How would you prepared 250ml of 0.35 M sodium sulfate solution Solution M = no of moles of solute /Vol of sol (in L) 0.35 = n / .25 => n= 0.0875 moles So mass of sodium sulphate to be added to water tomake the solution = n * Molecular mass of thecompound = 0.0875 * 142 = 12.425 g.