Ages of the first 6 presidents at inauguration Washington 57 J. .pdf
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Ages of the first 6 presidents at inauguration Washington 57 J. Adams 61 Jefferson 57 Madison 57 Monroe 58 JQ Adams 57 a. Find the mean of the data set b. Find the standard deviation (showing all work) c. How many of the president Solution Freaking show the work!!!.
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After class a student comments to me, “Once a poll has been taken,.pdf
After class a student comments to me, “Once a poll has been taken,
(the sample proportion with a certain opinion) is a known value, so it cannot have
a distribution of possible values. Therefore, I do not understand what you mean
by the sampling distribution of.” Write an explanation for this student.
Solution
A poll is just one sample of the population. If you took other samples (of the same
size) you would get different proportions. The distribution of the proportions of all the samples
taken is a sampling distribution..
Adjusting entries are required at the end of the period for some acc.pdf
Adjusting entries are required at the end of the period for some accounts. (1) Explain why this
process is required (15 points) and (2) develop the adjusting entry at the end of the period for
salary payable to employees $2400 (10 points).
Solution
Adjusting entries are required at the end of the period for some accounts, This process is required
due to accrual based of accounting i.e Mercantile Accounting , Adjustment entry are passed so as
to provide the correct income statement & balance sheet . Adjustment Entry are passed so as to
record the Expenses & Revenue accrued or earned in the period in which it lies.Adjustment entry
are passed to provide true & fair view of financial statement.
(2) Develop the adjusting entry at the end of the period for salary payable to employees $2400
Adjusting EntryAccount Titles and ExplanationDebitCreditSalary & Wages
Expenses2400Salary & Wages Payable2400.
advantages and disadvantages of balanced score cardSolution.pdf
advantages and disadvantages of balanced score card?
Solution
Advantages:
1) It Helps facilitates better communication, coordination and understanding of goals and
strategies accross teams and hierarchy of the organization.
2) Balanced scorecard method enables the firm to focus on all four aspects of a company\'s
performance i.e.
instead of focusing only on financial health, which helps to get proper view of the company
performance.
3) Balanced Scorecards system allows all the stakeholders to determine not only short term, but
long term objectives as well.
4) With the help of balanced scorecard, the organization can be sure that any strategic plan
implemented is inline with the desired outcome.
5) It helps to integrate innovation and process improvement methods such as six sigma and lean
manufacturing to a organizational goal. It also makes sure that the voice of the customer is
equally very important.
Disadvantages:
1) Balanced Scorecard do not consider direct financial analysis of economic value or risk
management. Selection of goal under Balanced Scorecard may not consider opportunity cost.
2) Balanced Scorecard may lead to new type of reporting without improving performance, it may
lead to new set of non-value-added reporting. or, may lead to deviation from achieving actual
goals.
3) Performance of balanced scorecard system may not be quantifiable. As quality levels, it
cannot be quantified except by surveys or management opinion..
Adjusting Entries and Financial StatementsRequired2. Prepare th.pdf
Adjusting Entries and Financial Statements
Required:
2. Prepare the following financial statements and schedule:
a. Income statement
Lundberg Company
Income Statement
For the Year Ended December 31, 20--
Net sales
$
Less cost of goods sold:
$
$
Cost of goods sold
Gross profit
$
Operating expenses:
$
Total operating expenses
Operating income
$
Other revenue:
$
Other expense:
Income before income taxes
$
Net income
$
b. Schedule of cost of goods manufactured
Lundberg Company
Schedule of Cost of Goods Manufactured
For the Year Ended December 31, 20--
$
Direct materials
$
$
Cost of materials used
$
Cost of direct materials used
$
Total manufacturing costs
Total work in process during the period
$
Cost of goods manufactured
$
c. Statement of retained earnings
Lundberg Company
Statement of Retained Earnings
For the Year Ended December 31, 20--
$
$
$
d. Balance sheet
Lundberg Company
December 31, 20--
Current assets:
$
$
Inventories:
$
Total current assets
$
Property, plant, and equipment:
$
$
$
Total property, plant, and equipment
Total assets
$
Current liabilities:
$
Total current liabilities
$
Long-term liabilities:
Total liabilities
$
$
Total stockholders\' equity
Total liabilities and stockholders\' equity
$Hide
Hint(s)
2. Prepare the following financial statements and schedule:
a. Income statement
Lundberg Company
Income Statement
For the Year Ended December 31, 20--
Net sales
$
Less cost of goods sold:
$
$
Cost of goods sold
Gross profit
$
Operating expenses:
$
Total operating expenses
Operating income
$
Other revenue:
$
Other expense:
Income before income taxes
$
Net income
$
Solution
(A). Lundberg Company
Income Statement For the year ended December/31/2014
(B).
