Secant is 1cosineRangeof cosine is(-1,1)Secant function cannot .pdf

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Secant is 1/cosine Rangeof cosine is(-1,1) Secant function cannot lie between (-1,1) So -0.43 is not in the rqnge of secant function Solution Secant is 1/cosine Rangeof cosine is(-1,1) Secant function cannot lie between (-1,1) So -0.43 is not in the rqnge of secant function.

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The IUPAC names of the above compounds areZ-4,5-dichloro pent-4-e.pdf

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sumOfSquares import java.util.*; public class Arraylistoperation { public static void main(String args[]) { ArrayList list = createSquaresList(10); printList(list); } public static ArrayList createSquaresList(int n) { ArrayList squares= new ArrayList<>(); double s = 0.0; for (double i = 0.0; i <= n-1; i++) { s = i*i; squares.add(s); } return squares; for(int i = 0; i < m.size(); i++) { s+= m.get(i); } return s; } } Like wise sumOfCubes Solution sumOfSquares import java.util.*; public class Arraylistoperation { public static void main(String args[]) { ArrayList list = createSquaresList(10); printList(list); } public static ArrayList createSquaresList(int n) { ArrayList squares= new ArrayList<>(); double s = 0.0; for (double i = 0.0; i <= n-1; i++) { s = i*i; squares.add(s); } return squares; for(int i = 0; i < m.size(); i++) { s+= m.get(i); } return s; } } Like wise sumOfCubes.

sumOfSquaresimport java.util.;public class Arraylistoperation.pdf

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Ro is the reproduction number. It gives the average number of people who will catch a diseae from one person. Ro = C * P * D C = the number of contacts made by the infectious person per unit time (day, week, month, etc.) P = chance of transmission per contact with the infectious person D = the duration which an infected person remains infectious to others Hence, RO = 1000 x 0.0002 x 3 = 0.6 Solution Ro is the reproduction number. It gives the average number of people who will catch a diseae from one person. Ro = C * P * D C = the number of contacts made by the infectious person per unit time (day, week, month, etc.) P = chance of transmission per contact with the infectious person D = the duration which an infected person remains infectious to others Hence, RO = 1000 x 0.0002 x 3 = 0.6.

Ro is the reproduction number. It gives the average number of people.pdf

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the salt bridge acts as a porous wall between the electrolytes one can use graphite sheets instead of that the air bubble occupies good enough space and limits the transfer of ions to a good extent Solution the salt bridge acts as a porous wall between the electrolytes one can use graphite sheets instead of that the air bubble occupies good enough space and limits the transfer of ions to a good extent.

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Native Americans may have very high frequency of O alleles in their blood group because of the following reasons- 1. The native American population might have evolved from a single (possibly) common ancestor (the founders) that had allele O as the most prevalent allele of the gene for ABO blood group. 2. Because the founder population has prevalent O allele in the gene pool, the resultant native American population also has O allele as the prevalent one. Solution Native Americans may have very high frequency of O alleles in their blood group because of the following reasons- 1. The native American population might have evolved from a single (possibly) common ancestor (the founders) that had allele O as the most prevalent allele of the gene for ABO blood group. 2. Because the founder population has prevalent O allele in the gene pool, the resultant native American population also has O allele as the prevalent one..

Native Americans may have very high frequency of O alleles in their .pdf

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Medieval theatre brought many contributions to the theatre that continue to be incorporated in productions around the world to this day. The major contributions of the Medieval theatre are the use of the vernacular, spectacle, stage direction and the use of farce. Prior to Medieval theatre, all drama was performed in Latin or Greek, however Medieval theatre evolved to the use of the vernacular about 1200 A.D. Performances that were spoken in the vernacular provided opportunities for larger audiences, who included members of lower socio-economic status, who would have otherwise been excluded from understanding the performances. Medieval theatre differed from the classical theatre for it emphasized spectacle. In addition, it presented various actions on stage in time and space and presented a combination of the sublime with detailed realism. Approximately 1400 A.D., the dramas were performed with spectacle; no longer dependent exclusively on the spoken word, but incorporating music, dance, costume and set design. The spectacle of the later Medieval theatre made it necessary to have detailed stage directions. A sample of documented staging drawings and directions remain from the 15th- century morality play The Castle of Perseverance. The evolution to the dependence on detailed stage direction made possible the great Shakespearean stage.Farce contributed to modern theatre in that it allowed the author and the actors to ridicule and criticize their superiors whether it be in the church or in society, without retribution. This was a transition to all the future theatre including Shakespeare, who employed the use of farce with ease. Solution Medieval theatre brought many contributions to the theatre that continue to be incorporated in productions around the world to this day. The major contributions of the Medieval theatre are the use of the vernacular, spectacle, stage direction and the use of farce. Prior to Medieval theatre, all drama was performed in Latin or Greek, however Medieval theatre evolved to the use of the vernacular about 1200 A.D. Performances that were spoken in the vernacular provided opportunities for larger audiences, who included members of lower socio-economic status, who would have otherwise been excluded from understanding the performances. Medieval theatre differed from the classical theatre for it emphasized spectacle. In addition, it presented various actions on stage in time and space and presented a combination of the sublime with detailed realism. Approximately 1400 A.D., the dramas were performed with spectacle; no longer dependent exclusively on the spoken word, but incorporating music, dance, costume and set design. The spectacle of the later Medieval theatre made it necessary to have detailed stage directions. A sample of documented staging drawings and directions remain from the 15th- century morality play The Castle of Perseverance. The evolution to the dependence on detailed stage direction made possible the grea.

