructor
Fraction(int n,int d)
{
num=n;
den=d;
}
//print fraction object
public void print()
{
System.out.println(num+\"/\"+den);
}
//return double value of fraction
public void printAsDouble()
{
try
{
double div=(double)num/(double)den;
System.out.println(div);
}
catch(ArithmeticException e)
{
System.out.println(\"infinity\");
}
catch(Exception e)
{
System.out.println(e);
}
}
//add two fractions
public Fraction add(Fraction param)
{
int tnum=(this.num *param.den)+(this.den*param.num);
int tden=this.den*param.den;
this.num=tnum;
this.den=tden;
return this;
}
//multiply two fractions
public Fraction multiply(Fraction param)
{
int tnum=(this.num *param.num);
int tden=this.den*param.den;
this.num=tnum;
this.den=tden;
return this;
}
}
public static void main(String[] args)
{
Scanner stdIn = new Scanner(System.in);
Fraction c, d, x; // Fraction objects
System.out.println(\"Enter numerator; then denominator.\");
c = new Fraction(stdIn.nextInt(), stdIn.nextInt());
c.print();
System.out.println(\"Enter numerator; then denominator.\");
d = new Fraction(stdIn.nextInt(), stdIn.nextInt());
d.print();
x = new Fraction(); // create a fraction for number 0
System.out.println(\"Sum:\");
x.add(c).add(d);
x.print();
x.printAsDouble();
x = new Fraction(1, 1); // create a fraction for number 1
System.out.println(\"Product:\");
x.multiply(c).multiply(d);
x.print();
x.printAsDouble();
System.out.println(\"Enter numerator; then denominator.\");
x = new Fraction(stdIn.nextInt(), stdIn.nextInt());
x.printAsDouble();
} //end main Modify the code so that it can handle negative numerators and negative
denominators, and provide a helping method that performs fraction reduction. Sample session
using negative numbers and reduction Enter numerator, then denominator. -5 -8 5/8 Enter
numerator, then denominator. 4 -10 2/5 Sum: 9/40 0.225 Product: 0.25 Enter numerator, then
denominator. 0 -0 indeterminate
Solution
//Fraction.java
import java.util.Scanner;
public class Fraction {
//instance variables
int num;
int den;
//default construtcor
Fraction()
{
num=0;
den=1;
}
// greatest common divisor to reduce fraction
int gcd(int n1, int n2)
{
if (n2 != 0)
return gcd(n2, n1 % n2);
else
return n1;
}
//parametrized constructor
Fraction(int n,int d)
{
num=n;
den=d;
if(d == 0)
{
System.out.println(\"indeterminate\");
System.exit(1);
}
int hcf = gcd(num,den);
num = num/hcf;
den = den/hcf;
}
//print fraction object
public void print()
{
if( (num < 0 && den > 0))
System.out.println(num+\"/\"+den);
else if((num > 0 && den < 0))
System.out.println(\"-\" + num+\"/\"+ (-1*den));
else if(num < 0 && den < 0)
System.out.println( (-1*num)+\"/\"+ (-1*den));
else
System.out.println(num+\"/\"+den);
}
//return double value of fraction
public void printAsDouble()
{
try
{
double div=(double)num/(double)den;
System.out.println(div);
}
catch(ArithmeticException e.
Kim’s revenue one week ago were $251 less than three times Janes rev.pdf
Kim’s revenue one week ago were $251 less than three times Janes revenue. Collectively they
sold $1123. Determine how much each person sold last week.
Solution
Let janes revene=x
kanes revenue=y
y-3x=251--------(!)
x+y=1123---------(2)
solving(1) and (2) we get
subtract (2) from (1)
x+y-y+3x=1123-251
4x=872
x=872/4
x =218
substitute this in (2) to get y
y=1123-218
y =905
janes revenue=$218
Kim’s =$905.
I am having a hard time with this problem, can you help me #5. .pdf
I am having a hard time with this problem, can you help me ???
#5. fill in the copy contructor so that it sets its data to a copy of the data of the Coin that is passed
in. Be sure that it creates a DEEP COPY. ( assuming that the Country class has a copy
constructor that creates one).
public class Coin {
//data
protected Country country;
protected String coinName;
protected int value;
// constructor
// default constructor
public Coin()
{
this.country=new Country(\"US\");
this.coinName=\"Quater\";
this.value=25;
}
//parametirezed constructor
public Coin(Country where,String theName,int theValue)
{
this.country=where;
this.coinName=theName;
this.value=theValue;
}
//copy constructor
public Coin(Coin another)
{
}
//methods
//getValue()-returns its value
public int getValue()
{
return value;
}
//toString-returns its String representation
public String tostring()
{
return coinName+\"with value\"+value;
}
}
Solution
// Copy constructor modified
public Coin(Coin another)
{
this.country=new Country(another.country); // call to the copy Constructor of Country class
this.coinName=another.coinName; // assigns instance member coinName of another object to
coinName of //current object
this.value=another.value; // assigns instance member value of another object to value of current
object
}.
How has television influenced the political process, specifically th.pdf
How has television influenced the political process, specifically the political campaigning
Solution
No aspect of the political process has been affected more by television than political campaigns
and elections. The first presidential election to see extensive use of television was the 1952 race
between Dwight D. Eisenhower and Adlai Stevenson. In that campaign, Richard M. Nixon, as
Eisenhower\'s vice-presidential candidate, \"took his case to the people\" to defend himself on
television against corruption charges in the famous \"Checkers\" speech. However, the most
significant innovation related to the role of television in the 1952 campaign was undoubtedly
Eisenhower\'s use of short spot commercials to enhance his television image. The Eisenhower
campaign utilized the talent of successful product advertising executive Rosser Reeves to devise
a series of short spots that appeared, just like product ads, during commercial breaks in standard
television programming slots. Not only did this strategy break new ground for political
campaigning, but many observers have credited the spots with helping Eisenhower to craft a
friendly, charming persona that contributed to his eventual electoral success. Stevenson made it
easier for the Eisenhower campaign by refusing to participate in this type of electronic
campaigning. Although Stevenson did produce television commercials for the 1956 campaign,
he was never able to overcome Eisenhower\'s popularity.
