Arsenic is implanted into a lightly doped p-type Si substrate at an e.pdf
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Arsenic is implanted into a lightly doped p-type Si substrate at an energy of 75keV. The dose is 1 times 10^14/cm^2. The Si substrate is tilted 7 degree with respect to the ion beam to make it appear amorphous. The implanted region is assumed to be rapidly annealed so that complete electrical activation is achieved. What is the peak electron concentration produced? Solution uploaded image.
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C++Write a function bool isLevel(int a, int n) which determines i.pdf
C++
Write a function bool isLevel(int *a, int n) which determines if the array a is a valid level-order
listing of a BBST.
Solution
If the level order is represented in the array with an index i, a node i\'s left child is 2i, right child
is 2i+1 and parent of i is i/2.
bool isLevel(int *a, int n){
int j=1; // flag variable
for (i=1;i.
According to Mendels Law of Segregation which of the following is s.pdf
According to Mendel\'s Law of Segregation which of the following is s true statement? Each
gamete receives both of the parent\'s alleles for the each gene. Alleles segregate into different
gametes with equal frequency. Allele frequencies (i.e., proportions) in gametes cannot be
predicted in advance. Dominant alleles segregate into gametes more frequently than recessive
alleles. Recessive alleles segregate into gametes more frequently than dominant alleles.
Solution
Allele frequencies (Le., proportions) in gametes cannot be predicted in advance..
A concerned mother brings her 2-year-old daughter to the clinic with.pdf
A concerned mother brings her 2-year-old daughter to the clinic with the complaint of fever,
irritability, and difficulty eating. Based upon what you have learned so far in class, what are
possible diagnoses and how would you differentiate between them?
Solution
In children the symptoms of epiglottitis include fever with chills difficulty swallowing refusing
to eat restlessness and irritability.
This disease can be diagnosed by observing X-rays and the wind pipe laryngoscopy.
The doctors day observed the swollen epiglottis by observing his throat.
Blood test also help observed infection ,other immunologic test also help for identifying the
antibodies to specific bacteria ore viruses.
Epiglottitis maybe misdiagnosed as strep throat. other misdiagnosis include infectious diseases
like diphtheria infectious mononucleosis, peritonsillar abscess.
An important misleading diagnosis is croup which occurs in younger children having viral
prodrome the children with croup has barking cough and rarely appears toxic they also it
experience sore throat, dyspnea and vomitings.
Epiglottis is very rare disease where as crop is very common epiglottis is caused by haemophilus
influenzae type b virus ,croup is caused by parainfluenza, rsv and enteror viruses ,epiglottis is
common in between the children 3 to 7 years where as crop is common between 3 months to 3
years. Fever is less in croup disease whereas fever > 39°c is observed in epiglottitis. Croup Is
benign where as epiglottitis is potentially critical.
Bacterial tracheitis may also mislead epiglottitis diagnosis..
A study compared 4 groups with 6 observations per group. An statisti.pdf
A study compared 4 groups with 6 observations per group. An statistic of 2.83 was reported. Fill
in the blanks. Give your answers to two decimal places. Considering the degrees of freedom, the
entries from Table E that correspond to this distribution are _Answer 1_ _Answer 2_.
Table E
TABLE E Chi-square distribution critical values Upper tail probability p df .25 .20 .15 .10 .05
.025 .02 .01 .005 .0025 .001 .0005 1 1.32 1.64 2.07 2.71 3.84 5.02 5.41 6.63 7.88 9.14 10.83
12.12 2 2.77 3.22 3.79 4.61 5.99 7.38 7.82 9.21 10.60 11.98 13.82 15.20 3 4.11 4.64 5.32 6.25
7.81 9.35 9.84 11.34 12.84 14.32 16.27 17.73 4 5.39 5.99 6.74 7.78 9.49 11.14 11.67 13.28
14.86 16.42 18.47 20.00 5 6.63 7.29 8.12 9.24 11.07 12.83 13.39 15.09 16.75 18.39 20.51 22.11
6 7.84 8.56 9.45 10.64 12.59 14.45 15.03 16.81 18.55 20.25 22.46 24.10 7 9.04 9.80 10.75 12.02
14.07 16.01 16.62 18.48 20.28 22.04 24.32 26.02 8 10.22 11.03 12.03 13.36 15.51 17.53 18.17
20.09 21.95 23.77 26.12 27.87 9 11.39 12.24 13.29 14.68 16.92 19.02 19.68 21.67 23.59 25.46
27.88 29.67 10 12.55 13.44 14.53 15.99 18.31 20.48 21.16 23.21 25.19 27.11 29.59 31.42 11
13.70 14.63 15.77 17.28 19.68 21.92 22.62 24.72 26.76 28.73 31.26 33.14 12 14.85 15.81 16.99
18.55 21.03 23.34 24.05 26.22 28.30 30.32 32.91 34.82 13 15.98 16.98 18.20 19.81 22.36 24.74
25.47 27.69 29.82 31.88 34.53 36.48 14 17.12 18.15 19.41 21.06 23.68 26.12 26.87 29.14 31.32
33.43 36.12 38.11 15 18.25 19.31 20.60 22.31 25.00 27.49 28.26 30.58 32.80 34.95 37.70 39.72
16 19.37 20.47 21.79 23.54 26.30 28.85 29.63 32.00 34.27 36.46 39.25 41.31 17 20.49 21.61
22.98 24.77 27.59 30.19 31.00 33.41 35.72 37.95 40.79 42.88 18 21.60 22.76 24.16 25.99 28.87
31.53 32.35 34.81 37.16 39.42 42.31 44.43 19 22.72 23.90 25.33 27.20 30.14 32.85 33.69 36.19
38.58 40.88 43.82 45.97 20 23.83 25.04 26.50 28.41 31.41 34.17 35.02 37.57 40.00 42.34 45.31
47.50 21 24.93 26.17 27.66 29.62 32.67 35.48 36.34 38.93 41.40 43.78 46.80 49.01 22 26.04
27.30 28.82 30.81 33.92 36.78 37.66 40.29 42.80 45.20 48.27 50.51 23 27.14 28.43 29.98 32.01
35.17 38.08 38.97 41.64 44.18 46.62 49.73 52.00 24 28.24 29.55 31.13 33.20 36.42 39.36 40.27
42.98 45.56 48.03 51.18 53.48 25 29.34 30.68 32.28 34.38 37.65 40.65 41.57 44.31 46.93 49.44
52.62 54.95 30 34.80 36.25 37.99 40.26 43.77 46.98 47.96 50.89 53.67 56.33 59.70 62.16 40
45.62 47.27 49.24 51.81 55.76 59.34 60.44 63.69 66.77 69.70 73.40 76.09 50 56.33 58.16 60.35
63.17 67.50 71.42 72.61 76.15 79.49 82.66 86.66 89.56 60 66.98 68.97 71.34 74.40 79.08 83.30
84.58 88.38 91.95 95.34 99.61 102.7 80 88.13 90.41 93.11 96.58 101.9 106.6 108.1 112.3 116.3
120.1 124.8 128.3 100 109.1 111.7 114.7 118.5 124.3 129.6 131.1 135.8 140.2 144.3 149.4
153.2
Solution.
Why is it important that chromosomes can cross over in Meiosis and n.pdf
Why is it important that chromosomes can cross over in Meiosis and not in Mitosis?
Solution
Crossing over results in genetic recombination. It is responsible for genetic diversity of the
population. Genetic recombination and natural selection are the driving force behind evolution.
Meiosis is called sex division, it is responsible for gamate formation. Crossing over occurs when
chiasma is formed and this random exchange of information leads to unique gametes formation
and genetic recombination to occur..
Write a one-page statement showing that you have A knowledge of cur.pdf
Write a one-page statement showing that you have \"A knowledge of current events and
contemporary issues (non-engineering related) and how it might benefit your engineering
career.\" Please discuss not only how you will benefit, but why you will benefit. Give examples
to illustrate your points
Solution
There are many critical roles of engineering in addressing the large-scale pressing challenges
being faced by the societies worldwide. Such large-scale major challenges include access to
affordable health care; tackling the coupled issues of energy, transportation and climate change;
providing more equitable access to information for our populations; clean drinking water; natural
and man-made disaster mitigation, environmental protection and natural resource management,
among legion others. In and of itself, mobilizing the engineering community to become more
efficient in delivering real products and services of benefit to society, especially in the
developing world, is a vitally important international responsibility. Engineering as a human
strive is also facing numerous additional challenges of its own, including attracting and holding
back broader cross-sections of our youth, particularly women; strengthening the educational
enterprise; forging more effective interdisciplinary alliances with the natural and social sciences
and the arts; enhancing our focus on innovation, entrepreneurship and job creation, and;
promoting increased public awareness and support for the engineering enterprise..
Which of the following is the purpose of valves in the venous circul.pdf
Which of the following is the purpose of valves in the venous circulatory system? A. Promoting
movement of oxygenated blood toward the heart B. Facilitating stasis of blood in the veins C.
Propelling blood through the vena cava D. Preventing backward flow of deoxygenated blood.
Solution
Answer:
D. Preventing backward flow of deoxygenated blood.
The main function of venous valves is one-way direction of blood. They have to assure the clear
blood flow from the surface to the depth or from the peripheral tissue towards towards the heart..
When society makes a particular good or service illegal is it making.pdf
When society makes a particular good or service illegal is it making any type of class-based
sociological statement?
Solution
Certain goods or services like drugs are harmful to socity or services like dance bars in mumbai
and prostitution are bad for society so they have been made illegal in india .it is for socitys good
and to some extent class based sociological statement.
Mihir Manek.
Recommended
C++Write a function bool isLevel(int a, int n) which determines i.pdf
C++
Write a function bool isLevel(int *a, int n) which determines if the array a is a valid level-order
listing of a BBST.
Solution
If the level order is represented in the array with an index i, a node i\'s left child is 2i, right child
is 2i+1 and parent of i is i/2.
bool isLevel(int *a, int n){
int j=1; // flag variable
for (i=1;i.
According to Mendels Law of Segregation which of the following is s.pdf
According to Mendel\'s Law of Segregation which of the following is s true statement? Each
gamete receives both of the parent\'s alleles for the each gene. Alleles segregate into different
gametes with equal frequency. Allele frequencies (i.e., proportions) in gametes cannot be
predicted in advance. Dominant alleles segregate into gametes more frequently than recessive
alleles. Recessive alleles segregate into gametes more frequently than dominant alleles.
