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JAI GURUDEV CHEMISTRY CLASSES// BY: - AJEET KUMAR// M.N. 7209985022// f- ajeet.jha3 GROUP-16 ELMENTS
1. WhydoesO3 act as powerful oxidizingagent?
Ans: - Ozone decomposesrapidlytogive nascent
oxygen;hence itisa goodoxidizingagent.
O3 → O2 + [O]
2. How is O3 estimatedquantitatively?
Ans:- O3 istreatedwithexcessof KIsolution.I2 is
liberatedwhichistitratedagainstastandard
solutionof Na2S2O3 usingstarchasan indicator.
3. Commenton the nature oftwo S-Obonds
formedin SO2 molecule.Are the two S-Obonds in
the molecule equal?
Ans:-
4. How is the presence ofSO2 detected?
Ans:- SO2 isa pungentsmellinggas.Itreduces
acidified orange solutionof K2Cr2O7 intogreen,
Cr2(SO4)3.
K2Cr2O7 + H2SO4 + SO2 = Cr2(SO4)3 + K2SO4 + H2O
5. Whyis Ka2 lessthan Ka1 for H2SO4 inwater?
Ans: - Ka2 lessthan Ka1 forH2SO4 inwater because it
isdifficulttogive H+
ionfromHSO4
-
.
6. Compare the parameter such as bond
dissociationenthalpy,electrongain enthalpyand
hydration enthalpy,compare the oxidizingpower
of F2 and Cl2.
Ans:- The electrode potential of F2(+ 2.87 V) is
much higherthanthat of Cl2 (+1.3eV),therefore,F2
ismuch strongeroxidizingagentthanCl2.

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1

  • 1. JAI GURUDEV CHEMISTRY CLASSES// BY: - AJEET KUMAR// M.N. 7209985022// f- ajeet.jha3 GROUP-16 ELMENTS 1. WhydoesO3 act as powerful oxidizingagent? Ans: - Ozone decomposesrapidlytogive nascent oxygen;hence itisa goodoxidizingagent. O3 → O2 + [O] 2. How is O3 estimatedquantitatively? Ans:- O3 istreatedwithexcessof KIsolution.I2 is liberatedwhichistitratedagainstastandard solutionof Na2S2O3 usingstarchasan indicator. 3. Commenton the nature oftwo S-Obonds formedin SO2 molecule.Are the two S-Obonds in the molecule equal? Ans:- 4. How is the presence ofSO2 detected? Ans:- SO2 isa pungentsmellinggas.Itreduces acidified orange solutionof K2Cr2O7 intogreen, Cr2(SO4)3. K2Cr2O7 + H2SO4 + SO2 = Cr2(SO4)3 + K2SO4 + H2O 5. Whyis Ka2 lessthan Ka1 for H2SO4 inwater? Ans: - Ka2 lessthan Ka1 forH2SO4 inwater because it isdifficulttogive H+ ionfromHSO4 - . 6. Compare the parameter such as bond dissociationenthalpy,electrongain enthalpyand hydration enthalpy,compare the oxidizingpower of F2 and Cl2. Ans:- The electrode potential of F2(+ 2.87 V) is much higherthanthat of Cl2 (+1.3eV),therefore,F2 ismuch strongeroxidizingagentthanCl2.