This early use of television for political advertising was the beginning of a trend that has grown
so dramatically that televised political advertising is now the major form of communication
between candidates and voters in the American electoral system. Every presidential campaign
since 1952 has relied heavily on political television spots. In the 1992 election, Bill Clinton,
George Bush, Ross Perot, and the national parties spent over $120 million dollars for production
and airing of television spots. Even below the presidential level, spots now dominate most major
statewide (particularly gubernatorial and U. S. Senate) and Congressional races in the United
States, accounting for 50-75% of campaign budgets.
Several reasons account for the preeminence of television advertising in politics. First, television
spots and their content are under the direct control of the candidate and his/her campaign.
Second, the spots can reach a much wider audience than other standard forms of electoral
communication. Third, the spots, because they occur in the middle of other programming fare,
have been shown to overcome partisan selectivity (e.g., the spots are generally seen by all voters,
not just those whose political party is the same as that of the candidate). Finally, research has
shown that voters actually learn more (particularly about issues) from political spots than they do
from television news or television debates.
The use of television advertising in political campaigns has often been criticized for \"lowe.
HISTORY Why is it called American revolutionSolutionThe .pdf
HISTORY: Why is it called \"American revolution\"?
Solution
The revolt has got his name as American revolution because of two major changes
1) Many new laws and reqgulations have been made at this time by the American people against
the british colonial rule prevailing that time in America
2) Secondly, the people in America refused to be under the dictatorship or British rule and
actually merged to form the coalition of independent states without any interference from the
British rules.
Explain what #include does in a source codeSolution Th.pdf
Explain what \"#include \" does in a source code?
Solution
The \"# include\" statement \"grabs the attention\" of the pre-processor (the process that occurs
before your program is actually compiled) and \"tells\" the pre-processor to include whatever
follows the \"# include\" statement. While the pre-processor can be told to do quite a bit, in this
instance it\'s being asked to recognize a header file (which is denoted with a \".h\" following the
name of that header, indicating that it\'s a header).
Simpler words:
The preprocessor reads the primary source file into memory, and scans for commands such as
#include. ... The directive is for the preprocessor, which actually has very little to do with the C
compiler except that they are always bundled togethe.
dNdS ratios reflect patterns of genetic divergence that have accumu.pdf
dN/dS ratios reflect patterns of genetic divergence that have accumulated between species over
time. A dN/dS ratio of 1.0 is consistent with a neutral model of evolution. Look back at the
relationship between dN and dS for both the lysin and VERL genes. What is the most likely
hypothesis explaining the pattern that species with more distantly related gene sequences tend to
have lower dN/dS ratios?
Additional info: using MEGA software, it was found that the dN/dS ratio for lysin was 1.237
(positive selection) and the dN/dS ratio for VERL was about 1 (neutral selection).
Solution
dN/dS ratio is a statistical test to quantify selection pressure on protein coding regions of
microbes. Two things taken into consideration here, rate of substitution at silent sites (dS-
assumed neutral) and rate of substitution at non-silent sites(dN- positive).
Because both the species are divergent from each other we observe lower dN/dS ratio. The
sequesence which are present in the exsisting species are essential for their survival, so they can
not afford to change the sequence. They have more distantly related gene sequences, so they do
not have any similarity and do not need significant changes in the sequence..
Discuss the complexity of problem definition and the importance of a.pdf
Discuss the complexity of problem definition and the importance of accurate data to successfully
apply quantitaive analysis in management.
Solution
The quantitative methods contain two component parts, the quantitative and method, with
asymmetrical attention to the quantitative term.
Speaking about method, interest is focused upon the so- called Scientific Method. Science is the
mastering of things of the real world, by knowledge about the truth. The term method drives to
dialogue on methodology in science which is clouded, as the phrase scientific method is used in
two different ways. The one is very general, as a process of improving understanding. Although
vague, it is considered as a powerful definition, since it leaves room for criticizing dogmatic
clinging to beliefs and prejudices, or appreciating careful and systematic reasoning about
empirical evidence. The other is the traditional sense, and supports that there is a unique standard
method, which is central to identity of the science. In effect, scientific progress requires many
methods, so there is not a unique standard method, though taught as a straightforward testing
hypotheses derived from theories in order to test those theories. The more acceptable definition
of scientific method is a process by which scientists, collectively and over time, endeavour to
construct an accurate (that is reliable, consistent and non-arbitrary) representation of the real
world. The popular hypothetic-deductive standard method is excluding consideration of the
process of discovery in science. Rather, research is defined as a penetrating process of learning
and understanding the substance of actual things and facts, by use of different methods. The
research process incorporates formulation of a research issue and construction of a conceptual
framework, by using all available information sources.
The quantitative methods have a number of attributes, such as: they employ measurable data to
reach comparable and useful results, assume alternative plans for achieving objectives, plan data,
concerning observations collection, configuration and elaboration by statistical and econometric
stochastic methods, check data reliability, choose appropriate sampling method, use carefully the
estimates of the parameters for forecasting and planning purposes, etc. since they derive from ex-
post data concerning past.
In an increasingly complex business environment managers have to grapple with a problems and
issues which range from the relatively trivial to the strategic. In such an environment the
quantitative techniques have an important role. It is obvious that life for any manager in any
organization is becoming increasingly difficult and complex. Although there are many factors
contributing to this, figure 1 illustrates some of the major pressures making decision making
increasingly problematic. Organizations find them selves operating in an increasingly complex
environment. Changes in government policy, privatiz.
Define the following terms i. Hydraulic gradientii. Seepageiii. Cr.pdf
Define the following terms
i. Hydraulic gradientii. Seepageiii. Critical hydraulic gradient
iv. Pipingv. Anisotropy
vi. Hydraulic conductivity
vii. Liquefaction
viii. Flow net
ix. Pore pressure
Solution
1. Hydraulic Gradient: It is the head loss per unit seepage length.
2. Seepage: movement of fluid particles through porous media
3. Critical Hydraulic Gradient: It is the Hydraulic Gradient at critical condition, i.e., when
seepage force just balances the buoyant force of an element of soil.
