Topic 
ka`pPkmam´cnI¯nsâ 
]c¸fhv 
Std : VIII
ka`pPkmam´cnIw 
1) c−p tPmSn FXnÀhi§Ä kam´camWv. 
2) FÃm hi§fpw tImWpIfpw Xperamb 
NXpÀ`pPamWv.
kkaa``ppPPkkmmaamm´ccnnII¯nnssââ 
hnIÀW§Ä bYm{Iaw d1,d2 
BBWv.
ka`pPkmam´cnI¯nsâ 
]c¸fhv 
ka`pPkmam´cnI¯nsâ ]c¸fhv 
=4X Hcp{XntImW¯nsâ ]c¸fhv
ka`pPkmam´cnI¯nsâ ]c¸fhv 
= 4 x d1d2/8 
= d1d2/2
ka`pPkmam´cnI¯nsâ 
]c¸fhv 
ka`pPkmam´cnI¯nsâ 
]c¸fhv hnIÀW§fpsS 
KpW^e¯nsâ ]IpXnbmWv.
THANKS

Equilateral parallelogram