HOAc + NAOH = OAc- + H2O 0.1 0.03 0.07 0 0.03 pH .pdf

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HOAc + NAOH = OAc- + H2O 0.1 0.03 0.07 0 0.03 pH =pKa + 0.03/0.07 = 4.75 + 0.4285 = 5.1785 Solution HOAc + NAOH = OAc- + H2O 0.1 0.03 0.07 0 0.03 pH =pKa + 0.03/0.07 = 4.75 + 0.4285 = 5.1785.

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The IUPAC names of the above compounds areZ-4,5-dichloro pent-4-e.pdf

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sumOfSquares import java.util.*; public class Arraylistoperation { public static void main(String args[]) { ArrayList list = createSquaresList(10); printList(list); } public static ArrayList createSquaresList(int n) { ArrayList squares= new ArrayList<>(); double s = 0.0; for (double i = 0.0; i <= n-1; i++) { s = i*i; squares.add(s); } return squares; for(int i = 0; i < m.size(); i++) { s+= m.get(i); } return s; } } Like wise sumOfCubes Solution sumOfSquares import java.util.*; public class Arraylistoperation { public static void main(String args[]) { ArrayList list = createSquaresList(10); printList(list); } public static ArrayList createSquaresList(int n) { ArrayList squares= new ArrayList<>(); double s = 0.0; for (double i = 0.0; i <= n-1; i++) { s = i*i; squares.add(s); } return squares; for(int i = 0; i < m.size(); i++) { s+= m.get(i); } return s; } } Like wise sumOfCubes.

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Ro is the reproduction number. It gives the average number of people who will catch a diseae from one person. Ro = C * P * D C = the number of contacts made by the infectious person per unit time (day, week, month, etc.) P = chance of transmission per contact with the infectious person D = the duration which an infected person remains infectious to others Hence, RO = 1000 x 0.0002 x 3 = 0.6 Solution Ro is the reproduction number. It gives the average number of people who will catch a diseae from one person. Ro = C * P * D C = the number of contacts made by the infectious person per unit time (day, week, month, etc.) P = chance of transmission per contact with the infectious person D = the duration which an infected person remains infectious to others Hence, RO = 1000 x 0.0002 x 3 = 0.6.

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Native Americans may have very high frequency of O alleles in their blood group because of the following reasons- 1. The native American population might have evolved from a single (possibly) common ancestor (the founders) that had allele O as the most prevalent allele of the gene for ABO blood group. 2. Because the founder population has prevalent O allele in the gene pool, the resultant native American population also has O allele as the prevalent one. Solution Native Americans may have very high frequency of O alleles in their blood group because of the following reasons- 1. The native American population might have evolved from a single (possibly) common ancestor (the founders) that had allele O as the most prevalent allele of the gene for ABO blood group. 2. Because the founder population has prevalent O allele in the gene pool, the resultant native American population also has O allele as the prevalent one..

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