College students often make up a substantial portion of the popul.pdf
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College students often make up a substantial portion of the population of college cities and towns. State College, Pennsylvania, ranks first with 71.1% of its population made up of college students. What is the probability that in a random sample of 150 people from State College, more than 50 are not college students? Solution Given p=1-0.711=0.289 By using Normal approximation, X~Normal(mean=n*p=150*0.289=43.35, s=n*p*(1-p)=sqrt(150*0.289*0.711)=5.55) The probability is P(X>50)=P((X-mean)/s >(50-43.35)/5.55) =P(Z> 1.2) =0.1151 (check standard normal table).
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Complete the PEM Assembly Flow using the processes listed below Wafe.pdf
Complete the PEM Assembly Flow using the processes listed below Wafer rightarrow
rightarrow rightarrow rightarrow rightarrow rightarrow rightarrow Ship Wafer Encapsulation
Wire Bond Deflash Ship Trim/Form Dice Die Attach
Solution
Order of processes is as follows:
(a) Wafer
(g) Dice
(h) Die Attach
(c) Wire Bond
(b) Encapsulation
(d) Deflash
(f) Trim/Form
(e) Ship.
classify the give differential equation as to type and order. classif.pdf
classify the give differential equation as to type and order. classify the ordinary differential
equations as to linearity. (2xy-y2) dx + ex dy = 0
Solution
Its first order nonlinear ordinary diff.equation. And this in non-homogeneous
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Classify the data as either qualitative or quantitative. A large reco.pdf
Classify the data as either qualitative or quantitative. A large record company reported the
following sales figures (below) for various music media last year. What kind of data is provided
by the information in the second column?
Solution
QUANTITATIVE.
Cisco Systems, Inc. (CSCO) has a current dividend of $0.84 per share..pdf
Cisco Systems, Inc. (CSCO) has a current dividend of $0.84 per share. The current stock price
price of Home Depot is $24.45. Cisco has a dividend payout of 43.97% and an expected return
on equity of 16.42%. What is the cost of Cisco common equity? (1)
Solution
Dividend payout ratio = Dividend per share/Earnings available for equity share holders
43.97% = 0.84/Earning available for equity share holders
Earnings available for equity share holders = 0.84/43.97%
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Cost of equity = Dividend per share/market price per share
= 0.84/24.45 x 100
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Consider the following function Reduce all fractions to lowest terms..pdf
Consider the following function Reduce all fractions to lowest terms. R(x) = 4 [[-x/3]] POINTS
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Class C and Class F fly ashes are used extensively as pozzolanic mate.pdf
Class C and Class F fly ashes are used extensively as pozzolanic materials in concrete. Discuss
the following: What is a pozzolanic reaction?
Solution
Pozzolanic reaction is the chemical reaction which occurs between the pozzolans ( Fly ash ) and
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In short, CH + SH C-S-H.
City A+ has a population of 314,159 people on January 1, 2010. The po.pdf
City A+ has a population of 314,159 people on January 1, 2010. The population is growing at a
rate of 1,500 people per year. Find a linear population model P(t) = P0 + at for the population of
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Solution
p(0)=314,159.
Consider the annual maximum series for the US Geological survey gatin.pdf
Consider the annual maximum series for the US Geological survey gating station on Clear
Creek near Pearland, TX The statistics of the transformed flows are for given average of log of
values (y-bar), standard deviation of log values (Sy), skewness (Gs), and sample site (n), Using
the Pearson Type III distribution compare the discharges for given recurrence interval with and
without the US Water Resource Council recommendation on s coefficients. The map skew (Gm)
is given.
