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PowerPoint Lecture Slides
Essenfials of Statisflcs for tfae Behavioral
Sciences
Seventh Edition
by Frederick J. Gravetter and Larry B. Wallnau
• Understand z-score as location in distribution
• Transform Xvalue into z-score
• Transform z-score into X value
• Describe effects of standardizing a distribution
• Transform scores to standardized distribution
• Identify and describe location of every
score in the distribution
• Standardize an entire distribution
• Takes different distributions and makes them
equivalent and comparable
4d 4ô 4B č0 52 čd ô õg ôD ô2 ód ńa ó8 @ 72 74 lb 78 BÜ BE ßd 8ć+ 88 g0 92 9d gô 98
x=76
a4 4a ae to s2 sa in æ ao sy ód Ó OB 7s 72 7d zb 7a g0 s2 8d 8ó aa so m 9d 90 9a
• Exact location is described by z-score
—
Sign tells whether score is located
above or below the mean
Number tells distance between score
and mean in standard deviation units
Figure 5.2 Relationship of z-scores
and locations
—
2 —
1 0 +1 +2
• A z-score of z = +1.00 indicates a position
in a distribution
• Above the mean by 1 point
• Above the mean by a distance equal to 1
standard deviation
• Below the mean by 1 point
• Below the mean by a distance equal to 1
standard deviation
• Decide if each of the following statements
is True or False.
• A negative z-score always indicates
a location below the mean
• A score close to the mean has a
z-score close to 1.00
• A z-score of z +1.00 indicates a position
in a distribution
• Above the mean by a distance equal to 1
standard deviation
• Sign ïndicates that score is below
the mean
• Scores close to 0 have z-scores
close to 0.00
80 90 100 110 120
—
2 —
1 0 +1 +2
• If 2o = 10 then o = 5
• Why
59
ó points
29 43 57 71
I ‹ I
—
2 —
1 0 +1
30 d0 50 ó0
Joe
85
< Original scores (g 57 ana ‹r 14}
z — z-Scores (ç = 0 and rr = I )
+ 2
70
‹— Standardizea scores (y —50 and ‹r — 0)
• Numerator is a deviation score
• Denominator expresses deviation in
standard deviation units
• For a population with g = 50 and o = 10,
what is the X value corresponding to
z=0.4?
• 50.4
• 10
•54
•10.4
—1.5 —
1.0 —0.5 0 +0.5 +l .0 +l .5
Frequency
Frequency
80
Population of scores
(Kvolues)
10
110 120
Transform ło z
-2
PoDulałion of z-scores
zvciIues)
+2
• For a population with g = 50 and o = 10,
what is the X value corresponding to
z=0.4?
• 54
Extreme
(z Deyond —2.00}
200
Representative
individuals
(znear 0)
Population
of
nontreateo rots
380 400 420
J.00
Extreme
individuals
(z Deyond +2.00)
440
00 2.00
X - 418
X
• Decide if each of the following statements
is True or False.
• Transforming an entire distribution of
scores into z-scores will not change the
shape of the distribution.
• If a sample of n = 10 scores is transformed
into z-scores, there will be five positive z
scores and five negative z-scores.
• A score of X=59 comes from a distribution with
y=63 and o=8. This distribution is standardized
so that the new distribution has y=63 and o=8.
What is the new value of the original score?
• 45
• A score of X=59 comes from a distribution with
y=63 and o=8. This distribution is standardized
so that the new distribution has y=63 and o=8.
What is the new value of the original score?
• 59
• 45
• 46
• 55
• Numerator is a deviation score
• Denominator expresses deviation in
standard deviation units
• Decide if each of the following statements
is True or False.
• If y = 40 and X = 50 corresponds
to z=+2.00, then o = 10 points
• If o 20, a score above the mean
by 10 points will have z = 1.00
• All z-scores are comparable to each other
• Scores from different distributions can be
converted to z-scores
• The z-scores (standardized scores) allow the
comparison of scores from two different
distributions along
• Interpretation of research results depends on
determining if (treated) sample is noticeably
different from the population
• One technique for defining noticeably
different uses z-scores.
• Every X value can be transformed to a z-score
• Characteristics of z-score transformation
—Same shape as original distribution
—Mean of z-score distribution is always 0.
—Standard deviation is always 1.00
• A z-score distribution is called a
standardized distribution
5.4 Other Standardized Distributions
• Process of standardization is widely used
—AT has g = 500 and cr = 100
—IQ has y = 100 and o = 15 Point
• Standardizing a distribution has two steps
—Original raw scores transformed to z-scores
—The z-scores are transformed to new X values
so that the specificy and o are attained.
• Last week Andi had exams in Chemistry and in
Spanish. On the chemistry exam, the mean was
g = 30 with rr = 5, and Andi had a score of X = 45.
On the Spanish exam, the mean was y = 60 with
o = 6 and Andi had a score of X = 65. For which
class should Andi expect thebetter grade?
• Chemistry
• Last week Andi had exams in Chemistry and in
Spanish. On the chemistry exam, the mean was
g = 30 with rr = 5, and Andi had a score of X = 45.
On the Spanish exam, the mean was y = 60 with
o = 6 and Andi had a score of X = 65. For which
class should Andi expect thebetter grade?