Account ParticularsAmountAmountNet Sales$405Less: Cost of Goods Sold$190Gross
Profit$215Operating ExpencessWages Exp$70Ofice Exp$1Bad debt Exp$3Utilities
Exp$4$78Operating Profit Before Interest& Tax Expences $137Non-operating
ExpencessInterest Exp $7ncome Tax Exp$18$25Non-operating Expencess$112Non-Operating
IncomeInerest Revenue$3$3Net Income$115.
Aeroplanes arrive at ChicagoSolution Using a.pdf
Aeroplanes arrive at Chicago
Solution
Using a normal approximation to the Poisson distribution we have a mean of 5.5
and a standard deviation of v5.5= 2.3452 Using a continuity correction we have z= (7.5 -
5.5)/2.3452= 0.85 Checking a normal table we find P(x>7) = .1977..
After an effective orientation, the employee should emerge with info.pdf
After an effective orientation, the employee should emerge with information about which three
matters?
Solution
The employees should emerge with the following information
(1) vision and mission of the organization
(2) their role in the organization both as an individual as well as a team player
(3) their rights and things they are accountable for.
All of Ralphs ranch land was divided equally among his six child.pdf
All of Ralph\'s ranch land was divided equally among his six children. His daughter Lynn\'s
portion of the ranch land was divided equally among her four children. How much of Ralph\'s
ranch land was inherited by 1 of Lynn\'s children
All of Ralph\'s ranch land was divided equally among his six children. His daughter Lynn\'s
portion of the ranch land was divided equally among her four children. How much of Ralph\'s
ranch land was inherited by 1 of Lynn\'s children
Solution
ynn received 1/6 of the land. She then divided her 1/6 of the land in 4 parts. So each of her kids
received 1/4 of her piece.
Therefore, each of Lynn\'s kids received 1/4*1/6 = 1/24.
All numbers are equal Figure out what is wrong with the proof below.pdf
All numbers are equal Figure out what is wrong with the proof below Proof: let n be a natural
number. Let Sn be the statement that in a set of n numbers all number are equal We will prove
by induction that Sn is true for all natural numbers n=1,2,3,
Solution
You need to verify S1 and S2 both are true or not, here you have verified only S1.
Recommended
After class a student comments to me, “Once a poll has been taken,.pdf
After class a student comments to me, “Once a poll has been taken,
(the sample proportion with a certain opinion) is a known value, so it cannot have
a distribution of possible values. Therefore, I do not understand what you mean
by the sampling distribution of.” Write an explanation for this student.
Solution
A poll is just one sample of the population. If you took other samples (of the same
size) you would get different proportions. The distribution of the proportions of all the samples
taken is a sampling distribution..
Adjusting entries are required at the end of the period for some acc.pdf
Adjusting entries are required at the end of the period for some accounts. (1) Explain why this
process is required (15 points) and (2) develop the adjusting entry at the end of the period for
salary payable to employees $2400 (10 points).
Solution
Adjusting entries are required at the end of the period for some accounts, This process is required
due to accrual based of accounting i.e Mercantile Accounting , Adjustment entry are passed so as
to provide the correct income statement & balance sheet . Adjustment Entry are passed so as to
record the Expenses & Revenue accrued or earned in the period in which it lies.Adjustment entry
are passed to provide true & fair view of financial statement.
(2) Develop the adjusting entry at the end of the period for salary payable to employees $2400
Adjusting EntryAccount Titles and ExplanationDebitCreditSalary & Wages
Expenses2400Salary & Wages Payable2400.
advantages and disadvantages of balanced score cardSolution.pdf
advantages and disadvantages of balanced score card?
Solution
Advantages:
1) It Helps facilitates better communication, coordination and understanding of goals and
strategies accross teams and hierarchy of the organization.
2) Balanced scorecard method enables the firm to focus on all four aspects of a company\'s
performance i.e.
instead of focusing only on financial health, which helps to get proper view of the company
performance.
3) Balanced Scorecards system allows all the stakeholders to determine not only short term, but
long term objectives as well.
4) With the help of balanced scorecard, the organization can be sure that any strategic plan
implemented is inline with the desired outcome.
5) It helps to integrate innovation and process improvement methods such as six sigma and lean
manufacturing to a organizational goal. It also makes sure that the voice of the customer is
equally very important.
Disadvantages:
1) Balanced Scorecard do not consider direct financial analysis of economic value or risk
management. Selection of goal under Balanced Scorecard may not consider opportunity cost.
2) Balanced Scorecard may lead to new type of reporting without improving performance, it may
lead to new set of non-value-added reporting. or, may lead to deviation from achieving actual
goals.