4. Piping: It is the gradual erosion of soil particles.
5. Anisotropy: exhibition of different property in different directions.
6. Hydraulic Conductivity: It is the ease with which a fluid (water) can move through pore
spaces.
7. Liquefaction: It is a phenomenon in which soil loses it\'s strength and stiffness in response to
an applied stress.
8. Flow Net: It is the network of equipotential lines and flow lines.
9. Pore Pressure: It is the pressure of water filling the void space between solid particles..
Describe how the principle of consistency can be applied to interfac.pdf
Describe how the principle of consistency can be applied to interface navigation, display
organization, and data entry.(own word)
Solution
The principle of consistency can be applied to interface navigation, display organization, and
data entry.
Interface Navigation:-
Display Organization:-
Data Entry:-.
Chapter 8 was tough for me. When determining the lumber needs of the.pdf
Chapter 8 was tough for me. When determining the lumber needs of the West Street Video. Am I
correct to think that the lumber needed is the roof-framing plan?
Solution
Lumber is basically timber that is the type of wood which is processed and used in making
various structure such as beam, roof, plank etc
Yes lumber needed roof framing plan in order to provide appropriate support to the roof . it also
decide the shape and size of the roof..
{public int idata;data item (key) public double ddata;data item p.pdf
{public int idata;//data item (key) public double ddata;//data item publis link next;//next link in
list public link int id double dd)//constructor} idata = id; ddata=dd;} public void display link
()//display ourself {system out. Print (\"{\" + idata + \", \" + ddata + \"}\");}}//end class link
class linklist {private link first;//ref to first link on list public link list ()//constructor {first =
null;//no links on lists yet public void insertfirst (int id, double dd)//make new link link new link
= new link (id, dd); newlink.next = first;//it points to old first link first = newlink;//now first
points to this} public link find (int key)//find link with given key {link current = first;
while(current.idata ! = key)}//(assumes non-empty list){//starts at first\'//while no match, if
(current.next == null)//if end of list return null; else}\'//didnt find it//not end list//not end of list,
//go to next link//found it return current;}
Solution
public class Link {
public int iData;
public double dData;
public Link next;
/**
* @param iData
* @param dData
*/
public Link(int iData, double dData) {
this.iData = iData;
this.dData = dData;
}
public void displayLink() {
System.out.println(\"{\" + iData + \", \" + dData + \"} \");
}
}
public class LinkList {
private Link first;
public LinkList() {
// TODO Auto-generated constructor stub
first = null;
}
public void insertFirst(int id, double dd) {
Link newLink = new Link(id, dd);
}
public Link find(int key) {
Link current = first;
while (current.iData != key) {
if (current.next == null)
return null;
else
current = current.next;
}
return current;
}
}.
You have been given a file that contains fields relating to CD infor.pdf
You have been given a file that contains fields relating to CD information. Using the steps of
normalization, create a logical data model that represents this file in third normal form. The
fields include the following:
• Musical group name
• Musicians in group
• Date group was formed Group’s agent
• CD title 1
• CD title 2
• CD title 3
• CD 1 length
• CD 2 length
• CD 3 length
The assumptions are as follows:
• Musicians in group contains a list of the members of the people in the musical group.
• Musical groups can have more than one CD, so both group name and CD title are needed to
uniquely identify a particular CD.
Solution.
Write a java method named flipLines that accepts as its parameter a .pdf
Write a java method named flipLines that accepts as its parameter a Scanner for an input file and
that writes to the console the same file\'s contents with successive pairs of lines reversed in order.
Solution
public static void flipLines(Scanner input) {
while (input.hasNextLine()) {
String first = input.nextLine();
if (input.hasNextLine()) {
String second = input.nextLine();
System.out.println(second); }
System.out.println(first); } }.
Which of the following isare true regarding router operationA. R.pdf
Which of the following is/are true regarding router operation?
A. Routers work at Layer 3 only.
B. Routers work at Layers 1, 2, and 3 to accomplish their tasks.
C. Routers only examine Layer 3 addresses.
D. Routers must examine the Layer 2 address to accept the frame first, and then will look at the
Layer 3 address.
Solution
B and D are correct. All devices must work at the Physical layer, and the router must also
examine the Layer 2 address to determine if the frame is intended for it or not. After the frame’s
physical address is verified, the router moves up to Layer 3 and examines the IP address.
A and C are incorrect. When a device is said to work at a given layer, it means the device works
at all layers up to that level. Routers work at Layer 3; therefore, they perform functions at Layers
1 through 3..
When the temprature is increased to make a doped semiconductor becom.pdf
When the temprature is increased to make a doped semiconductor become intrinsic, the
conductivity of the material decreases. T or F (explain)
Solution
True, when temparature increases conductivity of doped semiconductor diode decreases so it
becomes intrinsic. Because for conductors temperature increases conductivity decreases, that is
conductors are negative temperature coefficients..
What is the probability II-2 is a carrier of the disease (number bet.pdf
What is the probability II-2 is a carrier of the disease (number between 0 and 1)?
II-1 and II-2 are expecting a child. The sonogram shows they will be having a son. What is the
probability he will develop the disease late in life?
II-1 and II-2 have their son. At an early age, it is apparent that he is color-blind. What is the
chance he will develop the disease late in life? disease DEB color blind pedigree color blind and
disease A recessive trait for a late-onset neurological disease is located 8 map units from the
recessive deutan color blindness trait, on the X chromosome. Below is a pedigree from a family
in which both traits are found. The woman\'s husband is color-blind, and she has two sons who
show the disease but are not color blind. Her daughter shows neither trait, and is well past the
age where the symptoms appear.
Solution
1. If II-2 must be a carrier then the probability is 1, that the individual is a career.
2. The probability of the son between II-1 and II-2 (career woman) to have the disease is 0.5.
3. Though, he has been identified as color-blind at an early age, the chance he will develop the
disease late in life would be 0.5..
