A ball is dropped from a height of 10 meters above the ground. Using the kinematic equation and conservation of energy, the theoretical speed of the ball when it reaches a height of 3 meters can be calculated to be approximately 12 meters per second. The document outlines the potential and kinetic energy equations used to solve for the speed, along with experimental setup, data, and further questions about varying the mass, height, and initial velocity of the ball.

1. Potential Energy
Case of a free-falling ball

2. What is the speed at h = 3 m
h = 10 m
Assumption:
No air friction
m = 1kg

3. Experimental Setup

4. Experimental Data and Analysis
height
Frame / time
v=
dx
dt
speed

5. Using kinematic equation
a=
dv
dt
vfinal=vinitat
xfinal=xinitvinit t
1
2
a t
2

6. Theoretical Calculation using
Potential Energy
U =mgh
K =
1
2
mv
2
U K =EM

7. Theoretical Results
mg hinit−hfinal=
1
2
mvfinal
2
vfinal=2g h
v=2×9.8m/s
2
×7m
v≈12 m/s

8. Further Questions
● What happens if we change the mass of the
ball?
● What happens if we change the height?
● What happens if throw the ball downward
instead of falling from rest?