3) Performance of balanced scorecard system may not be quantifiable. As quality levels, it
cannot be quantified except by surveys or management opinion..
Adjusting Entries and Financial StatementsRequired2. Prepare th.pdf
Adjusting Entries and Financial Statements
Required:
2. Prepare the following financial statements and schedule:
a. Income statement
Lundberg Company
Income Statement
For the Year Ended December 31, 20--
Net sales
$
Less cost of goods sold:
$
$
Cost of goods sold
Gross profit
$
Operating expenses:
$
Total operating expenses
Operating income
$
Other revenue:
$
Other expense:
Income before income taxes
$
Net income
$
b. Schedule of cost of goods manufactured
Lundberg Company
Schedule of Cost of Goods Manufactured
For the Year Ended December 31, 20--
$
Direct materials
$
$
Cost of materials used
$
Cost of direct materials used
$
Total manufacturing costs
Total work in process during the period
$
Cost of goods manufactured
$
c. Statement of retained earnings
Lundberg Company
Statement of Retained Earnings
For the Year Ended December 31, 20--
$
$
$
d. Balance sheet
Lundberg Company
December 31, 20--
Current assets:
$
$
Inventories:
$
Total current assets
$
Property, plant, and equipment:
$
$
$
Total property, plant, and equipment
Total assets
$
Current liabilities:
$
Total current liabilities
$
Long-term liabilities:
Total liabilities
$
$
Total stockholders\' equity
Total liabilities and stockholders\' equity
$Hide
Hint(s)
2. Prepare the following financial statements and schedule:
a. Income statement
Lundberg Company
Income Statement
For the Year Ended December 31, 20--
Net sales
$
Less cost of goods sold:
$
$
Cost of goods sold
Gross profit
$
Operating expenses:
$
Total operating expenses
Operating income
$
Other revenue:
$
Other expense:
Income before income taxes
$
Net income
$
Solution
(A). Lundberg Company
Income Statement For the year ended December/31/2014
(B).
Account ParticularsAmountAmountNet Sales$405Less: Cost of Goods Sold$190Gross
Profit$215Operating ExpencessWages Exp$70Ofice Exp$1Bad debt Exp$3Utilities
Exp$4$78Operating Profit Before Interest& Tax Expences $137Non-operating
ExpencessInterest Exp $7ncome Tax Exp$18$25Non-operating Expencess$112Non-Operating
IncomeInerest Revenue$3$3Net Income$115.
Aeroplanes arrive at ChicagoSolution Using a.pdf
Aeroplanes arrive at Chicago
Solution
Using a normal approximation to the Poisson distribution we have a mean of 5.5
and a standard deviation of v5.5= 2.3452 Using a continuity correction we have z= (7.5 -
5.5)/2.3452= 0.85 Checking a normal table we find P(x>7) = .1977..
After an effective orientation, the employee should emerge with info.pdf
After an effective orientation, the employee should emerge with information about which three
matters?
Solution
The employees should emerge with the following information
(1) vision and mission of the organization
(2) their role in the organization both as an individual as well as a team player
(3) their rights and things they are accountable for.
All of Ralphs ranch land was divided equally among his six child.pdf
All of Ralph\'s ranch land was divided equally among his six children. His daughter Lynn\'s
portion of the ranch land was divided equally among her four children. How much of Ralph\'s
ranch land was inherited by 1 of Lynn\'s children
All of Ralph\'s ranch land was divided equally among his six children. His daughter Lynn\'s
portion of the ranch land was divided equally among her four children. How much of Ralph\'s
ranch land was inherited by 1 of Lynn\'s children
Solution
ynn received 1/6 of the land. She then divided her 1/6 of the land in 4 parts. So each of her kids
received 1/4 of her piece.
Therefore, each of Lynn\'s kids received 1/4*1/6 = 1/24.
All numbers are equal Figure out what is wrong with the proof below.pdf
All numbers are equal Figure out what is wrong with the proof below Proof: let n be a natural
number. Let Sn be the statement that in a set of n numbers all number are equal We will prove
by induction that Sn is true for all natural numbers n=1,2,3,
Solution
You need to verify S1 and S2 both are true or not, here you have verified only S1.
All human blood can be ABO typed as belonging to one of group A,.pdf
All human blood can be \"ABO\" typed as belonging to one of group A, B, O, or AB types. The
actual distribution varies slightly among different group of people, but for a randomly chosen
person from North America, the following are the approximate probabilities:Blood type O, A, B,
AB and Probability 0.45, 0.40, 0.11, 0.04. Consider an accident victim with type B blood. She
can only receive a transfusion from a person with type B or type O blood. What is the probability
that a randomly chosen person will be suitable donor?
