In the paramyxoviruses, cleavage of the F0 protein into two subunits .pdf

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In the paramyxoviruses, cleavage of the F0 protein into two subunits F1 and F2 is important for which of the following? glycosylation of the protein creation of the transmembrane domain formation of the envelope exposing the fusion peptide Solution Answer: D. exposing the fusion peptide Explanation: Paramyxoviruses contain two membrane glycoproteins, the fusion protein (F) and the hemagglutinin-neuraminidase protein (HN). The F protein is synthesized as an uncleaved, inactive form (F0) and is cleaved into F1 and F2 subunits. Cleavage of the F protein by a trypsin- like protease is required for virus infectivity. The exposure of a new hydrophobic domain at the N terminus of the F1 subunit appears to be essential for the membrane fusion activity of the F protein. The other glycoprotein, HN, binds to sialic acid-containing receptors and possesses neuraminidase activity..

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We are interested in whether the proportions of female suicide victims for ages 15 to 24 are the same for the white and the black races in the united states. we randomly pick one year, 1992, to compose the races. The number of suicides estimate for black in 1992 for the white females is 4930. 580 were aged 15 to 24. The estimate for black females is 330. 40 were aged 15 to 24. we will let female suicide victims be our population. (source: the National Center for Health statistics, U.S. Dept. of Health and Human services) Solution.

We are interested in whether the proportions of female suicide victim.pdf

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True or false Fruits attract animals that act as pollinators T.pdf

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the observed locations of integrated retroviral proviruses within host cell chromosomes suggest: a) Specificity b) Preference Solution Answer: b). Preference Explanation: Retroviruses differ in their preferences for sites for viral DNA integration in the chromosomes of infected cells. Human immunodeficiency virus (HIV) integrates preferentially within active transcription units, whereas murine leukemia virus (MLV) integrates preferentially near transcription start sites and CpG islands.

the observed locations of integrated retroviral proviruses within ho.pdf

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The general name for something that binds to a protein is Select one: substrate domain coenzyme inhibitor ligand Solution C. Coenzyme A coenzyme can bind to the protein portion of the enzyme either covalently or noncovalently. Some cofactor are simple metal ions and other cofactor are complex organic group which are called coenzyme. Binding of coenzyme is necessary for the activity of the protein..

The general name for something that binds to a protein is Select one.pdf

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serial communication, parallel communication, SPI and ADC\'s. Write a paragraph about serial communication and how ADC\'s work. Solution Serial Communication: Serial Communication is process of sending data one by one at a time over a communication channel. Parallel communication: Parallel Communication is method of conveying multiple bits at a time over a communication channel. Serial Peripheral Interface: This is used to send data between microcontrollers and small peripherals. It uses clocks and data lines along with a select line to choose the device we wish to talk to. ADC working: ADC takes input signal as analog signal. It uses a circuit which converts this analog signal to appropriate digital signal. You can refer to wikipedia or any other links for the circuit which converts analog signal to digital signal..

serial communication, parallel communication, SPI and ADCs. Write .pdf

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The first part of the assignment involves creating very basic GUI controls: a frame, panel, and slider. Create a JFrame. Add a title to the frame called Flight Reservation. Set the frame size to 475 by 500 pixels. Create a JPanel inside of the frame. You will be adding all of your UI components to this JPanel. [6 pts] Inside of the panel, create a label that says \"Choose Color.\" Right below it, make a slider that changes the background color of the panel when the slider is moved to a particular color. The slider values should be RGB color values from 0 to 255 (or black to white). Assume that the RGB values for red, green, and blue are the same value - for instance: (240, 240, 240). The slider label\'s text should be replaced with the RGB value that the slider is currently on. [8 pts] Q2: Add functionality to search for an Itinerary. Create labels and text fields that allow the user to enter an airline, a source airport, and a destination airport, as well as the departure time and the arrival time to search for one or more available flights in an Itinerary. Also, create a ComboBox that will allow the user to select from a list of flight Itineraries. Each item in the ComboBox represents an Itinerary element, e.g. the first comboBoxelement is the first Itinerary in the array. [15 pts] Make sure all text fields have error checking and exception handling for invalid input. For example, if the user enters an integer as a departure time instead of a String (ie 1200 instead of 12:00 PM), a JOptionPane error message should appear stating, \"Incorrect format for departure time.\" If the airline they entered is not in the Airline enum, then the option pane should say, \"Airline unavailable. Please choose a different airline.\" If the airport they entered is not in the Airport enum, then the option pane should say, \"Unknown city.\" Make sure the times are in hh:mm format. [8 pts] Q3: Create a button that says Search and a button that says View. When the user clicks Search, the combobox will get populated. When the user clicks View, if all the fields are filled out and have valid input, a JOptionPane with a message dialog should appear stating, \"Flight search successful!\" The frame should open a new JFrame with the title, \"Flight Information,\" and a size of 475 by 500 pixels. This frame has the flight information displayed in a JTextArea. [6 pts] Q4: On the Flight Information frame, you will need to display information for each Flight in the Itinerary [7 points]: Airline: Display the airline Model: The model of the airplane should be generated from the Plane object inside of the Flight class. Departure Airport: Display the source airport Departure City: Display the departure city based on the departure airport (use the getAirportCity() method you implemented in the Unit 3 assignment to get the airport city) Destination Airport: Display the destination airport Destination City: Display the destination city based on the destination airport (use the g.

