The document summarizes the analysis and design of a truss bridge to support a car. It first calculates the external forces on the bridge from the weight of the car. It then analyzes the forces on each member of the truss using static equilibrium equations. It finds the maximum compression force is 7,544 N and acts on two members, while the minimum tension force is 1,886 N and acts on another member.

1. CAR BRIDGE DESIGNED BY MAJD KHALIL ALAA DWIKAT

2. TRUSSES

3. EXTERNAL FORCES FIRST STEP : WE SHOULD FIND THE EXTERNAL FORCES BY THE EQUATION OF STATIC EQUILIBRIUM: THESE FORCES ARE: 1- PIN A 2- ROLLER D 3- WEIGHT OF CAR

4. ∑ FX=0; AX=0; ∑ FY=0; YA+YD-9800=0; ∑ MA=0; 9800(6)-YA(9)=0 YA=6533.3 N YD=3266.7 N

5. 2-ANALYSIS THE FORCES ON EACH MEMBER BY STATIC EQUATION PIN A: ∑ FY=0; 6.5KN-AGSIN60=0; AG=7.5KN (COMPRESSION) ∑ FX=0;AB-AGCOS60 AB=3.7KN (TENSION)

6. PIN G: ∑ FY=0; AGSIN60-GBSIN60=0 GB=7.5KN (TENSION) ∑ FX=0; AGCOS60+GBCOS60 -GF=0 GF=7.5KN (COMPRESSION)

7. PIN B: ∑ FY=0; GBSIN60+FBIN60-9800=0; FB=3.7KN (TENSION) ∑ FX=0; BC-AB-GBCOS60 +FBCOS60=0; BC=5.6KN (TENSION)

8. THE MAXIMAM TENSION FORCE ON MEMBER AG=7544 N THE MAXIMAM COMPRESSION FORCE ON MEMBER GB & GF =7544 N MINIMAM TENSION FORCE ON MEMBER CD=1886 N