Solution
The probability that the donor is suitable equals the probability that the blood is
type B or type O is P(B) + P(O) = .45 + .11 = .56.
All debentures are bonds but not all bonds are debenturestrue or f.pdf
All debentures are bonds but not all bonds are debentures
true or false
Solution
true: all debentures are bonds but not all bonds are debentures.
both the debentures and bonds are debt instruments.but bonds are generally considered safe
compared to debentures with little risk.
debentures are more specific compared to bonds, debentures are not asset backed..
All code should be in C++Using the UnsortedList class (UnsortedLis.pdf
All code should be in C++
Using the UnsortedList class (UnsortedList.h file below) write a function sublist which extracts
elements that are smaller than a given item from the given list and forms a new list. The
precondition of the function is: the list has been initialized and is not empty. The postconditions
are: newList contains all the items of the list whose values are less than the given item.
Implement the sublist function as a friend function of the UnsortedList class whose declaration
is:
friend void sublist(const UnsortedList& list,
const ItemType& item,
UnsortedList& newList);
(Hint: The UnsortedList class has private members
ItemType list[MAX_LENGTH];
int length;
and the member functions getLength, resetList, insert, remove, etc.)
//**********************************************************
// SPECIFICATION FILE (UnsortedList.h)
// This file gives the specification of a basic class
// template for unsorted array-based lists.
// The list components are not assumed to be in order by
// value.
//**********************************************************
#ifndef UNSORTEDLIST_H
#define UNSORTEDLIST_H
#include
#include // Needed for the exit function
using namespace std;
const int MAX_LENGTH = 100; // Maximum number of components
template // You may also choose to use
// typedef statement
class UnsortedList
{
public:
// Constructor
UnsortedList();
// Post: Empty list has been created. length has been set to zero.
// Knowledge responsibilities
int getLength() const;
// Post: Returns the length of the list
bool isEmpty() const;
// Post: Returns true if list is empty; false otherwise
bool isFull() const;
// Post: Returns true if list is full; false otherwise
bool isInList(const ItemType& item) const;
// Post: Returns true if item is int the list; false otherwise
int seqSearch(const ItemType& item) const;
// Function to search the list for a given item.
// Post: If item is found, returns the index in the array where
// item is found; otherwise, return -1.
// Action Responsibilities
void resetList();
// Post: The list becomes empty. length has been set to zero.
void insert(const ItemType& item);
// Function to insert item to the end of the list. However, first
// the list is searched to see whether the item to be inserted is
// already in the list.
// Post: list[length] = item and length++. If item is already in
// the list or the list is already full, an appropriate message is
// displayed.
void remove(const ItemType& item);
// Function to remove item from the list.
// Post: If item is found in the list, it is removed from the list
// and length is decremented by one.
// Overloaded [] operator declaration.
// This function returns a reference to the element in the
// array indexed by index.
ItemType& operator[](const int& index);
// Additional operations
void sort();
// Post: list items have been put into ascending order by selection sort
void selectionSort();
// Function to sort the items in the list.
// Post: list items have been put int.
Algebra Use the given zero to find the remaining zeros of the functi.pdf
Algebra Use the given zero to find the remaining zeros of the function. h(x) = 2x4 + 3x3 +16x2
+ 27x - 18; zero: - 3i the remaining zeros of h are . (Use a comma to separate answers as
needed. Use integers or fractions for any numbers in the expression.)
Solution
{ 3i, -2, 1/2}.
Alice and Ben decide to meet at 4 pm at the library to study. Alice .pdf
Alice and Ben decide to meet at 4 pm at the library to study. Alice has a class beforehand, so she
should arrive between 4:00 and 4:05 pm. Ben comes from off campus and should arrive between
4:00 and 4:10 pm. Let X and Y represent how late Alice and Ben are for their 4 pm meeting. X
is uniformly distributed over the [0,5] minutes interval and Y is uniformly distributed over the
[0,10] minutes interval. Alice and Ben arrive independently. a. Find the marginal density
functions fX(x) and fY(y). b. Find the joint density function fXY(x,y). c. Find E(X), V(X),
E(Y), V(Y), Cov(X,Y), Corr(X,Y). d. Find the probability that both Alice and Ben will be late
by no more than 2 minutes each. e. Find the probability that Alice will arrive before Ben.