The first part of the assignment involves creating very basic GUI co.pdf

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Suppose that a heap stores 210 elements. What is its height? (show work with diagrams) Solution A binary heap is a complete binary tree which satisfies the heap ordering property. The maximum number of nodes at level l of the heap is 2l. Therefore a heap of height h stores at most 20+ 21+:+ 2h= 2h +1 – 1 node. If h= 6, then the heap stores at most 27 – 1 =127 elements, which is not enough .so the heap must be of height 7,since for height 7 a heap can store 28 – 1 =255. The last level of the heap is not full..

Suppose that a heap stores 210 elements. What is its height (show w.pdf

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Oxfam used its existing opt-in e-mail list only for this campaign; i.pdf

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Please distinguish between the .h and .cpp file, create a fully working c++ program using the diagram provided. Section 1: Homework Objectives 1. Given a class UML, learn to write a C++ class declaration. 2. Learn how to define/call constructor, accessor, mutator or toString( ) Section 2: Background In this homework, according to the given UML class diagram, you’re required to design a BankAccount class. You are also required to write a driver’s program to test it. Section 3: Program description 3.1 Introduction According to the following UML diagram, design a BankAccount class. BankAccount -id: string = \"?\" -balance: double = 0.0 -address: string = \"?\" +BankAccount() +BankAccount(string, double, string) +getID(): string +getBalance(): double +getAddress(): string +setID(string): void +deposit(double): bool +withdraw(double): bool +updateAddress(string):void +toString(): string +addInterest(): void +equals(BankAccount): bool Member variables and member functions\' description Member Variable Data Type Description id string This represents a bank account\'s unique ID, such as \"123-456- 789\" balance double This is the account balance. address string This represents a bank account customer\'s mailing address, such as \"12345 Via Linda Rd. Phoenix, AZ 85048\" Member Function Function Description BankAccount() This is the default constructor and it should initialize all member varible by the initial value defined inside the UML. For example, id should be initialized to \"?\" etc. BankAccount(string newID, double newBal, string newAddress) This is the overloadded constructor. It takes three input parameters and initialize the three member variables accordingly with the three input parameters. string getID() This is the accessor for member variable id double getBalance() This is the accessor for member variable balance string getAddress() This is the accessor for member variable address void setID(string newID) This is the mutator for member variable id. It takes a new id as input and change the member variable id accordingly bool deposit(double amount) This is a mutator for member variable balance. It takes an amount as input parameter, if the amount of deposit is negative, the balance will not be changed and the function should return false; otherwise, the deposited amount (parameter value) will be added to the balance and the function returns true. bool withdraw(double amount) This is a mutator for member variable balance. It takes an amount as input parameter, if the balance is less than the withdraw amount (parameter value) or the withdraw amount is less than zero, the function should return false, otherwise subtract the balance by withdraw amount and return true. void updateAddress(string newAddress) This is a mutator for member variable address. In case the bank account\'s customer want to change his/her address, we will use this function. string toString() The toString function will display an bank account info. in the following format.