Solution
Allele frequencies (Le., proportions) in gametes cannot be predicted in advance..
A concerned mother brings her 2-year-old daughter to the clinic with.pdf
A concerned mother brings her 2-year-old daughter to the clinic with the complaint of fever,
irritability, and difficulty eating. Based upon what you have learned so far in class, what are
possible diagnoses and how would you differentiate between them?
Solution
In children the symptoms of epiglottitis include fever with chills difficulty swallowing refusing
to eat restlessness and irritability.
This disease can be diagnosed by observing X-rays and the wind pipe laryngoscopy.
The doctors day observed the swollen epiglottis by observing his throat.
Blood test also help observed infection ,other immunologic test also help for identifying the
antibodies to specific bacteria ore viruses.
Epiglottitis maybe misdiagnosed as strep throat. other misdiagnosis include infectious diseases
like diphtheria infectious mononucleosis, peritonsillar abscess.
An important misleading diagnosis is croup which occurs in younger children having viral
prodrome the children with croup has barking cough and rarely appears toxic they also it
experience sore throat, dyspnea and vomitings.
Epiglottis is very rare disease where as crop is very common epiglottis is caused by haemophilus
influenzae type b virus ,croup is caused by parainfluenza, rsv and enteror viruses ,epiglottis is
common in between the children 3 to 7 years where as crop is common between 3 months to 3
years. Fever is less in croup disease whereas fever > 39°c is observed in epiglottitis. Croup Is
benign where as epiglottitis is potentially critical.
Bacterial tracheitis may also mislead epiglottitis diagnosis..
A study compared 4 groups with 6 observations per group. An statisti.pdf
A study compared 4 groups with 6 observations per group. An statistic of 2.83 was reported. Fill
in the blanks. Give your answers to two decimal places. Considering the degrees of freedom, the
entries from Table E that correspond to this distribution are _Answer 1_ _Answer 2_.
Table E
TABLE E Chi-square distribution critical values Upper tail probability p df .25 .20 .15 .10 .05
.025 .02 .01 .005 .0025 .001 .0005 1 1.32 1.64 2.07 2.71 3.84 5.02 5.41 6.63 7.88 9.14 10.83
12.12 2 2.77 3.22 3.79 4.61 5.99 7.38 7.82 9.21 10.60 11.98 13.82 15.20 3 4.11 4.64 5.32 6.25
7.81 9.35 9.84 11.34 12.84 14.32 16.27 17.73 4 5.39 5.99 6.74 7.78 9.49 11.14 11.67 13.28
14.86 16.42 18.47 20.00 5 6.63 7.29 8.12 9.24 11.07 12.83 13.39 15.09 16.75 18.39 20.51 22.11
6 7.84 8.56 9.45 10.64 12.59 14.45 15.03 16.81 18.55 20.25 22.46 24.10 7 9.04 9.80 10.75 12.02
14.07 16.01 16.62 18.48 20.28 22.04 24.32 26.02 8 10.22 11.03 12.03 13.36 15.51 17.53 18.17
20.09 21.95 23.77 26.12 27.87 9 11.39 12.24 13.29 14.68 16.92 19.02 19.68 21.67 23.59 25.46
27.88 29.67 10 12.55 13.44 14.53 15.99 18.31 20.48 21.16 23.21 25.19 27.11 29.59 31.42 11
13.70 14.63 15.77 17.28 19.68 21.92 22.62 24.72 26.76 28.73 31.26 33.14 12 14.85 15.81 16.99
18.55 21.03 23.34 24.05 26.22 28.30 30.32 32.91 34.82 13 15.98 16.98 18.20 19.81 22.36 24.74
25.47 27.69 29.82 31.88 34.53 36.48 14 17.12 18.15 19.41 21.06 23.68 26.12 26.87 29.14 31.32
33.43 36.12 38.11 15 18.25 19.31 20.60 22.31 25.00 27.49 28.26 30.58 32.80 34.95 37.70 39.72
16 19.37 20.47 21.79 23.54 26.30 28.85 29.63 32.00 34.27 36.46 39.25 41.31 17 20.49 21.61
22.98 24.77 27.59 30.19 31.00 33.41 35.72 37.95 40.79 42.88 18 21.60 22.76 24.16 25.99 28.87
31.53 32.35 34.81 37.16 39.42 42.31 44.43 19 22.72 23.90 25.33 27.20 30.14 32.85 33.69 36.19
38.58 40.88 43.82 45.97 20 23.83 25.04 26.50 28.41 31.41 34.17 35.02 37.57 40.00 42.34 45.31
47.50 21 24.93 26.17 27.66 29.62 32.67 35.48 36.34 38.93 41.40 43.78 46.80 49.01 22 26.04
27.30 28.82 30.81 33.92 36.78 37.66 40.29 42.80 45.20 48.27 50.51 23 27.14 28.43 29.98 32.01
35.17 38.08 38.97 41.64 44.18 46.62 49.73 52.00 24 28.24 29.55 31.13 33.20 36.42 39.36 40.27
42.98 45.56 48.03 51.18 53.48 25 29.34 30.68 32.28 34.38 37.65 40.65 41.57 44.31 46.93 49.44
52.62 54.95 30 34.80 36.25 37.99 40.26 43.77 46.98 47.96 50.89 53.67 56.33 59.70 62.16 40
45.62 47.27 49.24 51.81 55.76 59.34 60.44 63.69 66.77 69.70 73.40 76.09 50 56.33 58.16 60.35
63.17 67.50 71.42 72.61 76.15 79.49 82.66 86.66 89.56 60 66.98 68.97 71.34 74.40 79.08 83.30
84.58 88.38 91.95 95.34 99.61 102.7 80 88.13 90.41 93.11 96.58 101.9 106.6 108.1 112.3 116.3
120.1 124.8 128.3 100 109.1 111.7 114.7 118.5 124.3 129.6 131.1 135.8 140.2 144.3 149.4
153.2
Solution.
Why is it important that chromosomes can cross over in Meiosis and n.pdf
Why is it important that chromosomes can cross over in Meiosis and not in Mitosis?
Solution
Crossing over results in genetic recombination. It is responsible for genetic diversity of the
population. Genetic recombination and natural selection are the driving force behind evolution.
Meiosis is called sex division, it is responsible for gamate formation. Crossing over occurs when
chiasma is formed and this random exchange of information leads to unique gametes formation
and genetic recombination to occur..
Write a one-page statement showing that you have A knowledge of cur.pdf
Write a one-page statement showing that you have \"A knowledge of current events and
contemporary issues (non-engineering related) and how it might benefit your engineering
career.\" Please discuss not only how you will benefit, but why you will benefit. Give examples
to illustrate your points
Solution
There are many critical roles of engineering in addressing the large-scale pressing challenges
being faced by the societies worldwide. Such large-scale major challenges include access to
affordable health care; tackling the coupled issues of energy, transportation and climate change;
providing more equitable access to information for our populations; clean drinking water; natural
and man-made disaster mitigation, environmental protection and natural resource management,
among legion others. In and of itself, mobilizing the engineering community to become more
efficient in delivering real products and services of benefit to society, especially in the
developing world, is a vitally important international responsibility. Engineering as a human
strive is also facing numerous additional challenges of its own, including attracting and holding
back broader cross-sections of our youth, particularly women; strengthening the educational
enterprise; forging more effective interdisciplinary alliances with the natural and social sciences
and the arts; enhancing our focus on innovation, entrepreneurship and job creation, and;
promoting increased public awareness and support for the engineering enterprise..
Which of the following is the purpose of valves in the venous circul.pdf
Which of the following is the purpose of valves in the venous circulatory system? A. Promoting
movement of oxygenated blood toward the heart B. Facilitating stasis of blood in the veins C.
Propelling blood through the vena cava D. Preventing backward flow of deoxygenated blood.
Solution
Answer:
D. Preventing backward flow of deoxygenated blood.
The main function of venous valves is one-way direction of blood. They have to assure the clear
blood flow from the surface to the depth or from the peripheral tissue towards towards the heart..
When society makes a particular good or service illegal is it making.pdf
When society makes a particular good or service illegal is it making any type of class-based
sociological statement?
Solution
Certain goods or services like drugs are harmful to socity or services like dance bars in mumbai
and prostitution are bad for society so they have been made illegal in india .it is for socitys good
and to some extent class based sociological statement.
Mihir Manek.
Which physical topology has all systems connecting to a central conn.pdf
Which physical topology has all systems connecting to a central connection device?
A. Bus
B. Ring
C. Star
D. Mesh
Solution
C is correct. A star topology connects all devices to a central point.
A, B, and D are incorrect. A is incorrect because all devices are connected to a single wire. B is
incorrect because it connects all devices in a circle, with one device connected directly to the
next. D is incorrect because it has all devices connected directly to all other devices..
What is the role of RFID chips in logistics What is the role o.pdf
What is the role of RFID chips in logistics?
What is the role of RFID chips in logistics?
Solution
Radio-frequency identification (RFID) uses electromagnetic fields to automatically identify and
track tags attached to objects. The tags contain electronically stored information. Passive tags
collect energy from a nearby RFID reader\'s interrogating radio waves. Active tags have a local
power source such as a battery and may operate at hundreds of meters from the RFID reader.
Unlike a barcode, the tag need not be within the line of sight of the reader, so it may be
embedded in the tracked object. RFID is one method for Automatic Identification and Data
Capture (AIDC).[1]
The emergence of RFID (Radio Frequency Identification) technology has been greatly increased
efficiency in the production process management, material flow management, logistics and
transport, retail and distribution and other fields of the national economy industries, including
electronic information industry. RFID may eventually replace the ubiquitous bar code in the
future and become the main technology in logistics and supply chain management field
RFID in Logistics Management
Logistics management involves the efficient control of some or all of the supply chain functions,
including:
– Product research and development
– Sourcing and purchasing
– Manufacturing
– Production planning
– Sales, marketing, and forecasting
– Inventory management
– Cross-docking and flow-through
– Customer service
– Transportation
– Freight payment
– Information reporting
Using RFID logistics tracking has helped many organizations solve the main challenge at every
node in their supply chains: the lack of visibility of logistics data. RFID technology is a powerful
solution that improves asset visibility, data quality, inventory management, and interoperability
in an end-to-end integrated supply chain. In fact, the U.S. Department of Defense (DoD) issued a
mandate in 2005 that requires all of their suppliers to use RFID in marking any items that are
sold to the DoD. The need for this mandate arose from decades of logistical challenges faced by
the military with regard to the supply chain.
