How is a Decision Support Systems (DSS) different from a Management .pdf

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How is a Decision Support Systems (DSS) different from a Management Information Systems( MIS)? Solution MIS provides information about the performance of an organization Think of entire company (the firm) as a system. An MIS provides management with feedback. MIS Periodic reports Pre-specified, generic reports. DSS Special reports that may only be generated once May not know what kind of report to generate until the problem surfaces; specialized reports. In a DSS, a manager generates the report through an interactive interface Flexible & Adaptable reports DSS Reporting is produced through analytical modeling, not just computing an average, or plotting a graph. Business Models are programmed into a DSS.

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Discuss ONE risk that a company faces when trying to diversify internationally. Provide examples, and also discuss how this risk can be mitigated Solution One very significant risk that a Company faces when trying to diversify internationally is the cultural risk because there are certain Dominant cultures that express the core values that are shared by a majority of the organization’s members while there are also certain subcultures which could be regarded as the minicultures within an organization, typically defined by department designations and geographical separation. Hence in terms of implications, both these cultures impact the tolerance level of the people belonging to different cultures in a major way. Here, it is a rare ability to bridge such a perception gap which has already been rooted down into the beliefs of the people hailing from different culture. Further, the National culture has all more greater impact than the Organizational culture on the minds of the people. In certain culture, there is a facilitation of commitment to something larger than self-interest that enhances the stability of the social system. However, it may not get along well with that of the other cultures where social commitment does not form an intrinsic part of the culture. This is where the ideologies clashes between the cultures and there arises the challenge of tolerance. Here, if the leaders are not intellectually brilliant, the diversity management issue will fail. Further, when the Company goes international, the diversified team ethical issues are more critical to barriers to change and diversity which also comes in the way of welcoming or accepting another culture in harmony with that of one culture. The gestures and cultural characteristics are one culture may be complete inverse from that of the other, which may again pose as a barrier to tolerate other cultures. Some cultures are liberal while some are way too conservative hence arises the issue of tolerance to other cultures. Hence despite investing in multicultural teams training, some alliances still fail. If the leaders are not intellectually brilliant, they would find it difficult to manage these barriers because their own culture has not taught to see the other cultures in such details hence this intellect needs to be cultivated as well. Usually the Companies fail in persuading and controlling people when the Company diversifies because of the faulty applications of the management theories due to: Therefore, in order to mitigate the same, one needs to understand the behavior of the employees working at some other international location and thereby attempting to create a more efficient organization on the basis of such a study. This strategy could help in applying various scientific theories to study these individuals working in a Corporate set-up in order to optimize the performance of overall human resource even in a culturally diversified set up. Understanding the work culture and the d.

Discuss ONE risk that a company faces when trying to diversify inte.pdf

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Describe at least one reason why transitioning from PVST+ to Rapid P.pdf

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CASE 2-1 BUILDING UP OUR ASSETS: DHR CONSTRUCTION In August 2011, when the Dow Jones Industrial Average dipped under 8,000 from a high of almost 11,500, Richard Davis and Stephen Hodgetts, academics, friends, and coauthors, were lamenting their ever-shrinking retirement funds. As Hodgetts was fond of saying, “America believes in education: The average professor earns more money in a year than a professional athlete earns in a whole week.” After a long discussion, they decided that they needed to take direct control of their investments and not be prisoners to the rise and fall of the stock market. Davis had done enough preliminary research on the real estate market in their area and convinced Hodgetts that there was money to be made in property ownership and renting starter homes (three bedrooms, two baths) to individuals with poor credit who could not afford a home but who had excellent rental track records. Davis and Hodgetts formed D&H Management and found six families in three months who were happy to rent and eventually purchase homes in the $175K price range. The deal was so attractive that D&H even had a waiting list of new tenants. The six homes, though, gobbled up their initial investment and required additional capital. The New Firm: DHR Construction, LLC Their construction company started off as just a smallcapital-raising venture. Hodgetts and Davis would finish off the basements of their rental homes, get the homes reappraised, and then remortgage the properties, pulling out an additional $10K to $20K per home. These funds could then be used as down payments for future rental homes. In chatting about this matter with some of their renters, Davis and Hodgetts were approached by one of them to perform all of the nonlicensed work (excluding electrical, plumbing, HVAC, etc.). Davis explained to the renters (Alan and Wilma Bronson) that they would have to form their own company and act as any other subcontractor. After completing a few basements, Alan and Wilma enjoyed working on these basements so much that they approached Davis and Hodgetts about figuring out a way that Davis and Hodgetts could keep them occupied all year round. In essence, Alan would quit his job and work as a subcontractor for Davis and Hodgetts. This was not possible, though, since there was not enough work to keep Alan and Wilma busy. Yet a few days later the situation dramatically changed. One of Davis’s students, David Russ, who was designing their basements, said that he thought that Davis and Hodgetts could cut out the middleman in terms of the rental business if they built their own homes. Davis thought that Russ was crazy at the time, but they talked after class and Russ said that he would be happy to act as the general contractor and that he knew all of the subcontractors who were needed in order to construct new homes. Alan and Wilma would do all of the interior work, and Alan could hire some part-time workers to help himself out. Davis and Hodgetts coul.