Please distinguish between the .h and .cpp file, create a fully work.pdf

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JUST DO QUESTION 4 1. When you are preparing a budget where could you gather information and data from? 2. How could you estimate parameters for your budget? 3. What are the four stages involved in developing a budget? 4. List and describe the 4 most common budgeting approaches. 5. You have discussed with the human resource manager the new budget. Why is i now important that you incorporate their suggestions and make the modifications to the budget promptly? Solution Four most common budgeting approaches are:.

JUST DO QUESTION 4 1. When you are preparing a budget where could yo.pdf

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Information about dengue fever is provided on the following pages. After studying this information, outline the chain of infection by identifying the reservoir(s), portal(s) of exit, mode(s) of transmission, portal(s) of entry, and factors in host susceptibility. Reservoirs: Portals of exit: Modes of transmission: Portals of entry: Factors in host susceptibility: Solution Reservoirs : Wild monkeys Portals of exit : Mosquitoes Modes of transmission : Female Aedes aegypti Mosquito bite Portals of entry : skin and blood Factors in host susceptibility : all humans are equally susceptible to dengue. recent research suggests that Oligoadenylate synthetases play an important role in the immune response against dengue virus. People living in dengue endemic urban areas are very susceptible.While a person who survives a bout of dengue caused by one serotype develops lifelong immunity to that serotype, there is no cross-protection against the three other serotypes..

Information about dengue fever is provided on the following pages. A.pdf

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A toothcomb, rhinarium or moist nose, and vertical clinging and leaping locomotion, is characteristic of apes savannah baboons. prosimians such as lorises and lemurs. New World monkeys. The first primates probably evolved from primitive that lived before the Cenozoic era. Birds insectivories grassland herbivories hominoids marine mammals Continental drift refers to the movement and masses on top of a partially moiten layer of the earth\'s mantle, resulting in movement of the continents over time. the movement of species from one continent to another in pursuit of gene flow over large continental regions, the result of population movements. a dance step performed by Fred Astaire and Ginger Rogers during the Mooene. Solution Ans 16. \'c\' is the correct answer. Explanation: The given characteristics of are strepsirhines; and the best examples of strepsirhines are lemurs and loris. Ans 17. \'d\' is the correct answer. Explanation: Hominoids were the great apes which lived before Cenozoic era. First primates evolved in early Paleocene from these. Ans 18. a Continental drift refers to movement of continents on Earth. Option \'a\' gives the statement of continental drift theory..

A toothcomb, rhinarium or moist nose, and vertical clinging and leapi.pdf

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If wolves will not cross a highway, what type of isolating mechanism is this? If wolves will not cross a highway, what type of isolating mechanism is this? Solution Answer: If wolves do not cross a highway, the highway may be considered as a geographical barrier and favour conditions for the formation of allopatric species (when populations of the same species get isolated due to geographical separation that prevents interbreeding). Example: Formation of new squirrel species after the formation of grand canyon. Due to this geographical isolation, the north and south species cannot interbreed..

If wolves will not cross a highway, what type of isolating mechani.pdf

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I don\'t understand numbers 14 and 15, please help.. PROBLEM BAS 12, A plant of genotype is testcrossed wil 18 If the two loci are 10 m apart, what proportion of progeny will be AB/ab 13. The A locus and the Dlocus nked that no are so tightly recombination is ever observed between if Ad 1. Ad is crossed with ab,aD d the F, is intercrossed, what phenotypes will be seen in the Fa and in what proportions? 14. The R and Sloci are 35 m.u. apart. If a plant of genotype is selfed, what progeny phenotypes will be seen and in what proportions 15. The cross EE. FF x efe fif s de, and the F1 is then backcrossed with the recessive parent. The progeny gen. ocypes are inferred from the phenotypes. The progeny genotypes, written as the gametic contributions of the heterozygous parent, are in the following proportions: E. F 2 Explain these results. Progeny Class phenotypes. Solution Answers: 14. R S/r s * R S/r s Gametes: 1/2 (1 – 0.35) R S 1/2 (1 – 0.35) r s 1/2 (0.35) R s 1/2 (0.35) r S F1 genotypes will be: 0.1056 R S/R S 0.1138 r s/r S 0.1056 r s/r s 0.1138 r s/R s 0.2113 R S/r s 0.0306 R s/R s 0.1138 R S/r S 0.0306 r S/r S 0.1138 R S/R s 0.0613 R s/r S F1 phenotypes will be: 0.6058 R S 0.1056 r s 0.1444 R s 0.1444 r S 15. The cross: E/e · F/f * e/e · f/f. The progeny should be in a 1:1:1:1 ratio if independent assortment takes place, which is not observed. So, linkage exists. E f and e F are recombinants and equals one-third of the progeny. The two genes are 33.3 map units (m.u.) apart. RF = 100% * 1/3 = 33.3%.