RFID has proven to alleviate various logistical problems associated with the DoD supply chain.
RFID technology, in combination with the Internet, allows the DoD to disseminate accurate,
real-time data to commanders worldwide so that assets can be easily located and used according
to the Department’s highest priorities..
tut all words or phases will be inca. cach likathawnb tha bat wer.pdf
tut all words or phases will be inca. cach likathawnb tha bat werd or parase selouief, Sea
Eucaryine cells are biggey and nicee si eucary ulic eells, ay rlsmnuinn, an Another organelle rare
iin i a12 or s, Irweund e-erer lly allouurwte cells isthe which generates the
eralesthecheninalenAL lly-allouarylicerntraethedresinr nanttic eds and ay ihe plasma memmanc
irvrm Clicaryotic cell, and the ecil Ln contrast, the remove all of its membrane-enclosed orge
photosynthesis. If we were to strip iway ibe pigs, we at\'Nuo type of orga found celly In Ehe
cells her plants and signe, and many leng, fine liaisi ents of protein that are we would be left with
the responsible for cell shape and structure and th which cultsins manypr re and thereby form the
cell\'s chloroplast nucleus chromosome reticulum niosomes mitochondrion endoplasmic reti
cytoskeleton mbrane of theen
Solution
Eukaryotic cells are bigger and … than prokaryotic cells. By definition all eukaryotic cells have
a nucleus, usually the most prominent organelle. Another organelle found essentially in all
eukaryotic cells is the mitochondria, which generates the chemical energy for the cell. In contrast
the chloroplast is a type of organelle found only in the cells of plants and algae and performs
photosynthesis. If we were to strip away the plasma membrane from a eukaryotic cell and all of
its membrane enclosed organelles we would be left with the cytosol, which contains many lone
fine filaments of proteins that are responsible for cell shape and structure and thereby form the
cell`s cytoskeleton..
Theories of law enforcementSubjectDiscuss the positive and negati.pdf
Theories of law enforcement/Subject
Discuss the positive and negative effects of community policing. Identify some community
policing programs and explain their effectiveness. What is the primary focus of community
policing? Can a community policing program be effectively managed from a central agency?
Some officers disagree with community policing because of the feeling that spending time with
the good citizens is a waste of time and should be left to the politicians. What do you think
Solution
Discuss the positive and negative effects of community policing. Identify some community
policing programs and explain their effectiveness. What is the primary focus of community
policing? Can a community policing program be effectively managed from a central agency?
Some officers disagree with community policing because of the feeling that spending time with
the good citizens is a waste of time and should be left to the politicians. What do you think
--------------------------------------------------------------------------------------------------------------------
--------------------------------------------------
Community policing is a philosophy that promotes organizational strategies, which support the
systematic use of partnerships and problem-solving techniques, to proactively address the
immediate conditions that give rise to public safety issues such as crime, social disorder, and fear
of crime.
Community policing is a philosophy of full service personalized policing, where the same officer
patrols and works in the same area on a permanent basis, from a decentralized place, working in
a proactive partnership with citizens to identify and solve problems.
Positive effects of Community policing :
Prevent crime
Address /Reduce fear of crime
Elicit the citizen development
Creative problem solving
Create active cooperation with Employee & Resident
Negative effect of community pricing :
The effects to examine is liability lawsuits
Risk taking leads to more litigation\'s and community-oriented policing involves risk taking due
to the modern management that is involved in community oriented policing
Nature & Extent of civil liability
Community pricing is dependent on community .Each community is different.
Primary focus of community policing:
The main focus of community policing is to solve the problems of society.For police
departments its not possible to control each & every thing , so they take some help from society .
The problems where arises these teams are helping to solve the problems.
Community policing programs :
DRUG ABUSE RESISTANCE EDUCATION
Every 15 Minutes\" is an award-winning, two-day program designed to discourage young people
from drinking and driving.
McGruff the Crime Dog makes appearances at events which emphasize child safety concerns
The Community Opportunities Program For Youth (C.O.P.Y. Kids) was created to improve the
relationship between Spokane youths and police officers, as well as engender a sense of
community responsib.
What does a blower door doSolutionA blower door is a device w.pdf
What does a blower door do?
Solution
A blower door is a device which is used to measure the air tightness of buildings. It is also used
to find out the air flow in between the building zones, to test duct network air tightness and aslo
to physically locate air leakage sites n the building envelope.There are 3 primary components of
blower door. They are:
1)calibrated variable speed fan
2)pressure measuring instrument
3)mounting system.
The US population in millions is P(t) today, where time t is measured.pdf
The US population in millions is P(t) today, where time t is measured in years. For each
statement, choose one of the expression A-H that represents it.
Solution
P(t) is in millions
1) The population after 100,000 people have emigrated
==> Population is decreased by 100,000 = 0.1 million people
==> P(t) - 0.1 (Option D)
2) Ten percent of the population we have today
==> (10/100) P(t) = 0.1 P(t) (Option G)
3) Todays population plus 10 million immigrants = P(t) + 10 (Option H)
4) The population 10 years before today = P(t - 10) [ Option A].
Please make a comment for all the codesOr explain this pro.pdf
Please make a comment for all the codes
Or explain this program code!!
//Date.h
#ifndef DateFormat
#define DateFormat
#include
using std::string;
class Date {
public:
Date();
Date( int, int );
Date( int, int, int );
Date( string, int, int );
void setDay11(int);
void setMonth11( int );
void print11() const;
void printDDDYYYY11( ) const;
void printMMDDYY11( ) const;
void printMonthDDYYYY11( ) const;
~Date();
private:
int month1;
int day1;
int year1;
int checkDay(int)const;
int daysInMonth(int)const;
bool isLeapYear()const;
int convertDDToDDD()const;
void setMMDDFromDDD(int);
string convertMMToMonth(int)const;
void setMMFromMonth(string);
int convertYYYYToYY()const;
void setYYYYFromYY(int);
};
#endif
//Main.cpp
include
using std::cout;
using std::endl;
#include \"Date.h\"
int main()
{
Date date1( 252,1999 );
Date date2( 2,25,04 );
Date date3( \"September\", 1, 2000 );
Date date4;
date1.print11();
date2.print11();
date3.print11();
date4.print11();
cout << \'\ \';
date1.printDDDYYYY11();
date2.printDDDYYYY11();
date3.printDDDYYYY11();
date4.printDDDYYYY11();
cout << \'\ \';
date1.printMMDDYY11();
date2.printMMDDYY11();
date3.printMMDDYY11();
date4.printMMDDYY11();
cout << endl;
date1.printMonthDDYYYY11();
date2.printMonthDDYYYY11();
date3.printMonthDDYYYY11();
date4.printMonthDDYYYY11();
return 0;
}
//Date.cpp
#include
using std::cout;
using std::endl;
#include
using std::setw;
using std::setfill;
include
using std::time;
using std::localtime;
using std::tm;
using std::time_t;
#include \"Date.h\"
Date::Date()
{
struct tm *ptr;
time_t t1 = time( 0 );
ptr = localtime( &t1 );
day1 = ptr->tm_mday;
month1 = 1 + ptr->tm_mon;
year1 = ptr->tm_year + 1900;
}
Date::Date( int ddd1, int yyyy1 )
{
year1=yyyy1;
setMMDDFromDDD(ddd1);
}
Date::Date( int mm1, int dd1, int yy1 )
{
setYYYYFromYY( yy1 );
mm1 );
setDay11( dd1 );
}
Date::Date(string monthName2,int dd1,int yyyy1)
{
setMMFromMonth(monthName2);
setDay11(dd1);
year1=yyyy1;
}
void Date::setDay11( int d1 )
{
day1 = checkDay(d1); }
void Date::setMonth11( int m1 )
{
if(m1>0&& m1<=12)
month1=m1;
else
{
month1=1;
cout<<\"invalid month(\"<0 && testDay<=daysInMonth(month1))
return testDay;
if(month1==2 && testDay==29 && isLeapYear())
return testDay;
cout<<\"invalid day(\"<=2000?year1-2000:year1-1900);
}
void Date::setYYYYFromYY(int yy)
{
year1=(yy<7?yy+2000:yy+1900);
}
Please make a comment for all the codes
Or explain this program code!!
//Date.h
#ifndef DateFormat
#define DateFormat
#include
using std::string;
class Date {
public:
Date();
Date( int, int );
Date( int, int, int );
Date( string, int, int );
void setDay11(int);
void setMonth11( int );
void print11() const;
void printDDDYYYY11( ) const;
void printMMDDYY11( ) const;
void printMonthDDYYYY11( ) const;
~Date();
private:
int month1;
int day1;
int year1;
int checkDay(int)const;
int daysInMonth(int)const;
bool isLeapYear()const;
int convertDDToDDD()const;
void setMMDDFromDDD(int);
string convertMMToMonth(int)const;
void setMMFromMonth(string);
int convertYYY.
The purpose of a database is to. Select one store lists of data invo.pdf
The purpose of a database is to. Select one: store lists of data involving multiple themes test and
troubleshoot newly installed software design the source code for computer programs describe
and build computer architectures The first step in protecting oneself from data breaches is. Select
one: securing credit and debit card details learning the technologies used for these activities
understanding how they happen installing necessary software to protect from possible breaches
Solution
Question 3:
The purpose of a Database is to
Answer: a. store list of data involoving multiple themes
Question 4:
First step in protecting oneself from a data breaches is
Answer: c. Understanding how they happen.