Solution
Frequency Factors K for Gamma and log-Pearson Type III Distributions
Recurrence Interval In Years
1.0101
2
5
10
25
50
100
200
SKEW COEFFICIENT
Cs
Percent Chance (>=) = 1-F
99
50
20
10
4
2
1
0.5
3
-0.667
-0.396
0.420
1.180
2.278
3.152
4.051
4.970
2.9
-0.690
-0.390
0.440
1.195
2.277
3.134
4.013
4.904
2.8
-0.714
-0.384
0.460
1.210
2.275
3.114
3.973
4.847
2.7
-0.740
-0.376
0.479
1.224
2.272
3.093
3.932
4.783
2.6
-0.769
-0.368
0.499
1.238
2.267
3.071
3.889
4.718
2.5
-0.799
-0.360
0.518
1.250
2.262
3.048
3.845
4.652
2.4
-0.832
-0.351
0.537
1.262
2.256
3.023
3.800
4.584
2.3
-0.867
-0.341
0.555
1.274
2.248
2.997
3.753
4.515
2.2
-0.905
-0.330
0.574
1.284
2.240
2.970
3.705
4.444
2.1
-0.946
-0.319
0.592
1.294
2.230
2.942
3.656
4.372
2
-0.990
-0.307
0.609
1.302
2.219
2.912
3.605
4.298
1.9
-1.037
-0.294
0.627
1.310
2.207
2.881
3.553
4.223
1.8
-1.087
-0.282
0.643
1.318
2.193
2.848
3.499
4.147
1.7
-1.140
-0.268
0.660
1.324
2.179
2.815
3.444
4.069
1.6
-1.197
-0.254
0.675
1.329
2.163
2.780
3.388
3.990
1.5
-1.256
-0.240
0.690
1.333
2.146
2.743
3.330
3.910
1.4
-1.318
-0.225
0.705
1.337
2.128
2.706
3.271
3.828
1.3
-1.383
-0.210
0.719
1.339
2.108
2.666
3.211
3.745
1.2
-1.449
-0.195
0.732
1.340
2.087
2.626
3.149
3.661
1.1
-1.518
-0.180
0.745
1.341
2.066
2.585
3.087
3.575
1
-1.588
-0.164
0.758
1.340
2.043
2.542
3.022
3.489
0.9
-1.660
-0.148
0.769
1.339
2.018
2.498
2.957
3.401
0.8
-1.733
-0.132
0.780
1.336
1.993
2.453
2.891
3.312
0.7
-1.806
-0.116
0.790
1.333
1.967
2.407
2.824
3.223
0.6
-1.880
-0.099
0.800
1.328
1.939
2.359
2.755
3.132
0.5
-1.955
-0.083
0.808
1.323
1.910
2.311
2.686
3.041
0.4
-2.029
-0.066
0.816
1.317
1.880
2.261
2.615
2.949
0.3
-2.104
-0.050
0.824
1.309
1.849
2.211
2.544
2.856
0.2
-2.178
-0.033
0.830
1.301
1.818
2.159
2.472
2.763
0.1
-2.252
-0.017
0.836
1.292
1.785
2.107
2.400
2.67
0
-2.326
0.000
0.842
1.282
1.751
2.054
2.326
2.576
-0.1
-2.4
0.017
0.846
1.27
1.716
2.000
2.252
2.482
-0.2
-2.472
0.033
0.850
1.258
1.680
1.945
2.178
2.388
-0.3
-2.544
0.050
0.853
1.245
1.643
1.890
2.104
2.294
-0.4
-2.615
0.066
0.855
1.231
1.606
1.834
2.029
2.201
-0.5
-2.686
0.083
0.856
1.216
1.567
1.777
1.955
2.108
-0.6
-2.755
0.099
0.857
1.200
1.528
1.720
1.880
2.016
-0.7
-2.824
0.116
0.857
1.183
1.488
1.663
1.806
1.926
-0.8
-2.891
0.132
0.856
1.166
1.448
1.606
1.733
1.837
-0.9
-2.957
0.148
0.854
1.147
1.407
1.549
1.660
1.749
-1
-3.022
0.164
0.852
1.128
1.366
1.492
1.588
1.664
-1.1
-3.087
0.180
0.848
1.107
1.324
1.435
1.518
1.581
-1.2
-3.149
0.195
0.844
1.086
1.282
1.379
1.449
1.501
-1.3
-3.2.
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Order of processes is as follows:
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(g) Dice
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(d) Deflash
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classify the give differential equation as to type and order. classif.pdf
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QUANTITATIVE.
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= 1.91 Per share
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Consider the following function Reduce all fractions to lowest terms..pdf
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Class C and Class F fly ashes are used extensively as pozzolanic mate.pdf
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Solution
Pozzolanic reaction is the chemical reaction which occurs between the pozzolans ( Fly ash ) and
the calcium hydroxide to give CSH gel.
Ca(OH)2 + H4SiO4 CaH2SiO4·2 H2O
In short, CH + SH C-S-H.
City A+ has a population of 314,159 people on January 1, 2010. The po.pdf
City A+ has a population of 314,159 people on January 1, 2010. The population is growing at a
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Solution
p(0)=314,159.
Consider the annual maximum series for the US Geological survey gatin.pdf
Consider the annual maximum series for the US Geological survey gating station on Clear
Creek near Pearland, TX The statistics of the transformed flows are for given average of log of
values (y-bar), standard deviation of log values (Sy), skewness (Gs), and sample site (n), Using
the Pearson Type III distribution compare the discharges for given recurrence interval with and
without the US Water Resource Council recommendation on s coefficients. The map skew (Gm)
is given.