What does the following statement meanThere is co-translation tra.pdf
What does the following statement mean:
There is co-translation translocation on a growing polypeptide chain.
Solution
In a part of protein synthesis, as the signal sequence emerges from the ribosome, it is recognized
and bound by SRP (signal recognition particle), which escorts the complex to the ER membrane
and SRP directs both the binding of the ribosome to the ER membrane and insersion of the
nascent polypeptide into the transmembrane channel. Then, translation resumes and the growing
polypeptide chain is translocated across the membrane.
This process of tranlational machinary halts for a while and translocate to the ER and where
translation will resume. This process is called co-translation translocation on a growing
popypeptide chain..
What are the two main points of the fluid mosaic modelWhat affect.pdf
What are the two main points of the fluid mosaic model?
What affects fluidity of the plasma membrane? Why is fluidity important?
Describe the 6 functions of membrane proteins.
Which two aspects of a membrane confer selective permeability?
Compare channel and carrier proteins. Can channel proteins participate in active transport?
Solution
Fluid mosaic model was proposed by Singer and Nicolson to explain the selective permeability
of the plasma membrane. According to it, plasma membrane is a mosaic of phospholipids,
cholesterol and proteins. The proteins are embedded in the phospholipid bilayer. THe
phospholipids have hydrophobic tail end and hydrophilic head.
The mosaic nature of the plasma membrane helps it to be fluid. The fluidity is interrupted by
occasional membrane proteins. The ratio of saturated to unsaturated fatty acids also contribute to
the fluidity of the membrane. Unsaturated fatty acids \"kinks\" help the membrane to be fluid at
low temperatures. Cholesterol also helps to keep the membrane in a uniform state of fluidity.
Functions of membrane proteins include
The size of the pores and hydrophilic/hydrophobicity prevents or allows the permeability of most
of the molecules. the other important aspect which confer selective permeability to the cell is the
membrane proteins
Channel proteins are lipoproteins, while carrier proteins are glycoproteins.
Carrier proteins can transport molecules or ions against the concentration gradient, while channel
protein cannot.
Carrier proteins move across the membrane, whereas channel proteins do not move while
transporting molecules or ions.
Carrier proteins can mediate both active and passive transport, while channel proteins can
mediate only passive transport.
using javascript in html i want to add names to a list and store the.pdf
using javascript in html i want to add names to a list and store them in local storage. Then i want
to collect those names and automatically add them to an options scroll bar so that the user can be
able to select them for another use. Please provide the actual code step by step with comments
Solution
Local storagetext.
True or False – Isotopes are irrelevant in biology.False – most bi.pdf
True or False – Isotopes are irrelevant in biology.
False – most biologically relevant elements have isotopes
True – there are no biological elements with isotopes
False – only carbon has isotopes
True – only chemists are concerned with isotopesa.
False – most biologically relevant elements have isotopesb.
True – there are no biological elements with isotopesc.
False – only carbon has isotopesd.
True – only chemists are concerned with isotopes
Solution
False – most biologically relevant elements have isotopes
The most abundant elements in living organisms C, H, N, O, P and S have isotope forms. They
are relevant in biology.a.
False – most biologically relevant elements have isotopes.
The haploid number of chromosomes for dogs is 39. How many TOTAL chr.pdf
The haploid number of chromosomes for dogs is 39. How many TOTAL chromatids would be
found in a normal somatic cell from a dog?
Solution
Ans. A chromosome and its duplicated copy (formed during S-phase of cell division) are called
sister chromatid of each other; and form a chromatid-pair when together. A sister- chromatid pair
separates into two independent chromosomes during anaphase.
A chromatid is equivalent to one chromosome. Or, both the terms represent the condensed form
of a single linear DNA but named differently depending on the stage of cell cycle..
Now,
Total number of chromosomes in normal somatic cell = 2 n ; [n = haploid number]
= 2 x (39) = 78
It is noteworthy that the term “chromatid” is restricted for “the condensed form of DNA during
M-phase of cell division - as long as two sister chromatids are connected to each other”. In all
placed except this, the term chromosome is used to represent the condensed form of DNA. That
is, technically, a normal somatic cell does not have its DNA in form of chromatid, it’s in form of
chromosome only.
For the time being, it’s assumed that “chromatid” represents a “chromosome”.
So, number of chromatids in normal somatic cell = 78.
The use of DNA sequence data has revolutionized the field of phyloge.pdf
The use of DNA sequence data has revolutionized the field of phylogenetics. Give at least two
reasons why this is the case as compared to the the pre-DNA sequence era?
Solution
The major advantage of DNA sequence data is it has made available large number of potential
characters for comparison and inferring the relationship. The number of nucleotide characters
made available for comparison is tremendous due to the PCR reaction. The second major
advantage of DNA sequence data is that substitution within structural genes are decoupled from
its changes in morphology..
678020731-Sumas-y-Restas-Para-Colorear.pdf
KKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKK
More Related Content
More from aroramobiles1
How has television influenced the political process, specifically th.pdf
How has television influenced the political process, specifically the political campaigning
Solution
No aspect of the political process has been affected more by television than political campaigns
and elections. The first presidential election to see extensive use of television was the 1952 race
between Dwight D. Eisenhower and Adlai Stevenson. In that campaign, Richard M. Nixon, as
Eisenhower\'s vice-presidential candidate, \"took his case to the people\" to defend himself on
television against corruption charges in the famous \"Checkers\" speech. However, the most
significant innovation related to the role of television in the 1952 campaign was undoubtedly
Eisenhower\'s use of short spot commercials to enhance his television image. The Eisenhower
campaign utilized the talent of successful product advertising executive Rosser Reeves to devise
a series of short spots that appeared, just like product ads, during commercial breaks in standard
television programming slots. Not only did this strategy break new ground for political
campaigning, but many observers have credited the spots with helping Eisenhower to craft a
friendly, charming persona that contributed to his eventual electoral success. Stevenson made it
easier for the Eisenhower campaign by refusing to participate in this type of electronic
campaigning. Although Stevenson did produce television commercials for the 1956 campaign,
he was never able to overcome Eisenhower\'s popularity.