Stadents version-p. 2 0. (Table 3) item(s) at the deli bar causing .pdf
Stadent\'s version-p. 2 0. (Table 3) item(s) at the deli bar causing the outbreak, investigators
reanal and controls who ate at the deli bar during March 9-10. abled Gastroenteritis at a
University in Texas Student\'s version-p. 17 PART VI-DESIGNING AN EPIDEMIOLOGIC
STUDY TO REFINE THE HYPOTHESIS (STUDY #2) By March 13, one hundred and twenty-
five persons with vomiting or diarthea had been reported to TDH. TDH invited staff fiom the
Centers for Disease Control and Prevention (CDC) to participate in the ongoing investigation.
CDC staff suggested submission of fresh stool specimens from ill students for viral studies
including reverse transcriptase-polymerase chain reaction (RT-PCR). TDH and CDC staff
decided to undertake an unmatched case-control study to further explore the source of the
outbreak. Question 18 Who should be enrolled as subjects for this study?
Solution
persons with vomiting or diarrea that is the enroolled as subjects for this study.
A major hurricane is a hurricane with wind speeds of 111 miles per h.pdf
A major hurricane is a hurricane with wind speeds of 111 miles per hour or greater. During the
20th century, the mean number of major hurricanes to strike the U.S. mainland per year was
about 0.66. Find the probability that in a given year a) exactly one major hurricane will strike the
U.S. mainland, b) at most one major hurricane will strike the U.S. mainland, and c) more than
one major hurricane will strike the U.S. mainland
Solution.
1.In which case(s) is there constructive interference for two ligh.pdf
1.
In which case(s) is there constructive interference for two light waves meeting at the same point
at a given instant? (Select all that apply.)
A) Both waves are at their minimum
B) One wave is at its maximum, one wave is at zero.
C) Both waves are at their maximum
D) One wave is at its minimum, one wave is at zero.
E) One wave is at its maximum, the other is at its minimum
2.
In which situation(s) is there destructive interference when two waves intersect at one point? (At
an instant of time.)
A) Both waves are at a maximum
B) One wave is at a maximum, the other is at zero
C) One wave is at a minimum; the other is at a maximum
D) Both waves are at a minimum
E) One wave is at a minimum, the other is at zero
3.
When light goes through a very narrow slit, it spreads out from that slit in all directions beyond
the slit due to:
A) diffraction
B) dispersion
C) interference
D) refraction
E) reflection
4.
Light encounters two very narrow slits closely spaced together. Constructive interference of light
coming from these two slits will occur when
A) the wavelength of the light equals the width of the slits
B) the wavelength of the light equals the separation of the slits
C) the light from one slit has to travel a distance that is longer than that traveled by the light
from the other slit equal to half the wavelength of the light
D) light from one slit at its crest encounters light from the other slit at its trough
E) the light from one slit has to travel a distance that is longer than that traveled by the light
from the other slit equal to twice the wavelength of the light
5.
Equations 17.7 and 17.8 depend on which assumption?
A) The screen is very close to the slits
B) the slits are much wider than the wavelength of the light
C) small angles (in radians)
D) large angles (in radians)
6.
You shine both red and blue light through a double slit. What can you say about their
interference patterns?
A) The red bright fringes will be closer together than will be the blue bright fringes.
B) The red and blue bright fringes will be the same distance apart from each other.
C) The blue bright fringes will be closer together than will be the red bright fringes.
7.
You compare a double-slit interference pattern with the interference pattern due to a diffraction
grating of the same spacing as that of the double-slit. The most noticeable difference would be
that:
A) The peaks of the diffraction grating are much broader than that for the double-slit
B) The peaks of the diffraction grating are much farther apart than for the double-slit
C) The peaks of the diffraction grating are much sharper than that for the double-slit
D) The peaks of the diffraction grating are much closer together than for the double-slit
E) The center point is a maximum, not a minimum
F) The center point is a minimum, not a maximum
Solution
(1).Both waves are at their maximum
(2).One wave is at a minimum; the other is at a maximum
(3).diffraction
(4).the light from one slit has to travel a dis.
List and describe three examples of secondary sexual characteristics.pdf
List and describe three examples of secondary sexual characteristics each for males and females.
Solution
Secondary sex characteristics are features that appear at sexual maturity in animals and during
puberty in humans, Secondary sex characteristics are Traits that distinguish the biological sexes
of a species, but are not directly part of the reproductive system.
Examples of secondary sex characteristics in humans include shorter stature and wider pelvis,
breast development, and more fat in the thighs and buttocks in women and broader shoulders,
greater muscle mass, more facial and other body hair, and “male pattern” baldness in men.
Male secondary sexual characteristics of hair:
The pubic regions is usually the first to develop hair
Facial hair begins at the corner of the mouth and spreads to the midline - followed by the rest of
the face
Body hair develops long before facial hair growth is complete (arm pit, legs, arms, buttocks,
back)
Male secondary sexual characteristics of vocal changes:
Rapid growth of the larynx - larger and stronger
The thyroid cartilage increases in dimension creating the Adam\'s apple
Vocal cords lengthen and thicken.
Male secondary sexual characteristics of the body:
Increase in body size, weight and strength (musculature)
Correlated to increase in testosterone levels
Female secondary sexual characteristics of hair:
The pubic regions is usually the first to develop hair
Body hair develops slightly later (arm pit, legs, arms)
female secondary sexual characteristics of the pelvis:
Broadens and changes from a narrow funnel-like outlet, to a broad oval outlet, flaring at the hip
Fat cells increase in number around the buttocks and thighs
Female secondary sexual characteristics of the breasts:
Tanner Stages
Tanner I
no glandular tissue, typically age 10 and younger
Tanner II
Breast bud forms, with small area of surrounding glandular tissue, 10-11.5
Tanner III
breast begins to become more elevated, and extends beyond the borders of the areola, 11.5-13
Tanner IV
increased breast size and elevation, 13-15
Tanner V
breast reaches final adult size, 15+.
Let X1, X2,... be independent, identically distributed random variab.pdf
Let X1, X2,... be independent, identically distributed random variables with E[X] = 2 and
var(X)=9, and let Yi = Xi/2i . We also define Tn and An to be the sum and the sample mean,
respectively, of the random variables Y1,...,Yn.
(a) Evaluate the mean and variance of Yn, Tn, and An.
(b) Does Yn converge in probability? If so, to what value?
(c) Does Tn converge in probability? If so, to what value?
(d) Does An converge in probability? If so, to what value?
Solution.
In SoS development process, explain why it is important that system s.pdf
In SoS development process, explain why it is important that system selection and architecture
design should be concurrent activities and why there should be close links between them.
Solution
The SoS development process play an important role in large and complex entities in the
application domain and organization essential requirements for development strategies using
System selection and Architecture Design.
Architecture design is same as System selection. An entire architecture design is SoS
development stage which depends upon various parameters using interface and integration
development process exists in application system..
Go onto the APOD website (httpapod.nasa.govapod) and look in th.pdf
Go onto the APOD website (http://apod.nasa.gov/apod/) and look in the archive (or search) for a
cool looking galaxy or of the Milky Way. Post the image to this forum as well as a link to the
APOD picture. Share your picture with the rest of the class. From the description, describe what
kind of galaxy it is and anything interesting about it. Use your own words, no need to simply re-
type what is already written there. Relate this particular galaxy back to something you’ve learned
in this class about the diversity of galaxy types and why there is such diversity,
Solution
link: http://apod.nasa.gov/apod/
Want to take a fast trip to the edge of the Solar System? Consider a ride on a Heliopause
Electrostatic Rapid Transit System (HERTS). The concept is currently being tested and it might
take only 10 to 15 years to make the trip of over 100 Astronomical Units (15 billion kilometers).
That\'s fast compared to the 35 years it took Voyager 1, presently humanity\'s most distant
spacecraft, to approach the heliopause or outer boundary of the influence of the solar wind.
HERTS would use an advanced electric solar sail that works by extending multiple, 20 kilometer
or so long, 1 millimeter thin, positively charged wires from a rotating spacecraft. The
electrostatic force generated repels fast moving solar wind protons to create thrust. Compared to
a reflective solar light sail, another propellantless deep space propulsion system, the electric solar
wind sail could continue to accelerate at greater distances from the Sun, still developing thrust as
it cruised toward the outer planets..
give an examples of a decisions made under uncertainty give a.pdf
give an examples of a decisions made under uncertainty
give an examples of a decisions made under uncertainty
Solution
Let\'s take am example of floods. During floods, a lot of panic is caused and there\'s an
environment of uncertainty among the victims which leads to uncertain decision making. Some
people flee from home and take only their important documaents with them while stay at the
higher ground and see whether the flood worsens or not and the decide their next approach..
Explain the role of the loop of Henlé in the formation of urine and .pdf
Explain the role of the loop of Henlé in the formation of urine and how this is achieved
Solution
The renal cortex and renal medulla contain several nephrons that carryout the filtration of the
fluids and remove the wastes in the form of urine. The nephrons contain their renal corpuscles in
the cortex. The cortical nephrons consist of loop of Henle in the renal medulla near the junction
along with the renal cortex, while the loop of Henle of juxta-medullary nephrons is located in the
renal medulla. The cortical nephrons vary because some are superficial cortical nephrons and
some are midcortical nephrons, depending on location of renal corpuscle in the cortex.
The nephron loop is otherwise called as loop of Henle or loop of Hundle. It is U – shaped tube
extends from the proximal convoluted tube. The nephron loop consists of ascending and
descending limbs. The ascending limb is found in the renal cortex extends from proximal
convoluted tubule PCT into the renal medulla. The descending limb from renal medulla then
passes into the renal cortex and empties the content of distal convoluted tubule (DCT). The
nephron loop also performs the function of reabsorption of water and ions across the
concentration gradient. It has the primary function of concentrating the salts in the interstitium.
The proximal convoluted tubule (PCT) is divided into convoluted and straight parts of the
nephron. The PCT carries out the reabsorption of water, organic substances and some ions from
the original filtrate. The filtrate absorbs the water and solutes in PCT through the peritubular
capillaries. The organic solutes like glucose and amino acids are absorbed at PCT.
The distal convoluted tubule (DCT) carries out the reabsorption of water and sodium ions and
secretion under hormone stimulation. The distal convoluted tubule is different in structure and
function when compared to proximal convoluted tubule. Cells lining the tubule contain several
mitochondria to produce enough energy (ATP) for active transport of solutes.
