Q. The House managed to load the die in such a way that the faces \"2\" and \"4\" show up twice
as frequently as all other faces. Meanwhile, all the other faces still show up with equal
frequency. What is the probability of getting a \"5\" when rolling this loaded die?
Solution
If the proabilty of getting a 2 or a 4 is twice the probability of getting any of the
other numbers, then the probability of a 2 or 4 is 1/4, and the probabilty of any other number is
XXXXX This is found by letting x represent the probabilty of the other numbers, and then 2x
represents the probabilty of 2 and 4. This gives: P(1) + P(2) + P(3) + P(4) + P(5) + P(6) = 1.00
x + 2x + x + 2x + x + x = 1.00 8x = 1.00 x = 1/8 Then the probabilty of a 5 with the loaded die
is 1/8.
Q. The House managed to load the die in such a way that the faces .pdf
1. Q. The House managed to load the die in such a way that the faces "2" and "4" show up twice
as frequently as all other faces. Meanwhile, all the other faces still show up with equal
frequency. What is the probability of getting a "5" when rolling this loaded die?
Solution
If the proabilty of getting a 2 or a 4 is twice the probability of getting any of the
other numbers, then the probability of a 2 or 4 is 1/4, and the probabilty of any other number is
XXXXX This is found by letting x represent the probabilty of the other numbers, and then 2x
represents the probabilty of 2 and 4. This gives: P(1) + P(2) + P(3) + P(4) + P(5) + P(6) = 1.00
x + 2x + x + 2x + x + x = 1.00 8x = 1.00 x = 1/8 Then the probabilty of a 5 with the loaded die
is 1/8