This early use of television for political advertising was the beginning of a trend that has grown
so dramatically that televised political advertising is now the major form of communication
between candidates and voters in the American electoral system. Every presidential campaign
since 1952 has relied heavily on political television spots. In the 1992 election, Bill Clinton,
George Bush, Ross Perot, and the national parties spent over $120 million dollars for production
and airing of television spots. Even below the presidential level, spots now dominate most major
statewide (particularly gubernatorial and U. S. Senate) and Congressional races in the United
States, accounting for 50-75% of campaign budgets.
Several reasons account for the preeminence of television advertising in politics. First, television
spots and their content are under the direct control of the candidate and his/her campaign.
Second, the spots can reach a much wider audience than other standard forms of electoral
communication. Third, the spots, because they occur in the middle of other programming fare,
have been shown to overcome partisan selectivity (e.g., the spots are generally seen by all voters,
not just those whose political party is the same as that of the candidate). Finally, research has
shown that voters actually learn more (particularly about issues) from political spots than they do
from television news or television debates.
The use of television advertising in political campaigns has often been criticized for \"lowe.
HISTORY Why is it called American revolutionSolutionThe .pdf
HISTORY: Why is it called \"American revolution\"?
Solution
The revolt has got his name as American revolution because of two major changes
1) Many new laws and reqgulations have been made at this time by the American people against
the british colonial rule prevailing that time in America
2) Secondly, the people in America refused to be under the dictatorship or British rule and
actually merged to form the coalition of independent states without any interference from the
British rules.
Explain what #include does in a source codeSolution Th.pdf
Explain what \"#include \" does in a source code?
Solution
The \"# include\" statement \"grabs the attention\" of the pre-processor (the process that occurs
before your program is actually compiled) and \"tells\" the pre-processor to include whatever
follows the \"# include\" statement. While the pre-processor can be told to do quite a bit, in this
instance it\'s being asked to recognize a header file (which is denoted with a \".h\" following the
name of that header, indicating that it\'s a header).
Simpler words:
The preprocessor reads the primary source file into memory, and scans for commands such as
#include. ... The directive is for the preprocessor, which actually has very little to do with the C
compiler except that they are always bundled togethe.
dNdS ratios reflect patterns of genetic divergence that have accumu.pdf
dN/dS ratios reflect patterns of genetic divergence that have accumulated between species over
time. A dN/dS ratio of 1.0 is consistent with a neutral model of evolution. Look back at the
relationship between dN and dS for both the lysin and VERL genes. What is the most likely
hypothesis explaining the pattern that species with more distantly related gene sequences tend to
have lower dN/dS ratios?
Additional info: using MEGA software, it was found that the dN/dS ratio for lysin was 1.237
(positive selection) and the dN/dS ratio for VERL was about 1 (neutral selection).
Solution
dN/dS ratio is a statistical test to quantify selection pressure on protein coding regions of
microbes. Two things taken into consideration here, rate of substitution at silent sites (dS-
assumed neutral) and rate of substitution at non-silent sites(dN- positive).
Because both the species are divergent from each other we observe lower dN/dS ratio. The
sequesence which are present in the exsisting species are essential for their survival, so they can
not afford to change the sequence. They have more distantly related gene sequences, so they do
not have any similarity and do not need significant changes in the sequence..
Discuss the complexity of problem definition and the importance of a.pdf
Discuss the complexity of problem definition and the importance of accurate data to successfully
apply quantitaive analysis in management.
Solution
The quantitative methods contain two component parts, the quantitative and method, with
asymmetrical attention to the quantitative term.
Speaking about method, interest is focused upon the so- called Scientific Method. Science is the
mastering of things of the real world, by knowledge about the truth. The term method drives to
dialogue on methodology in science which is clouded, as the phrase scientific method is used in
two different ways. The one is very general, as a process of improving understanding. Although
vague, it is considered as a powerful definition, since it leaves room for criticizing dogmatic
clinging to beliefs and prejudices, or appreciating careful and systematic reasoning about
empirical evidence. The other is the traditional sense, and supports that there is a unique standard
method, which is central to identity of the science. In effect, scientific progress requires many
methods, so there is not a unique standard method, though taught as a straightforward testing
hypotheses derived from theories in order to test those theories. The more acceptable definition
of scientific method is a process by which scientists, collectively and over time, endeavour to
construct an accurate (that is reliable, consistent and non-arbitrary) representation of the real
world. The popular hypothetic-deductive standard method is excluding consideration of the
process of discovery in science. Rather, research is defined as a penetrating process of learning
and understanding the substance of actual things and facts, by use of different methods. The
research process incorporates formulation of a research issue and construction of a conceptual
framework, by using all available information sources.
The quantitative methods have a number of attributes, such as: they employ measurable data to
reach comparable and useful results, assume alternative plans for achieving objectives, plan data,
concerning observations collection, configuration and elaboration by statistical and econometric
stochastic methods, check data reliability, choose appropriate sampling method, use carefully the
estimates of the parameters for forecasting and planning purposes, etc. since they derive from ex-
post data concerning past.
In an increasingly complex business environment managers have to grapple with a problems and
issues which range from the relatively trivial to the strategic. In such an environment the
quantitative techniques have an important role. It is obvious that life for any manager in any
organization is becoming increasingly difficult and complex. Although there are many factors
contributing to this, figure 1 illustrates some of the major pressures making decision making
increasingly problematic. Organizations find them selves operating in an increasingly complex
environment. Changes in government policy, privatiz.
Define the following terms i. Hydraulic gradientii. Seepageiii. Cr.pdf
Define the following terms
i. Hydraulic gradientii. Seepageiii. Critical hydraulic gradient
iv. Pipingv. Anisotropy
vi. Hydraulic conductivity
vii. Liquefaction
viii. Flow net
ix. Pore pressure
Solution
1. Hydraulic Gradient: It is the head loss per unit seepage length.
2. Seepage: movement of fluid particles through porous media
3. Critical Hydraulic Gradient: It is the Hydraulic Gradient at critical condition, i.e., when
seepage force just balances the buoyant force of an element of soil.