CASE 2-1 BUILDING UP OUR ASSETS DHR CONSTRUCTIONIn August 2011, w.pdf

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C++ Write a function that takes two numbers are parameters and returns their product. Create a program that program the prompts for to numbers, then uses this function calcuate the product, and then displays the product. Solution #include using namespace std; int product(int number1,int number2) //function to compute product of two numbers { return (number1 * number2); //return product } int main() { int num1,num2; cout<<\"Enter two numbers\"; cin>>num1>>num2; cout<<\"\ Product of \"<.

C++ Write a function that takes two numbers are parameters and retu.pdf

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B.1 Reaction of a Hydrate Addition of Water (2) Appearance Heating (1) Initial Final Why did water droplets form at the mouth of the test tube when heated? lue color ted ought to hae n the r outh artho at tempt tube . 05 When the hydrate of Cuso, 5H0) was heated, did the reaction proceed in the direction of the reactants or products? produc Copyright © 2014 Pearson Education, Inc. Solution CuSO4.5H2O 5. when heated CuSO4.5H2O, the reaction proceeds to the right handside, that is towards the product end. It looses it water of crystallization to form anhydrous CuSO4 salt. Color changed to white. 6. When water was added, the reaction proceeded to the left handside, such that towards the reactant end. The color changed to blue due to the formation of CuSO4.5H2O..

B.1 Reaction of a Hydrate Addition of Water (2) Appearance Heating (1.pdf

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Assignment is: \"Page 349-350 #4 and #5 Use the \"Linked List lab\" you have been working on in class and add the two functions the questions are asking you to develop: divideMid and divideAt. Be sure to include comments Use meaningful identifier names (constants where appropriate) Turn in .cpp file AND Turn in a \"print-screen\' of your output (press \"print-screen\' on keyboard, then \'paste\' in MS-Word)\" How do you solve QUESTION #4 in the book data structures using c++ by D.S. Malik in Visiual Studios using the linked list below with what is being asked? Please need help Linked list : #include #include using namespace std; struct nodeType { int info; nodeType *link; }; void createList(nodeType*& first, nodeType*& last); void printList(nodeType*& first); void insertFront(nodeType*& first); void insertBack(nodeType*& last); void deleteFirst(nodeType*& first); void deleteLast(nodeType*& last, nodeType* first); int main() { nodeType *first, *last; int num; createList(first, last); int choice; while(true) { cout<<\"1. Insert Front.\ 2. Insert Last.\ 3. Delete Front.\ 4. Delete Last.\ 5. Print List.\ 6. Exit.\ \"; cout<<\"Enter your choice: \"; cin>>choice; switch(choice) { case 1: insertFront(first); break; case 2: insertBack(last); break; case 3: deleteFirst(first); break; case 4: deleteLast(last, first); break; case 5: printList(first); break; case 6: return 0; default: cout<<\"Invalid menu option. Try again.\"<>number; while (number != -999) { newNode = new nodeType; // create new node newNode->info = number; newNode->link = NULL; if (first == NULL) { first = newNode; last = newNode; } else { last->link = newNode; last = newNode; } cout<<\"Enter an integer (-999 to stop): \"; cin>>number; } // end of while-loop } // end of build list function void deleteFirst(nodeType*& first) { nodeType *temp; temp= first; first= temp->link; delete temp; return; } void deleteLast(nodeType*& last, nodeType* current) { nodeType *temp; while(current->link != NULL) { temp=current; current=current->link; } temp=last; current->link=NULL; delete temp; last = current; return; } void insertFront(nodeType*& front) { int num; cout<<\"\ Enter the number to insert: \"; cin>>num; nodeType *newNode = new nodeType; newNode->info=num; newNode->link= front; front= newNode; return; } void insertBack(nodeType*& last) { int num; cout<<\"\ Enter the number to insert: \"; cin>>num; nodeType *newNode = new nodeType; newNode->info=num; newNode->link= NULL; last->link= newNode; last = newNode; return; } void printList(nodeType*& first) { cout<<\"Inside printList...printing linked list...\ \"<info << \" \"; current = current->link; } cout< #include using namespace std; struct nodeType { int info; nodeType *link; }; void createList(nodeType*& first, nodeType*& last); void printList(nodeType*& first); void insertFront(nodeType*& first); void insertBack(nodeType*& last); void deleteFirst(nodeType*& first); void deleteLast(nodeType*& last, nodeType* first); int main() { nodeType *firs.