The transport of the ions in the DCT is mediated by the activity of the endocrine system. The
DCT reabsorbs more calcium and secretes more phosphate in the presence of parathyroid
hormone. In the presence of aldosterone, more sodium is reabsorbed and potassium is secreted.
The atrial natriuretic peptide (ANP) stimulates the DCT to secrete more sodium. The DCT also
secretes hydronium and ammonium ions to regulate pH of the blood.
The collecting duct collects the tubular fluid across the osmotic gradient in the renal medulla.
Each collecting duct arises from the distal convoluted tubule and the filtrate is delivered to
collecting duct at the connecting tubule. The collecting duct starts in the renal cortex and extends
into the renal medulla. The urine is passed into collecting ducts by the medullary interstitium.
The urine passed into the collecting duct contains high sodium concentration because of the
counter current multiplier system in the loop of Hen.
Extend your work on the OCC logo to add shapes that curve1 the blue.pdf
Extend your work on the OCC logo to add shapes that \'curve1 the blue Cs into looking
something more like the actual logo:
Solution
import java.awt.Color;
import java.util.Comparator;
/**
* a straightforward red-black tree category.
*/
public category RedBlackTree extends BinarySearchTree Associate in Nursing empty
RedBlackTree which will solely settle for Comparables as
* items.
*/
public RedBlackTree()
/**
* Constructs Associate in Nursing empty RedBlackTree that orders its things in keeping with
the
* given comparator.
*/
public RedBlackTree(Comparator c)
/**
* The nodes during a red-black tree store a color beside the particular information
* within the node.
*/
category Node extends LinkedBinaryTreeNode
}
/**
* Adds one information item to the tree. If there\'s already Associate in Nursing item within the
* tree that compares up to the item being inserted, it\'s \"overwritten\"
* by the new item. Overrides BinarySearchTree.add as a result of the tree must
* be adjusted when insertion.
*/
public void add(Object data)
BinaryTreeNode n = root;
whereas (true) else if (comparisonResult < 0)
n = n.getLeft();
} else zero
if (n.getRight() == null)
n = n.getRight();
}
}
}
/**
* Removes the node containing the given price. will nothing if there\'s no
* such node.
*/
public void remove(Object data) else if (node.getLeft() != null && node.getRight() != null) 2
kids, Copy forerunner information in.
BinaryTreeNode forerunner = predecessor(node);
node.setData(predecessor.getData());
node = (Node) predecessor;
}
// At this time node has zero or one kid
Node pullUp = leftOf(node) == null ? rightOf(node) : leftOf(node);
if (pullUp != null) regulate if pullUp could be a double black.
if (node == root) else if (node.getParent().getLeft() == node) else
if (isBlack(node))
} else if (node == root) to drag up once deleting a root means that we have a tendency to empty
the tree
setRoot(null);
} else lookout
if (isBlack(node))
node.removeFromParent();
}
}
/**
* Classic formula for fixing up a tree when inserting a node.
*/
personal void adjustAfterInsertion(Node n) issues, if they exist
if (n != null && n != root && isRed(parentOf(n))) to ascertain if additional work
// needed
if (isRed(siblingOf(parentOf(n))))
// Step 2b: reconstitute for a parent United Nations agency is that the left kid of the
// forebear. this may need one right rotation if n is
// also
// a left kid, or a left-right rotation otherwise.
else if (parentOf(n) == leftOf(grandparentOf(n)))
setColor(parentOf(n), Color.black);
setColor(grandparentOf(n), Color.red);
rotateRight(grandparentOf(n));
}
// Step 2c: reconstitute for a parent United Nations agency is that the right kid of the
// forebear. this may need one left rotation if n is
// also
// a right kid, or a right-left rotation otherwise.
else if (parentOf(n) == rightOf(grandparentOf(n)))
setColor(parentOf(n), Color.black);
setColor(grandparentOf(n), Color.red);
rotateLeft(grandparentOf(n));
}
}
// Step 3: Color the foundation black
setColo.
Distinguish between a micelle, a bilayer, and a liposome. What are t.pdf
Distinguish between a micelle, a bilayer, and a liposome. What are the forces that maintain these
structures?
Solution
Liposomes are composed of a lipid bilayer separating an aqueous internal compartment from the
bulk aqueous phase.
Micelles are closed lipid monolayers with a fatty acid core and polar surface, or polar core with
fatty acids on the surface (inverted micelle).
A lipid bilayer is also termed as a bimolecular sheet in which the hydrophobic tails of each
individual plane interact with one another, constituting a hydrophobic core which acts as a
permeability barrier.
Micelle is a smaller structure, generally less than 20 nm (200 Å) in diameter. But a bilayer sheet
can be of larger dimensions, e.g. a millimeter (106 nm or 107 Å).
Vander wall forces, electrostatic and hydrogen-bonding attractions between the polar head
groups and water molecules maintain the structures ..
Describe how a bacterium with peritrichous flagella moves. How does .pdf
Describe how a bacterium with peritrichous flagella moves. How does this allow cells to move
up a gradient of a an attractant or down the gradient of a repellent?
Solution
The flagella is present in bacteria. They can take 100\'s of rotations. By taking these rotations
they can move freely. If a bacterium has a peritrichous arrangement of flagella, such as
Escherichia coli, Salmonella, Proteus, and Enterobacter, the flagella rotates in a
counterclockwise directionwhich causes them to form a single bundle that propels the bacterium
in long, straight or curved runs without a change in direction. Some flagella which rotates in
clockwise diraction forms in the bundle causes the flagellas to be pushed apart from the bundle
triggering a tumbling motion. Every time the bacterium tumbles it rerotates itself in a different
directions. In the presence of a chemical gradient, their movements become biased. When the
bacterium is moving away from higher concentrations of repellents or towards higher
concentrations of attractants the runs become longer and the tumbles less frequent.
Therefore an increasing concentration of attractant or decreasing concentration of repellent in
both the conditions are beneficial causes less tumbling and runs longer; a decreasing
concentration of attractant or increasing concentration of repellent both conditions are harmful
causes normal tumbling and a greater chance of reorienting in a \"better\" direction. As a result,
the organism\'s net movement is toward the optimum environment..
Most of the bacteria with polar flagella like, such as Pseudomonas aeruginosa, they can rotate
their flagella both in clockwise direction and counterclockwise direction. If the flagellum is
rotating counterclockwise directions, it pushes the bacterium forward. When it rotates clockwise
directions, it pulls the bacterium backward. These bacteria can change their direction by
changing the rotation of their flagella. Some bacteria with polar flagella, such as Rhodobacter
sphaeroides, can only rotate their flagellum clockwise. Therefore in this case, clockwise rotation
pushes the bacterium forward. Every time the bacterium stops, it reorients itself in a new
direction..
CLASS 11 CBSE B.St Project AIDS TO TRADE - INSURANCE
Class 11 CBSE Business Studies Project ( AIDS TO TRADE - INSURANCE)
Supporting (UKRI) OA monographs at Salford.pptx
How libraries can support authors with open access requirements for UKRI funded books
Wednesday 22 May 2024, 14:00-15:00.
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Which physical topology has all systems connecting to a central conn.pdf
Which physical topology has all systems connecting to a central connection device?
A. Bus
B. Ring
C. Star
D. Mesh
Solution
C is correct. A star topology connects all devices to a central point.
A, B, and D are incorrect. A is incorrect because all devices are connected to a single wire. B is
incorrect because it connects all devices in a circle, with one device connected directly to the
next. D is incorrect because it has all devices connected directly to all other devices..
What is the role of RFID chips in logistics What is the role o.pdf
What is the role of RFID chips in logistics?
What is the role of RFID chips in logistics?
Solution
Radio-frequency identification (RFID) uses electromagnetic fields to automatically identify and
track tags attached to objects. The tags contain electronically stored information. Passive tags
collect energy from a nearby RFID reader\'s interrogating radio waves. Active tags have a local
power source such as a battery and may operate at hundreds of meters from the RFID reader.
Unlike a barcode, the tag need not be within the line of sight of the reader, so it may be
embedded in the tracked object. RFID is one method for Automatic Identification and Data
Capture (AIDC).[1]
The emergence of RFID (Radio Frequency Identification) technology has been greatly increased
efficiency in the production process management, material flow management, logistics and
transport, retail and distribution and other fields of the national economy industries, including
electronic information industry. RFID may eventually replace the ubiquitous bar code in the
future and become the main technology in logistics and supply chain management field
RFID in Logistics Management
Logistics management involves the efficient control of some or all of the supply chain functions,
including:
– Product research and development
– Sourcing and purchasing
– Manufacturing
– Production planning
– Sales, marketing, and forecasting
– Inventory management
– Cross-docking and flow-through
– Customer service
– Transportation
– Freight payment
– Information reporting
Using RFID logistics tracking has helped many organizations solve the main challenge at every
node in their supply chains: the lack of visibility of logistics data. RFID technology is a powerful
solution that improves asset visibility, data quality, inventory management, and interoperability
in an end-to-end integrated supply chain. In fact, the U.S. Department of Defense (DoD) issued a
mandate in 2005 that requires all of their suppliers to use RFID in marking any items that are
sold to the DoD. The need for this mandate arose from decades of logistical challenges faced by
the military with regard to the supply chain.
RFID has proven to alleviate various logistical problems associated with the DoD supply chain.
RFID technology, in combination with the Internet, allows the DoD to disseminate accurate,
real-time data to commanders worldwide so that assets can be easily located and used according
to the Department’s highest priorities..
tut all words or phases will be inca. cach likathawnb tha bat wer.pdf
tut all words or phases will be inca. cach likathawnb tha bat werd or parase selouief, Sea
Eucaryine cells are biggey and nicee si eucary ulic eells, ay rlsmnuinn, an Another organelle rare
iin i a12 or s, Irweund e-erer lly allouurwte cells isthe which generates the
eralesthecheninalenAL lly-allouarylicerntraethedresinr nanttic eds and ay ihe plasma memmanc
irvrm Clicaryotic cell, and the ecil Ln contrast, the remove all of its membrane-enclosed orge
photosynthesis. If we were to strip iway ibe pigs, we at\'Nuo type of orga found celly In Ehe
cells her plants and signe, and many leng, fine liaisi ents of protein that are we would be left with
the responsible for cell shape and structure and th which cultsins manypr re and thereby form the
cell\'s chloroplast nucleus chromosome reticulum niosomes mitochondrion endoplasmic reti
cytoskeleton mbrane of theen
Solution
Eukaryotic cells are bigger and … than prokaryotic cells. By definition all eukaryotic cells have
a nucleus, usually the most prominent organelle. Another organelle found essentially in all
eukaryotic cells is the mitochondria, which generates the chemical energy for the cell. In contrast
the chloroplast is a type of organelle found only in the cells of plants and algae and performs
photosynthesis. If we were to strip away the plasma membrane from a eukaryotic cell and all of
its membrane enclosed organelles we would be left with the cytosol, which contains many lone
fine filaments of proteins that are responsible for cell shape and structure and thereby form the
cell`s cytoskeleton..
