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PARABOLAS IN REAL
WORLD
Vertex
(2,2)
(1,2)
EQUATION
Y=A(X-H)^2+2
2=2A
Divide by 2
A=1
Final Equation
Final Equation Y=ax^2+bx=c
Y=1(X-2)^2+2
Foiled Y=1(x-2) (x-2)+2
Y=x^2-2x-2x+4+2
X^2-4x+6
A=-.083
B=.442
C=1.544
Actual Equation
Y=ax^2+bx+c
Y=-.083(x)^2+.442(X)+1.544
Similarities
My original equation is very similar to my final
equation, my first equation was equal to 1 and my
second equation was equal to 3.
COMPARING
Y=1(X-2)^2+2 Y=.083(X)^2+.442(X)+1.544
Y=1(X-2)(X-2)+2 Y= .083(X)^2+.442(X)+1.544
Y=X^2-2X-2X+4+2
Y=X^2-4X+4+2
Y=X^2-4X+6

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