Assignment isPage 349-350 #4 and #5 Use the Linked List lab.pdf

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You maintain several virtual machines (VMs) in an offline state. How.pdf

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Which of the following statements is not TRUE?1)For a 64-bit computer, its memory address space is 264, not 642;2)A process is a program in execution;3)A child process has a different UID (User Identification) as its parent;4)DMA (Direct Memory Access) controls the flow of data between memory and some controller without constant CPU intervention. Solution Answer: 2 , 3 and 4 are true . 1 is false only process becomes program when it is been put from start state for processing. Every child has different UID with the parent. And we know that DMA controls the data flow..

Which of the following statements is not TRUE1)For a 64-bit compute.pdf

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You are running an ELISA on a sample to test for the presence of antigens from the influenza A virus. When it comes time to add the antibody, you realize that you only have antibodies for the influenza B virus. Would these antibodies give you accurate results? Why or why not? Solution Influenza virus is divided into three main types 1. Influenza A 2. Influenza B 3. Influenza C Influenza A virus is mostly observed in a wide variety of birds and mammalian species and Influenza B is mostly confined to humans. Influenza A and B have significant differences in antigens that are present in their membrane proteins. Antibodies are specific to antigens, as the antigens present on influenza A membrane are different from influenza B, the addition of influenza B antibodies instead of influenza A antibodies would result in inaccurate results..

You are running an ELISA on a sample to test for the presence of .pdf

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You are to write an efficient program that will read a dictionary of 100,000 words, and then check a document of 2,000,000 words. The program should insert into an array the position of each misspelled word. I have provided the driver program SpellRunner.cpp, and the necessary class stubs in speller.h, and speller.cpp. You may add any classes and/or code you wish to speller.cpp, and speller.h. You may also use, and alter any Weiss files. CreateDocs.out creates files used for testing. Doc-3-4-1 and Dict-3-4-1 are two testing files for small file. _____________________________________________________________________________ _________________ SpellRunner.cpp #include #include #include #include #include #include \"CPUTimer.h\" #include \"mynew.h\" #include \"speller.h\" // uncomment line below for DOS/Windows OS. // #define DOS #ifdef DOS #include #else #include #endif extern int maxRAM; extern int currentRAM; using namespace std; char* readDictionary(char *filename, char **dictionary, int dictSize) { int fileSize; char *s; struct stat statbuf; stat(filename, &statbuf); fileSize = statbuf.st_size; s = new char[fileSize + 1]; ifstream inf(filename); inf.read(s, fileSize); inf.close(); s[fileSize] = \'\\0\'; dictionary[0] = strtok(s, \"\ \"); for(int i = 1; i < dictSize; i++) dictionary[i] = strtok(NULL, \"\ \ \"); return s; } // readDictionary char* readDocument(char **document, int dictSize, int docSize, int seed) { char *s, filename[80]; int fileSize; struct stat statbuf; sprintf(filename, \"Doc-%d-%d-%d.txt\", dictSize, docSize, seed); stat(filename, &statbuf); fileSize = statbuf.st_size; s = new char[fileSize + 100]; ifstream inf(filename); inf.read(s, fileSize); inf.close(); s[fileSize] = \'\\0\'; document[0] = strtok(s, \"\ \"); for(int i = 1; i < docSize; i++) document[i] = strtok(NULL, \"\ \ \"); return s; } // readDocument() void readWrongs(int *wrongs, int dictSize, int docSize, int seed, int &wrongCount) { char filename[80]; wrongCount = 0; sprintf(filename, \"Wrongs-%d-%d-%d.txt\", dictSize, docSize, seed); ifstream inf(filename); while(inf >> wrongs[wrongCount++]); wrongCount--; } // readWrongs() void checkAnswers(int wrongs[], int wrongCount, int misspelled[], int misspelledCount) { for(int i = 0; i < wrongCount && i < misspelledCount; i++) if(wrongs[i] < misspelled[i]) { cout << \"Speller missed misspelled word # \" << wrongs[i] << endl; return; } else if(wrongs[i] > misspelled[i]) { cout << \"Speller thought correctly spelled word # \" << misspelled[i] << \" was wrong\ \"; return; } if(wrongCount != misspelledCount) cout << \"Speller found \" << misspelledCount << \" misspelled words when \" << \" there were really \" << wrongCount << \" misspelled words.\ \"; } // checkAnswers void cleanup(char **dictionary, char *docFilePtr, char **document, int *wrongs, int *misspelled) { delete [] dictionary; delete [] docFilePtr; delete [] document; delete [] wrongs; delete [] misspelled; } // cleanup() int main(int argc, char* argv[]) { char .

