The document discusses a lap joint used to connect two metal plates of different thicknesses. A lap joint overlaps the ends of two members to connect them. The document provides an example of designing a single bolted lap joint between a 12mm thick plate and a 20mm thick plate to transmit a load of 70kN using M16 bolts. The solution calculates the shear capacity of the bolts and bearing strength of the thinner plate to determine that 3 bolts would be required to support the load.

1. BOLTED CONNECTION
LAP JOINT
Presented by
R. Ajith Kumar

2. • What is lap joint?
When the two members to
be connected together by overlapping then
the joint is called lap joint.
• Types
1. Single bolted lap joint
2. Double bolted lap joint

4. PROBLEMS
• Design a Lap joint between two plates of thickness 12mm and
20mm respectively. The joint has to transmit a factored load
of 70KN using M16 bolts of grade 4.6 and grade 410 plates?
Solution:
d= 16mm
do=dn= 16+2= 18
fub= 400 N/mm2
fup = 410 N/mm2
ynb= 1.25

5. e min = 1.7dn
P min= 2.5 d
t = 12mm
(thinner plate thickness)
a) Design Shear Capacity of bolt:
The bolts are in single shear since the top plate is only
12mm it is assumed that shear plate is through the threaded
portion and Nn=1 and Ns=0

6. Vdsb = Vnsb/ymb

7. b) Design bearing strength of thinner plate:

8. Now,
Bolt value = 28.97 KN ( least of above)
Therefore,
Required number of bolts = Factored load/ Bolt value
N = 70/28.97 = 2.41
Say, no of bolt need is 3

9. THANK YOU