Solution
Frequency Factors K for Gamma and log-Pearson Type III Distributions
Recurrence Interval In Years
1.0101
2
5
10
25
50
100
200
SKEW COEFFICIENT
Cs
Percent Chance (>=) = 1-F
99
50
20
10
4
2
1
0.5
3
-0.667
-0.396
0.420
1.180
2.278
3.152
4.051
4.970
2.9
-0.690
-0.390
0.440
1.195
2.277
3.134
4.013
4.904
2.8
-0.714
-0.384
0.460
1.210
2.275
3.114
3.973
4.847
2.7
-0.740
-0.376
0.479
1.224
2.272
3.093
3.932
4.783
2.6
-0.769
-0.368
0.499
1.238
2.267
3.071
3.889
4.718
2.5
-0.799
-0.360
0.518
1.250
2.262
3.048
3.845
4.652
2.4
-0.832
-0.351
0.537
1.262
2.256
3.023
3.800
4.584
2.3
-0.867
-0.341
0.555
1.274
2.248
2.997
3.753
4.515
2.2
-0.905
-0.330
0.574
1.284
2.240
2.970
3.705
4.444
2.1
-0.946
-0.319
0.592
1.294
2.230
2.942
3.656
4.372
2
-0.990
-0.307
0.609
1.302
2.219
2.912
3.605
4.298
1.9
-1.037
-0.294
0.627
1.310
2.207
2.881
3.553
4.223
1.8
-1.087
-0.282
0.643
1.318
2.193
2.848
3.499
4.147
1.7
-1.140
-0.268
0.660
1.324
2.179
2.815
3.444
4.069
1.6
-1.197
-0.254
0.675
1.329
2.163
2.780
3.388
3.990
1.5
-1.256
-0.240
0.690
1.333
2.146
2.743
3.330
3.910
1.4
-1.318
-0.225
0.705
1.337
2.128
2.706
3.271
3.828
1.3
-1.383
-0.210
0.719
1.339
2.108
2.666
3.211
3.745
1.2
-1.449
-0.195
0.732
1.340
2.087
2.626
3.149
3.661
1.1
-1.518
-0.180
0.745
1.341
2.066
2.585
3.087
3.575
1
-1.588
-0.164
0.758
1.340
2.043
2.542
3.022
3.489
0.9
-1.660
-0.148
0.769
1.339
2.018
2.498
2.957
3.401
0.8
-1.733
-0.132
0.780
1.336
1.993
2.453
2.891
3.312
0.7
-1.806
-0.116
0.790
1.333
1.967
2.407
2.824
3.223
0.6
-1.880
-0.099
0.800
1.328
1.939
2.359
2.755
3.132
0.5
-1.955
-0.083
0.808
1.323
1.910
2.311
2.686
3.041
0.4
-2.029
-0.066
0.816
1.317
1.880
2.261
2.615
2.949
0.3
-2.104
-0.050
0.824
1.309
1.849
2.211
2.544
2.856
0.2
-2.178
-0.033
0.830
1.301
1.818
2.159
2.472
2.763
0.1
-2.252
-0.017
0.836
1.292
1.785
2.107
2.400
2.67
0
-2.326
0.000
0.842
1.282
1.751
2.054
2.326
2.576
-0.1
-2.4
0.017
0.846
1.27
1.716
2.000
2.252
2.482
-0.2
-2.472
0.033
0.850
1.258
1.680
1.945
2.178
2.388
-0.3
-2.544
0.050
0.853
1.245
1.643
1.890
2.104
2.294
-0.4
-2.615
0.066
0.855
1.231
1.606
1.834
2.029
2.201
-0.5
-2.686
0.083
0.856
1.216
1.567
1.777
1.955
2.108
-0.6
-2.755
0.099
0.857
1.200
1.528
1.720
1.880
2.016
-0.7
-2.824
0.116
0.857
1.183
1.488
1.663
1.806
1.926
-0.8
-2.891
0.132
0.856
1.166
1.448
1.606
1.733
1.837
-0.9
-2.957
0.148
0.854
1.147
1.407
1.549
1.660
1.749
-1
-3.022
0.164
0.852
1.128
1.366
1.492
1.588
1.664
-1.1
-3.087
0.180
0.848
1.107
1.324
1.435
1.518
1.581
-1.2
-3.149
0.195
0.844
1.086
1.282
1.379
1.449
1.501
-1.3
-3.2.
Consider the ANOVA table for a simple linear regression given below. .pdf
Consider the ANOVA table for a simple linear regression given below. What is the value of the
mean square error for this regression analysis?