4. Piping: It is the gradual erosion of soil particles.
5. Anisotropy: exhibition of different property in different directions.
6. Hydraulic Conductivity: It is the ease with which a fluid (water) can move through pore
spaces.
7. Liquefaction: It is a phenomenon in which soil loses it\'s strength and stiffness in response to
an applied stress.
8. Flow Net: It is the network of equipotential lines and flow lines.
9. Pore Pressure: It is the pressure of water filling the void space between solid particles..
Describe how the principle of consistency can be applied to interfac.pdf
Describe how the principle of consistency can be applied to interface navigation, display
organization, and data entry.(own word)
Solution
The principle of consistency can be applied to interface navigation, display organization, and
data entry.
Interface Navigation:-
Display Organization:-
Data Entry:-.
Chapter 8 was tough for me. When determining the lumber needs of the.pdf
Chapter 8 was tough for me. When determining the lumber needs of the West Street Video. Am I
correct to think that the lumber needed is the roof-framing plan?
Solution
Lumber is basically timber that is the type of wood which is processed and used in making
various structure such as beam, roof, plank etc
Yes lumber needed roof framing plan in order to provide appropriate support to the roof . it also
decide the shape and size of the roof..
{public int idata;data item (key) public double ddata;data item p.pdf
{public int idata;//data item (key) public double ddata;//data item publis link next;//next link in
list public link int id double dd)//constructor} idata = id; ddata=dd;} public void display link
()//display ourself {system out. Print (\"{\" + idata + \", \" + ddata + \"}\");}}//end class link
class linklist {private link first;//ref to first link on list public link list ()//constructor {first =
null;//no links on lists yet public void insertfirst (int id, double dd)//make new link link new link
= new link (id, dd); newlink.next = first;//it points to old first link first = newlink;//now first
points to this} public link find (int key)//find link with given key {link current = first;
while(current.idata ! = key)}//(assumes non-empty list){//starts at first\'//while no match, if
(current.next == null)//if end of list return null; else}\'//didnt find it//not end list//not end of list,
//go to next link//found it return current;}
Solution
public class Link {
public int iData;
public double dData;
public Link next;
/**
* @param iData
* @param dData
*/
public Link(int iData, double dData) {
this.iData = iData;
this.dData = dData;
}
public void displayLink() {
System.out.println(\"{\" + iData + \", \" + dData + \"} \");
}
}
public class LinkList {
private Link first;
public LinkList() {
// TODO Auto-generated constructor stub
first = null;
}
public void insertFirst(int id, double dd) {
Link newLink = new Link(id, dd);
}
public Link find(int key) {
Link current = first;
while (current.iData != key) {
if (current.next == null)
return null;
else
current = current.next;
}
return current;
}
}.
You have been given a file that contains fields relating to CD infor.pdf
You have been given a file that contains fields relating to CD information. Using the steps of
normalization, create a logical data model that represents this file in third normal form. The
fields include the following:
• Musical group name
• Musicians in group
• Date group was formed Group’s agent
• CD title 1
• CD title 2
• CD title 3
• CD 1 length
• CD 2 length
• CD 3 length
The assumptions are as follows:
• Musicians in group contains a list of the members of the people in the musical group.
• Musical groups can have more than one CD, so both group name and CD title are needed to
uniquely identify a particular CD.
Solution.
Write a java method named flipLines that accepts as its parameter a .pdf
Write a java method named flipLines that accepts as its parameter a Scanner for an input file and
that writes to the console the same file\'s contents with successive pairs of lines reversed in order.
Solution
public static void flipLines(Scanner input) {
while (input.hasNextLine()) {
String first = input.nextLine();
if (input.hasNextLine()) {
String second = input.nextLine();
System.out.println(second); }
System.out.println(first); } }.
Which of the following isare true regarding router operationA. R.pdf
Which of the following is/are true regarding router operation?
A. Routers work at Layer 3 only.
B. Routers work at Layers 1, 2, and 3 to accomplish their tasks.
C. Routers only examine Layer 3 addresses.
D. Routers must examine the Layer 2 address to accept the frame first, and then will look at the
Layer 3 address.
Solution
B and D are correct. All devices must work at the Physical layer, and the router must also
examine the Layer 2 address to determine if the frame is intended for it or not. After the frame’s
physical address is verified, the router moves up to Layer 3 and examines the IP address.
A and C are incorrect. When a device is said to work at a given layer, it means the device works
at all layers up to that level. Routers work at Layer 3; therefore, they perform functions at Layers
1 through 3..
When the temprature is increased to make a doped semiconductor becom.pdf
When the temprature is increased to make a doped semiconductor become intrinsic, the
conductivity of the material decreases. T or F (explain)
Solution
True, when temparature increases conductivity of doped semiconductor diode decreases so it
becomes intrinsic. Because for conductors temperature increases conductivity decreases, that is
conductors are negative temperature coefficients..
What is the probability II-2 is a carrier of the disease (number bet.pdf
What is the probability II-2 is a carrier of the disease (number between 0 and 1)?
II-1 and II-2 are expecting a child. The sonogram shows they will be having a son. What is the
probability he will develop the disease late in life?
II-1 and II-2 have their son. At an early age, it is apparent that he is color-blind. What is the
chance he will develop the disease late in life? disease DEB color blind pedigree color blind and
disease A recessive trait for a late-onset neurological disease is located 8 map units from the
recessive deutan color blindness trait, on the X chromosome. Below is a pedigree from a family
in which both traits are found. The woman\'s husband is color-blind, and she has two sons who
show the disease but are not color blind. Her daughter shows neither trait, and is well past the
age where the symptoms appear.
Solution
1. If II-2 must be a carrier then the probability is 1, that the individual is a career.
2. The probability of the son between II-1 and II-2 (career woman) to have the disease is 0.5.
3. Though, he has been identified as color-blind at an early age, the chance he will develop the
disease late in life would be 0.5..
