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10.569 Synthesis of Polymers
Prof. Paula Hammond
Lecture 3: Step Growth Polymerization, Types of Monomers, Kinetics and
Equilibrium Considerations, Closed vs. Open Systems
Kinetics of Step Growth Polymerization (Chapter 2)
A + B → polymer + byproduct
rate of polymerization
=
Rp
d M d a d b
Rp k a b
dt dt dt
− − −
⎡ ⎤ ⎡ ⎤ ⎡ ⎤
⎣ ⎦ ⎣ ⎦ ⎣ ⎦
= = = = ⎡ ⎤⎡ ⎤
⎣ ⎦⎣ ⎦
Assume r =1, where r is the stoichiometric ratio.
b
a
r =
a b
=
⎡ ⎤ ⎡ ⎤
⎣ ⎦ ⎣ ⎦
Terminology n
p varies with t → o
n
a
p
a
⎡ ⎤
⎣ ⎦
=
⎡ ⎤
⎣ ⎦
( )
n
X p. 50
2
d a
k a
dt
− ⎡ ⎤
⎣ ⎦ = ⎡ ⎤
⎣ ⎦
2
d a
kt
a
− ⎡ ⎤
⎣ ⎦ =
⎡ ⎤
⎣ ⎦
1 1
o
kt
a a
− =
⎡ ⎤ ⎡ ⎤
⎣ ⎦ ⎣ ⎦
1
o
o
a
a kt
a
⎡ ⎤
⎣ ⎦
− = ⎡ ⎤
⎣ ⎦
⎡ ⎤
⎣ ⎦
1
o
a
a
⎡ ⎤
⎣ ⎦
π = −
⎡ ⎤
⎣ ⎦
in book, p
=
π (p. 46)
1
1
o
a
a
⎡ ⎤
⎣ ⎦
=
− π
⎡ ⎤
⎣ ⎦
1
1 1
1
o n
a kt p
= − = −
⎡ ⎤
⎣ ⎦ − π
Notes:
1.
1
M
t
∝
⎡ ⎤
⎣ ⎦ as time ↑, concentration of monomer ↓
2. n
p increases linearly with time
kf >> kr
LeChatlier’s Principle: remove water
a + b
kf
kr
c + d
a + b
kf
kr
c + d
To drive reaction forward
Citation: Professor Paula Hammond, 10.569 Synthesis of Polymers Fall 2006 course materials, MIT
OpenCourseWare (http://ocw.mit.edu/index.html), Massachusetts Institute of Technology, Date
Making esters:
COOH +
Keq
+ H2O
OH C O
O
COOH +
Keq
+ H2O
OH C O
O
Ester can hydrolyze with water and
go backwards (reverse rxn) → drug delivery
2
eq
COO H O
K
COOH OH
⎡ ⎤ ⎡ ⎤
⎣ ⎦
=
⎡ ⎤⎡ ⎤
⎣ ⎦⎣ ⎦
M
= =
⎣ ⎦
10.569, Synthesis of Polymers, Fall 2006 Lecture 3
Prof. Paula Hammond Page 2 of 5
Citation: Professor Paula Hammond, 10.569 Synthesis of Polymers Fall 2006 course materials, MIT
OpenCourseWare (http://ocw.mit.edu/index.html), Massachusetts Institute of Technology, Date
Assume at t M
0 : o
⎡ ⎤ ⎡ ⎤
⎣ ⎦ ⎣ ⎦
o
COOH OH M
= π = π = π
⎡ ⎤ ⎡ ⎤ ⎡ ⎤
⎣ ⎦ ⎣ ⎦ ⎣ ⎦
Put in terms of π:
o o
COO
⎡ ⎤
⎣ ⎦
“ “
[ ] =
OH
( )
1
o o o
COOH OH M M M
= = − π = −
⎡ ⎤ ⎡ ⎤ ⎡ ⎤ ⎡ ⎤ ⎡ ⎤
⎣ ⎦ ⎣ ⎦ ⎣ ⎦ ⎣ ⎦ ⎣ ⎦ π
( )
( )
2
2 2
1
o
o
M
K
M
π⎡ ⎤
⎣ ⎦
=
− π
⎡ ⎤
⎣ ⎦
( )
2
2
1
K
π
=
− π
1
2
1
2
1
K
K
π =
+
In closed system, limited by K (reaction constant).
