This transistor is operating in the cutoff Region Saturation Region. Active Region. Power Dissipation Region. Solution Given Transistor is an npn transistor From the figure it is clear that Base(B) is at 5V Emitter(E) is at 7V Collector(C) is at 10V. This implies Emitter Base Junction is reverse biased and Collector Base Juncition is also reverse Biased There fore the answer is The given npn transitor is in Cutoff region..