What does the following statement meanThere is co-translation tra.pdf
What does the following statement mean:
There is co-translation translocation on a growing polypeptide chain.
Solution
In a part of protein synthesis, as the signal sequence emerges from the ribosome, it is recognized
and bound by SRP (signal recognition particle), which escorts the complex to the ER membrane
and SRP directs both the binding of the ribosome to the ER membrane and insersion of the
nascent polypeptide into the transmembrane channel. Then, translation resumes and the growing
polypeptide chain is translocated across the membrane.
This process of tranlational machinary halts for a while and translocate to the ER and where
translation will resume. This process is called co-translation translocation on a growing
popypeptide chain..
What are the two main points of the fluid mosaic modelWhat affect.pdf
What are the two main points of the fluid mosaic model?
What affects fluidity of the plasma membrane? Why is fluidity important?
Describe the 6 functions of membrane proteins.
Which two aspects of a membrane confer selective permeability?
Compare channel and carrier proteins. Can channel proteins participate in active transport?
Solution
Fluid mosaic model was proposed by Singer and Nicolson to explain the selective permeability
of the plasma membrane. According to it, plasma membrane is a mosaic of phospholipids,
cholesterol and proteins. The proteins are embedded in the phospholipid bilayer. THe
phospholipids have hydrophobic tail end and hydrophilic head.
The mosaic nature of the plasma membrane helps it to be fluid. The fluidity is interrupted by
occasional membrane proteins. The ratio of saturated to unsaturated fatty acids also contribute to
the fluidity of the membrane. Unsaturated fatty acids \"kinks\" help the membrane to be fluid at
low temperatures. Cholesterol also helps to keep the membrane in a uniform state of fluidity.
Functions of membrane proteins include
The size of the pores and hydrophilic/hydrophobicity prevents or allows the permeability of most
of the molecules. the other important aspect which confer selective permeability to the cell is the
membrane proteins
Channel proteins are lipoproteins, while carrier proteins are glycoproteins.
Carrier proteins can transport molecules or ions against the concentration gradient, while channel
protein cannot.
Carrier proteins move across the membrane, whereas channel proteins do not move while
transporting molecules or ions.
Carrier proteins can mediate both active and passive transport, while channel proteins can
mediate only passive transport.
using javascript in html i want to add names to a list and store the.pdf
using javascript in html i want to add names to a list and store them in local storage. Then i want
to collect those names and automatically add them to an options scroll bar so that the user can be
able to select them for another use. Please provide the actual code step by step with comments
Solution
Local storagetext.
True or False – Isotopes are irrelevant in biology.False – most bi.pdf
True or False – Isotopes are irrelevant in biology.
False – most biologically relevant elements have isotopes
True – there are no biological elements with isotopes
False – only carbon has isotopes
True – only chemists are concerned with isotopesa.
False – most biologically relevant elements have isotopesb.
True – there are no biological elements with isotopesc.
False – only carbon has isotopesd.
True – only chemists are concerned with isotopes
Solution
False – most biologically relevant elements have isotopes
The most abundant elements in living organisms C, H, N, O, P and S have isotope forms. They
are relevant in biology.a.
False – most biologically relevant elements have isotopes.
The haploid number of chromosomes for dogs is 39. How many TOTAL chr.pdf
The haploid number of chromosomes for dogs is 39. How many TOTAL chromatids would be
found in a normal somatic cell from a dog?
Solution
Ans. A chromosome and its duplicated copy (formed during S-phase of cell division) are called
sister chromatid of each other; and form a chromatid-pair when together. A sister- chromatid pair
separates into two independent chromosomes during anaphase.
A chromatid is equivalent to one chromosome. Or, both the terms represent the condensed form
of a single linear DNA but named differently depending on the stage of cell cycle..
Now,
Total number of chromosomes in normal somatic cell = 2 n ; [n = haploid number]
= 2 x (39) = 78
It is noteworthy that the term “chromatid” is restricted for “the condensed form of DNA during
M-phase of cell division - as long as two sister chromatids are connected to each other”. In all
placed except this, the term chromosome is used to represent the condensed form of DNA. That
is, technically, a normal somatic cell does not have its DNA in form of chromatid, it’s in form of
chromosome only.
For the time being, it’s assumed that “chromatid” represents a “chromosome”.
So, number of chromatids in normal somatic cell = 78.
The use of DNA sequence data has revolutionized the field of phyloge.pdf
The use of DNA sequence data has revolutionized the field of phylogenetics. Give at least two
reasons why this is the case as compared to the the pre-DNA sequence era?
Solution
The major advantage of DNA sequence data is it has made available large number of potential
characters for comparison and inferring the relationship. The number of nucleotide characters
made available for comparison is tremendous due to the PCR reaction. The second major
advantage of DNA sequence data is that substitution within structural genes are decoupled from
its changes in morphology..