Solution
The error degrees of freedom are 14 since they must sum to 15. MSE = SSE/d.f. =
38.45/14 = 2.7464.
Consider the AC circuit shown in Figure P75 (a) Find the branch curre.pdf
Consider the AC circuit shown in Figure P75 (a) Find the branch currents I, I2, I3, I4, I5 and I6.
(b) Determine the complex power of each circuit element. (c) Are the complex powers in the
circuit balanced? Explain.
Solution
Please wait. I am uploading the image.
Christy Reed has been depositing $2,000 in her savings account every .pdf
Christy Reed has been depositing $2,000 in her savings account every December since 2001.
Her account earns 7 percent compounded annually.
Solution
1) Future Value = PMT(P/A,7%,12)
FV = $2000 x 7.943 = $15,886
2) Nper calculated in excel
Double Amount in year = NPER (Rate, pmt, pv,fv) = NPER(10%,0,1,-2) = 7.2 years
Triple Amount in years = NPER(10%,0,1,-3) = 11.5 years
Using F/P table @10% we can find NPER
year 1 F/P = 1.1
Year 7 F/P = 1.949 (its approx double the number) = NPER = 7
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Consider a continuous-time LTI system whose transfer function is give.pdf
Consider a continuous-time LTI system whose transfer function is given by: H(j omega) = sin
(4 omega)/omega If the input to this system is a periodic signal with period T = 8, determine the
corresponding system output y(t)
Solution
the correcsponding output for this functions is sinc(4t).
Consider a catchment that has undergone extensive urbanisation. What .pdf
Consider a catchment that has undergone extensive urbanisation. What are the changes you
would expect to this catchment in the following hydrographic characteristics? Peak discharge
for a given AEP Time to peak discharge Runoff volume for a similar storm event Include in
your discussion a justification for the projects change in the characteristic.
Solution
(A) Peak Discharge for a given AEP: Due to urbaniztion the type of use of land changes.
Developed lands are often requires Removal of vegetation and soil, grading the land surface, and
constructing drainage networks. This can increase runoff to streams from rainfall. As a result, the
peak discharge increases in nearby streams.
(B) Time to Peak Discharge: Time to peak discharge reduces due to urbanisation as more paving
to the ground surface which results in reduction in seepage. Reduction in seepage leads to
reduction in time for peak discharge.
(C) Runoff volume for a similar storm event: Due to urbaniztion, there is chance to increse in to
runoff volume due to following reasons
(i) More paving means lower percolation and seepage in ground surfce - this leads to increase in
runoff volume.
(ii) Urbaniztion creates obstructions to the flow of water, which agin helps in increasing the
runoff volume..
Compute the inverse cdfs of the following density functions and descr.pdf
Compute the inverse cdfs of the following density functions and describe how to generate
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I will use I[a,b] for the integral from a to b and E[a,b] for evaluated from a to b
For - infinity < x < 0, F(x) = |[-infinity,x] 1/2b e ^ x/b = 1/2 e ^x/b E[-infinity, x] =
1/2 e ^x/b - 0 = 1/2 e ^x/b
For 0 < x < infinity, as the value of integral above = 1/2 at 0, F(x) =
1/2 + |[0,x] 1/2b e^-x/b = 1/2 - 1/2e^-x/bE[0, x] =
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1 - Y = 1/2 e^-x/b
2 - 2Y = e^-x/b
ln(2-2Y) = -x/b
x = -ln(2-2Y) b Y >= 1/2
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x = ln(2Y) b Y <= 1/2
x = -ln(2-2Y) b Y >= 1/2
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(x-a)^k/(b-a)^k - 0 =
(x-a)^k/(b-a)^k
Then, if(x-a)^k/(b-a)^k = y
(x-a)^k =(b-a)^k y
Taking the k\'th root on both sides
x-a = (b-a) y^(1/k)
x = a +(b-a) y^(1/k)
.
Compute the correlation of X and Y. Compute the covariance of X and .pdf
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work in part (b) (i.e., don\'t do any new integration). Compute the correlation coefficient rho of
X and Y. Are X and Y uncorrelated? Justify your answer.
Solution
correlation of X willbe 3x/2+1/4
correlation of Y will be 3/4(y^2+1).
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The US House of Representatives is deeply concerned by ongoing and pervasive acts of antisemitic
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unwillingness to rectify this violation through action requires accountability.