Theories of law enforcementSubjectDiscuss the positive and negati.pdf
Theories of law enforcement/Subject
Discuss the positive and negative effects of community policing. Identify some community
policing programs and explain their effectiveness. What is the primary focus of community
policing? Can a community policing program be effectively managed from a central agency?
Some officers disagree with community policing because of the feeling that spending time with
the good citizens is a waste of time and should be left to the politicians. What do you think
Solution
Discuss the positive and negative effects of community policing. Identify some community
policing programs and explain their effectiveness. What is the primary focus of community
policing? Can a community policing program be effectively managed from a central agency?
Some officers disagree with community policing because of the feeling that spending time with
the good citizens is a waste of time and should be left to the politicians. What do you think
--------------------------------------------------------------------------------------------------------------------
--------------------------------------------------
Community policing is a philosophy that promotes organizational strategies, which support the
systematic use of partnerships and problem-solving techniques, to proactively address the
immediate conditions that give rise to public safety issues such as crime, social disorder, and fear
of crime.
Community policing is a philosophy of full service personalized policing, where the same officer
patrols and works in the same area on a permanent basis, from a decentralized place, working in
a proactive partnership with citizens to identify and solve problems.
Positive effects of Community policing :
Prevent crime
Address /Reduce fear of crime
Elicit the citizen development
Creative problem solving
Create active cooperation with Employee & Resident
Negative effect of community pricing :
The effects to examine is liability lawsuits
Risk taking leads to more litigation\'s and community-oriented policing involves risk taking due
to the modern management that is involved in community oriented policing
Nature & Extent of civil liability
Community pricing is dependent on community .Each community is different.
Primary focus of community policing:
The main focus of community policing is to solve the problems of society.For police
departments its not possible to control each & every thing , so they take some help from society .
The problems where arises these teams are helping to solve the problems.
Community policing programs :
DRUG ABUSE RESISTANCE EDUCATION
Every 15 Minutes\" is an award-winning, two-day program designed to discourage young people
from drinking and driving.
McGruff the Crime Dog makes appearances at events which emphasize child safety concerns
The Community Opportunities Program For Youth (C.O.P.Y. Kids) was created to improve the
relationship between Spokane youths and police officers, as well as engender a sense of
community responsib.
What does a blower door doSolutionA blower door is a device w.pdf
What does a blower door do?
Solution
A blower door is a device which is used to measure the air tightness of buildings. It is also used
to find out the air flow in between the building zones, to test duct network air tightness and aslo
to physically locate air leakage sites n the building envelope.There are 3 primary components of
blower door. They are:
1)calibrated variable speed fan
2)pressure measuring instrument
3)mounting system.
The US population in millions is P(t) today, where time t is measured.pdf
The US population in millions is P(t) today, where time t is measured in years. For each
statement, choose one of the expression A-H that represents it.
Solution
P(t) is in millions
1) The population after 100,000 people have emigrated
==> Population is decreased by 100,000 = 0.1 million people
==> P(t) - 0.1 (Option D)
2) Ten percent of the population we have today
==> (10/100) P(t) = 0.1 P(t) (Option G)
3) Todays population plus 10 million immigrants = P(t) + 10 (Option H)
4) The population 10 years before today = P(t - 10) [ Option A].
Please make a comment for all the codesOr explain this pro.pdf
Please make a comment for all the codes
Or explain this program code!!
//Date.h
#ifndef DateFormat
#define DateFormat
#include
using std::string;
class Date {
public:
Date();
Date( int, int );
Date( int, int, int );
Date( string, int, int );
void setDay11(int);
void setMonth11( int );
void print11() const;
void printDDDYYYY11( ) const;
void printMMDDYY11( ) const;
void printMonthDDYYYY11( ) const;
~Date();
private:
int month1;
int day1;
int year1;
int checkDay(int)const;
int daysInMonth(int)const;
bool isLeapYear()const;
int convertDDToDDD()const;
void setMMDDFromDDD(int);
string convertMMToMonth(int)const;
void setMMFromMonth(string);
int convertYYYYToYY()const;
void setYYYYFromYY(int);
};
#endif
//Main.cpp
include
using std::cout;
using std::endl;
#include \"Date.h\"
int main()
{
Date date1( 252,1999 );
Date date2( 2,25,04 );
Date date3( \"September\", 1, 2000 );
Date date4;
date1.print11();
date2.print11();
date3.print11();
date4.print11();
cout << \'\ \';
date1.printDDDYYYY11();
date2.printDDDYYYY11();
date3.printDDDYYYY11();
date4.printDDDYYYY11();
cout << \'\ \';
date1.printMMDDYY11();
date2.printMMDDYY11();
date3.printMMDDYY11();
date4.printMMDDYY11();
cout << endl;
date1.printMonthDDYYYY11();
date2.printMonthDDYYYY11();
date3.printMonthDDYYYY11();
date4.printMonthDDYYYY11();
return 0;
}
//Date.cpp
#include
using std::cout;
using std::endl;
#include
using std::setw;
using std::setfill;
include
using std::time;
using std::localtime;
using std::tm;
using std::time_t;
#include \"Date.h\"
Date::Date()
{
struct tm *ptr;
time_t t1 = time( 0 );
ptr = localtime( &t1 );
day1 = ptr->tm_mday;
month1 = 1 + ptr->tm_mon;
year1 = ptr->tm_year + 1900;
}
Date::Date( int ddd1, int yyyy1 )
{
year1=yyyy1;
setMMDDFromDDD(ddd1);
}
Date::Date( int mm1, int dd1, int yy1 )
{
setYYYYFromYY( yy1 );
mm1 );
setDay11( dd1 );
}
Date::Date(string monthName2,int dd1,int yyyy1)
{
setMMFromMonth(monthName2);
setDay11(dd1);
year1=yyyy1;
}
void Date::setDay11( int d1 )
{
day1 = checkDay(d1); }
void Date::setMonth11( int m1 )
{
if(m1>0&& m1<=12)
month1=m1;
else
{
month1=1;
cout<<\"invalid month(\"<0 && testDay<=daysInMonth(month1))
return testDay;
if(month1==2 && testDay==29 && isLeapYear())
return testDay;
cout<<\"invalid day(\"<=2000?year1-2000:year1-1900);
}
void Date::setYYYYFromYY(int yy)
{
year1=(yy<7?yy+2000:yy+1900);
}
Please make a comment for all the codes
Or explain this program code!!
//Date.h
#ifndef DateFormat
#define DateFormat
#include
using std::string;
class Date {
public:
Date();
Date( int, int );
Date( int, int, int );
Date( string, int, int );
void setDay11(int);
void setMonth11( int );
void print11() const;
void printDDDYYYY11( ) const;
void printMMDDYY11( ) const;
void printMonthDDYYYY11( ) const;
~Date();
private:
int month1;
int day1;
int year1;
int checkDay(int)const;
int daysInMonth(int)const;
bool isLeapYear()const;
int convertDDToDDD()const;
void setMMDDFromDDD(int);
string convertMMToMonth(int)const;
void setMMFromMonth(string);
int convertYYY.
The purpose of a database is to. Select one store lists of data invo.pdf
The purpose of a database is to. Select one: store lists of data involving multiple themes test and
troubleshoot newly installed software design the source code for computer programs describe
and build computer architectures The first step in protecting oneself from data breaches is. Select
one: securing credit and debit card details learning the technologies used for these activities
understanding how they happen installing necessary software to protect from possible breaches
Solution
Question 3:
The purpose of a Database is to
Answer: a. store list of data involoving multiple themes
Question 4:
First step in protecting oneself from a data breaches is
Answer: c. Understanding how they happen.
Stadents version-p. 2 0. (Table 3) item(s) at the deli bar causing .pdf
Stadent\'s version-p. 2 0. (Table 3) item(s) at the deli bar causing the outbreak, investigators
reanal and controls who ate at the deli bar during March 9-10. abled Gastroenteritis at a
University in Texas Student\'s version-p. 17 PART VI-DESIGNING AN EPIDEMIOLOGIC
STUDY TO REFINE THE HYPOTHESIS (STUDY #2) By March 13, one hundred and twenty-
five persons with vomiting or diarthea had been reported to TDH. TDH invited staff fiom the
Centers for Disease Control and Prevention (CDC) to participate in the ongoing investigation.
CDC staff suggested submission of fresh stool specimens from ill students for viral studies
including reverse transcriptase-polymerase chain reaction (RT-PCR). TDH and CDC staff
decided to undertake an unmatched case-control study to further explore the source of the
outbreak. Question 18 Who should be enrolled as subjects for this study?
Solution
persons with vomiting or diarrea that is the enroolled as subjects for this study.
A major hurricane is a hurricane with wind speeds of 111 miles per h.pdf
A major hurricane is a hurricane with wind speeds of 111 miles per hour or greater. During the
20th century, the mean number of major hurricanes to strike the U.S. mainland per year was
about 0.66. Find the probability that in a given year a) exactly one major hurricane will strike the
U.S. mainland, b) at most one major hurricane will strike the U.S. mainland, and c) more than
one major hurricane will strike the U.S. mainland
Solution.
1.In which case(s) is there constructive interference for two ligh.pdf
1.
In which case(s) is there constructive interference for two light waves meeting at the same point
at a given instant? (Select all that apply.)
A) Both waves are at their minimum
B) One wave is at its maximum, one wave is at zero.
C) Both waves are at their maximum
D) One wave is at its minimum, one wave is at zero.
E) One wave is at its maximum, the other is at its minimum
2.
In which situation(s) is there destructive interference when two waves intersect at one point? (At
an instant of time.)
