If Michael Jordan has a vertical leap of 1.29 m, then what is his takeoff speed and his hang time (total time to move upwards to the peak and then return to the ground)? Solution vf2 = vi2 + 2*a*d (0 m/s)2 = vi2 + 2*(-9.8 m/s2)*(1.29 m) 0 m2/s2 = vi2 - 25.28 m2/s2 25.28 m2/s2 = vi2 vi = 5.03 m/s To find hang time, find the time to the peak and then double it. vf = vi + a*t 0 m/s = 5.03 m/s + (-9.8 m/s2)*tup -5.03 m/s = (-9.8 m/s2)*tup (-5.03 m/s)/(-9.8 m/s2) = tup tup = 0.513 s hang time = 1.03 s.