This document contains a student's lab report for their analytical chemistry course. It includes 9 sets of concentration measurements and the calculations of the mean, standard deviation, and concentration for each set of measurements. The student determines the concentration in μmol for 5 different unknown samples based on calibration curves. They sign a statement of responsibility at the end of the report.

1. UNIVERSIDAD TÉCNICA DE MACHALA
Calidad, Pertenencia y Calidez
UNIDAD ACADEMICA DE CIENCIAS QUÍMICAS Y DE LA SALUD
CARRERA DE BIOQUÍMICA Y FARMACIA
CATEDRA DE ANALISIS DE MEDICAMENTOS
NOMBRE: Joselyn Chamaidan Loayza
DOCENTE: Bioq. Carlos Alberto García
CURSO: 9vo Semestre “B”
FECHA DE ENTREGA: 14/01/2019
DIARIO # 22
UNIDAD
Patrones de calidad. Normalización, campos de normalización
𝑀𝑒𝑑𝑖𝑎 = 0.367 + 0.369 + 0.379 + 0.401 + 0.414 + 0.420 + 0.435 + 0.442 + 0.453
𝑀𝑒𝑑𝑖𝑎 =
3.266
9
𝑀𝑒𝑑𝑖𝑎 = 0.362
0,367 0,369 0,379 0,401 0,414 0,420 0,435 0,442 0,453
0,348 0,338 0,322
𝑆2
= ∑
(0.367 − 0.362)2
+ (0.369 − 0.362) 2
+(0.379 − 0.362)2
+ (0.401 − 0.362)2
+ (0.414 − 0.362)2
+ (0.420 − 0.362)2
+ (0.435 − 0.362)2
+ ( 0.422 − 0. .362)2
+ (0.453 − 0.362)2
9 − 1
𝑆2 =
(0.000025) + (0.000049) + (0.00028) + (0.00152) + (0.0027) + (0.00336) + (0.0053) + (0.0036) + (0.00828)
8
𝑆2 = 0.00313
𝑆 = √0.00313 = 0.030
𝑥 =
0.362 − 0.0236
0.0006
𝑥 = 564𝜇𝑚𝑜𝑙

2. 𝑀𝑒𝑑𝑖𝑎 = 0.220 + 0.225 + 0.301 + 0.315 + 0.356 + 0.381 + 0.390 + 0.398 + 0.402
𝑀𝑒𝑑𝑖𝑎 =
2.988
9
𝑀𝑒𝑑𝑖𝑎 = 0.332
𝑀𝑒𝑑𝑖𝑎 = 0.449 + 0.452 + 0.465 + 0.479 + 0.490 + 0.499 + 0.505 + 0.515 + 0.530
𝑀𝑒𝑑𝑖𝑎 =
4.384
9
𝑀𝑒𝑑𝑖𝑎 = 0.487
0,220 0,225 0,301 0,315 0,356 0,381 0,390 0,398 0,402
0,348 0,338 0,322
0,449 0,452 0,465 0,479 0,490 0,499 0,505 0,515 0,530
𝑆2
= ∑
(0.220 − 0.332)2
+ (0.225 − 0.332) 2
+(0.301 − 0.332)2
+ (0.315 − 0.332)2
+ (0.356 − 0.332)2
+ (0.381 − 0.332)2
+ (0.390 − 0.332)2
+ ( 0.398 − 0. .332)2
+ (0.402 − 0.332)2
9 − 1
𝑆2 =
(0.0125) + (0.0114) + (0.00096) + (0.000289) + (0.000576) + (0.00240) + (0.00336) + (0.00435) + (0.0049)
8
𝑆2 = 0.0407
𝑆 = √0.0407 = 0.06736
𝑥 =
0.332 − 0.0236
0.0006
𝑥 = 514𝜇𝑚𝑜𝑙
𝑆2
= ∑
(0.449 − 0.487)2
+ (0.452 − 0.487) 2
+(0.465 − 0.487)2
+ (0.479 − 0.487)2
+ (0.490 − 0.487)2
+ (0.499 − 0.487)2
+ (0.505 − 0.487)2
+ ( 0.515 − 0.487)2
+ (0.530 − 0.487)2
9 − 1
𝑆2 =
(0.00144) + (0.00122) + (0.000484) + (0.000064) + (0.000009) + (0.000144) + (0.000324) + (0.000784) + (0.00184)
8
𝑆2 = 0.00789
𝑆 = √0.00789 = 0.0265
𝑥 =
0.487 − 0.0236
0.0006
𝑥 = 772.33 𝜇𝑚𝑜𝑙

3. 𝑀𝑒𝑑𝑖𝑎 = 0.101 + 0.110 + 0.165 + 0.190 + 0.200 + 0.204 + 0.220 + 0.225 + 0.235
𝑀𝑒𝑑𝑖𝑎 =
1.65
9
𝑀𝑒𝑑𝑖𝑎 = 0.18
0,101 0,110 0,165 0,190 0,200 0,204 0,220 0,225 0,235
𝑆2
= ∑
(0.101 − 0.18)2
+ (0.110 − 0.18) 2
+(0.165 − 0.18)2
+ (0.190 − 0.18)2
+ (0.200 − 0.18)2
+ (0.204 − 0.18)2
+ (0.220 − 0.18)2
+ ( 0.225 − 0.18)2
+ (0.235 − 0.18)2
9 − 1
𝑆2 =
(0.00624) + (0.0049) + (0.000225) + (0.0001) + (0.0004) + (0.000576) + (0.0016) + (0.002025) + (0.003025)
8
𝑆2 = 0.002386
𝑆 = √0.002386 = 0.0459
𝑥 =
0.18 − 0.0236
0.0006
𝑥 = 240 𝜇𝑚𝑜𝑙

4. 𝑀𝑒𝑑𝑖𝑎 = 0.315 + 0.322 + 0.326 + 0.333 + 0.341 + 0.350 + 0.366 + 0.370 + 0.380
𝑀𝑒𝑑𝑖𝑎 =
3.103
9
𝑀𝑒𝑑𝑖𝑎 = 0.344
FIRMA DE RESPONSABILIDAD
___________________________
Joselyn Chamaidan Loayza
070461139-1
0,315 0,322 0,326 0,333 0,341 0,350 0,366 0,370 0,380
𝑆2
= ∑
(0.315 − 0.344)2
+ (0.322 − 0.344) 2
+(0.326 − 0.344)2
+ (0.333 − 0.344)2
+ (0.341 − 0.344)2
+ (0.350 − 0.344)2
+ (0.366 − 0.344)2
+ ( 0.370 − 0.344)2
+ (0.380 − 0.344)2
9 − 1
𝑆2 =
(0.000841) + (0.000484) + (0.000324) + (0.000121) + (0.000009) + (0.000036) + (0.000484) + (0.000676) + (0.00129)
8
𝑆2 = 0.000533
𝑆 = √0.002386 = 0.0217
𝑥 =
0.344 − 0.0236
0.0006
𝑥 = 534 𝜇𝑚𝑜𝑙