That also means rxn and polymer limited by K.
1
2
1
1
1
n
p K
= = +
− π
where n
p is the # average degree of polymerization (# of units in polymer)
Polyesterification: K: 1 ∼ 10
n
p ∼ 2 - 5 monomers
Polyamidation: K: 100 – 1000
n
p : 10 - 40
In between: removing some of the water
Open Driven System
Removing byproduct
- H2O by temperature, low pressure, or N2 blowing of water
- Acid like HCl, base neutralization
( )
2 n
H O MW p
↔
⎡ ⎤
⎣ ⎦ How H2O affects n
p
COH + + H2O
OH C O
O
O
COH + + H2O
OH C O
O
O
( )
2 2
2
1
o
COO H O H O
K
COOH OH M
π
⎡ ⎤ ⎡ ⎤ ⎡ ⎤
⎣ ⎦ ⎣ ⎦ ⎣ ⎦
= =
⎡ ⎤⎡ ⎤ − π
⎡ ⎤
⎣ ⎦⎣ ⎦ ⎣ ⎦
10.569, Synthesis of Polymers, Fall 2006 Lecture 3
Prof. Paula Hammond Page 3 of 5
Citation: Professor Paula Hammond, 10.569 Synthesis of Polymers Fall 2006 course materials, MIT
OpenCourseWare (http://ocw.mit.edu/index.html), Massachusetts Institute of Technology, Date
2
1
1 1
eq
o
H O
K
M
⎡ ⎤
π ⎣ ⎦
= ⋅ ⋅
− π − π ⎡ ⎤
⎣ ⎦
1
1
n
p =
− π
1 1 1
1 1
1 1 1 1
n
p
π − π
= − = − = −
− π − π − π − π
( ) 2
1
eq
n n
o
H O
K p p
M
⎡ ⎤
⎣ ⎦
= ⋅ −
⎡ ⎤
⎣ ⎦
( )
2
1
o
eq
n n
M K
H O
p p
⎡ ⎤
⎣ ⎦
=
⎡ ⎤
⎣ ⎦
−
only get down to a certain water concentration
→ solve for best n
p possible
Polyesterification Using Acid Catalysis
COH + HA C OH
OH
O
k1
k2 +
A
-
COH + HA C OH
OH
O
k1
k2 +
+
A
-
-
Acid
catalyst
More active than COOH
[ ][ ]
COOH
HA
k
k
K
⎥
⎥
⎦
⎤
⎢
⎢
⎣
⎡
=
=
2
1
12
C OH
OH
+
A
-
C OH
OH
+
+
A
-
-
k3
k4
C OH
OH
+
A
-
OH
+ C OH
OH
+
A
-
OH
k3
k4
C OH
OH
+
A
-
C OH
OH
+
+
A
-
-
OH
+ C OH
OH
+
+
A
-
-
OH
Slow step
(rate-determining step)
k5
k6
C OH
OH
+
A
-
OH
..
..
..
.. + H2O + HA
C O
O
k5
k6
C OH
OH
+
+
A
-
-
OH
..
..
..
.. + H2O + HA
C O
O
catalyst regeneration
[ ]
dt
COOH
d
Rp
−
= Rate of disappearance of carboxylic monomer
p
R ( )
3 2
k C OH OH
+
⎡ ⎤
= ⎡ ⎤
⎣ ⎦
⎣ ⎦
(from previous page)
3 12
k K HA COOH OH
= ⎡ ⎤⎡ ⎤⎡
⎣ ⎦⎣ ⎦⎣ ⎤
⎦
From equilibrium expression [HA] is constant because it’s regenerated.