• Chemistry
• Spanish
• There is not enough information to know
• Populations are most common context for
computing z-scores
• It is possible to compute z-scores for samples
—Indicates relative position of score in sample
—Indicates distance from sample mean
• Sample distribution can be transformed into
z-scores
—Same shape as original distribution
—Same mean M and standard deviation s

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Chapter 1 Standard scores.pptx

  • 1. PowerPoint Lecture Slides Essenfials of Statisflcs for tfae Behavioral Sciences Seventh Edition by Frederick J. Gravetter and Larry B. Wallnau
  • 2. • Understand z-score as location in distribution • Transform Xvalue into z-score • Transform z-score into X value • Describe effects of standardizing a distribution • Transform scores to standardized distribution
  • 3. • Identify and describe location of every score in the distribution • Standardize an entire distribution • Takes different distributions and makes them equivalent and comparable
  • 4. 4d 4ô 4B č0 52 čd ô õg ôD ô2 ód ńa ó8 @ 72 74 lb 78 BÜ BE ßd 8ć+ 88 g0 92 9d gô 98 x=76 a4 4a ae to s2 sa in æ ao sy ód Ó OB 7s 72 7d zb 7a g0 s2 8d 8ó aa so m 9d 90 9a
  • 5. • Exact location is described by z-score — Sign tells whether score is located above or below the mean Number tells distance between score and mean in standard deviation units
  • 6. Figure 5.2 Relationship of z-scores and locations — 2 — 1 0 +1 +2
  • 7. • A z-score of z = +1.00 indicates a position in a distribution • Above the mean by 1 point • Above the mean by a distance equal to 1 standard deviation • Below the mean by 1 point • Below the mean by a distance equal to 1 standard deviation
  • 8. • Decide if each of the following statements is True or False. • A negative z-score always indicates a location below the mean • A score close to the mean has a z-score close to 1.00
  • 9. • A z-score of z +1.00 indicates a position in a distribution • Above the mean by a distance equal to 1 standard deviation
  • 10. • Sign ïndicates that score is below the mean • Scores close to 0 have z-scores close to 0.00
  • 11. 80 90 100 110 120 — 2 — 1 0 +1 +2
  • 12. • If 2o = 10 then o = 5 • Why
  • 13.
  • 15. 29 43 57 71 I ‹ I — 2 — 1 0 +1 30 d0 50 ó0 Joe 85 < Original scores (g 57 ana ‹r 14} z — z-Scores (ç = 0 and rr = I ) + 2 70 ‹— Standardizea scores (y —50 and ‹r — 0)
  • 16. • Numerator is a deviation score • Denominator expresses deviation in standard deviation units
  • 17. • For a population with g = 50 and o = 10, what is the X value corresponding to z=0.4? • 50.4 • 10 •54 •10.4
  • 18. —1.5 — 1.0 —0.5 0 +0.5 +l .0 +l .5 Frequency Frequency
  • 19. 80 Population of scores (Kvolues) 10 110 120 Transform ło z -2 PoDulałion of z-scores zvciIues) +2
  • 20. • For a population with g = 50 and o = 10, what is the X value corresponding to z=0.4? • 54
  • 21. Extreme (z Deyond —2.00} 200 Representative individuals (znear 0) Population of nontreateo rots 380 400 420 J.00 Extreme individuals (z Deyond +2.00) 440 00 2.00 X - 418 X
  • 22. • Decide if each of the following statements is True or False. • Transforming an entire distribution of scores into z-scores will not change the shape of the distribution. • If a sample of n = 10 scores is transformed into z-scores, there will be five positive z scores and five negative z-scores.
  • 23. • A score of X=59 comes from a distribution with y=63 and o=8. This distribution is standardized so that the new distribution has y=63 and o=8. What is the new value of the original score? • 45
  • 24. • A score of X=59 comes from a distribution with y=63 and o=8. This distribution is standardized so that the new distribution has y=63 and o=8. What is the new value of the original score? • 59 • 45 • 46 • 55
  • 25. • Numerator is a deviation score • Denominator expresses deviation in standard deviation units
  • 26. • Decide if each of the following statements is True or False. • If y = 40 and X = 50 corresponds to z=+2.00, then o = 10 points • If o 20, a score above the mean by 10 points will have z = 1.00
  • 27. • All z-scores are comparable to each other • Scores from different distributions can be converted to z-scores • The z-scores (standardized scores) allow the comparison of scores from two different distributions along
  • 28. • Interpretation of research results depends on determining if (treated) sample is noticeably different from the population • One technique for defining noticeably different uses z-scores.
  • 29. • Every X value can be transformed to a z-score • Characteristics of z-score transformation —Same shape as original distribution —Mean of z-score distribution is always 0. —Standard deviation is always 1.00 • A z-score distribution is called a standardized distribution
  • 30. 5.4 Other Standardized Distributions • Process of standardization is widely used —AT has g = 500 and cr = 100 —IQ has y = 100 and o = 15 Point • Standardizing a distribution has two steps —Original raw scores transformed to z-scores —The z-scores are transformed to new X values so that the specificy and o are attained.
  • 31. • Last week Andi had exams in Chemistry and in Spanish. On the chemistry exam, the mean was g = 30 with rr = 5, and Andi had a score of X = 45. On the Spanish exam, the mean was y = 60 with o = 6 and Andi had a score of X = 65. For which class should Andi expect thebetter grade? • Chemistry
  • 32. • Last week Andi had exams in Chemistry and in Spanish. On the chemistry exam, the mean was g = 30 with rr = 5, and Andi had a score of X = 45. On the Spanish exam, the mean was y = 60 with o = 6 and Andi had a score of X = 65. For which class should Andi expect thebetter grade? • Chemistry • Spanish • There is not enough information to know
  • 33. • Populations are most common context for computing z-scores • It is possible to compute z-scores for samples —Indicates relative position of score in sample —Indicates distance from sample mean • Sample distribution can be transformed into z-scores —Same shape as original distribution —Same mean M and standard deviation s