I dont understand numbers 14 and 15, please help.. PROBLEM BAS .pdf

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How many divisors of 2310 have exactly three prime factors A toy pi.pdf

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Graphs A and B depict two ways of determining how molecules (in this case, molecules (X, Y, Z)can gain entry into a cell: (A)Increase the extracellular concentration (Co) of the molecule and measure flux and (B) keep Co constant and measure the intracellular concentration (Ci) of the molecule over time until equilibrium is reached. Which molecule enters by simple diffusion? explain? Which of the molecules enters by facilitated diffusion? explain? Which molecule enters by active transport? explain? Solution (a) The molecule Z enters the cell by simple diffusion. The reason is that, as the extra-cellular concentration (Co) is increased, the flux also increases exponentially. In simple diffusion, the transport of molecules is from a region of high concentration to a region of low concentration. Therefore, as the concentration is increased in the exterior of cell, the flux increases and since it is a passive transportation process, no energy is expended. (b) The molecule X enters the cell by facilitated diffusion. The reason is that, when the extracellular concentration is kept constant, the intracellular concentration (Ci) increases with time until the Co equals Ci. Facilitated diffusion is similar diffusion but with the need of proteins to help in the process. (c) The molecule Y enters the cell by active transport. The reason is that, even when the extracellular concentration is not increased, the Ci increases ith the help of energy driven active transport process..

Graphs A and B depict two ways of determining how molecules (in this .pdf

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Comment upon Charles Greene’s (1975) suggestion that follower performance may shape the behavior (e.g., consideration and initiating structure) that the leader engages in. Solution Leadership theories explore the relationship between leaders, followers and situational factors. Leaders and followers do not exist independent of one another. The presence of one is dependent on the of the other. At the same time, each has a unique role to play. While leaders and followers maintain distinctive roles, a leadership relationship is based on leader-follower reciprocity hence generating a leadership system within a situational context. Reciprocity is based on expected results of behaviors and actions. By fulfilling their respective roles, leaders and followers make a feedback loop. This continuous communication and interaction drives leader-follower reciprocity. As leaders and followers try to fulfill their roles towards achieving expected ends within the parameters of their current situation, they make an interconnected mechanism where cause and effect are difficult to differentiate from one another. Thus, leadership must be studied as a system rather than a sum of individual parts. In his article, The Reciprocal Nature of Influence between Leader and Subordinate, Greene explains that leaders and their followers share mutual influence . Greene stated, “The expectation is that the individual whose behavior causes another to be positively reinforced will in return be rewarded by the other.”.

Comment upon Charles Greene’s (1975) suggestion that follower perfor.pdf

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Describe the five major phases of a product life cycle. Give examples of safety activities appropriate to each. Solution Five major phases of a product life cycle are explained as below- Introduction Stage: 2. Growth Stage: 3. Expansion Stage: 4. Maturity Stage: 5. Decline Stage: Product Life Cycle Examples Watching recorded television and the various stages of each method: Introduction – 3D TVs Growth – Blue ray discs/DVR Maturity – DVD Decline – Video cassette.

Describe the five major phases of a product life cycle. Give example.pdf

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Early primates likely evolved to exploit new niches provided bya.ins.pdf

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Argue against increased social responsibility Solution Social responsibility is supported on the ground of moral emotions. But it exhibits time, hence, there is an opportunity cost associated with it. Often wealth are misused in this regard. In the name of social work political house, big firms, even self centered persons try to appropriate a lum-sum portion of the wealth. Social responsibility often makes the helped people to take it for grant that this should be continued for infinite time despite if they get into a situation of no need of that. Many people express themselves eligible to get help from it where they are actually not in many cases. Social responsibility often leads to distinguish people by class where the results get boomerang..

Argue against increased social responsibilitySolutionSocial re.pdf

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