If two loci R/r and W/w are linked and are 14 map units apart, and an Rw/rW individual is testcrossed, you will obtain: Solution The map distance is 14 mu indicates that the recombination frequency between the two genes is 14%. Therefore, the frequency of recombinants is 14% whereas the frequency of parental genotypes is 86%. The following are the genotype frequencies of the offspring: * Rw / rw - 43% * rW / rw - 43% * RW / rw - 7% * rw / rw - 7%.