You are to write an efficient program that will read a dictionary of.pdf

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X = C B - B C D; Use Accumulator Register-Register (LoadSt.pdf

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Tic-Tac-Toe Simulator [C# Visual Basic] Create an application that simulates a game of tic-tac-toe. Figure 7-45 shows an example of the application’s form. The form shown in the figure uses eight large Label controls to display the Xs and Os. The application should use a two-dimensional int array to simulate the game board in memory. When the user clicks the New Game button, the application should step through the array, storing a random number in the range of 0 through 1 in each ele- ment. The number 0 represents the letter O, and the number 1 represents the letter X. The form should then be updated to display the game board. The application should display a message indicating whether player X won, player Y won, or the game was a tie. Tic-Tac-Toe X O O X ins New Game Solution Answer:- Tic-Tac-Toe Game : The application should begin with a form that contains the following elements:- 1) A label saying \"Welcome to Tic-Tac-Toe\" 2) Two option buttons enclosed in a frame. The captions for the option buttons should be \"X\" and \"O\". The caption for the frame should be \"Select \'X\' or \'O\' and click OK\". 3) A command button with the caption \"OK\". 4) When the user clicks OK, exit this form and display the main form (the game board). 5) At the start of each game, the application should select who should go first at random, and display an appropriate message to the user in a message box (either \"You go first this time.\" or \"This time, I will go first.\") 6) The game board should be set up with an array of label controls indexed 0 through 8. When a player clicks one of the available labels, an \"X\" or an \"O\" (depending on the user\'s initial selection) should appear in that label. Then the computer should make its move. 7) When the program detects a win, a line should be drawn through the \"three in a row\". If the player wins, the message \"YOU WIN !!!\" should flash across the game board; if the computer wins, the message \"YOU LOSE!!!\" (or \"I WIN!!!\" or \"COMPUTER WINS!!!\") should flash across the game board. If the game ends in a tie, the message \"IT\'S A TIE!!!\" should flash across the game board. (Hint: To get the flashing message, use a label in conjunction with a timer and toggle the label\'s Visible property on and off.) 8) The program should provide options to play a new game and to quit. 9) The program should provide keep four counts: games played, games won, games lost, and games tied. These counts should be displayed on the form. 10) The overall appearance of the application should be tasteful and suggest \"fun\". Experiment with various colors and fonts until you get it the way you want it. The Computer\'s AI Algorithm Your program should implement the following algorithm to try to make the computer win: (1) Examine the board for a winning move, and if you find one, make that move â€“ otherwise proceed to step (2). (2) Examine the board to see if your opponent has a winning move, and if so, select that square to blo.

Tic-Tac-Toe Simulator [C# Visual Basic] Create an application th.pdf

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Which substance has ionic bonds LiI H2O NH3 Br2 Which substance has ionic bonds LiI H2O NH3 Br2 Which substance has ionic bonds LiI H2O NH3 Br2 Solution There are two different ways to determine whether the bond is ionic or not. They are 1. If a compound is made of a metal atom and a non-metal atom, then the bonding will be ionic 2. And it can also be decided from the electronegativity difference between the two atoms of a molecule. If the electronegativity difference is over or close to 1.7 (this value varies in literature from 1.6-2.1), then the bond between the atom might be ionic..

Which substance has ionic bondsLiIH2ONH3Br2Which sub.pdf

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What is a culture? A subculture? Give an example of each. Solution Culture is the shared beliefs, characteristics and knowledge of a group of people based on ideological beliefs, religion, social status, education, age, ethnicity etc. Examples of culture are Western culture, Eastern culture, African-American culture, Asian culture, middle class culture. Subculture is a subset of culture and share a distinct identity. Examples of sub culture are: pop culture, bikers, hippies..

