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1
Given point (-2,6,3) and vector
( ) , express
in cylindrical and spherical
coordinates. Evaluate in the
Cartesian, cylindrical, and spherical
systems.
x y
P
y x z P and
at P
  
A a a
A
A
Solution
2
3
2 2
2 2
2, 6, 3
( 2) 6 40
2 10 2 3.16
6.32
Given
x y z
x y
X

   
  
   
 

4
1 1
1 0
0
2, 6, 3
6
tan tan
2
tan ( 3) 108
{ 180 72 108}
( , , ) (6.32,108 ,3)
Given
x y z
y
x
z

 
 

   
  

  
 
 
2 2 2
2, 6, 3
4 36 9 49 7
Given
x y z
r x y z
   
   
    
5
2 2
1
1
1 0
2, 6, 3
tan
40
tan
3
tan 2.11 65
Given
x y z
x y
z
 


   

 

 
6
2 2
1
1
1 0
0 0
2, 6, 3
tan
40
tan
3
tan 2.11 65
( , , ) (7,65 ,108 )
Given
x y z
x y
z
r

 



   

 

 
 

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Mathew ED.doc

  • 1. 1 Given point (-2,6,3) and vector ( ) , express in cylindrical and spherical coordinates. Evaluate in the Cartesian, cylindrical, and spherical systems. x y P y x z P and at P    A a a A A Solution
  • 2. 2
  • 3. 3 2 2 2 2 2, 6, 3 ( 2) 6 40 2 10 2 3.16 6.32 Given x y z x y X               
  • 4. 4 1 1 1 0 0 2, 6, 3 6 tan tan 2 tan ( 3) 108 { 180 72 108} ( , , ) (6.32,108 ,3) Given x y z y x z                      2 2 2 2, 6, 3 4 36 9 49 7 Given x y z r x y z             
  • 5. 5 2 2 1 1 1 0 2, 6, 3 tan 40 tan 3 tan 2.11 65 Given x y z x y z              
  • 6. 6 2 2 1 1 1 0 0 0 2, 6, 3 tan 40 tan 3 tan 2.11 65 ( , , ) (7,65 ,108 ) Given x y z x y z r                  