Integrate by substitution. Then evaluate your answer at x = 0 with a constant of integration C = 3. Type only the final numerical value, rounded to the nearest hundredth. Integral 3 e^6x+1 dx Solution let u = 6x + 1, then (1/6) du = dx --> (1/6) int 3e^u du --> (3/6)e^(6x+1) + C --> (1/2)e^(6x+1) + C at x = 0 and C = 3, (1/2)e + 3 answer.