1. 1° We have two number one variable and one constant.
The variable is to multiply the number called (A), and the constant num
ber 100, called (C).
2 ° A variable (A) we subtract (-1) The result will be (D), which
provided us the first twodigits of the final result (X)
(A) (-1) = (D)
3° In the constant (C) we subtract the variable (A), E l result is (E) whi
ch provides us the second two digits of the final result (X)
(B) - (A) = (E)
4 ° Is the result of the algorithm is the union of (D) and (E), without
altering the final resultwill be called (X).
"(D) (E)"= (X)
ELIANI LONDOÑO TAMAYO TECNOLOGO SISTEMAS