I hope this is clear this time. Solution Moment of inertia is nothing but second moment of area and is the indicator of flexural stiffness of the member. In given problem, Moment of Inertia (MI) = BD3/12-(bd3/12) = 10*113/12-(2*3.5*53/12) = 1109.16 -72.9 = 1036.2 in4. (about strong axis as the member is symmetrical about XX or strong axis. Now MI about weak axis, YY axis or vertical axis (11*103/12)-(5*73/12) = 916.67-142.91 = 773.75 in4 Hightlighted values are the answers for the MI of strong and weak, ie horizontal and vertical axis respectively..