In the pedigree below, the rare trait is autosomal recessive. If the.pdf

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In the pedigree below, the rare trait is autosomal recessive. If the frequency of heterozygotes for the trait in the general population is 1/15, then what is the probability of II-2 having an affected child with his phenotypically normal wife (she is not shown)? 4. In the pedigree below, the rare trait is autosomal recessive. If the frequency of heterozygotes for the trait in the general population is 1/15, then what is the probability of Il-2 having an affected child with his phenotypically normal wife (she is not shown)? (3 pts) Solution In the given pedigree chart, II-1 is affected by a rare recessive autosomal disease. Hence his parents are heterozygous for the trait. The second progeny of the F2 generation, II-2 is normal and marries a girl who is also normal. For II-2 and his wife to have an affected child, both of them need to be heterozygous. P (II-2 being heterozygous) = 2/3 x 1/15 = 2/45 Now, chances the couple will have an affected child = 1/4 Therefore P( parents being heterozygous and child born is affected) = 2/45 x 1/4 = 1/90.

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You are installing a KVM switch for a small business customer so that he can use a single keyboard, monitor, and mouse to manage two separate hardware servers. The KVM switch will allow him to toggle back and forth between the two machines with the peripheral devices. To successfully install the KVM switch, what special tools will you need? A. A set of hex wrenches B. A Phillips screwdriver C. ESD protection devices D. None Solution D. You shouldn’t need to use any special tools when installing the KVM switch, since the cable connections are usually tightened by hand and you don’t need to open up any of the machines..

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What is the F2 generation when the F1 generation of +++/y cv f is crossed with +++/Y? Can recombination be seen in the F2 generation? Solution Recombination seen in the F2 generation as +++/yY cv. Two parental types, carrying either the Y+ y+ allele combination seen in the original mother (the female of the P generation) or the Y y+ allele combination seen in the original father (the male of the P generation). The remaining half of the gametes will be of two recombinant types, in which reshuffling has produced either YY or Y y allele combinations not seen in the P generation parents of the F1 females..

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