'
p
d COOH
R k COO
dt
− ⎡ ⎤
⎣ ⎦
= = ⎡ ⎤⎡
⎣ ⎦⎣
H OH⎤
⎦ where '
3 12
k k K HA
= ⎡ ⎤
⎣ ⎦ constant
Self-catalyzed: [HA] = [COOH]
2
"
p
d COOH
R k COO
dt
− ⎡ ⎤
⎣ ⎦
= = ⎡ ⎤ ⎡
⎣ ⎦ ⎣
H OH⎤
⎦ K
where k k3 12
" =
3
"
p
d M
R k
dt
− ⎡ ⎤
⎣ ⎦
= = ⎡ ⎤
⎣ ⎦
M separate and integrate
"
2 2
1 1
2
o
k t
M M
= −
⎡ ⎤ ⎡ ⎤
⎣ ⎦ ⎣ ⎦
( )
1
o
M M
= −
⎡ ⎤ ⎡ ⎤
⎣ ⎦ ⎣ ⎦ π
( ) ( )
2 2 '
2
1
2 1
1
n o
p M
= = ⎡ ⎤
⎣ ⎦
− π
k t +
Much slower because of time-dependence ( t )
That’s why people add acid to drive reaction.
High Temperature
- increase k
- remove byproduct (evaporate H2O)
Bulk or mass conditions (no solvent)
- [M]o is maximum
- no need to separate product
10.569, Synthesis of Polymers, Fall 2006 Lecture 3
Prof. Paula Hammond Page 4 of 5
Citation: Professor Paula Hammond, 10.569 Synthesis of Polymers Fall 2006 course materials, MIT
OpenCourseWare (http://ocw.mit.edu/index.html), Massachusetts Institute of Technology, Date
10.569, Synthesis of Polymers, Fall 2006 Lecture 3
Prof. Paula Hammond Page 5 of 5
Citation: Professor Paula Hammond, 10.569 Synthesis of Polymers Fall 2006 course materials, MIT
OpenCourseWare (http://ocw.mit.edu/index.html), Massachusetts Institute of Technology, Date
- viscosity η low until high π
- direct processing
Use solvent
- monomers are not miscible with each other but miscible with solvent
- allow high T
- dilute viscous media (carrier for viscous media)
→ improves processing
- improves heat and mass transfer

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lec03_09112006(1).pdf

  • 1. 10.569 Synthesis of Polymers Prof. Paula Hammond Lecture 3: Step Growth Polymerization, Types of Monomers, Kinetics and Equilibrium Considerations, Closed vs. Open Systems Kinetics of Step Growth Polymerization (Chapter 2) A + B → polymer + byproduct rate of polymerization = Rp d M d a d b Rp k a b dt dt dt − − − ⎡ ⎤ ⎡ ⎤ ⎡ ⎤ ⎣ ⎦ ⎣ ⎦ ⎣ ⎦ = = = = ⎡ ⎤⎡ ⎤ ⎣ ⎦⎣ ⎦ Assume r =1, where r is the stoichiometric ratio. b a r = a b = ⎡ ⎤ ⎡ ⎤ ⎣ ⎦ ⎣ ⎦ Terminology n p varies with t → o n a p a ⎡ ⎤ ⎣ ⎦ = ⎡ ⎤ ⎣ ⎦ ( ) n X p. 50 2 d a k a dt − ⎡ ⎤ ⎣ ⎦ = ⎡ ⎤ ⎣ ⎦ 2 d a kt a − ⎡ ⎤ ⎣ ⎦ = ⎡ ⎤ ⎣ ⎦ 1 1 o kt a a − = ⎡ ⎤ ⎡ ⎤ ⎣ ⎦ ⎣ ⎦ 1 o o a a kt a ⎡ ⎤ ⎣ ⎦ − = ⎡ ⎤ ⎣ ⎦ ⎡ ⎤ ⎣ ⎦ 1 o a a ⎡ ⎤ ⎣ ⎦ π = − ⎡ ⎤ ⎣ ⎦ in book, p = π (p. 46) 1 1 o a a ⎡ ⎤ ⎣ ⎦ = − π ⎡ ⎤ ⎣ ⎦ 1 1 1 1 o n a kt p = − = − ⎡ ⎤ ⎣ ⎦ − π Notes: 1. 