Solution
(a)
fX(x)
= 1/5 for x in [0,5] and
= 0 for other x
fY(y)
= 1/10 for y in [0,10] and
= 0 for other y
(b)
Since X and Y are independent
fXY(x,y) = fX(x) * fY(y)
= 1/50 for x in [0,5] and y in [0,10]
= 0 for other x and y
(c)
for uniform distr. E = (a+b)/2 V = (a-b)^2/12
E(X) = (5+0)/2 = 2.5
E(Y) = 10/2 = 5
V(X) = (5-0)^2/12 = 25/12
V(Y) = (10-0)^2/12 = 25/3
Cov(X,Y) = 0 (since x and y are independent)
Cor(X,Y) = 0 (same reason)
(d)
P(X<2,Y<2)
= (double integral) fXY dx dy from x =0 to 2 and y = 0 to 2
= (1/50)*(2-0)*(2-0)
= 2/25
(e)
P(X.
algebra complex number solve z7 =1SolutionAccording to the f.pdf
algebra complex number
solve z7 =1
Solution
According to the fundamental theorem of algebra, the equation z7=1 has 7 roots, called the roots
of unity. Only one of them is obvious: z=1. The other six require polar form. First write 1 in
polar form:
1 = ePi*in, where n is any integer.
Then set
z7=ePi*in
and take the seventh root:
z=ePi*in/7
Now substitute in values for n. You only need the values n=0,1,2,3,4,5, and 6, because the
answer will repeat itself for all other n (due to the periodicity of complex exponentials).
For n=0, you get the obvious solution,
z0=e0=1.
For n=1, you get
z1=ePi*i/7,
which you can write in standard form using Euler\'s identity:
z1=cos(Pi/7)+i sin(Pi/7)
In this way, you get the seven seventh roots of unity.
If you graph them in the complex plane, you will find they all lie equally spaced on the unit
circle..
Alan invested his money at 5 ½ compounded quarterly and Paula inve.pdf
Alan invested his money at 5 ½ % compounded quarterly and Paula invested her money at 6%
compounded annually. Which one of the two rates is higher?
Solution
The formula for compound interest is:
A = P(1 + r/n)^(nt)
where P is the principal (initial investment), r is the rate written as a decimal, n is the number of
times per year you are compounding (so for monthly compounding, say, n=12), t is the number
of years the investment has been earning interest, and A is the total amount in the account after t
years.
For Alan:
r = .055, n = 4 for quarterly compounding
For Paula:
r = .06, n = 1 for annual (once per year) compounding
If both Alan and Paula invest P amount of money for t years, we plug these rates into the
compound interest formula:
AAlan = P(1 + .055/4)^(4t)
= P(1.01375)^(4t)
= P[(1.01375)^4]^t (multiplying exponents is the same as raising a power to a power)
= P(1.05614481)^t
APaula = P(1 + .06/1)^(1*t)
= P(1.06)^t
Since after investing P initial dollars for t years, Alan will have P(1.05614481)^t dollars and
Paula will have P(1.06)^t dollars, and since P(1.06)^t > P(1.05614481)^t as both bases are
greater than 1 and 1.06 > 1.056...., Paula has the better rate for her investment..
Alberts Company has current earnings of $4.20 per share. The compa.pdf
Albert\'s Company has current earnings of $4.20 per share. The company intends to use part of
its earnings for investments that will generate a return of 20%. The cost of capital of Albert\'s is
15%, and its current stock price is $40. What is the percentage of the earnings Albert\'s intends to
reinvest (i.e., the retention ratio)? What is the value of Albert’s growth opportunities?
Solution
EPS = 4.20
r = 20%
Ko = 15%
Po = EPS/Ke-g
40 = 4.20/(0.15-g)
0.15 - g = 0.105
g = 4.5%
g = b * r
0.045 = b * 0.20
b = 22.5%
Retention Ration = 22.5%
Dividend Payout Ration = 100%-22.5% = 77.5%
Dividend = 4.20 * 77.5% = 3.255
Value of growth opportunity = value of firm with growth - value of firm without growth
= D1/(Ke-g) - EPS/Ke
= 3.255/(0.15-0.045) - 4.20/0.15
= 31 - 28
= 3.
Airline passengers arrive randomly and independetly at the passenger.pdf
Airline passengers arrive randomly and independetly at the passenger screening facility at a
major international airport. the mean arrival rate is 10 passengers per minute. compute the
probability of no arrivals in a 15 second period.
Solution
Mean in 15 sec period is 10/4= 2.5. So using the Poisson distribution the probability
of no arrivals is e^(-2.5)= 0.08208.
After reading MartinSolution A civil court h.pdf
After reading Martin
Solution
A civil court hears a transnational dispute between private parties, which, according
to the forum’s choice of law rules, is governed by a foreign lex causae. One party submits that it
considers the foreign statute applicable to the dispute to be incompatible with the constitutional
law of the lex causae and wishes to lead evidence to that effect, or ask the court to inquire into
that question, with a view to having the impugned provision disapplied and the dispute decided
on the basis of other provisions of the lex causae. How will the court respond to that submission;
what does the forum’s private international law require it to do in these circumstances? This
question will be addressed in this essay with respect to the laws of England as applied by the
German courts on the one hand and those of Germany applied by English courts on the other.
