All health professionals are allowed to practise in their field of car.docx
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All health professionals are allowed to practise in their field of care as soon as they graduate from the necessary college/university. True False Question 7 ( 0.5 points) A unique concept introduced by Alberta in 2013, to provide a direct access to a variety of non emergency services Family community centres Family care centres Family nonemergency care Family care clinics Question 4 ( 0.5 points) Which of the following is a strategy by hospitals to cut down their costs? Closing down for some days Denying patients and referring them to other hospitals instead Same-day admissions All of these The Smudging Ceremony involved burning of medicine such as grass, or sage. True False .
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// A structure to represent a Deque
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int rear;
int size;
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{
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void insertrear(int key);
void deletefront();
void deleterear();
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bool isEmpty();
int getFront();
int getRear();
};
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bool Deque::isFull()
{
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front == rear+1);
}
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bool Deque::isEmpty ()
{
return (front == -1);
}
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{
// check whether Deque if full or not
if (isFull())
{
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}
// If queue is initially empty
if (front == -1)
{
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rear = 0;
}
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front = front-1;
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}
// function to inset element at rear end
// of Deque.
void Deque ::insertrear(int key)
{
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{
cout << " Overflow\n " << endl;
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}
// If queue is initially empty
if (front == -1)
{
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}
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}
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{
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{
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}
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{
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{
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{
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// C++ implementation of De-queue using circular
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{
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int rear;
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{
return ((front == 0 && rear == size-1)||
front == rear+1);
}
// Checks whether Deque is empty or not.
bool Deque::isEmpty ()
{
return (front == -1);
}
// Inserts an element at front
void Deque::insertfront(int key)
{
// check whether Deque if full or not
if (isFull())
{
cout << "Overflow\n" << endl;
return;
}
// If queue is initially empty
if (front == -1)
{
front = 0;
rear = 0;
}
// front is at first position of queue
else if (front == 0)
front = size - 1 ;
else // decrement front end by '1'
front = front-1;
// insert current element into Deque
arr[front] = key ;
}
// function to inset element at rear end
// of Deque.
void Deque ::insertrear(int key)
{
if (isFull())
{
cout << " Overflow\n " << endl;
return;
}
// If queue is initially empty
if (front == -1)
{
front = 0;
rear = 0;
}
// rear is at last position of queue
else if (rear == size-1)
rear = 0;
// increment rear end by '1'
else
rear = rear+1;
// insert current element into Deque
arr[rear] = key ;
}
// Deletes element at front end of Deque
void Deque ::deletefront()
{
// check whether Deque is empty or not
if (isEmpty())
{
cout << "Queue Underflow\n" << endl;
return ;
}
// Deque has only one element
if (front == rear)
{
front = -1;
rear = -1;
}
else
// back to initial position
if (front == size -1)
front = 0;
else // increment front by '1' to remove current
// front value from Deque
front = front+1;
}
// Delete element at rear end of Deque
void Deque::deleterear()
{
if (isEmpty())
{
cout << " Underflow\n" << endl ;
return ;
}
// Deque has only one element
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{
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rear = -1;
}
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else
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}
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{
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Activity- Simulating meiosis 1. Cut out the chromosomes on the second to last page of this lab. One color of chromosomes is inherited from one parent, and the other is inherited from the other parent. Use a paper clip to keep identical sister chromatids together. 2. Use the circles representing cells provided on the last two pages. Meiosis I Prophase I 1. Put all four of the chromosomes that you cut out and place them in the large oval cell labeled A pole and B pole. 2. Bring the members of the homologous pairs together forming a tetrad- Why do you think these are called a tetrad? 3. Crossing-over is the exchange of genetic material between two homologous chromosomes. It creates genetic recombination during meiosis. Simulate crossingover by cutting off one yellow and blue circle from two nonsister chromatids of a single homologous pair and reattaching the circles on with tape. Why did we exchange from nonsister and not from sister chromatids? MetaphaseI Move the homologous chromosome pairs to the equator (middle of the cell) in such a way that the members of each pair can be moved towards opposite sides of the cell AnaphaseI Separate the each member of the homologous pair, moving them toward opposite poles of the cell TelophaseI Do the 2 chromosomes inherited from the father have to stay together after meiosis I? So, what are two ways that meiosis can create genetic recombination? Interkinesis Interkinesis is the periods of time between meiosis I and meiosis II. Meiosis II Prophase II Choose the chromosomes from each pole to represent those in the new parental cell undergoing meiosis II. Place them inside the top two cells on the next page. Metaphase II Move the chromosomes (made out of the sister chromatids) to the equator of this cell. How many chromosomes are at this equator? Anaphase II Pull apart the two sister chromatids Telophase II Once the sister chromatids are apart they are now each called a chromosome. Move each chromosome to its separate pole. Now these chromosomes are in their own cell in a new nucleus. Conclusions Do the new nuclei contain a haploid or diploid chromosome number compared to the original cell? Suppose you had worked with both daughter cells after meiosis I. How many cells would be present when meiosis II was complete? How many chromosomes are in the parental cell undergoing meiosis II (at the beginning of meiosis II? How many chromosomes are in the daughter cell (at the end of meiosis II)? How is this possible? Explain below. To summarize meiosis: the original parent cell has the diploid ( 2 n ) number of chromosomes, and the daughter cells at the end of meiosis II have the number of chromosomes. Meiosis is cell division in which the chromosome number does what?
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Syllabus
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Introduction to objective, scope and outcome the subject
Chapter 2
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