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Ma301 group project 1 [autosaved]
- 2. See Wenyu
- 3. Keith Kwan
- 4. Carissa Lim
- 6. Proof Let <BOP be y. <OBP = <OPB = (180 - y)/2 (base angle of isosceles OBP; OB=OP – radii) Let <AOB be x. <AOB = (x + y) <OAP = <OPA = [180 - (x+y)] / 2 (base < of isosceles OAP; OA=OP – radii) <OPB - <OPA = <APB (180 – y) – [180 - (x+y)] 2 2 = 180 – y – 180 + x + y 2 = x 2 Task A - Content Knowledge <AOB = 2 <APB; < at centre = 2 < at circumference P O y x B A