The study will deal exclusively with the effects which an incompatibility of primary legislation
with constitutional norms of the lex causae creates from a private international law perspective
and will therefore not address the questions of ‘unconstitutional’ subordinate legislation and,
falling into a very similar category from a European law perspective, national primary legislation
in contravention of EC law1. It is conceded that the practical scope of the problem of
constitutional review of provisions of the foreign lex causae in the forum courts with respect to
the laws of two states that, like England and Germany, by and large, share common values and,
as member states of the European Community, show significant convergence or even uniformity
in many areas of the law, is indeed a limited one. This finding is reinforced by the distinct
‘homeward trend’ of the English choice of law rules governing important areas of the law such
as family law2. The fact, however, that the only case that has - so far - come to the English
courts where the court was squarely faced with the question of permissibility of constitutional
review of the foreign lex causae provision, related to the corporate law of another EC member
state (Italy)3, demonstrates at least a residual practical importance of this matter. Furthermore, a
considerable number of aspects that will be discussed in the course of this study will also be
applicable to instances where German or English law will have to be applied in fora other than
England or Germany. However, what makes the present topic particularly interesting, are the
respective peculiarities of English and German constitutional law and their practical effect on
transnational civil litigation of the kind in issue. In trying to find a satisfactory answer to the
question as to how the English and German forum courts should react when faced with an
allegation of ‘unconstitutionality’ of a lex causae statute, jurisprudence and, to a larger extent,
influential scholarly writing will be presented and critically examined. In chapter II, the attitude
taken by E.
বাংলাদেশ অর্থনৈতিক সমীক্ষা (Economic Review) ২০২৪ UJS App.pdf
বাংলাদেশের অর্থনৈতিক সমীক্ষা ২০২৪ [Bangladesh Economic Review 2024 Bangla.pdf] কম্পিউটার , ট্যাব ও স্মার্ট ফোন ভার্সন সহ সম্পূর্ণ বাংলা ই-বুক বা pdf বই " সুচিপত্র ...বুকমার্ক মেনু 🔖 ও হাইপার লিংক মেনু 📝👆 যুক্ত ..
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All human blood can be ABO typed as belonging to one of group A,.pdf
All human blood can be \"ABO\" typed as belonging to one of group A, B, O, or AB types. The
actual distribution varies slightly among different group of people, but for a randomly chosen
person from North America, the following are the approximate probabilities:Blood type O, A, B,
AB and Probability 0.45, 0.40, 0.11, 0.04. Consider an accident victim with type B blood. She
can only receive a transfusion from a person with type B or type O blood. What is the probability
that a randomly chosen person will be suitable donor?
Solution
The probability that the donor is suitable equals the probability that the blood is
type B or type O is P(B) + P(O) = .45 + .11 = .56.
All debentures are bonds but not all bonds are debenturestrue or f.pdf
All debentures are bonds but not all bonds are debentures
true or false
Solution
true: all debentures are bonds but not all bonds are debentures.
both the debentures and bonds are debt instruments.but bonds are generally considered safe
compared to debentures with little risk.
debentures are more specific compared to bonds, debentures are not asset backed..
All code should be in C++Using the UnsortedList class (UnsortedLis.pdf
All code should be in C++
Using the UnsortedList class (UnsortedList.h file below) write a function sublist which extracts
elements that are smaller than a given item from the given list and forms a new list. The
precondition of the function is: the list has been initialized and is not empty. The postconditions
are: newList contains all the items of the list whose values are less than the given item.
Implement the sublist function as a friend function of the UnsortedList class whose declaration
is:
friend void sublist(const UnsortedList& list,
const ItemType& item,
UnsortedList& newList);
(Hint: The UnsortedList class has private members
ItemType list[MAX_LENGTH];
int length;
and the member functions getLength, resetList, insert, remove, etc.)
//**********************************************************
// SPECIFICATION FILE (UnsortedList.h)
// This file gives the specification of a basic class
// template for unsorted array-based lists.
// The list components are not assumed to be in order by
// value.
//**********************************************************
#ifndef UNSORTEDLIST_H
#define UNSORTEDLIST_H
#include
#include // Needed for the exit function
using namespace std;
const int MAX_LENGTH = 100; // Maximum number of components
template // You may also choose to use
// typedef statement
class UnsortedList
{
public:
// Constructor
UnsortedList();
// Post: Empty list has been created. length has been set to zero.