Medieval theatre brought many contributions to the theatre that cont.pdf

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Internet protocol(IP) is one of the core TCP/IP protocols that belongs to the network layer of the OSI model and provides information about how and where data should be delivered, including the data’s source and destination addresses. It is a subprotocol that allows TCP/IP to internetwork. It is unreliable and connectionless protocol which does not gurantee data delievery. Solution Internet protocol(IP) is one of the core TCP/IP protocols that belongs to the network layer of the OSI model and provides information about how and where data should be delivered, including the data’s source and destination addresses. It is a subprotocol that allows TCP/IP to internetwork. It is unreliable and connectionless protocol which does not gurantee data delievery..

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First C++ code written... I think it\'s quite efficient with all the test set included in path data. The simplest data set looks like: -1 -3 0 -1 -5 0 -3 -5 0 -2 -4 0 -2 -6 0 -4 -6 0 1 2 0 3 4 0 5 6 0 used vector saving clauses and map saving assignments. the main recursive function looks like following: /* 1. If the set of clauses is empty, it returns true 2. Otherwise, if the set of clauses contains an empty clause, it returns false 3. Otherwise, if there is a unit clause, it applies unit propagation and then calls itself recursively 4. Otherwise, if there is a pure literal, it applies the pure literal rule and then calls itself recursively 5. Otherwise, it applies either the resolution rule or the splitting rule and calls itself recursively */ Find the attached zip folder. I have referred this code example in my project. It will solve your problem. Implement following code : clause.cpp #include #include \"clause.h\" using namespace std; using namespace Sat; void Clause::readClause(istream& is) { static int lit = 0; if (lit != 0) addLiteral(lit); while (!is.eof()) { is >> lit; if (lit == 0) break; addLiteral(lit); } is >> lit; } void Clause::dumpClause() const { int i; cout << \"(\"; for (i = 0; i < numLits() - 1; ++i) { cout << getLit(i) << \", \"; } if (numLits() != 0) { cout << getLit(i); } cout << \")\" << endl; } Clause_impl.cpp #include #include #include \"clause.h\" #include \"clause_impl.h\" using namespace std; using namespace Sat; //size_t ClauseImpl::clause_num = 0; // Add a literal to the clause void ClauseImpl::addLiteral(int lit){ add_lits(lit); } // Get the largest variable in the clause int ClauseImpl::maxVar() const{ int max = -1; for (int i = 0; i < lits.size(); ++ i) { if(max < abs(lits[i])) max = abs(lits[i]); } return max; } // Get the number of variables in the clause int ClauseImpl::numLits() const{ return lits.size(); } // Get the i^th literal in the clause int ClauseImpl::getLit(int i) const{ return lits.at(i) ; } vector ClauseImpl::get_lits() const {return lits;} void ClauseImpl::add_lits(int lit) { lits.push_back(lit); } bool ClauseImpl::hasLit(int a) const { for (int i = 0; i < lits.size(); ++ i) { if (lits[i] == a) { return true; } } return false; } debug.cpp #include #include \"debug.h\" using namespace std; namespace DebugUtil { ostream& operator<<(ostream& os, const Exception& e) { return os << e.toString(); } void assertError(const string& file, int line, const string& cond) { ostringstream ss; ss << \"in \" << file << \":\" << line << \" (\" << cond << \")\ \"; throw Exception(ss.str()); } } // end of namespace DebugUtil formula.cpp #include \"debug.h\" #include \"clause.h\" #include \"formula.h\" using namespace std; using namespace Sat; void Formula::readClauses(istream& is) { while (!is.eof()) { Clause& c = addClause(); c.readClause(is); int tmp = c.maxVar(); if (tmp > maxVar) maxVar = tmp; } } void Formula::dumpClauses() { for (int i = 0; i < numClauses(); ++i) { getClause(i).dumpClause(); } } solver.cp.

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