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247– Παράδειγμα 5.13 στο βαρυτικό πεδίο
ΓΕΛ Νυδριού Λευκάδος
Γουρζής Στάθης – Φυσικός
ΥΣΕΦΕ 2020 - 2021
και =>
=> =>
½ m1.υ1
2 = ½ m1.(υ2m2/m1)2 =½ m1υ2
2m2
2 /m1
2 = ½ υ2
2 m2
2/m1
=> 0 = - G (m1.m2)/l + ½ m2
2 /m1 . υ2
2 + ½ m2.υ2
2 =>
=> G (m1.m2)/l = ½ m2
2 /m1 .υ2
2 + ½ m2.υ2
2
=>
=> G (m1.m2)/l = ½ (m2
2 /m1.υ2
2 + m2.υ2
2 ) =>
=> 2G (m1.m2) /l = m2
2 /m1.υ2
2 + m2.υ2
2
=>
=>
=>
=>
2G (m1.m2) /l = (m2
2 /m1 + m2).υ2
2
2G ((m1.m2) /l) . m1= (m2
2 /m1 + m2).υ2
2 m1
2G ((m1.m2) /l). m1= (m2
2 .m1 /m1 + m2m1).υ2
2=> =>
=> 2G ((m1.m2) /l). m1= (m2
2 + m2m1).υ2
2 =>
=>
2G (m1
2.m2) /l= m2 (m2 + m1).υ2
2
=>
=>
2G ((m1.m2) /l). m1= m2 (m2 + m1).υ2
2
=>
2G (m1
2 )/l= (m2 + m1).υ2
2 =>
=>
=>
m1
2 (2G /l(m2 + m1))= υ2
2 =>=>
m1 (2G /l(m2 + m1))= υ2
m1 (2G /l(m2 + m1))= υ2
υ1 =m1 (2G /l(m2 + m1)) m2/m1
=>
=>
υ1 = (2G /l(m2 + m1)) m2
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247 - Paradeigma 5 13 barutiko pedio

  • 1. 247– Παράδειγμα 5.13 στο βαρυτικό πεδίο ΓΕΛ Νυδριού Λευκάδος Γουρζής Στάθης – Φυσικός ΥΣΕΦΕ 2020 - 2021
  • 2.
  • 3.
  • 4.
  • 5.
  • 6.
  • 7.
  • 8.
  • 9. και => => => ½ m1.υ1 2 = ½ m1.(υ2m2/m1)2 =½ m1υ2 2m2 2 /m1 2 = ½ υ2 2 m2 2/m1
  • 10. => 0 = - G (m1.m2)/l + ½ m2 2 /m1 . υ2 2 + ½ m2.υ2 2 => => G (m1.m2)/l = ½ m2 2 /m1 .υ2 2 + ½ m2.υ2 2 => => G (m1.m2)/l = ½ (m2 2 /m1.υ2 2 + m2.υ2 2 ) => => 2G (m1.m2) /l = m2 2 /m1.υ2 2 + m2.υ2 2 => => => => 2G (m1.m2) /l = (m2 2 /m1 + m2).υ2 2 2G ((m1.m2) /l) . m1= (m2 2 /m1 + m2).υ2 2 m1
  • 11. 2G ((m1.m2) /l). m1= (m2 2 .m1 /m1 + m2m1).υ2 2=> => => 2G ((m1.m2) /l). m1= (m2 2 + m2m1).υ2 2 => => 2G (m1 2.m2) /l= m2 (m2 + m1).υ2 2 => => 2G ((m1.m2) /l). m1= m2 (m2 + m1).υ2 2 => 2G (m1 2 )/l= (m2 + m1).υ2 2 => => => m1 2 (2G /l(m2 + m1))= υ2 2 =>=> m1 (2G /l(m2 + m1))= υ2
  • 12. m1 (2G /l(m2 + m1))= υ2 υ1 =m1 (2G /l(m2 + m1)) m2/m1 => => υ1 = (2G /l(m2 + m1)) m2