A) Both waves are at a maximum
B) One wave is at a maximum, the other is at zero
C) One wave is at a minimum; the other is at a maximum
D) Both waves are at a minimum
E) One wave is at a minimum, the other is at zero
3.
When light goes through a very narrow slit, it spreads out from that slit in all directions beyond
the slit due to:
A) diffraction
B) dispersion
C) interference
D) refraction
E) reflection
4.
Light encounters two very narrow slits closely spaced together. Constructive interference of light
coming from these two slits will occur when
A) the wavelength of the light equals the width of the slits
B) the wavelength of the light equals the separation of the slits
C) the light from one slit has to travel a distance that is longer than that traveled by the light
from the other slit equal to half the wavelength of the light
D) light from one slit at its crest encounters light from the other slit at its trough
E) the light from one slit has to travel a distance that is longer than that traveled by the light
from the other slit equal to twice the wavelength of the light
5.
Equations 17.7 and 17.8 depend on which assumption?
A) The screen is very close to the slits
B) the slits are much wider than the wavelength of the light
C) small angles (in radians)
D) large angles (in radians)
6.
You shine both red and blue light through a double slit. What can you say about their
interference patterns?
A) The red bright fringes will be closer together than will be the blue bright fringes.
B) The red and blue bright fringes will be the same distance apart from each other.
C) The blue bright fringes will be closer together than will be the red bright fringes.
7.
You compare a double-slit interference pattern with the interference pattern due to a diffraction
grating of the same spacing as that of the double-slit. The most noticeable difference would be
that:
A) The peaks of the diffraction grating are much broader than that for the double-slit
B) The peaks of the diffraction grating are much farther apart than for the double-slit
C) The peaks of the diffraction grating are much sharper than that for the double-slit
D) The peaks of the diffraction grating are much closer together than for the double-slit
E) The center point is a maximum, not a minimum
F) The center point is a minimum, not a maximum
Solution
(1).Both waves are at their maximum
(2).One wave is at a minimum; the other is at a maximum
(3).diffraction
(4).the light from one slit has to travel a dis.
List and describe three examples of secondary sexual characteristics.pdf
List and describe three examples of secondary sexual characteristics each for males and females.
Solution
Secondary sex characteristics are features that appear at sexual maturity in animals and during
puberty in humans, Secondary sex characteristics are Traits that distinguish the biological sexes
of a species, but are not directly part of the reproductive system.
Examples of secondary sex characteristics in humans include shorter stature and wider pelvis,
breast development, and more fat in the thighs and buttocks in women and broader shoulders,
greater muscle mass, more facial and other body hair, and “male pattern” baldness in men.
Male secondary sexual characteristics of hair:
The pubic regions is usually the first to develop hair
Facial hair begins at the corner of the mouth and spreads to the midline - followed by the rest of
the face
Body hair develops long before facial hair growth is complete (arm pit, legs, arms, buttocks,
back)
Male secondary sexual characteristics of vocal changes:
Rapid growth of the larynx - larger and stronger
The thyroid cartilage increases in dimension creating the Adam\'s apple
Vocal cords lengthen and thicken.
Male secondary sexual characteristics of the body:
Increase in body size, weight and strength (musculature)
Correlated to increase in testosterone levels
Female secondary sexual characteristics of hair:
The pubic regions is usually the first to develop hair
Body hair develops slightly later (arm pit, legs, arms)
female secondary sexual characteristics of the pelvis:
Broadens and changes from a narrow funnel-like outlet, to a broad oval outlet, flaring at the hip
Fat cells increase in number around the buttocks and thighs
Female secondary sexual characteristics of the breasts:
Tanner Stages
Tanner I
no glandular tissue, typically age 10 and younger
Tanner II
Breast bud forms, with small area of surrounding glandular tissue, 10-11.5
Tanner III
breast begins to become more elevated, and extends beyond the borders of the areola, 11.5-13
Tanner IV
increased breast size and elevation, 13-15
Tanner V
breast reaches final adult size, 15+.
Let X1, X2,... be independent, identically distributed random variab.pdf
Let X1, X2,... be independent, identically distributed random variables with E[X] = 2 and
var(X)=9, and let Yi = Xi/2i . We also define Tn and An to be the sum and the sample mean,
respectively, of the random variables Y1,...,Yn.
(a) Evaluate the mean and variance of Yn, Tn, and An.
(b) Does Yn converge in probability? If so, to what value?
(c) Does Tn converge in probability? If so, to what value?
(d) Does An converge in probability? If so, to what value?
Solution.
In SoS development process, explain why it is important that system s.pdf
In SoS development process, explain why it is important that system selection and architecture
design should be concurrent activities and why there should be close links between them.
Solution
The SoS development process play an important role in large and complex entities in the
application domain and organization essential requirements for development strategies using
System selection and Architecture Design.
Architecture design is same as System selection. An entire architecture design is SoS
development stage which depends upon various parameters using interface and integration
development process exists in application system..
Go onto the APOD website (httpapod.nasa.govapod) and look in th.pdf
Go onto the APOD website (http://apod.nasa.gov/apod/) and look in the archive (or search) for a
cool looking galaxy or of the Milky Way. Post the image to this forum as well as a link to the
APOD picture. Share your picture with the rest of the class. From the description, describe what
kind of galaxy it is and anything interesting about it. Use your own words, no need to simply re-
type what is already written there. Relate this particular galaxy back to something you’ve learned
in this class about the diversity of galaxy types and why there is such diversity,
Solution
link: http://apod.nasa.gov/apod/
Want to take a fast trip to the edge of the Solar System? Consider a ride on a Heliopause
Electrostatic Rapid Transit System (HERTS). The concept is currently being tested and it might
take only 10 to 15 years to make the trip of over 100 Astronomical Units (15 billion kilometers).
That\'s fast compared to the 35 years it took Voyager 1, presently humanity\'s most distant
spacecraft, to approach the heliopause or outer boundary of the influence of the solar wind.
HERTS would use an advanced electric solar sail that works by extending multiple, 20 kilometer
or so long, 1 millimeter thin, positively charged wires from a rotating spacecraft. The
electrostatic force generated repels fast moving solar wind protons to create thrust. Compared to
a reflective solar light sail, another propellantless deep space propulsion system, the electric solar
wind sail could continue to accelerate at greater distances from the Sun, still developing thrust as
it cruised toward the outer planets..
give an examples of a decisions made under uncertainty give a.pdf
give an examples of a decisions made under uncertainty
give an examples of a decisions made under uncertainty
Solution
Let\'s take am example of floods. During floods, a lot of panic is caused and there\'s an
environment of uncertainty among the victims which leads to uncertain decision making. Some
people flee from home and take only their important documaents with them while stay at the
higher ground and see whether the flood worsens or not and the decide their next approach..
Explain the role of the loop of Henlé in the formation of urine and .pdf
Explain the role of the loop of Henlé in the formation of urine and how this is achieved
Solution
The renal cortex and renal medulla contain several nephrons that carryout the filtration of the
fluids and remove the wastes in the form of urine. The nephrons contain their renal corpuscles in
the cortex. The cortical nephrons consist of loop of Henle in the renal medulla near the junction
along with the renal cortex, while the loop of Henle of juxta-medullary nephrons is located in the
renal medulla. The cortical nephrons vary because some are superficial cortical nephrons and
some are midcortical nephrons, depending on location of renal corpuscle in the cortex.
The nephron loop is otherwise called as loop of Henle or loop of Hundle. It is U – shaped tube
extends from the proximal convoluted tube. The nephron loop consists of ascending and
descending limbs. The ascending limb is found in the renal cortex extends from proximal
convoluted tubule PCT into the renal medulla. The descending limb from renal medulla then
passes into the renal cortex and empties the content of distal convoluted tubule (DCT). The
nephron loop also performs the function of reabsorption of water and ions across the
concentration gradient. It has the primary function of concentrating the salts in the interstitium.
The proximal convoluted tubule (PCT) is divided into convoluted and straight parts of the
nephron. The PCT carries out the reabsorption of water, organic substances and some ions from
the original filtrate. The filtrate absorbs the water and solutes in PCT through the peritubular
capillaries. The organic solutes like glucose and amino acids are absorbed at PCT.
The distal convoluted tubule (DCT) carries out the reabsorption of water and sodium ions and
secretion under hormone stimulation. The distal convoluted tubule is different in structure and
function when compared to proximal convoluted tubule. Cells lining the tubule contain several
mitochondria to produce enough energy (ATP) for active transport of solutes.
The transport of the ions in the DCT is mediated by the activity of the endocrine system. The
DCT reabsorbs more calcium and secretes more phosphate in the presence of parathyroid
hormone. In the presence of aldosterone, more sodium is reabsorbed and potassium is secreted.
The atrial natriuretic peptide (ANP) stimulates the DCT to secrete more sodium. The DCT also
secretes hydronium and ammonium ions to regulate pH of the blood.
The collecting duct collects the tubular fluid across the osmotic gradient in the renal medulla.
Each collecting duct arises from the distal convoluted tubule and the filtrate is delivered to
collecting duct at the connecting tubule. The collecting duct starts in the renal cortex and extends
into the renal medulla. The urine is passed into collecting ducts by the medullary interstitium.
The urine passed into the collecting duct contains high sodium concentration because of the
counter current multiplier system in the loop of Hen.
Extend your work on the OCC logo to add shapes that curve1 the blue.pdf
Extend your work on the OCC logo to add shapes that \'curve1 the blue Cs into looking
something more like the actual logo:
Solution
import java.awt.Color;
import java.util.Comparator;
/**
* a straightforward red-black tree category.
*/
public category RedBlackTree extends BinarySearchTree Associate in Nursing empty
RedBlackTree which will solely settle for Comparables as
* items.
*/
public RedBlackTree()
/**
* Constructs Associate in Nursing empty RedBlackTree that orders its things in keeping with
the
* given comparator.
*/
public RedBlackTree(Comparator c)
/**
* The nodes during a red-black tree store a color beside the particular information
* within the node.
*/
category Node extends LinkedBinaryTreeNode
}
/**
* Adds one information item to the tree. If there\'s already Associate in Nursing item within the
* tree that compares up to the item being inserted, it\'s \"overwritten\"
* by the new item. Overrides BinarySearchTree.add as a result of the tree must
* be adjusted when insertion.