More from aroramobiles1 (20)
How has television influenced the political process, specifically th.pdf
How has television influenced the political process, specifically th.pdf
HISTORY Why is it called American revolutionSolutionThe .pdf
HISTORY Why is it called American revolutionSolutionThe .pdf
Explain what #include does in a source codeSolution Th.pdf
Explain what #include does in a source codeSolution Th.pdf
dNdS ratios reflect patterns of genetic divergence that have accumu.pdf
dNdS ratios reflect patterns of genetic divergence that have accumu.pdf
Discuss the complexity of problem definition and the importance of a.pdf
Discuss the complexity of problem definition and the importance of a.pdf
Define the following terms i. Hydraulic gradientii. Seepageiii. Cr.pdf
Define the following terms i. Hydraulic gradientii. Seepageiii. Cr.pdf
Describe how the principle of consistency can be applied to interfac.pdf
Describe how the principle of consistency can be applied to interfac.pdf
Chapter 8 was tough for me. When determining the lumber needs of the.pdf
Chapter 8 was tough for me. When determining the lumber needs of the.pdf
{public int idata;data item (key) public double ddata;data item p.pdf
{public int idata;data item (key) public double ddata;data item p.pdf
You have been given a file that contains fields relating to CD infor.pdf
You have been given a file that contains fields relating to CD infor.pdf
Write a java method named flipLines that accepts as its parameter a .pdf
Write a java method named flipLines that accepts as its parameter a .pdf
Which of the following isare true regarding router operationA. R.pdf
Which of the following isare true regarding router operationA. R.pdf
When the temprature is increased to make a doped semiconductor becom.pdf
When the temprature is increased to make a doped semiconductor becom.pdf
What is the probability II-2 is a carrier of the disease (number bet.pdf
What is the probability II-2 is a carrier of the disease (number bet.pdf
What does the following statement meanThere is co-translation tra.pdf
What does the following statement meanThere is co-translation tra.pdf
What are the two main points of the fluid mosaic modelWhat affect.pdf
What are the two main points of the fluid mosaic modelWhat affect.pdf
using javascript in html i want to add names to a list and store the.pdf
using javascript in html i want to add names to a list and store the.pdf
True or False – Isotopes are irrelevant in biology.False – most bi.pdf
True or False – Isotopes are irrelevant in biology.False – most bi.pdf
The haploid number of chromosomes for dogs is 39. How many TOTAL chr.pdf
The haploid number of chromosomes for dogs is 39. How many TOTAL chr.pdf
The use of DNA sequence data has revolutionized the field of phyloge.pdf
The use of DNA sequence data has revolutionized the field of phyloge.pdf
Recently uploaded
678020731-Sumas-y-Restas-Para-Colorear.pdf
KKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKK
Palestine last event orientationfvgnh .pptx
An EFL lesson about the current events in Palestine. It is intended to be for intermediate students who wish to increase their listening skills through a short lesson in power point.
Unit 8 - Information and Communication Technology (Paper I).pdf
This slides describes the basic concepts of ICT, basics of Email, Emerging Technology and Digital Initiatives in Education. This presentations aligns with the UGC Paper I syllabus.
How to Make a Field invisible in Odoo 17
It is possible to hide or invisible some fields in odoo. Commonly using “invisible” attribute in the field definition to invisible the fields. This slide will show how to make a field invisible in odoo 17.
The Challenger.pdf DNHS Official Publication
Read| The latest issue of The Challenger is here! We are thrilled to announce that our school paper has qualified for the NATIONAL SCHOOLS PRESS CONFERENCE (NSPC) 2024. Thank you for your unwavering support and trust. Dive into the stories that made us stand out!
How libraries can support authors with open access requirements for UKRI fund...
How libraries can support authors with open access requirements for UKRI funded books
Wednesday 22 May 2024, 14:00-15:00.
1.4 modern child centered education - mahatma gandhi-2.pptx
Child centred education is an educational approach that priorities the interest, needs and abilities of the child in the learning process.
Acetabularia Information For Class 9 .docx
Acetabularia acetabulum is a single-celled green alga that in its vegetative state is morphologically differentiated into a basal rhizoid and an axially elongated stalk, which bears whorls of branching hairs. The single diploid nucleus resides in the rhizoid.
Home assignment II on Spectroscopy 2024 Answers.pdf
Answers to Home assignment on UV-Visible spectroscopy: Calculation of wavelength of UV-Visible absorption
Digital Tools and AI for Teaching Learning and Research
This Presentation in details discusses on Digital Tools and AI for Teaching Learning and Research
Model Attribute Check Company Auto Property
In Odoo, the multi-company feature allows you to manage multiple companies within a single Odoo database instance. Each company can have its own configurations while still sharing common resources such as products, customers, and suppliers.
special B.ed 2nd year old paper_20240531.pdf
Instagram:-
https://instagram.com/special_education_needs_01?igshid=YmMyMTA2M2Y=
WhatsApp:-
https://chat.whatsapp.com/JVakNIYlSV94x7bwunO3Dc
YouTube:-
https://youtube.com/@special_education_needs
Teligram :- https://t.me/special_education_needs
Slide Shere :-
https://www.slideshare.net/shabnambano20?utm_campaign=profiletracking&utm_medium=sssite&utm_source=ssslideview
The geography of Taylor Swift - some ideas
Geographical themes connected with Taylor Swift's ERAS tour - coming to the UK in June 2024
"Protectable subject matters, Protection in biotechnology, Protection of othe...
Protectable subject matters, Protection in biotechnology, Protection of other biological materials, Ownership and period of protection
Recently uploaded (20)
Unit 8 - Information and Communication Technology (Paper I).pdf
Unit 8 - Information and Communication Technology (Paper I).pdf
How libraries can support authors with open access requirements for UKRI fund...
How libraries can support authors with open access requirements for UKRI fund...
1.4 modern child centered education - mahatma gandhi-2.pptx
1.4 modern child centered education - mahatma gandhi-2.pptx
Home assignment II on Spectroscopy 2024 Answers.pdf
Home assignment II on Spectroscopy 2024 Answers.pdf
Digital Tools and AI for Teaching Learning and Research
Digital Tools and AI for Teaching Learning and Research
Adversarial Attention Modeling for Multi-dimensional Emotion Regression.pdf
Adversarial Attention Modeling for Multi-dimensional Emotion Regression.pdf
"Protectable subject matters, Protection in biotechnology, Protection of othe...
"Protectable subject matters, Protection in biotechnology, Protection of othe...
Mitochondria and chloroplasts have small genomes becauseQuestion .pdf
- 1. Mitochondria and chloroplasts have small genomes because: Question 8 options: their bacterial ancestors did over time, much of their DNA has migrated to the host cell nucleus they lack most coding DNA the genes the need to function are shorter than eukaryotic genes their bacterial ancestors did over time, much of their DNA has migrated to the host cell nucleus they lack most coding DNA the genes the need to function are shorter than eukaryotic genes Solution Answer : The correct answer is A (their bacterial ancestors). Both mitochondria and chloroplasts are closely realed to prokaryotes and also lacks introns, which are the non coding sequences.