What is a culture A subculture Give an example of each.Solutio.pdf

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The last major idea in population dynamics is the idea of a minimum threshold for a species in a habitat. For some species, survival is not possible if the population size gets too small because of natural interdependence. (Keep in mind that this is over and above the minimum threshold of two animals required for sexual reproduction.) A differential equation that models that situation is dN/ dt = rN (1 N/ T )( 1 N/ K) where 0 < T < K. Based on your experiences so far, choose appropriate values of r, T, and K and plot a slope field. (a) Convince yourself that your slope field indeed models a population of animals that is subject to a minimum threshold in order to survive. (b) Describe the stability of each equilibrium you see. (c) Investigate the affect of harvesting on this population. Explain how harvesting affects the equilibria and include slope fields to support your answer. (d) Draw a bifurcation diagram and point out the bifurcation point. What does that mean in terms of harvesting? Solution Exponential development is the rate of growth of population in the presence of unlimited resources. Exponential development is also know as Density independent growth. dN/dt = rN dN is the adjustment or change in population measure \"r\" is rate of increment of population (births-passings) Logistic growth is the rate of development of populace when resources are constrained. The growth is named as density dependent growth. We represent the logistic growth by Sigmoidal or S-formed growth bend or curve. dN/dt = rN [1-N/K]; where K is the carrying capacity Carrying capacity is basically the maximum size of the population supported by the environment. The development in populace stops at K. The natural or environmental components modify and make the K to change. a) Natural growth equation more genereally represented as P(t) = P0 * ert where P is the populace at given time t and r is the rate of development of populace Logistic Growth dependably will exist in between carrying capacity, K and it will indicate S formed development curve while exponential development or growth seems to move higher. This development pattern is found in populaces that have entry to constrained resources. The loest populace develops exponentially at first. Be that as it may, when the constrained resources begin demonstrating their effects the development or growth slows down and achieves a the carrying capacity or limiting value. b) Logistic growth demonstrates discrete and continuous development models. The discrete model demonstrates that populace development is reliant on most extreme rate of development, carrying capacity, and rate of per-capita increment of the populace. Logistic growth is ceaseless when the individual imitates at the rate that decreases as a linear function of size of populace. Equation for persistent model is dN/dt = r*N (1-N/K) In populaces that are lower than K will increment in size while that are higher than K will diminish in size. K will stay stea.

The last major idea in population dynamics is the idea of a minimum .pdf

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Python ProgramDo not use import please. Problem 1 Rolodex (Note .pdf

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The partial pressure of oxygen in the alveolar gas is affected by certain situations. Classify each of the following conditions as causing an increase, decrease, or no change in alveolar PO_2. Solution Increase in pO2 will occur due to Increased alveolar ventilation and unchanged metabolism Decreased metabolism and unchanged alveolar ventilation. Decreased pO2 will occur due to Decreased alveolar ventilation and unchanged metabolism Increased metabolism and unchanged alveolar ventilation Breathing air with low pO2 No change in pO2 will occur due to Proportional increase in metabolism and alveolar ventilation Remember that, metabolism requires oxygen so it lowers partial pressure of oxygen whereas alveolar ventilation always increase pO2..

The partial pressure of oxygen in the alveolar gas is affected by cer.pdf

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QUESTION 8 ____ are considered to be product or service market stakeholders. Employees and customers Customers and vendors Owners and managers Government and banks Employees and customers Customers and vendors Owners and managers Government and banks Solution Suppliers and customers are considered as Product or Service market stakeholders. Employees, Owners and Managers are Internal Stakeholders Government is considered as External Stakeholders Banks are considered as Capital market stakeholders So Answer is Customers and Vendors..

QUESTION 8____ are considered to be product or service market stak.pdf

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A student had a set of solutions labeled A-E which contained in no order aquoeous soultions of KOH,H2SO4,Fe(NO3)2, HBr, and Mg(NO3)2. After the initial pH test they determined that A was a base,B/C were neutral and D/E were acids. They then mixed B and C with D and then E and got a precipitate with the BD and CE mixtures but not the BE or CD mixtures. They then came to the following erroneous conclusions A:KOH, B:FE(NO3)2 C:Mg(NO3)2 D: HBr and E: H2SO4 with the only correct identification being that solution A was KOH. What did they do wrong and what test should they have done to confirm their results? Solution What wrong they did war that they have not done the qualitative analysis of all the A, B, C, D and E to conclude what are the ions or species present. After that, qualitative analysis for the precipitate is also important. only looking at the acidic or basic behaviour of their solution, it is very difficult to confirm the species..

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A small insect viewed through a convex lens is 1.2 cm from the lens a.pdf

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