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• The Committee on Oversight and Accountability is investigating the sources of funding and other support flowing to groups espousing pro-Hamas propaganda and engaged in antisemitic harassment and intimidation of students. The Committee on Oversight and Accountability is the principal oversight committee of the US House of Representatives and has broad authority to investigate “any matter” at “any time” under House Rule X.
• The Committee on Ways and Means has been investigating several universities since November 15, 2023, when the Committee held a hearing entitled From Ivory Towers to Dark Corners: Investigating the Nexus Between Antisemitism, Tax-Exempt Universities, and Terror Financing. The Committee followed the hearing with letters to those institutions on January 10, 202
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Consider the ANOVA table for a simple linear regression given below. .pdf
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mean square error for this regression analysis?
Solution
The error degrees of freedom are 14 since they must sum to 15. MSE = SSE/d.f. =
38.45/14 = 2.7464.
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Consider the AC circuit shown in Figure P75 (a) Find the branch currents I, I2, I3, I4, I5 and I6.
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Please wait. I am uploading the image.
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Christy Reed has been depositing $2,000 in her savings account every December since 2001.
Her account earns 7 percent compounded annually.
Solution
1) Future Value = PMT(P/A,7%,12)
FV = $2000 x 7.943 = $15,886
2) Nper calculated in excel
Double Amount in year = NPER (Rate, pmt, pv,fv) = NPER(10%,0,1,-2) = 7.2 years
Triple Amount in years = NPER(10%,0,1,-3) = 11.5 years
Using F/P table @10% we can find NPER
year 1 F/P = 1.1
Year 7 F/P = 1.949 (its approx double the number) = NPER = 7
Year = 12 F/P = 3.138 (its approx triple the number = NPER = 12.
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Consider a continuous-time LTI system whose transfer function is given by: H(j omega) = sin
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Solution
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Consider a catchment that has undergone extensive urbanisation. What .pdf
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would expect to this catchment in the following hydrographic characteristics? Peak discharge
for a given AEP Time to peak discharge Runoff volume for a similar storm event Include in
your discussion a justification for the projects change in the characteristic.
Solution
(A) Peak Discharge for a given AEP: Due to urbaniztion the type of use of land changes.
Developed lands are often requires Removal of vegetation and soil, grading the land surface, and
constructing drainage networks. This can increase runoff to streams from rainfall. As a result, the
peak discharge increases in nearby streams.
(B) Time to Peak Discharge: Time to peak discharge reduces due to urbanisation as more paving
to the ground surface which results in reduction in seepage. Reduction in seepage leads to
reduction in time for peak discharge.
(C) Runoff volume for a similar storm event: Due to urbaniztion, there is chance to increse in to
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(ii) Urbaniztion creates obstructions to the flow of water, which agin helps in increasing the
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random variables from these distributions based on the inverse-cdf method. f(x) = 1 / 2b e -|x|/b,
b > 0, x R. (1) f(x) = k(x - a) k-1 / (b - a)k, k > 0, a x b. (2).
Solution
I will use I[a,b] for the integral from a to b and E[a,b] for evaluated from a to b
For - infinity < x < 0, F(x) = |[-infinity,x] 1/2b e ^ x/b = 1/2 e ^x/b E[-infinity, x] =
1/2 e ^x/b - 0 = 1/2 e ^x/b
For 0 < x < infinity, as the value of integral above = 1/2 at 0, F(x) =
1/2 + |[0,x] 1/2b e^-x/b = 1/2 - 1/2e^-x/bE[0, x] =
1/2 - 1/2 e^-x/b - -1/2 = 1 - 1/2e^-x/b
Then, if 1/2 e^x/b = Y, e^x/b = 2Y, and x/b = ln(2Y) and x = ln(2Y) b Y <= 1/2
if1 - 1/2e^-x/b = Y
1 - Y = 1/2 e^-x/b
2 - 2Y = e^-x/b
ln(2-2Y) = -x/b
x = -ln(2-2Y) b Y >= 1/2
Our solution is
x = ln(2Y) b Y <= 1/2
x = -ln(2-2Y) b Y >= 1/2
where Y ~ U[0,1]
As f(x) = k(x-a)^(k-1)/(b-a)^k a <= x <= b
F(x) = I[a,x] k(x-a)^(k-1)/(b-a)^k =(x-a)^k/(b-a)^k E[a,x] =
(x-a)^k/(b-a)^k - 0 =
(x-a)^k/(b-a)^k
Then, if(x-a)^k/(b-a)^k = y
(x-a)^k =(b-a)^k y
Taking the k\'th root on both sides
x-a = (b-a) y^(1/k)
x = a +(b-a) y^(1/k)
.
Compute the correlation of X and Y. Compute the covariance of X and .pdf
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