An ordinary deck of 52 cards is shuffled. What is the probability th.pdf
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An ordinary deck of 52 cards is shuffled. What is the probability that the top four cardshave (a) different denominations? (b) different suits? Solution a) P(diff deno)=(52*48*44*40)/(52*51*50*49)=0.6761 b) There are 24 different ways to get 4 cards of different suits (H,S,C,D or H,S,D,C, or H,C,S,D...). Each combination is equally likely, so we’ll find the probability of one of them, and then multiply it by 24 to get the answer. The probability of H,S,C,D is (13/52) * (13/51) * (13/50) * (13/49) = 0.0044. So multiply by 24 to get 0.105.
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An urn contains 12 white, 5 yellow and 13 black marbles. A marble is.pdf
An urn contains 12 white, 5 yellow and 13 black marbles. A marble is chosen at random from the
urn, and it is noted that is not one of the black marbles. What is the sample space in view of this
knowledge? What it the probability that it is yellow?
Solution
probability of the ball being yellow = 5/12+5 =5/17 hope my answer is correct and
please appreciate my help by awarding me karma points..
An SRS of 18 recent birth records at the local hospital was selected.pdf
An SRS of 18 recent birth records at the local hospital was selected. In the sample, the average
birth weight was 119.6 ounces and the standard deviation was 6.5 ounces. Assume that in the
population of all babies born in this hospital, the birth weights follow a Normal distribution, with
mean ?. Reference: Ref 18-1 The standard error of the mean is
Solution
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An organizations budgets will often be prepared to coverA)one m.pdf
An organization\'s budgets will often be prepared to cover:
A)one month
B) one quarter
C)one year
D)Periods longer than one year
E)All the above are correct
Solution
Stock budgets are prepared usually for month.
Cash budgets are prepared usually quarterly.
Sale budgets are prepared usually for one year
Capital budgeting budgets are prepared over the life time of the assets.
Hence,
Correct option is (E).
An optical source has a spectral width of 1300 nm. What type of opti.pdf
An optical source has a spectral width of 1300 nm. What type of optical source is it likely to be?
A
LED
B
All of these
C
Coherent source
D
Wideband source
E
Laser Diode
D is correct why?
An optical source has a spectral width of 1300 nm. What type of optical source is it likely to be?
Solution
Fiber optics are the communication medium through which the signals can be send and also the
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An object is thrown with an initial velocity of 14 ft per second. It.pdf
An object is thrown with an initial velocity of 14 ft per second. Its height is given by h= -14t^2 +
56 at time t seconds. After how many seconds does it hit the ground?
Solution
we have...
speed = 14 ft/second
distance or h = -14t^2 + 56
also we know that ...Distance = speed * time
putting the above values in the formula..we get
-14t^2 + 56 = 14 * t
taking common 14 from LHS ,,we get
14 ( -t^2 + 4) = 14 * t
divide both sides by 14 and we get ...
-t^2 + 4 = t
or 0 = t^2 + t - 4
solve the value of t by discriminent and you get the value of t
and put the value of t in formula ..distance = speed * time
and you get distance also.,..
An NMOS transistor with kn=4 mAV2 and Vt=.5 V is operated with Vos=.pdf
An NMOS transistor with kn=4 mA/V2 and Vt=.5 V is operated with Vos=1 V. At what value of
VDS does the transistor enter the saturation region? What value of ID is obtained in saturation?
Solution
NMOS will enter saturation when, Vds = Vgs -Vt = 1 - 0.5 = 0.5V
Id = Kn * (Vgs-Vt)2 in saturation
= 4 * (0.5)2 = 1mA
so Id = 1mA.
An object is launched straight upward from a platform. Its height ab.pdf
An object is launched straight upward from a platform. Its height above ground is
h(t) = h0+ v0t ? 16.1t2
where h is in feet and t is in seconds. The graph of h is shown below.
Find both unknown constants, accurate to 1 decimal place.
Solution
h(t) = h0 + v0t - 16.1t^2
As can be seen, the maximum height is reached at t = 2.5 :
So, -b/(2a) = 2.5
-v0 / (2*-16.1) = 2.5
v0 / (32.2) = 2.5
v0 = 2.5 * 32.2
v0 = 80.5 ---> Answer for v0
When t = 1 , h = 90
90 = h0 + 80.5*1 - 16.1*1^2
h0 = 90 - 80.5 + 16.1
h0 = 25.6
So, the constants are :
v0 = 80.5
AND
h0 = 25.6.
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An LBO (leveraged buy-out) means that a private company takes over another company by
borrowing an enormous amount of money (often by issuing speculative, or \"junk\" bonds) and
uses those borrowed funds to buy-back the common stock. After the take-over, which of the
following ratios would be the best indicator that this has happened::
Net Profit Margin
ACP, Average collection period
TIE, Times Interest Earned
Accumulated Depreciationa.
Net Profit Marginb.
ACP, Average collection periodc.
TIE, Times Interest Earnedd.
Accumulated Depreciation
Solution
c)Times interest earned
=EBIT/interest
as they have borrowed lot of mony the interest value will be high.
