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EFFECTS OF CLASSICAL MUSIC ON TEST SCORES 13
	
  
Figure 1: Independent Sample t test
Interval/Ratio measurement of dependent variable (test score)
t = M1 – M2______________
√ Σd2
/1 + Σd2
/2 × n1 + n2
(n1 + n2 – 2) n1 × n2
t = 5.8-5.1________________ = _______0.7_______ = 0.7 .
√ 13.6 + 14.9 × 10 + 10 √ (28.5 ) ( 20 ) √(1.58)(0.2)
(10+10-2) (10 × 10) ( 18 ) ( 100 )
t= __0.7 = 0.7 = 1.24
√0.32 0 .56 Degrees of freedom = (n1 + n2 – 2) = (10 + 10 – 2) = 18
Critical Value = 1.734
P > 0.05, NS
MUSIC
GROUP
SILENCE
GROUP
Score
Deviation
(X-M)
Squared Deviation
(X-M)2 Score
Deviation
(X-M)
Squared Deviation
(X-M)2
4 -1.8 3.24 3 -2.1 4.41
5 -0.8 0.64 7 1.9 3.61
7 1.2 1.44 5 -0.1 0.01
7 1.2 1.44 5 -0.1 0.01
4 -1.8 3.24 6 0.9 0.81
7 1.2 1.44 4 -1.1 1.21
6 0.2 0.04 7 1.9 3.61
7 1.2 1.44 4 -1.1 1.21
6 0.2 0.04 5 0.1 0.01
5 -0.8 0.64 5 0.1 0.01
M1=5.8 Σd2
1=13.6 M2=5.1 Σd2
2=14.9
(sum of squares) (sum of squares)

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T TEST

  • 1. EFFECTS OF CLASSICAL MUSIC ON TEST SCORES 13   Figure 1: Independent Sample t test Interval/Ratio measurement of dependent variable (test score) t = M1 – M2______________ √ Σd2 /1 + Σd2 /2 × n1 + n2 (n1 + n2 – 2) n1 × n2 t = 5.8-5.1________________ = _______0.7_______ = 0.7 . √ 13.6 + 14.9 × 10 + 10 √ (28.5 ) ( 20 ) √(1.58)(0.2) (10+10-2) (10 × 10) ( 18 ) ( 100 ) t= __0.7 = 0.7 = 1.24 √0.32 0 .56 Degrees of freedom = (n1 + n2 – 2) = (10 + 10 – 2) = 18 Critical Value = 1.734 P > 0.05, NS MUSIC GROUP SILENCE GROUP Score Deviation (X-M) Squared Deviation (X-M)2 Score Deviation (X-M) Squared Deviation (X-M)2 4 -1.8 3.24 3 -2.1 4.41 5 -0.8 0.64 7 1.9 3.61 7 1.2 1.44 5 -0.1 0.01 7 1.2 1.44 5 -0.1 0.01 4 -1.8 3.24 6 0.9 0.81 7 1.2 1.44 4 -1.1 1.21 6 0.2 0.04 7 1.9 3.61 7 1.2 1.44 4 -1.1 1.21 6 0.2 0.04 5 0.1 0.01 5 -0.8 0.64 5 0.1 0.01 M1=5.8 Σd2 1=13.6 M2=5.1 Σd2 2=14.9 (sum of squares) (sum of squares)