1 M t ∝ ⎡ ⎤ ⎣ ⎦ as time ↑, concentration of monomer ↓ 2. n p increases linearly with time kf >> kr LeChatlier’s Principle: remove water a + b kf kr c + d a + b kf kr c + d To drive reaction forward Citation: Professor Paula Hammond, 10.569 Synthesis of Polymers Fall 2006 course materials, MIT OpenCourseWare (http://ocw.mit.edu/index.html), Massachusetts Institute of Technology, Date
  • 2. Making esters: COOH + Keq + H2O OH C O O COOH + Keq + H2O OH C O O Ester can hydrolyze with water and go backwards (reverse rxn) → drug delivery 2 eq COO H O K COOH OH ⎡ ⎤ ⎡ ⎤ ⎣ ⎦ = ⎡ ⎤⎡ ⎤ ⎣ ⎦⎣ ⎦ M = = ⎣ ⎦ 10.569, Synthesis of Polymers, Fall 2006 Lecture 3 Prof. Paula Hammond Page 2 of 5 Citation: Professor Paula Hammond, 10.569 Synthesis of Polymers Fall 2006 course materials, MIT OpenCourseWare (http://ocw.mit.edu/index.html), Massachusetts Institute of Technology, Date Assume at t M 0 : o ⎡ ⎤ ⎡ ⎤ ⎣ ⎦ ⎣ ⎦ o COOH OH M = π = π = π ⎡ ⎤ ⎡ ⎤ ⎡ ⎤ ⎣ ⎦ ⎣ ⎦ ⎣ ⎦ Put in terms of π: o o COO ⎡ ⎤ ⎣ ⎦ “ “ [ ] = OH ( ) 1 o o o COOH OH M M M = = − π = − ⎡ ⎤ ⎡ ⎤ ⎡ ⎤ ⎡ ⎤ ⎡ ⎤ ⎣ ⎦ ⎣ ⎦ ⎣ ⎦ ⎣ ⎦ ⎣ ⎦ π ( ) ( ) 2 2 2 1 o o M K M π⎡ ⎤ ⎣ ⎦ = − π ⎡ ⎤ ⎣ ⎦ ( ) 2 2 1 K π = − π 1 2 1 2 1 K K π = + In closed system, limited by K (reaction constant). That also means rxn and polymer limited by K. 1 2 1 1 1 n p K = = + − π where n p is the # average degree of polymerization (# of units in polymer) Polyesterification: K: 1 ∼ 10 n p ∼ 2 - 5 monomers Polyamidation: K: 100 – 1000 n p : 10 - 40 In between: removing some of the water Open Driven System Removing byproduct - H2O by temperature, low pressure, or N2 blowing of water - Acid like HCl, base neutralization ( ) 2 n H O MW p ↔ ⎡ ⎤ ⎣ ⎦ How H2O affects n p
  • 3. COH + + H2O OH C O O O COH + + H2O OH C O O O ( ) 2 2 2 1 o COO H O H O K COOH OH M π ⎡ ⎤ ⎡ ⎤ ⎡ ⎤ ⎣ ⎦ ⎣ ⎦ ⎣ ⎦ = = ⎡ ⎤⎡ ⎤ − π ⎡ ⎤ ⎣ ⎦⎣ ⎦ ⎣ ⎦ 10.569, Synthesis of Polymers, Fall 2006 Lecture 3 Prof. Paula Hammond Page 3 of 5 Citation: Professor Paula Hammond, 10.569 Synthesis of Polymers Fall 2006 course materials, MIT OpenCourseWare (http://ocw.mit.edu/index.html), Massachusetts Institute of Technology, Date 2 1 1 1 eq o H O K M ⎡ ⎤ π ⎣ ⎦ = ⋅ ⋅ − π − π ⎡ ⎤ ⎣ ⎦ 1 1 n p = − π 1 1 1 1 1 1 1 1 1 n p π − π = − = − = − − π − π − π − π ( ) 2 1 eq n n o H O K p p M ⎡ ⎤ ⎣ ⎦ = ⋅ − ⎡ ⎤ ⎣ ⎦ ( ) 2 1 o