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Ejemplos matriz inversa
- 1. MATRICES INVERSAS
PROBLEMA 1
2 4 6
A=
4 5 6
3 1 -2
2 4 6 2 4
4 5 6 4 5
3 1 -2 3 1
A= -20+72+24-90-12+32 = 6
5 6
A11= 1 -2 (5 · -2)- (1 · 6) = -10-6 = 16
4 6
A12= - 3 -2 - [(4 · -2)- (3 · 6)] = 8 + 18 = 26
4 5
A13= (4 · 1)- (3 · 5)= 4 - 15 = -11
3 1
4 6
A21= - - [(4 · -2)- (1 · 6)] = 8 + 6 = 14
1 -2
2 6
A22= 3 -2 (2 · -2)- (3 · 6) = -4 - 18 = -22
2 4
A23 = - 3 1 - [(2 · 1)- (3 · 4)] = -2 + 12 = 10
4 6
A31= 5 6 (4 · 6)- (5 · 6) = 24 - 30 = -6
2 6
A32 = - 4 6 - [(2 · 6)- (4 · 6)] = -12 + 24 = 12
- 2. -16 14 -6 2 4 6
A-1 = 26 -22 12 4 5 6
-11 10 -6 3 1 -2
-16 (2) + 14 (4) -6 (3) = 6 -11 (2) + 10 (4) -6 (3) = 0 26 (2) -22 (4) +12 (3) = 0
-16 (4) + 14 (5) -6 (1) = 0 -11 (4) + 10 (5) -6 (1) = 0 26 (4) -22 (5) +12 (1) = 6
-16 (6) + 14 (6) -6 (-2)= 0 -11 (6) + 10 (6) -6 (-2)= 6 26 (6) -22 (6) +12 (-2)= 0
6 0 0
0 6 0
A-1 = 0 0 6
1 0 0
0 1 0
A-1 = 0 0 1
PROBLEMA 2
3 1 0
A= 1 -1 2
1 1 1
3 1 0 3 1
1 -1 2 1 -1
1 1 1 1 1
A= -3 + 2 - 6 - 1 = -8
-1 2
A11 = 1 1 (-1 · 1)- (1 · 2) = -1-2 = -3
1 2
A12 = - 1 1 - [(1 · 1)- (1 · 2)] = -1 + 2 = 1
1 2
A13 = 1 1 (-1 · 1)- (1 · 2) = -1-2 = -3
- 3. 1 0
A21= - 1 1 - [(1 · 1)- (1 · 0)] = -1 + 0 = -1
3 0
A22= 1 1 (3 · 1)- (1 · 0) = 3 - 0 = 3
3 1
A23= - 1 1 - [(3 · 1)- (1 · 1)] = -3 + 1 = -2
1 0
A31= -1 2 (1 · 2)- (-1 · 0) = 2 - 0 = 2
3 0
A32= - 1 2 - [(3 · 2)- (1 · 0)] = -6 - 0 = -6
3 1
A33= 1 -1 (3 · -1)- (1 · 1) = -3 - 1 = -4
-3 -1 2 3 1 0
-1
A = 1 3 -6 1 -1 2
2 -2 -4 1 1 1
-3(3) -1 (1) + 2(1) = -8 1(3) + 3(1) - 6(1) = 0 2(3) - 2(1) - 4(1) = 0
-3(1) - 1(-1) + 2(1) = 0 1(1) + 3(-1) - 6(1) = -8 2(1) - 2(-1) - 4(1) = 0
-3(0) - 1(2) + 2(1)= 0 1(0) + 3(2) - 6 (1)= 0 2(0) - 2(2) - 4(1)= -8
-8 0 0
0 -8 0
A-1 = 0 0 -8
-1 0 0
-1
A = 0 -1 0
0 0 -1
- 4. PROBLEMA 3
1 2 3
A= 1 1 2
0 1 2
1 2 3 1 2
1 1 2 1 1
0 1 2 0 1
A= 2 + 3 - 2 - 4 = -1
1 2
A11= 1 2 (1 · 2)- (1 · 2) = 2-2 = 0
1 2
A12 = - 0 2 - [(1 · 2)- (0 · 2)] = -2 - 0 = -2
1 1
A13= 0 1 (1 · 1)- (0 · 1) = 1- 0 = 1
2 3
A21= - 1 2 - [(2 · 2)- (1 · 3)] = -4 + 3 = -1
1 3
A22= 0 2 (1 · 2)- (0 · 3) = 2 - 0 = 2
1 2
A23= - 0 1 - [(1 · 1)- (0 · 1)] = -1 - 0 = -1
2 3
A31= 1 2 (2 · 2)- (1 · 3) = 4 - 3 = 1
1 3
A32= - 1 2 - [(1 · 2)- (1 · 3)] = -2 +3 = 1
1 2
A33= 1 1 (1 · 1)- (1 · 2) = 1 - 2 = -1
- 5. 0 -1 1 1 2 3
A-1 = -2 2 1 1 1 2
1 -1 -1 0 1 2
-1 (1) + 1(0) = -1 -2(1) + 2 (1) + 1(0) = 0 1(1) - 1 (1) - 1(0) = 0
- 1(1) + 1(1) = 0 -2(2) + 2(1) + 1(1) = -1 1(2) - 1(1) - 1(1) = 0
- 1(2) + 1(2)= 0 -2(3) + 2(2) + 1(2)= 0 1(3) - 1(2) - 1(2)= -1
-1 0 0
0 -1 0
A-1 = 1
0 0 -1
-1 0 0
0 -1 0
A-1 =
0 0 -1