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Gate 2018 ce02 q9 ga quantitative
- 3. π¦ β π§
log π
=
π§ β π₯
ππππ
=
π₯ β π¦
ππππ
=
1
10
- 4. π¦ β π§
log π
=
π§ β π₯
ππππ
=
π₯ β π¦
ππππ
=
1
10
π¦βπ§ + π§βπ₯ +(π₯βπ¦)
ππππππ
=
1
1000
- 5. π¦ β π§
log π
=
π§ β π₯
ππππ
=
π₯ β π¦
ππππ
=
1
10
π¦βπ§ + π§βπ₯ +(π₯βπ¦)
ππππππ
=
1
1000
0
ππππππ
=
1
1000
=
0
0