CONSUMER EQUILIBRIUM FOR HINDI MEDIUM PERSON

1. miHkksDrk lkE;
DR.EKRAMUDDIN SIDDIQUI
PGT ECONOMICS
JNV FAIZABAD (U.P.)

2. miHkksDrk
lkE;
miHkksDrk lkE; dh fLFkfr rc
gksrk gS tc miHkksDrk nh
gqbZ cktkj dher ij viuh vk; bl
izdkj O;; djrk gS fd mls vf/kDre
lUrskl izkIr gksA

3. mi;ksfxrk dh /kkj.kk
oLrqvksa esa bPNk dks
lUrq’V djus dh ‘’kfDr mi;ksfxrk
dgykrh gS A
vFkok
oLrqvksa dk og xq.k
mi;ksfxrk dgykrk gS tks bPNk
dks lUrq’V djrk gS A

4. dqy vSkj lhekUr mi;ksfxrk
dqy mi;ksfxrk TU dk vFkZ
lhekUr mi;ksfxrk MU: ∆TU/∆Q
?kVrh lhekUr mi;ksfxrk
dqy vSkj lhekUr mi;ksfxrk odz
dqy vSkj lhekUr mi;ksfxrk
dh /kkj.kk

5. dqy mi;ksfxrk dh /kkj.kk
dqy mi;ksfxrk & oLrqvksa dh lHkh
bdkbvksa ds miHkksx ls izkIr gksus okyh
mi;ksfxrkvksa dk ;ksx dqy mi;ksfxrk dgykrk
gS A
tSls & ,d oLrq ls 10 mi;ksfxrk $ nwljh oLrq
ls 11 mi;ksfxrk = dqy mi;ksfxrk
TU = ∑MU

6. lhekUr mi;ksfxrk dh /kkj.kk
lhekUr mi;ksfxrk & oLrq dh ,d vfrfjDr
bdkbZ ds miHkskx ls dqy mi;ksfxrk esa tks
ifjorZu mls lhekUr mi;ksfxrk dgrs gS A
;fn 10oha bdkbZ ls dqy mi;ksfxrk 100
izkIr gksrh gS rFkk 11oha bdkbZ ls dqy
mi;ksfxrk 111 izkIr gksrh gS rks lhekUr
mi;ksfxrk ¾ 111 & 100 ¾ 11
MU = TU – TU

7. -2
0
2
4
6
8
10
12
14
16
0 1 2 3 4 5 6
Packets
of crisps
TU
in utils
0
1
2
3
4
5
6
0
7
11
13
14
14
13
Utility(utils)
Packets of crisps consumed (per day)
TU
Darren’s utility from consuming crisps (daily)

8. -2
0
2
4
6
8
10
12
14
16
0 1 2 3 4 5 6
Packets
of crisps
TU
in utils
0
1
2
3
4
5
6
0
7
11
13
14
14
13
MU
in utils
-
7
4
2
1
0
-1
Utility(utils)
Packets of crisps consumed (per day)
TU
Darren’s utility from consuming crisps (daily)

9. -2
0
2
4
6
8
10
12
14
16
0 1 2 3 4 5 6
Packets
of crisps
TU
in utils
0
1
2
3
4
5
6
0
7
11
13
14
14
13
MU
in utils
-
7
4
2
1
0
-1
Utility(utils)
Packets of crisps consumed (per day)
TU
MU
Darren’s utility from consuming crisps (daily)

10. -2
0
2
4
6
8
10
12
14
16
0 1 2 3 4 5 6
MU
∆TU = 2
∆Q = 1
MU = ∆TU / ∆Q
Utility(utils)
Packets of crisps consumed (per day)
TU
Darren’s utility from consuming crisps (daily)

11. -2
0
2
4
6
8
10
12
14
16
0 1 2 3 4 5 6
MU
MU = ∆TU / ∆Q = 2/1 = 2
Utility(utils)
Packets of crisps consumed (per day)
TU
∆TU = 2
∆Q = 1
Darren’s utility from consuming crisps (daily)

12. js[kkfprz
2
4
2
0
1
6
1
2
8
1 2 3 4 5 6
TUMU
X oLrq dk miHkksx
TUx
MUx

13. dqy mi;ksfxrk odz2
4
2
0
1
6
1
2
8
1 2 3 4 5 6
TU
X oLrq dk miHkksx
TUx
dqy mi;ksfxrk vkSj lhekUr
mi;ksfxrk esa lEcU/k

14. 10
8
6
4
2
0
-2
-4
Utility
ekrzk
1 2 3 4 5 6
lhekUr mi;ksfxrk odz
MUx
+ve
Zero
-ve