// Knowledge responsibilities
int getLength() const;
// Post: Returns the length of the list
bool isEmpty() const;
// Post: Returns true if list is empty; false otherwise
bool isFull() const;
// Post: Returns true if list is full; false otherwise
bool isInList(const ItemType& item) const;
// Post: Returns true if item is int the list; false otherwise
int seqSearch(const ItemType& item) const;
// Function to search the list for a given item.
// Post: If item is found, returns the index in the array where
// item is found; otherwise, return -1.
// Action Responsibilities
void resetList();
// Post: The list becomes empty. length has been set to zero.
void insert(const ItemType& item);
// Function to insert item to the end of the list. However, first
// the list is searched to see whether the item to be inserted is
// already in the list.
// Post: list[length] = item and length++. If item is already in
// the list or the list is already full, an appropriate message is
// displayed.
void remove(const ItemType& item);
// Function to remove item from the list.
// Post: If item is found in the list, it is removed from the list
// and length is decremented by one.
// Overloaded [] operator declaration.
// This function returns a reference to the element in the
// array indexed by index.
ItemType& operator[](const int& index);
// Additional operations
void sort();
// Post: list items have been put into ascending order by selection sort
void selectionSort();
// Function to sort the items in the list.
// Post: list items have been put int.
Algebra Use the given zero to find the remaining zeros of the functi.pdf
Algebra Use the given zero to find the remaining zeros of the function. h(x) = 2x4 + 3x3 +16x2
+ 27x - 18; zero: - 3i the remaining zeros of h are . (Use a comma to separate answers as
needed. Use integers or fractions for any numbers in the expression.)
Solution
{ 3i, -2, 1/2}.
Alice and Ben decide to meet at 4 pm at the library to study. Alice .pdf
Alice and Ben decide to meet at 4 pm at the library to study. Alice has a class beforehand, so she
should arrive between 4:00 and 4:05 pm. Ben comes from off campus and should arrive between
4:00 and 4:10 pm. Let X and Y represent how late Alice and Ben are for their 4 pm meeting. X
is uniformly distributed over the [0,5] minutes interval and Y is uniformly distributed over the
[0,10] minutes interval. Alice and Ben arrive independently. a. Find the marginal density
functions fX(x) and fY(y). b. Find the joint density function fXY(x,y). c. Find E(X), V(X),
E(Y), V(Y), Cov(X,Y), Corr(X,Y). d. Find the probability that both Alice and Ben will be late
by no more than 2 minutes each. e. Find the probability that Alice will arrive before Ben.
Solution
(a)
fX(x)
= 1/5 for x in [0,5] and
= 0 for other x
fY(y)
= 1/10 for y in [0,10] and
= 0 for other y
(b)
Since X and Y are independent
fXY(x,y) = fX(x) * fY(y)
= 1/50 for x in [0,5] and y in [0,10]
= 0 for other x and y
(c)
for uniform distr. E = (a+b)/2 V = (a-b)^2/12
E(X) = (5+0)/2 = 2.5
E(Y) = 10/2 = 5
V(X) = (5-0)^2/12 = 25/12
V(Y) = (10-0)^2/12 = 25/3
Cov(X,Y) = 0 (since x and y are independent)
Cor(X,Y) = 0 (same reason)
(d)
P(X<2,Y<2)
= (double integral) fXY dx dy from x =0 to 2 and y = 0 to 2
= (1/50)*(2-0)*(2-0)
= 2/25
(e)
P(X.
algebra complex number solve z7 =1SolutionAccording to the f.pdf
algebra complex number
solve z7 =1
Solution
According to the fundamental theorem of algebra, the equation z7=1 has 7 roots, called the roots
of unity. Only one of them is obvious: z=1. The other six require polar form. First write 1 in
polar form:
1 = ePi*in, where n is any integer.
Then set
z7=ePi*in
and take the seventh root:
z=ePi*in/7
Now substitute in values for n. You only need the values n=0,1,2,3,4,5, and 6, because the
answer will repeat itself for all other n (due to the periodicity of complex exponentials).
For n=0, you get the obvious solution,
z0=e0=1.
For n=1, you get
z1=ePi*i/7,
which you can write in standard form using Euler\'s identity:
z1=cos(Pi/7)+i sin(Pi/7)
In this way, you get the seven seventh roots of unity.
If you graph them in the complex plane, you will find they all lie equally spaced on the unit
circle..
Alan invested his money at 5 ½ compounded quarterly and Paula inve.pdf
Alan invested his money at 5 ½ % compounded quarterly and Paula invested her money at 6%
compounded annually. Which one of the two rates is higher?