*/
public void add(Object data)
BinaryTreeNode n = root;
whereas (true) else if (comparisonResult < 0)
n = n.getLeft();
} else zero
if (n.getRight() == null)
n = n.getRight();
}
}
}
/**
* Removes the node containing the given price. will nothing if there\'s no
* such node.
*/
public void remove(Object data) else if (node.getLeft() != null && node.getRight() != null) 2
kids, Copy forerunner information in.
BinaryTreeNode forerunner = predecessor(node);
node.setData(predecessor.getData());
node = (Node) predecessor;
}
// At this time node has zero or one kid
Node pullUp = leftOf(node) == null ? rightOf(node) : leftOf(node);
if (pullUp != null) regulate if pullUp could be a double black.
if (node == root) else if (node.getParent().getLeft() == node) else
if (isBlack(node))
} else if (node == root) to drag up once deleting a root means that we have a tendency to empty
the tree
setRoot(null);
} else lookout
if (isBlack(node))
node.removeFromParent();
}
}
/**
* Classic formula for fixing up a tree when inserting a node.
*/
personal void adjustAfterInsertion(Node n) issues, if they exist
if (n != null && n != root && isRed(parentOf(n))) to ascertain if additional work
// needed
if (isRed(siblingOf(parentOf(n))))
// Step 2b: reconstitute for a parent United Nations agency is that the left kid of the
// forebear. this may need one right rotation if n is
// also
// a left kid, or a left-right rotation otherwise.
else if (parentOf(n) == leftOf(grandparentOf(n)))
setColor(parentOf(n), Color.black);
setColor(grandparentOf(n), Color.red);
rotateRight(grandparentOf(n));
}
// Step 2c: reconstitute for a parent United Nations agency is that the right kid of the
// forebear. this may need one left rotation if n is
// also
// a right kid, or a right-left rotation otherwise.
else if (parentOf(n) == rightOf(grandparentOf(n)))
setColor(parentOf(n), Color.black);
setColor(grandparentOf(n), Color.red);
rotateLeft(grandparentOf(n));
}
}
// Step 3: Color the foundation black
setColo.
Distinguish between a micelle, a bilayer, and a liposome. What are t.pdf
Distinguish between a micelle, a bilayer, and a liposome. What are the forces that maintain these
structures?
Solution
Liposomes are composed of a lipid bilayer separating an aqueous internal compartment from the
bulk aqueous phase.
Micelles are closed lipid monolayers with a fatty acid core and polar surface, or polar core with
fatty acids on the surface (inverted micelle).
A lipid bilayer is also termed as a bimolecular sheet in which the hydrophobic tails of each
individual plane interact with one another, constituting a hydrophobic core which acts as a
permeability barrier.
Micelle is a smaller structure, generally less than 20 nm (200 Å) in diameter. But a bilayer sheet
can be of larger dimensions, e.g. a millimeter (106 nm or 107 Å).
Vander wall forces, electrostatic and hydrogen-bonding attractions between the polar head
groups and water molecules maintain the structures ..
Describe how a bacterium with peritrichous flagella moves. How does .pdf
Describe how a bacterium with peritrichous flagella moves. How does this allow cells to move
up a gradient of a an attractant or down the gradient of a repellent?
Solution
The flagella is present in bacteria. They can take 100\'s of rotations. By taking these rotations
they can move freely. If a bacterium has a peritrichous arrangement of flagella, such as
Escherichia coli, Salmonella, Proteus, and Enterobacter, the flagella rotates in a
counterclockwise directionwhich causes them to form a single bundle that propels the bacterium
in long, straight or curved runs without a change in direction. Some flagella which rotates in
clockwise diraction forms in the bundle causes the flagellas to be pushed apart from the bundle
triggering a tumbling motion. Every time the bacterium tumbles it rerotates itself in a different
directions. In the presence of a chemical gradient, their movements become biased. When the
bacterium is moving away from higher concentrations of repellents or towards higher
concentrations of attractants the runs become longer and the tumbles less frequent.
Therefore an increasing concentration of attractant or decreasing concentration of repellent in
both the conditions are beneficial causes less tumbling and runs longer; a decreasing
concentration of attractant or increasing concentration of repellent both conditions are harmful
causes normal tumbling and a greater chance of reorienting in a \"better\" direction. As a result,
the organism\'s net movement is toward the optimum environment..
Most of the bacteria with polar flagella like, such as Pseudomonas aeruginosa, they can rotate
their flagella both in clockwise direction and counterclockwise direction. If the flagellum is
rotating counterclockwise directions, it pushes the bacterium forward. When it rotates clockwise
directions, it pulls the bacterium backward. These bacteria can change their direction by
changing the rotation of their flagella. Some bacteria with polar flagella, such as Rhodobacter
sphaeroides, can only rotate their flagellum clockwise. Therefore in this case, clockwise rotation
pushes the bacterium forward. Every time the bacterium stops, it reorients itself in a new
direction..
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Personal development courses are widely available today, with each one promising life-changing outcomes. Tim Han’s Life Mastery Achievers (LMA) Course has drawn a lot of interest. In addition to offering my frank assessment of Success Insider’s LMA Course, this piece examines the course’s effects via a variety of Tim Han LMA course reviews and Success Insider comments.
June 3, 2024 Anti-Semitism Letter Sent to MIT President Kornbluth and MIT Cor...
Letter from the Congress of the United States regarding Anti-Semitism sent June 3rd to MIT President Sally Kornbluth, MIT Corp Chair, Mark Gorenberg
Dear Dr. Kornbluth and Mr. Gorenberg,
The US House of Representatives is deeply concerned by ongoing and pervasive acts of antisemitic
harassment and intimidation at the Massachusetts Institute of Technology (MIT). Failing to act decisively to ensure a safe learning environment for all students would be a grave dereliction of your responsibilities as President of MIT and Chair of the MIT Corporation.
This Congress will not stand idly by and allow an environment hostile to Jewish students to persist. The House believes that your institution is in violation of Title VI of the Civil Rights Act, and the inability or
unwillingness to rectify this violation through action requires accountability.
Postsecondary education is a unique opportunity for students to learn and have their ideas and beliefs challenged. However, universities receiving hundreds of millions of federal funds annually have denied
students that opportunity and have been hijacked to become venues for the promotion of terrorism, antisemitic harassment and intimidation, unlawful encampments, and in some cases, assaults and riots.
The House of Representatives will not countenance the use of federal funds to indoctrinate students into hateful, antisemitic, anti-American supporters of terrorism. Investigations into campus antisemitism by the Committee on Education and the Workforce and the Committee on Ways and Means have been expanded into a Congress-wide probe across all relevant jurisdictions to address this national crisis. The undersigned Committees will conduct oversight into the use of federal funds at MIT and its learning environment under authorities granted to each Committee.
• The Committee on Education and the Workforce has been investigating your institution since December 7, 2023. The Committee has broad jurisdiction over postsecondary education, including its compliance with Title VI of the Civil Rights Act, campus safety concerns over disruptions to the learning environment, and the awarding of federal student aid under the Higher Education Act.
• The Committee on Oversight and Accountability is investigating the sources of funding and other support flowing to groups espousing pro-Hamas propaganda and engaged in antisemitic harassment and intimidation of students. The Committee on Oversight and Accountability is the principal oversight committee of the US House of Representatives and has broad authority to investigate “any matter” at “any time” under House Rule X.
• The Committee on Ways and Means has been investigating several universities since November 15, 2023, when the Committee held a hearing entitled From Ivory Towers to Dark Corners: Investigating the Nexus Between Antisemitism, Tax-Exempt Universities, and Terror Financing. The Committee followed the hearing with letters to those institutions on January 10, 202
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An EFL lesson about the current events in Palestine. It is intended to be for intermediate students who wish to increase their listening skills through a short lesson in power point.
Instructions for Submissions thorugh G- Classroom.pptx
This presentation provides a briefing on how to upload submissions and documents in Google Classroom. It was prepared as part of an orientation for new Sainik School in-service teacher trainees. As a training officer, my goal is to ensure that you are comfortable and proficient with this essential tool for managing assignments and fostering student engagement.
TESDA TM1 REVIEWER FOR NATIONAL ASSESSMENT WRITTEN AND ORAL QUESTIONS WITH A...
TESDA TM1 REVIEWER FOR NATIONAL ASSESSMENT WRITTEN AND ORAL QUESTIONS WITH ANSWERS.
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Macroeconomics- Movie Location
This will be used as part of your Personal Professional Portfolio once graded.
Objective:
Prepare a presentation or a paper using research, basic comparative analysis, data organization and application of economic information. You will make an informed assessment of an economic climate outside of the United States to accomplish an entertainment industry objective.
Polish students' mobility in the Czech Republic
Polish students mobility to the Czech Republic within eTwinning project "Medieval adventures with Marco Polo"
2024.06.01 Introducing a competency framework for languag learning materials ...
http://sandymillin.wordpress.com/iateflwebinar2024
Published classroom materials form the basis of syllabuses, drive teacher professional development, and have a potentially huge influence on learners, teachers and education systems. All teachers also create their own materials, whether a few sentences on a blackboard, a highly-structured fully-realised online course, or anything in between. Despite this, the knowledge and skills needed to create effective language learning materials are rarely part of teacher training, and are mostly learnt by trial and error.
Knowledge and skills frameworks, generally called competency frameworks, for ELT teachers, trainers and managers have existed for a few years now. However, until I created one for my MA dissertation, there wasn’t one drawing together what we need to know and do to be able to effectively produce language learning materials.
This webinar will introduce you to my framework, highlighting the key competencies I identified from my research. It will also show how anybody involved in language teaching (any language, not just English!), teacher training, managing schools or developing language learning materials can benefit from using the framework.
Overview on Edible Vaccine: Pros & Cons with Mechanism
This ppt include the description of the edible vaccine i.e. a new concept over the traditional vaccine administered by injection.
The approach at University of Liverpool.pptx
How libraries can support authors with open access requirements for UKRI funded books
Wednesday 22 May 2024, 14:00-15:00.
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June 3, 2024 Anti-Semitism Letter Sent to MIT President Kornbluth and MIT Cor...
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