15. dqy mi;ksfxrk vkSj lhekUr mi;ksfxrk
esa lEcU/k
1. fdlh oLrq ,d vfrfjDr bdkbZ ds
miHkksx djus ij lhekUr mi;ksfxrk ?
kVrh gS ysfdu dqy mi;ksfxrk c<rh
gSA
2. izFke pkj bdkbZ;ksa dh lhekUr
mi;ksfxrk /kukRed jgrh gS rks dqy
mi;ksfxrk c<rh tkrh gS A
3. tc lhekUr mi;ksfxrk ’kwU; jgrh gS
rks dqy mi;ksfxrk vf/kDre gksrh gS
A

16. ?kVrh lhekUr mi;ksfxrk dk fu;e
?kVrh lhekUr mi;ksfxrk dk fu;e ;g dgrk gS
fd ,d
oLrq dh vfrfjDr bdkbZ;ksa dk yxkrkj miHkksx
djus ij
izkIr gksus okyh lhekUr mi;ksfxrk ?kVrh tkrh
gS A

17. miHkksDrk lkE; & ,d oLrq ds lEcU/k esa
miHkskDrk )kjk oLrq dh [kjhnkjh rhu
dkjdksa ij fuHkZj djrh gS A
1. oLrq dh lhekUr mi;ksfxrk
2. oLrq dh dher
3. eqnzk dh lhekUr mi;ksfxrk

18. lhekUr mi;ksfxrk dh rkfydk
X dh bdkbZ MUx MUmoney
1 20 10
2 18 10
3 16 10
4 10 10
5 0 10
6 -5 10

19. js[kkfprzMUx/MUm
X oLrq dk miHkksx
1 2 3 4 5 6
20
18
16
14
12
10
8
6
4
2
0
MUx
MUmP E
Px =
MUx
MUm

20. miHkksDrk lkE; dh n’kk,a &,d
oLrq ds lEcU/k esa
oLrq dh dher =
eqnzk dh lhekUr
mi;ksfxrk
Px =
oLrq dh lhekUr
mi;ksfxrk
MUx
MUm
MUx
Px
=MUm

21. miHkksDrk lkE; dh ekU;rk,a
1. miHkksDrk foosd’khy gS A
2. miHkksDrk dh vk; fLFkj gS A
3. oLrq dh dher fLFkj gS A
4. eqnzk dh lhekUr mi;ksfxrk fLFkj gS A

22. eqnzk dh lhekUr mi;ksfxrk D;k
gS
eqnzk dh lhekUr mi;ksfxrk dk
vFkZ gS ^ ,d #i;s ds cjkcj ds
ewY; * A ekuk ,d #i;s dk ewY; =
4 ;wfVy gS

23. miHkksDrk lkE; dh n’kk,a &
nks oLrq ds lEcU/k esa
ekuk miHkksDrk X rFkk Y oLrq dk miHkksx
dj jgk gS &
X oLrq dh fLFkfr esa miHkksDrk lkE; =
Mum
Y oLrq dh fLFkfr esa miHkksDrk lkE; =
Mum
Px
MUx
Py
MUy
Px
MUx
Py
MUy

24. js[kkfprzh; mnkgj.k
ekuk Px = P = 1 Rs.
100
90
80
70
60
50
40
30
20
10
0
100
90
80
70
60
50
40
30
20
10
01 2 3 4 5 6 7 8 9 10 1 2 3 4 5 6 7 8 9 10 11 12
MUx
MUy

25. 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20
0
0
0
0
0
0
0
0
0
0
0
100
90
80
70
60
50
40
30
20
10MUxMUy
lkE; dk foUnq
fLFkj MUm
R

26. O;k[;k & lkE; voLFkk rc gksxh tc
vc pWwfd Px = Py =1
lkE; lehdj.k gksxk % MUx = MUy =
Mum A mijksDr fprz esa R foUnq ij
MUx = MUy (=25;wfVy)AmiHkksDrk
oLrq&X dh bdkbZ;ka vkSj oLrq&Y dh
12 bdkbZ;ka [kjhn jgk gS A oLrq&X dh
tc og 8oha bdkbZ;ka bdkbZ [kjhnrk
gS ]rc mldk MUx = 25 ;wfVy gS ( oLr
MUm
Py
MUy
Px
MUx
==

27. miHkksDrk )kjk ,d #i;s ds cjkcj
vuqHko dk xbZ lUrqf’V Hkh
MUy = 25 ;wfVy gS( ;g fLFkj
;k leku gS tSlk fd R foUnq ij
gS tgWk MUx = MUy =
Mum A pwfd izfr bdkbZ dher
Px = Py =1 #i;k
gS( miHkskDrk X rFkk Y ij 20
Rs [kpZ djrk gS rFkk lkE;