Solution
The formula for compound interest is:
A = P(1 + r/n)^(nt)
where P is the principal (initial investment), r is the rate written as a decimal, n is the number of
times per year you are compounding (so for monthly compounding, say, n=12), t is the number
of years the investment has been earning interest, and A is the total amount in the account after t
years.
For Alan:
r = .055, n = 4 for quarterly compounding
For Paula:
r = .06, n = 1 for annual (once per year) compounding
If both Alan and Paula invest P amount of money for t years, we plug these rates into the
compound interest formula:
AAlan = P(1 + .055/4)^(4t)
= P(1.01375)^(4t)
= P[(1.01375)^4]^t (multiplying exponents is the same as raising a power to a power)
= P(1.05614481)^t
APaula = P(1 + .06/1)^(1*t)
= P(1.06)^t
Since after investing P initial dollars for t years, Alan will have P(1.05614481)^t dollars and
Paula will have P(1.06)^t dollars, and since P(1.06)^t > P(1.05614481)^t as both bases are
greater than 1 and 1.06 > 1.056...., Paula has the better rate for her investment..
Alberts Company has current earnings of $4.20 per share. The compa.pdf
Albert\'s Company has current earnings of $4.20 per share. The company intends to use part of
its earnings for investments that will generate a return of 20%. The cost of capital of Albert\'s is
15%, and its current stock price is $40. What is the percentage of the earnings Albert\'s intends to
reinvest (i.e., the retention ratio)? What is the value of Albert’s growth opportunities?
Solution
EPS = 4.20
r = 20%
Ko = 15%
Po = EPS/Ke-g
40 = 4.20/(0.15-g)
0.15 - g = 0.105
g = 4.5%
g = b * r
0.045 = b * 0.20
b = 22.5%
Retention Ration = 22.5%
Dividend Payout Ration = 100%-22.5% = 77.5%
Dividend = 4.20 * 77.5% = 3.255
Value of growth opportunity = value of firm with growth - value of firm without growth
= D1/(Ke-g) - EPS/Ke
= 3.255/(0.15-0.045) - 4.20/0.15
= 31 - 28
= 3.
Airline passengers arrive randomly and independetly at the passenger.pdf
Airline passengers arrive randomly and independetly at the passenger screening facility at a
major international airport. the mean arrival rate is 10 passengers per minute. compute the
probability of no arrivals in a 15 second period.
Solution
Mean in 15 sec period is 10/4= 2.5. So using the Poisson distribution the probability
of no arrivals is e^(-2.5)= 0.08208.
After reading MartinSolution A civil court h.pdf
After reading Martin
Solution
A civil court hears a transnational dispute between private parties, which, according
to the forum’s choice of law rules, is governed by a foreign lex causae. One party submits that it
considers the foreign statute applicable to the dispute to be incompatible with the constitutional
law of the lex causae and wishes to lead evidence to that effect, or ask the court to inquire into
that question, with a view to having the impugned provision disapplied and the dispute decided
on the basis of other provisions of the lex causae. How will the court respond to that submission;
what does the forum’s private international law require it to do in these circumstances? This
question will be addressed in this essay with respect to the laws of England as applied by the
German courts on the one hand and those of Germany applied by English courts on the other.
The study will deal exclusively with the effects which an incompatibility of primary legislation
with constitutional norms of the lex causae creates from a private international law perspective
and will therefore not address the questions of ‘unconstitutional’ subordinate legislation and,
falling into a very similar category from a European law perspective, national primary legislation
in contravention of EC law1. It is conceded that the practical scope of the problem of
constitutional review of provisions of the foreign lex causae in the forum courts with respect to
the laws of two states that, like England and Germany, by and large, share common values and,
as member states of the European Community, show significant convergence or even uniformity
in many areas of the law, is indeed a limited one. This finding is reinforced by the distinct
‘homeward trend’ of the English choice of law rules governing important areas of the law such
as family law2. The fact, however, that the only case that has - so far - come to the English
courts where the court was squarely faced with the question of permissibility of constitutional
review of the foreign lex causae provision, related to the corporate law of another EC member
state (Italy)3, demonstrates at least a residual practical importance of this matter. Furthermore, a
considerable number of aspects that will be discussed in the course of this study will also be
applicable to instances where German or English law will have to be applied in fora other than
England or Germany. However, what makes the present topic particularly interesting, are the
respective peculiarities of English and German constitutional law and their practical effect on
transnational civil litigation of the kind in issue. In trying to find a satisfactory answer to the
question as to how the English and German forum courts should react when faced with an
allegation of ‘unconstitutionality’ of a lex causae statute, jurisprudence and, to a larger extent,
influential scholarly writing will be presented and critically examined. In chapter II, the attitude
taken by E.
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