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knowledge? What it the probability that it is yellow?
Solution
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Solution
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An organizations budgets will often be prepared to coverA)one m.pdf
An organization\'s budgets will often be prepared to cover:
A)one month
B) one quarter
C)one year
D)Periods longer than one year
E)All the above are correct
Solution
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Cash budgets are prepared usually quarterly.
Sale budgets are prepared usually for one year
Capital budgeting budgets are prepared over the life time of the assets.
Hence,
Correct option is (E).
An optical source has a spectral width of 1300 nm. What type of opti.pdf
An optical source has a spectral width of 1300 nm. What type of optical source is it likely to be?
A
LED
B
All of these
C
Coherent source
D
Wideband source
E
Laser Diode
D is correct why?
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Solution
Fiber optics are the communication medium through which the signals can be send and also the
signals can be received since the signals which have to sent have to be send as fast as possible
and this can be achived by this fiber optics. Multimode fiber is one which uses a wideband
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width of 1300 nm because it has low loss. that is it transmits the wave signal with low loss and
with efficient output..
An object is thrown with an initial velocity of 14 ft per second. It.pdf
An object is thrown with an initial velocity of 14 ft per second. Its height is given by h= -14t^2 +
56 at time t seconds. After how many seconds does it hit the ground?
Solution
we have...
speed = 14 ft/second
distance or h = -14t^2 + 56
also we know that ...Distance = speed * time
putting the above values in the formula..we get
-14t^2 + 56 = 14 * t
taking common 14 from LHS ,,we get
14 ( -t^2 + 4) = 14 * t
divide both sides by 14 and we get ...
-t^2 + 4 = t
or 0 = t^2 + t - 4
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Solution
NMOS will enter saturation when, Vds = Vgs -Vt = 1 - 0.5 = 0.5V
Id = Kn * (Vgs-Vt)2 in saturation
= 4 * (0.5)2 = 1mA
so Id = 1mA.
An object is launched straight upward from a platform. Its height ab.pdf
An object is launched straight upward from a platform. Its height above ground is
h(t) = h0+ v0t ? 16.1t2
where h is in feet and t is in seconds. The graph of h is shown below.
Find both unknown constants, accurate to 1 decimal place.
Solution
h(t) = h0 + v0t - 16.1t^2
As can be seen, the maximum height is reached at t = 2.5 :
So, -b/(2a) = 2.5
-v0 / (2*-16.1) = 2.5
v0 / (32.2) = 2.5
v0 = 2.5 * 32.2
v0 = 80.5 ---> Answer for v0
When t = 1 , h = 90
90 = h0 + 80.5*1 - 16.1*1^2
h0 = 90 - 80.5 + 16.1
h0 = 25.6
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v0 = 80.5
AND
h0 = 25.6.
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An LBO (leveraged buy-out) means that a private company takes over another company by
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uses those borrowed funds to buy-back the common stock. After the take-over, which of the
following ratios would be the best indicator that this has happened::
Net Profit Margin
ACP, Average collection period
TIE, Times Interest Earned
Accumulated Depreciationa.
Net Profit Marginb.
ACP, Average collection periodc.
TIE, Times Interest Earnedd.
Accumulated Depreciation
Solution
c)Times interest earned
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An issue of preferred stock is paying an annual dividend of $5. What is the preferred stock price
if the required rate of return is 11%?
Solution
part a: common stock growth, 14% here is irrelevant
cost of preferred stock (Kp)= 11%
pref. dividend (Pd) = $5
Market price of pref. stock= Pd/Kp
=$5/0.11
=$45.45
part b: dividend= $3.75
growth (g)= .08
RRR(Ke) = .16
Price of share = div(1+g)/ke-g
=$3.75*1.08/.16-.08
= $50.625.
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An IT security training program is a part of which of the following control categories?
a) Application controls
b) General controls
c) Administrative controls
d) Technical controls
Solution
c. The security-training program is a part of administrative controls, which in turn, can be a part
of management controls. Application controls relate to a specific application system, whereas
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B: 14.0%
C: 16.6%
D: 18.8%
E: 20.0%
Solution
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Earnings in second year = (10,800 x 0.5) x 20% = $1,080
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over the Internet. Which of the following controls is least suited to establish a secure intranet
over the Internet?
Use encrypted tunnels.
Install encrypted routers.
Install encrypted firewalls.
Implement password controls in the private Web server.
Solution
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Solution
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have property P, that means the communative property doesnt work. so (a/x)b and (b/x)a is not
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An issue of preferred stock is paying an annual dividend of $5. What.pdf
An issue of preferred stock is paying an annual dividend of $5. What is the preferred stock price
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Solution
part a: common stock growth, 14% here is irrelevant
cost of preferred stock (Kp)= 11%
pref. dividend (Pd) = $5
Market price of pref. stock= Pd/Kp
=$5/0.11
=$45.45
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growth (g)= .08
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Price of share = div(1+g)/ke-g
=$3.75*1.08/.16-.08
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these activities. As the most crucial natural resource, its utilization by humans results in different
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9
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