eq n n M K H O p p ⎡ ⎤ ⎣ ⎦ = ⎡ ⎤ ⎣ ⎦ − only get down to a certain water concentration → solve for best n p possible Polyesterification Using Acid Catalysis COH + HA C OH OH O k1 k2 + A - COH + HA C OH OH O k1 k2 + + A - - Acid catalyst More active than COOH [ ][ ] COOH HA k k K ⎥ ⎥ ⎦ ⎤ ⎢ ⎢ ⎣ ⎡ = = 2 1 12 C OH OH + A - C OH OH + + A - - k3 k4 C OH OH + A - OH + C OH OH + A - OH k3 k4 C OH OH + A - C OH OH + + A - - OH + C OH OH + + A - - OH Slow step (rate-determining step)
  • 4. k5 k6 C OH OH + A - OH .. .. .. .. + H2O + HA C O O k5 k6 C OH OH + + A - - OH .. .. .. .. + H2O + HA C O O catalyst regeneration [ ] dt COOH d Rp − = Rate of disappearance of carboxylic monomer p R ( ) 3 2 k C OH OH + ⎡ ⎤ = ⎡ ⎤ ⎣ ⎦ ⎣ ⎦ (from previous page) 3 12 k K HA COOH OH = ⎡ ⎤⎡ ⎤⎡ ⎣ ⎦⎣ ⎦⎣ ⎤ ⎦ From equilibrium expression [HA] is constant because it’s regenerated. ' p d COOH R k COO dt − ⎡ ⎤ ⎣ ⎦ = = ⎡ ⎤⎡ ⎣ ⎦⎣ H OH⎤ ⎦ where ' 3 12 k k K HA = ⎡ ⎤ ⎣ ⎦ constant Self-catalyzed: [HA] = [COOH] 2 " p d COOH R k COO dt − ⎡ ⎤ ⎣ ⎦ = = ⎡ ⎤ ⎡ ⎣ ⎦ ⎣ H OH⎤ ⎦ K where k k3 12 " = 3 " p d M R k dt − ⎡ ⎤ ⎣ ⎦ = = ⎡ ⎤ ⎣ ⎦ M separate and integrate " 2 2 1 1 2 o k t M M = − ⎡ ⎤ ⎡ ⎤ ⎣ ⎦ ⎣ ⎦ ( ) 1 o M M = − ⎡ ⎤ ⎡ ⎤ ⎣ ⎦ ⎣ ⎦ π ( ) ( ) 2 2 ' 2 1 2 1 1 n o p M = = ⎡ ⎤ ⎣ ⎦ − π k t + Much slower because of time-dependence ( t ) That’s why people add acid to drive reaction. High Temperature - increase k - remove byproduct (evaporate H2O) Bulk or mass conditions (no solvent) - [M]o is maximum - no need to separate product 10.569, Synthesis of Polymers, Fall 2006 Lecture 3 Prof. Paula Hammond Page 4 of 5 Citation: Professor Paula Hammond, 10.569 Synthesis of Polymers Fall 2006 course materials, MIT OpenCourseWare (http://ocw.mit.edu/index.html), Massachusetts Institute of Technology, Date
  • 5. 10.569, Synthesis of Polymers, Fall 2006 Lecture 3 Prof. Paula Hammond Page 5 of 5 Citation: Professor Paula Hammond, 10.569 Synthesis of Polymers Fall 2006 course materials, MIT OpenCourseWare (http://ocw.mit.edu/index.html), Massachusetts Institute of Technology, Date - viscosity η low until high π - direct processing Use solvent - monomers are not miscible with each other but miscible with solvent - allow high T - dilute viscous media (carrier for viscous media) → improves processing - improves heat and mass transfer